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Biology B · Edexcel 9BI0 · Paper 3: General and Practical Principles in Biology · June 2019

Edexcel A Level Biology B Paper 3: General and Practical Principles in Biology June 2019 question paper 9BI0/03

2h 30m 120 marks

Edexcel 9BI0 · Paper 3

11 questions
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Question 1

A student investigated the water potential of potato cells.

The student used this method.

● six potato cubes of the same shape and size were cut from the same potato

● each cube was weighed

● each cube was then placed into a different concentration of sucrose solution

● each cube was removed from the sucrose solution after one hour

● each cube was then reweighed and the percentage change in mass was calculated

The table below shows the results of the investigation.

Concentration of sucrose solution / mol dm–3Percentage change in mass (%)
0.0+18.0
0.2+5.0
0.4–8.0
0.6–16.0
0.8–23.5
1.0–24.0
(a)

The student was given a 1.0 mol dm–3 sucrose solution.

State how the student used this solution to make a 0.8 mol dm–3 sucrose solution.

(1)

Answer
Mark scheme for question 1(a)
(b)

Sketch a graph you could use to identify the water potential of potato cells.

(2)

Answer
Mark scheme for question 1(b)
(c)

The method used by the student could be improved to obtain a more accurate value for the water potential of these potato cells.

Justify three improvements that could be made.

(3)

Answer
Mark scheme for question 1(c)

Question 2

Negative feedback control of blood plasma concentration is an example of homeostasis.

A student investigated the effect of drinking water on the volume of urine produced.

The student drank one dm3 of water and waited for half an hour. The student then collected the urine produced every 30 minutes for four hours.

The graph shows the results of this investigation.

Figure for question 2
(a)(i)

Determine the total volume of urine produced during the first two hours.

(1)

Answer
Mark scheme for question 2(a)(i)
(a)(ii)

Explain the role of negative feedback in the control of blood plasma concentration during the first hour after drinking water.

(4)

Answer
Mark scheme for question 2(a)(ii)
(b)

The next day the student drank one dm3 of dilute salt solution with the same water potential as blood plasma.

The student waited half an hour and collected the urine produced every 30 minutes for four hours.

Sketch a graph to predict the results.

Figure for question 2

(1)

Answer
Mark scheme for question 2(b)

Question 3

A student used a light microscope to determine the mean percentage germination of pollen grains.

The photograph shows one high power field of view observed by the student.

Figure for question 3
(a)

The student used a paintbrush to obtain pollen grains from a flower.

Describe the steps taken by the student to see these pollen grains using a microscope.

(3)

Answer
Mark scheme for question 3(a)
(b)

The actual diameter of pollen grain P is 30 µ m.

Calculate the magnification of pollen grain P.

(2)

Answer
Mark scheme for question 3(b)
(c)

The graph shows the results of the investigation.

Figure for question 3
(c)(i)

Explain why the student plotted standard deviation bars on the graph.

(2)

Answer
Mark scheme for question 3(c)(i)
(c)(ii)

Determine the time when the photograph was taken.

(2)

Answer
Mark scheme for question 3(c)(ii)

Question 4

Plant pigments are involved in photosynthesis.

The action spectrum of chloroplasts and the absorption spectrum of the pigments can be determined.

(a)(i)

State the difference between an action spectrum and an absorption spectrum.

(1)

Answer
Mark scheme for question 4(a)(i)
(a)(ii)

State how an action spectrum and an absorption spectrum show that chlorophyll is used in photosynthesis.

(1)

Answer
Mark scheme for question 4(a)(ii)
(b)

Cadmium is an environmental pollutant that affects the synthesis of plant pigments.

A scientist investigated the effect of cadmium on the synthesis of chlorophyll and carotenoid pigments in plants.

The scientist used the following steps in the method.

Step 1: plants were grown in darkness for one week to produce yellow leaves

Step 2: maths symbolleaf discs of the same diameter were taken from the first pair of these leaves

Step 3: maths symbola total of 25 discs was put into tubes containing different cadmium chloride concentrations

Step 4: these tubes were kept at 27 °C and exposed to the same source of light

The table shows information about the pigments chlorophyll a and chlorophyll b and the carotenoids present in the leaf discs after 48 hours.

Cadmium chloride concentration / a.u.Mean concentration of chlorophyll / mg kg‑1Mean concentration of carotenoid / mg kg‑1Ratio of chlorophyll a : bRatio of carotenoid : chlorophyll
0.0384 ± 4.2444 ± 6.21.231.15
0.1204 ± 4.9270 ± 4.51.001.32
1.0180 ± 3.6207 ± 5.20.831.15
3.0146 ± 4.1140 ± 3.10.810.95
5.0126 ± 2.791 ± 1.00.560.71
10.0102 ± 1.964 ± 1.10.800.63
(b)(i)

Analyse the data to deduce the effect of cadmium on the synthesis of plant pigments.

(3)

Answer
Mark scheme for question 4(b)(i)
(b)(ii)

Justify the method used by the scientist.

(5)

Answer
Mark scheme for question 4(b)(ii)

Question 5

Liver cells contain an enzyme called catalase.

This enzyme changes hydrogen peroxide in the liver cells into water and oxygen.

A group of students used the apparatus shown to compare the activity of catalase in raw liver tissue and in boiled liver tissue.

Figure for question 5

The students used the following method.

● a burette filled with water is placed in a beaker containing water

● add hydrogen peroxide to the conical flask

● open the conical flask and drop 0.1g of raw liver into the hydrogen peroxide

● replace the bung on the conical flask

● after 10 seconds pinch the rubber tube to stop any more oxygen entering the burette

● measure the volume of oxygen collected in the burette

● repeat this method for boiled liver

The table shows the results obtained by each student.

StudentVolume of oxygen collected in 10 seconds / cm3
Raw liverBoiled liver
1190
2400
3280
4380
5420
6290
7340
8460
9380
(a)

Explain why no oxygen was produced when boiled liver was added to the hydrogen peroxide.

(3)

Answer
Mark scheme for question 5(a)
(b)

Explain why it was important to measure the volume of oxygen in the first 10 seconds.

(2)

Answer
Mark scheme for question 5(b)
(c)

The results for the volume of oxygen collected by each student using raw liver were different.

Give four possible improvements to the method used by these students that would reduce the variability of the results.

(4)

Answer
Mark scheme for question 5(c)

Question 6

A student measured the distribution of two plant species at the coast.

The distribution was measured from the high water line to 170 m inland.

(a)

State what is meant by the term species.

(1)

Answer
Mark scheme for question 6(a)
(b)
Figure for question 6
(b)(i)

Compare and contrast the distribution of marram grass and elder trees.

(2)

Answer
Mark scheme for question 6(b)(i)
(b)(ii)

Explain how the student could have collected the data shown in the diagram.

(3)

Answer
Mark scheme for question 6(b)(ii)
(c)

The student measured the water content of the soil from the high water line to 170 m inland.

Describe how the student could have carried out these measurements.

(3)

Answer
Mark scheme for question 6(c)
(d)

Marram grass leaves are adapted to enable the plants to survive in dry soil.

The photograph shows a section of a marram grass leaf, as seen using a light microscope.

Figure for question 6

Explain how the structure of this leaf ensures that the water potential at X remains high.

(3)

Answer
Mark scheme for question 6(d)

Question 7

Figure for question 7
(a)

Explain what type of molecule is shown in the diagram.

(2)

Answer
Mark scheme for question 7(a)
(b)

Describe how soya bean plants can be genetically modified to produce large numbers of GM soya bean plants.

(4)

Answer
Mark scheme for question 7(b)
(c)

Some plants have been genetically modified to express viral antigens.

These plants are used as edible vaccines and stimulate immunity when eaten.

Devise an investigation that a scientist could use to measure the effectiveness of this vaccine in mice.

(5)

Answer
Mark scheme for question 7(c)

Question 8

Figure for question 8
(a)

Describe what happens to oxygen at the end of the electron transport chain.

(2)

Answer
Mark scheme for question 8(a)
(b)

A scientist investigated the oxygen consumption of four different mammals.

The table shows the results of this investigation.

MammalBody mass / kgOxygen consumption / dm3 h‑1Oxygen consumption / dm3 kg−1 h−1
Shrew0.0020.02161.08101
Cat31.55.0010‑1
Human80243.0010‑1
Elephant400050
(b)(i)

Calculate the oxygen consumption of the elephant.

Convert your answer into standard form.

........ dm3 kg−1 h−1

(2)

Answer
Mark scheme for question 8(b)(i)
(b)(ii)

Explain the relationship between body mass and oxygen consumption in these mammals.

(4)

Answer
Mark scheme for question 8(b)(ii)
(c)

The diagram shows a respirometer.

Figure for question 8

Explain how a student could modify this respirometer and use it to measure the mean oxygen consumption of a rat.

(4)

Answer
Mark scheme for question 8(c)

Question 9

The diagram shows the time taken in seconds for an impulse to travel through the human heart.

Figure for question 9
(a)

Analyse the information to explain how the times shown in the diagram relate to the cardiac cycle.

(5)

Answer
Mark scheme for question 9(a)
(b)

The mean heart rate of this heart was 72 beats per minute.

Calculate how long the ventricles are relaxed during one cardiac cycle.

(2)

Answer
Mark scheme for question 9(b)
(c)

The effect of exercise on the pH of blood plasma and heart rate was investigated.

The investigation used a sample of three people.

The table shows the results of the investigation before and after excercise.

ActivityMean pH of blood plasmaMean heart rate / beats min‑1
Rest7.472
Exercise7.294
(c)(i)

Analyse the data to explain how the pH of blood plasma affects heart rate.

(4)

Answer
Mark scheme for question 9(c)(i)
(c)(ii)

There were errors in the design of this investigation that reduced the validity of the data.

Explain how this investigation should have been designed to ensure the data was valid.

(4)

Answer
Mark scheme for question 9(c)(ii)

Question 10

When a mouse is put in a new environment, it will move around to find a safe place to live.

This is called exploratory behaviour.

A student investigated exploratory behaviour by putting a mouse into a large box.

The bottom of the box was marked into squares. There were four corner squares (C), two middle squares (M) and six side squares (S).

The marked bottom of the box is shown in the diagram.

CSSC
SMMS
CSSC

The mouse moved about on the bottom of the box. The square occupied by the mouse was recorded every 10 seconds for 10 minutes.

The table shows the results of this investigation.

Total number of times square occupied by the mouse
Corner squareMiddle squareSide square
42612

The student tested the null hypothesis that mice show no significant preference for corner, middle or side squares.

(a)(i)

Calculate the Chi squared value using the formula shown.

Question 10, shown as an image

(2)

Answer
Mark scheme for question 10(a)(i)
(a)(ii)

The table shows some critical values of Chi squared at different degrees of freedom.

Degrees ofp value
freedom0.9000.5000.1000.0500.010
10.0160.4552.7063.8416.635
20.2111.3864.6055.9919.210
30.5842.3666.2517.81511.345
41.0643.3577.7799.48813.277

Use your calculated Chi squared value and this table to comment on the conclusion the student should make about the null hypothesis.

(4)

Answer
Mark scheme for question 10(a)(ii)
(b)

The method used by the student had limitations.

Justify how the student could modify the investigation to address these limitations.

(3)

Answer
Mark scheme for question 10(b)
(c)

The mouse uses its eyes when exploring in the box.

Describe the role of rod cells in initiating action potentials to the brain of the mouse.

(5)

Answer
Mark scheme for question 10(c)

Question 11

The adult American bullfrog, Rana catesbeiana, can live in water or on land.

Adult frogs lay eggs in water where they are fertilised.

The fertilised eggs develop into tadpoles that live only in water.

The photograph shows a tadpole.

Figure for question 11
(a)

State the domain to which Rana catesbeiana belongs.

(1)

Answer
Mark scheme for question 11(a)
(b)

Adult frogs use lungs for gas exchange but tadpoles use gills.

Explain how gills are adapted for gas exchange.

(3)

Answer
Mark scheme for question 11(b)
(c)
(c)(i)

Human activity can cause pollution that reduces the oxygen concentration in water.

Explain why a low oxygen concentration in the water would lower the pH of the blood of the tadpole.

(3)

Answer
Mark scheme for question 11(c)(i)
(c)(ii)
Figure for question 11

(9)

Answer
Mark scheme for question 11(c)(ii)

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