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Biology B · Edexcel 9BI0 · Paper 2: Advanced Physiology, Evolution and Ecology · June 2022

Edexcel A Level Biology B Paper 2: Advanced Physiology, Evolution and Ecology June 2022 question paper 9BI0/02

1h 45m 90 marks

Edexcel 9BI0 · Paper 2

9 questions
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Question 1

The diagram shows DNA replication.

Figure for question 1
(a)

Which of the following is the name of the bond labelled X on the diagram?

Question 1, shown as an image

(1)

Answer
Mark scheme for question 1(a)
(b)

Describe the roles of three named enzymes involved in DNA replication.

(3)

Answer
Mark scheme for question 1(b)
(c)

A section of double-stranded DNA has a total number of 10 000 nucleotides.

Adenine makes up 35% of the nucleotides in this section of double‑stranded DNA.

Calculate the total number of cytosine nucleotides found in this section of DNA.

(2)

Answer
Mark scheme for question 1(c)

Question 2

Plant growth substances and phytochromes are chemicals that affect the growth of plants.

(a)(i)

Which row of the table shows the concentrations required for the fastest growth of lateral buds?

Figure for question 2

(1)

Answer
Mark scheme for question 2(a)(i)
(a)(ii)

Some types of auxin affect the activity of cells in the same way as hormones such as oestrogen affect human cells.

These auxins pass through the cell membrane and affect the synthesis of enzymes.

Explain how these auxins affect the synthesis of enzymes.

(3)

Answer
Mark scheme for question 2(a)(ii)
(b)

Phytochrome is involved in the germination of seeds.

The effect of red (R) light and far-red (FR) light on the germination of lettuce seeds was investigated.

A scientist exposed five groups of 50 seeds to red light for one minute.

The seeds were planted and the mean number that germinated was calculated.

Another five groups each of 50 seeds were then exposed to red light for one minute, followed by far-red light for four minutes.

These seeds were planted and the mean number that germinated was calculated.

The experiment was repeated with different combinations of red light and far‑red light.

The results are shown in the table.

Sequence of red (R) and far‑red (FR) lightMean number of seeds that germinatedStandard deviation (SD)
R45± 4
R, FR5± 2
R, FR, R45± 5
R, FR, R, FR10± 4
R, FR, R, FR, R40± 9

Analyse the data to comment on the effect of red (R) and far-red (FR) light on the germination of lettuce seeds.

(4)

Answer
Mark scheme for question 2(b)

Question 3

The diagram shows the structure of an animal cell.

Figure for question 3
(a)(i)

Which of the following is the name of the structure labelled Q?

Question 3, shown as an image

(1)

Answer
Mark scheme for question 3(a)(i)
(a)(ii)

These cells were cultured in radioactively-labelled amino acids.

In which sequence would the cell structures in the diagram become radioactive during protein synthesis?

Question 3, shown as an image

(1)

Answer
Mark scheme for question 3(a)(ii)
(a)(iii)

Explain one function of lysosomes.

(2)

Answer
Mark scheme for question 3(a)(iii)
(b)
Figure for question 3
(b)(i)

The ratio shown in the graph can be calculated using the formula

Question 3, shown as an image

On day 2, the volume of the cell nucleus was 900 μm3.

Calculate the total volume of this cell on day 2.

Give your answer to two significant figures.

(3)

Answer
Mark scheme for question 3(b)(i)
(b)(ii)

Comment on the changes in the ratios as the zygote develops into a blastocyst.

(3)

Answer
Mark scheme for question 3(b)(ii)

Question 4

The autonomic nervous system controls the heart rate.

(a)

The diagram shows a human brain.

Figure for question 4
(a)(i)

Which region of the brain controls the heart rate?

Question 4, shown as an image

(1)

Answer
Mark scheme for question 4(a)(i)
(a)(ii)

Which one of the following would lead to an increase in heart rate?

Question 4, shown as an image

(1)

Answer
Mark scheme for question 4(a)(ii)
(b)
Figure for question 4
(b)(i)

An atrioventricular valve in the healthy heart has a surface area of 3.5 cm2.

Determine the force that is applied to this atrioventricular valve when it closes.

Use the formula

Question 4, shown as an image

(3)

Answer
Mark scheme for question 4(b)(i)
(b)(ii)

Explain why people with an atrioventricular valve that leaks find exercise difficult.

(4)

Answer
Mark scheme for question 4(b)(ii)

Question 5

The diagram shows a section of a human retina.

Figure for question 5
(a)

Which of the following is the name of the cell labelled X?

Question 5, shown as an image

(1)

Answer
Mark scheme for question 5(a)
(b)

Explain the role of rhodopsin in the generation of a nerve impulse in cell X when light falls on the retina.

(3)

Answer
Mark scheme for question 5(b)
(c)

* (c) A scientist investigated the effect of how the length of time a volunteer spent in darkness affected the sensitivity of their retina to light.

This is the method used:

• the volunteer sat in a room illuminated with white light for twenty minutes

• the lights were switched off and the room was placed into total darkness for one minute

• an LED emitting light of wavelength 500 nm at low light intensity was switched on

• the light intensity was gradually increased until the volunteer was able to see the LED and this minimum light intensity was recorded

• this was repeated with increasing lengths of time that the volunteer was kept in total darkness

• the investigation was then repeated with an LED that emitted red light with a wavelength of 620 nm.

The graph shows the results of this investigation.

Figure for question 5

The graph shows the relative sensitivity of rods and three types of cone to light of different wavelengths.

Figure for question 5

Analyse the graphs to explain the results of this investigation.

(6)

Answer
Mark scheme for question 5(c)

Question 6

The diagram shows a nephron.

Figure for question 6
(a)

Which labelled parts of this nephron would normally contain glucose?

Question 6, shown as an image

(1)

Answer
Mark scheme for question 6(a)
(b)

Oedema is an accumulation of tissue fluid. This is due to less tissue fluid being returned to the blood capillaries.

(b)(i)

Explain how tissue fluid is returned to capillaries.

(3)

Answer
Mark scheme for question 6(b)(i)
(b)(ii)

Furosemides are drugs that are used to reduce oedema. They are diuretics that increase urine production.

Furosemides reduce the active transport of sodium ions by the loop of Henle.

Explain how furosemides cause an increase in urine production.

(4)

Answer
Mark scheme for question 6(b)(ii)

Question 7

The photograph shows a tawny owl. These owls live in areas close to the Arctic Circle.

Figure for question 7

(Source: © LINDA WRIGHT/SCIENCE PHOTO LIBRARY)

Scientists investigated the feather colours of a population of tawny owls. Feather colours of the owls were scored on a scale of 1 to 11, according to how grey or brown they were.

Grey feathered owls were given a score between 6 and 1, with 1 being the most grey.

Brown feathered owls were given a score between 7 and 11, with 11 being the most brown.

The graph shows the percentages of owls in the population with each of the colour scores.

Figure for question 7
(a)

The scientists concluded that feather colour in owls is controlled by a single genetic locus. The brown allele is dominant to the grey allele.

(a)(i)

State what is meant by a dominant allele.

(1)

Answer
Mark scheme for question 7(a)(i)
(a)(ii)

Explain the range of feather colours, shown in the graph, in this population of owls.

(2)

Answer
Mark scheme for question 7(a)(ii)
(a)(iii)

In this population of 120 owls, 84 of them were grey.

Calculate the number of owls that are heterozygous for feather colour.

Use the Hardy-Weinberg equation

(3)

Answer
Mark scheme for question 7(a)(iii)
(b)

* (b) The scientists investigated the effect of climate change on the frequencies of these two alleles for feather colour in populations of tawny owls.

The percentage survival rates of both colours of owl were measured when there were different depths of snow.

The mean depth of snow was recorded each year between 1980 and 2007.

The percentage of owls that were coloured brown between 1960 and 2007 was also recorded.

The graphs show the results.

Figure for question 7 Figure for question 7

The scientists concluded that increased greenhouse gases from human activity are resulting in an increase in the frequency of the brown allele.

Analyse the data to evaluate this conclusion.

(6)

Answer
Mark scheme for question 7(b)

Question 8

The photograph shows a glacier that is melting. As the glacier gradually melts, it leaves behind bare rock.

Figure for question 8

(Source: © CHARLES D. WINTERS/SCIENCE PHOTO LIBRARY)

Scientists sampled the soil from areas that had been uncovered for different lengths of time after the glacier ice had melted.

The table shows the results from the samples.

Length of time since glacier melted / yearsSoil depth / cmMass of nitrate in soil / mg m–2Mass of leaf litter that falls to ground each year / g m–2 yr–1
55.23.81.5
156.44.11.7
407.05.312.8
1009.221.8277.0
15010.835.4335.0
20015.153.3277.0
25016.261.4261.0
(a)

Which of the following should be used to determine if there is an association between length of time since the glacial ice has melted and soil depth?

Question 8, shown as an image

(1)

Answer
Mark scheme for question 8(a)
(b)

Explain how succession brings about the changes in the soil during this period of time.

(5)

Answer
Mark scheme for question 8(b)
(c)

The roots of some of the plants growing around the glacier were found to contain an oxygen binding protein called leghaemoglobin.

The graph shows the oxygen dissociation curve for leghaemoglobin and the oxygen dissociation for haemoglobin.

Figure for question 8
(c)(i)

Leghaemoglobin is a protein that is similar in structure to myoglobin. Both of these proteins have one subunit.

Explain how the oxygen dissociation curve shows that the structure of leghaemoglobin is more similar to myoglobin than to haemoglobin.

(3)

Answer
Mark scheme for question 8(c)(i)
(c)(ii)

Explain how leghaemoglobin enables these plants to grow in waterlogged and compact soils.

(3)

Answer
Mark scheme for question 8(c)(ii)

Question 9

In Kenya, an in-situ conservation project has been set up to make paper from elephant dung.

This project aims to help conserve elephant populations, conserve biodiversity and help local communities.

(a)

Paper is produced from cellulose molecules present in elephant dung.

The diagram shows part of a cellulose molecule.

Figure for question 9
(a)(i)

Which of the following is the name of the monomer labelled X on the diagram?

Question 9, shown as an image

(1)

Answer
Mark scheme for question 9(a)(i)
(a)(ii)

Draw one of the products of the hydrolysis of this part of the cellulose molecule.

(2)

Answer
Mark scheme for question 9(a)(ii)
(a)(iii)

Explain how the structure of cellulose is adapted for its function in plant cell walls.

(3)

Answer
Mark scheme for question 9(a)(iii)
(b)

Elephant conservation often involves the setting up of protected areas to stop poaching. Local people are banned from entering these areas.

This method of elephant conservation sometimes causes conflict with local people, as elephants can trample and eat crops in nearby farmland. Farmers sometimes burn areas of grassland and forest to stop elephants destroying their farmland.

The new paper conservation project encourages local people to make paper from elephant dung they collect from the conservation area. The paper they make is sold at a high price.

Conservationists measured the effect of the new paper project on the index of diversity of the area over two years. They also measured the effect of a protected conservation area where local people were banned from entering on the index of diversity. The results are shown in the table.

AreaAt start of projectIndex of diversity After two years
Conservation area with paper project2.83.6
Conservation area where local people are banned from entering2.42.2
(b)(i)

State why calculating an index of diversity is a better measure of biodiversity than counting the number of different species.

(1)

Answer
Mark scheme for question 9(b)(i)
(b)(ii)

Give two advantages of in-situ conservation of elephants compared with ex-situ conservation of elephants.

(2)

Answer
Mark scheme for question 9(b)(ii)
(b)(iii)

Explain the effect of the new paper project on biodiversity compared with the protected area where local people were banned.

(4)

Answer
Mark scheme for question 9(b)(iii)
(c)

Describe the limitations of CITES in the conservation of organisms such as elephants.

(2)

Answer
Mark scheme for question 9(c)

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