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Biology B · Edexcel 9BI0 · Paper 1: Advanced Biochemistry, Microbiology and Genetics · October 2020

Edexcel A Level Biology B Paper 1: Advanced Biochemistry, Microbiology and Genetics October 2020 question paper 9BI0/01

1h 45m 90 marks

Edexcel 9BI0 · Paper 1

9 questions
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Question 1

The diagram shows a pollen tube entering the embryo sac of a flowering plant.

Figure for question 1

Complete the table to give the name of each labelled structure and the number of sets of chromosomes that each structure contains.

Figure for question 1

(4)

Answer
Mark scheme for question 1

Question 2

The table shows two differences between blood plasma and tissue fluid.

Figure for question 2
(a)

State how tissue fluid is formed.

(1)

Answer
Mark scheme for question 2(a)
(b)

Explain the differences between blood plasma and tissue fluids shown in the table.

(2)

Answer
Mark scheme for question 2(b)
(c)

Some of the tissue fluid is not reabsorbed into the blood capillary.

Describe what happens to the tissue fluid that is not reabsorbed into the blood capillary.

(2)

Answer
Mark scheme for question 2(c)

Question 3

Mosquitoes transmit a number of diseases, including malaria.

The photograph shows a mosquito, Anopheles gambiae.

This mosquito transmits malaria.

Figure for question 3

Source: © Sinclair Stammers / Science photo library

(a)(i)

State the genus of this mosquito.

(1)

Answer
Mark scheme for question 3(a)(i)
(a)(ii)

Mosquitoes belong to the class Insecta.

Some of the insects in this class are subdivided into a group called Diptera.

What is the name of the classification group that includes Diptera?

Question 3, shown as an image

(1)

Answer
Mark scheme for question 3(a)(ii)
(a)(iii)

Which of the following organisms causes the symptoms of malaria?

Question 3, shown as an image

(1)

Answer
Mark scheme for question 3(a)(iii)
(b)

From 2010 to 2015 there was a 29% decrease in the number of deaths from malaria. This was due to prevention and control measures.

(b)(i)

Explain one implication of a named method of controlling malaria.

(2)

Answer
Mark scheme for question 3(b)(i)
(b)(ii)

In 2015, the number of deaths from malaria was 429 000.

Calculate the number of deaths from malaria in 2010.

(2)

Answer
Mark scheme for question 3(b)(ii)
(c)

In 2015, the number of cases of malaria was 211 million. This increased to 216 million cases in 2016.

Give the change in the number of cases of malaria in standard form.

(1)

Answer
Mark scheme for question 3(c)
(d)

Scientists are researching new methods of controlling malaria.

One group used a procedure called gene drive.

This procedure resulted in female mosquitoes that could not bite or could not lay eggs.

One of the scientists said:

‘It will still be at least 5 to 10 years before we consider testing any mosquitoes with gene drive, but now we have some encouraging proof that we’re on the right path.’

Explain why this group are sharing the results of their research.

(2)

Answer
Mark scheme for question 3(d)

Question 4

The photograph shows a blood smear from a healthy person, as seen using a light microscope.

Figure for question 4

Source: © biophoto associates/science photo library

(a)(i)

Which row of the table identifies the cells labelled J and K ?

Figure for question 4

(1)

Answer
Mark scheme for question 4(a)(i)
(a)(ii)

Which is the approximate ratio of erythrocytes to leucocytes in this blood smear?

Question 4, shown as an image

(1)

Answer
Mark scheme for question 4(a)(ii)
(b)

Chronic myelogenous leukaemia (CML) is a blood disorder.

The photograph shows a blood smear from a person with CML, as seen using a light microscope.

Figure for question 4

Explain why a blood smear can be used to diagnose CML.

(2)

Answer
Mark scheme for question 4(b)
(c)
Figure for question 4

(4)

Answer
Mark scheme for question 4(c)

Question 5

The rubella virus stimulates the production of antibodies in humans but usually causes only mild infections.

However, infection of pregnant women can cause serious problems for the developing fetus.

(a)

*(a) Antibodies can be divided into five classes.

The table gives some information about these classes of antibody.

Figure for question 5

1 Colostrum is the first type of milk produced by the mother following birth.

The graph shows the levels of three of these classes of antibody produced in response to infection with the rubella virus.

Figure for question 5

Analyse the information in the table and the graph to assess the role of these five classes of antibody in the immune response to the rubella virus.

(6)

Answer
Mark scheme for question 5(a)
(b)

Vaccination against rubella has helped to reduce the incidence of infection.

Explain the importance of vaccinating as many people as possible against rubella.

(2)

Answer
Mark scheme for question 5(b)

Question 6

Norovirus is a single-stranded RNA, non-enveloped virus.

Norovirus is the most common cause of gastroenteritis.

(a)

The table shows some features used to classify viruses.

Which box in each row shows how these viruses are classified?

Figure for question 6

(3)

Answer
Mark scheme for question 6(a)
(b)

One study into the causes of gastroenteritis involved 162 patients.

This study found that 24.7% of these gastroenteritis cases were caused by viruses.

The pie chart shows the proportion of the different types of virus identified as causing these gastroenteritis cases.

Figure for question 6

Estimate the total number of gastroenteritis cases caused by noroviruses.

(3)

Answer
Mark scheme for question 6(b)
(c)

Norovirus is usually spread through the faecal-oral route.

The diagram shows the pathway that norovirus takes through the body.

Figure for question 6

Describe what happens inside the cells of the small intestine that have taken up the norovirus.

(3)

Answer
Mark scheme for question 6(c)
(d)

Noroviruses can infect an animal as individual viruses or as a cluster of viruses inside a lipid sphere.

A cluster of viruses inside a lipid sphere is called a stealth sphere.

The diagram shows a stealth sphere.

Figure for question 6
(d)(i)

Animals infected with stealth spheres develop gastroenteritis very quickly and with severe symptoms.

Animals infected with individual noroviruses develop gastroenteritis more slowly and with less severe symptoms.

Analyse the information to explain these findings.

(3)

Answer
Mark scheme for question 6(d)(i)
(d)(ii)

Scientists are hoping that new treatments for norovirus infections can be developed to target the stealth sphere.

Analyse the information to explain how targeting the stealth sphere could be used to treat these infections.

(2)

Answer
Mark scheme for question 6(d)(ii)

Question 7

Lipids and carbohydrates are used as respiratory substrates.

The respiration of lipids generates more ATP than the respiration of carbohydrates.

(a)

The table shows bonds that may be found in carbohydrates and lipids.

Which box in each row shows whether the bond may be found in these molecules?

Figure for question 7

(3)

Answer
Mark scheme for question 7(a)
(b)
Figure for question 7
(b)(i)

Where in a cell does the conversion of pyruvate to acetyl coenzyme A take place?

Question 7, shown as an image

(1)

Answer
Mark scheme for question 7(b)(i)
(b)(ii)

Explain why lipids can be respired only in aerobic conditions.

(3)

Answer
Mark scheme for question 7(b)(ii)
(c)

The electron transport chain uses hydrogen ions to generate ATP.

Explain why the respiration of lipids generates more ATP than the respiration of carbohydrates.

(2)

Answer
Mark scheme for question 7(c)
(d)

The respiratory quotient (RQ) can indicate which substrate is being used in respiration.

The formula used to calculate RQ is

Question 7, shown as an image
(d)(i)

State why the RQ for carbohydrate is 1.0.

(1)

Answer
Mark scheme for question 7(d)(i)
(d)(ii)

The table shows the formula for calculating the volume of oxygen used and the volume of carbon dioxide produced in the respiration of lipids.

The number of carbon atoms in the lipid is represented by n.

Volume of oxygen used / a.u.Volume of carbon dioxide produced / a.u.
4.5n + 3.753n + 6

Calculate the RQ for a lipid containing 21 carbon atoms.

(2)

Answer
Mark scheme for question 7(d)(ii)
(e)

Explain why an insect has an RQ of 1.0 at rest and an RQ of 0.7 during flight.

(3)

Answer
Mark scheme for question 7(e)

Question 8

Skin flora include bacteria that live on the skin.

Different parts of the body have different types of bacteria present.

Skin flora are beneficial as they inhibit the growth of pathogenic bacteria on the skin.

Skin flora compete for nutrients and space or secrete toxic chemicals.

(a)

The following are types of bacteria found in the female genital tract:

• Escherichia coli

• Klebsiella species

• Lactobacillus species

• Staphylococcus species.

(a)(i)

Describe how these types of bacteria present in the female genital tract could be identified.

(4)

Answer
Mark scheme for question 8(a)(i)
(a)(ii)

The photograph shows Lactobacilli on a skin cell from the female genital tract.

Figure for question 8

Source: © Janice Carr Content Providers (s): CDC/Dr. Mike Miller

Lactobacilli metabolise glycogen into lactic acid.

Explain how Lactobacilli inhibit the growth of pathogenic bacteria in the female genital tract.

(3)

Answer
Mark scheme for question 8(a)(ii)
(b)

Sperm cells are released into the female genital tract in seminal fluid.

Seminal fluid contains fructose instead of glucose.

The diagram shows the structure of fructose.

Figure for question 8
(b)(i)

Compare and contrast the structure of fructose with the structure of glucose.

(3)

Answer
Mark scheme for question 8(b)(i)
(b)(ii)

Explain the advantages of the presence of fructose in seminal fluid.

(3)

Answer
Mark scheme for question 8(b)(ii)

Question 9

The photograph shows a wombat, an animal that lives in dry parts of Australia.

Figure for question 9

Source: © Blue Gum Pictures/Alamy Stock Photo

Wombats are herbivores, feeding on grasses, leaves and bark. Wombats also dig in the soil for roots.

They have behavioural and physiological adaptations to survive periods of severe drought.

The effect of drought on the health of wild wombats was investigated.

Changes in body mass, body condition and the chemical constituents of stomach contents and faeces were recorded.

These changes were related to the changes in the quality and quantity of the food of wombats.

(a)

Explain why drought affects the quality and quantity of the food of wombats.

(5)

Answer
Mark scheme for question 9(a)
(b)

The table shows some of the measurements made in this investigation.

MeasurementBefore drought10 months into drought14 months into drought2 months after rain
Body condition index…………………………0.860.760.85
Body mass / kg26.425.121.225.2
Organic matter in stomach / g kg-1 dry matter946732704822
Mineral ion content in stomachlowhighhighlow
Moisture content of faeces / g kg-1 wet mass815603522748
(b)(i)

The body condition was expressed as a body condition index (BCI).

The BCI can be calculated using the formula

Question 9, shown as an image

The mass-for-length (Y) of a wombat can be calculated using the formula

Y = (body length × 0.73) – 34.5

A wombat before the drought had a body length of 86.4 cm and a mass of 26.4 kg.

Calculate the BCI of this wombat.

(2)

Answer
Mark scheme for question 9(b)(i)
(b)(ii)

*(ii) Analyse the data to explain the results of this investigation.

(6)

Answer
Mark scheme for question 9(b)(ii)

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