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Biology · AQA 7402 · Paper 2 · June 2019

AQA A Level Biology Paper 2 June 2019 question paper 7402/2

2h 91 marks

Practise the past exam questions by topic

AQA 7402 · Paper 2

10 questions
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Question 1

Succession occurs in natural ecosystems. Describe and explain how succession occurs.

[4 marks]

Figure 1 shows percentages of energy transferred from sunlight to a zebra in a grassland ecosystem.

Figure for question 1

Use Figure 1 to calculate the percentage of sunlight energy that would be transferred into the faeces and urine of a zebra. Give your answer to 3 significant figures.

[1 mark]

In this ecosystem the net productivity of the vegetation is 24 525kJ mmaths symbol2 yearmaths symbol1

Use this information and Figure 1 to calculate the energy stored in new tissues of the

Question 1, shown as an image
Question 1, shown as an image

[2 marks]

Question 2

Sickle cell disease (SCD) is a group of inherited disorders. People with SCD have sickle-shaped red blood cells. A single base substitution mutation can cause one type of SCD. This mutation causes a change in the structure of the beta polypeptide chains in haemoglobin.

Explain how a single base substitution causes a change in the structure of this polypeptide.

Do not include details of transcription and translation in your answer.

[3 marks]

Haematopoietic stem cell transplantation (HSCT) is a long-term treatment for SCD. In HSCT, the patient receives stem cells from the bone marrow of a person who does not have SCD. The donor is often the patient’s brother or sister. Before the treatment starts, the patient’s faulty bone marrow cells have to be destroyed.

Use this information to explain how HSCT is an effective long-term treatment for SCD.

[3 marks]

A new long-term treatment for SCD involves the use of gene therapy.

Figure 2 shows some of the stages involved in this treatment in a child with SCD.

Figure for question 2

Some scientists have concluded that this method of gene therapy will be a more effective long-term treatment for SCD than HSCT. Use all the information provided to evaluate this conclusion.

[3 marks]

Question 3

Figure for question 3

Explain why the student removed the shoot tip from each seedling.

[2 marks]

Explain why the student added glucose solution to each Petri dish.

[2 marks]

Explain why the lids were kept on the Petri dishes.

[2 marks]

Describe and explain the results shown in Table 1 and suggest how the results might have differed if lengths of root had been used.

[3 marks]

The student produced the different concentrations of IAA using a stock 1 g dm–3 solution of IAA (1 g dm–3 = 1 part per thousand) and distilled water.

Complete Table 2 with the volumes of stock IAA solution and distilled water required to produce 40cm3 of 10 ppm (parts per million) IAA solution.

Figure for question 3

[1 mark]

Question 4

Scientists investigated the effect of a decrease in pH on muscle contraction. The scientists did the investigation with four different preparations of isolated muscle tissue: A, B, C and D.

A - mouse muscle fibres at typical pH of mouse muscle tissue (control 1).

B - mouse muscle fibres at 0.5 pH units below typical pH.

C - rabbit muscle fibres at typical pH of rabbit muscle tissue (control 2).

D - rabbit muscle fibres at 0.5 pH units below typical pH.

They measured the force of muscle contraction of the muscle fibres at 12 °C, 22 °C and 32 °C

Figure 3 shows the results the scientists obtained for B and D compared with the appropriate control.

Figure for question 4

A student looked at the results and concluded that a decrease in pH does cause a decrease in the force of muscle contraction.

Use Figure 3 to evaluate this conclusion.

[4 marks]

Another group of scientists suggested that a decrease in the force of muscle contraction is caused by an increase in the concentration of inorganic phosphate, Pi, in muscle tissues.

Their hypothesis is that an increase in the concentration of Pi prevents the release of calcium ions within muscle tissues.

Explain how a decrease in the concentration of calcium ions within muscle tissues could cause a decrease in the force of muscle contraction.

[3 marks]

In muscles, pyruvate is converted to lactate during prolonged exercise.

Explain why converting pyruvate to lactate allows the continued production of ATP by anaerobic respiration.

[2 marks]

Question 5

Describe the role of glucagon in gluconeogenesis.

Do not include in your answer details on the second messenger model of glucagon action.

[2 marks]

The gene that codes for glucagon is 9.531 kilobases in length. The DNA helix makes one complete turn every 10 base pairs. Every complete turn is 3.4 nm in length.

Use this information to calculate the length in micrometres (µm) of the gene for glucagon. Give your answer to 3 significant figures.

[2 marks]

Metformin is a drug commonly used to treat type II diabetes. Metformin’s ability to lower the blood glucose concentration involves a number of mechanisms including:

• increasing a cell’s sensitivity to insulin

• inhibiting adenylate cyclase.

Explain how increasing a cell’s sensitivity to insulin will lower the blood glucose concentration.

[2 marks]

Explain how inhibiting adenylate cyclase may help to lower the blood glucose concentration.

[3 marks]

Question 6

In fruit flies, a gene for body colour has a dominant allele for grey body, G, and a recessive allele for black body, g.

A gene for eye colour has a dominant allele for red eyes, R, and a recessive allele for white eyes, r, and is located on the X chromosome.

Figure 4 shows the phenotypes of fruit flies over four generations.

Figure for question 6

Give the full genotype of the fly numbered 6 in Figure 4.

[1 mark]

Give one piece of evidence from Figure 4 to show that the allele for grey body colour is dominant.

[1 mark]

Explain one piece of evidence from Figure 4 to show that the gene for body colour is not on the X chromosome.

[2 marks]

A population of fruit flies contained 64% grey-bodied flies. Use the Hardy–Weinberg equation to calculate the percentage of flies heterozygous for gene G.

[2 marks]

Question 7

In photosynthesis, which chemicals are needed for the light-dependent reaction? Tick (✓) one box.

Figure for question 7

[1 mark]

Describe what happens during photoionisation in the light-dependent reaction.

[2 marks]

A student obtained a solution of pigments from the leaves of a plant. Then the student used paper chromatography to separate the pigments.

Figure 5 shows the chromatogram produced.

Figure for question 7

Explain why the student marked the origin using a pencil rather than using ink.

[1 mark]

Describe the method the student used to separate the pigments after the solution of pigments had been applied to the origin.

[2 marks]

Calculating the Rf values of the pigments can help to identify each pigment. An Rf value compares the distance the pigment has moved from the origin with the distance the solvent front has moved from the origin.

Question 7, shown as an image

The distance each pigment has moved is measured from the middle of each spot.

Pigment A has an Rf value of 0.95

Use Figure 5 to calculate the Rf value of pigment C.

Question 7, shown as an image

[1 mark]

The pigments in leaves are different colours. Suggest and explain the advantage of having different coloured pigments in leaves.

[1 mark]

Question 8

What is a DNA probe?

[2 marks]

DNA probes are used to detect specific base sequences of DNA.

The process is shown in Figure 6.

Figure for question 8

Describe how the DNA is broken down into smaller fragments.

[2 marks]

The DNA on the nylon membrane is treated to form single strands. Explain why.

[1 mark]

A scientist used DNA probes and electrophoresis to screen four volunteers for five different viral DNA fragments.

Figure 7 shows the results the scientist obtained. The lanes numbered 2 to 5 represent the four volunteers.

Figure for question 8

Lane 1 of Figure 7 enabled the size of the different viral fragments to be determined.

Suggest and explain how.

[2 marks]

The lengths of the viral DNA fragments were:

• 600 base pairs

• 250 base pairs

• 535 base pairs

• 300 base pairs

• 500 base pairs.

Which volunteers had at least one of the viral DNA fragments with 250 base pairs or 535 base pairs?

[1 mark]

Question 9

The sundew is a small flowering plant, growing in wet habitats such as bogs and marshes. The soil in bogs and marshes is acidic and has very low concentrations of some nutrients. The sundew can trap and digest insects.

Describe how you could estimate the size of a population of sundews in a small marsh.

[5 marks]

Suggest and explain how digesting insects helps the sundew to grow in soil with very low concentrations of some nutrients.

[2 marks]

Question 10

Figure for question 10

Damage to the myelin sheath of neurones can cause muscular paralysis (lines 2–4).

Explain how.

[3 marks]

Sometimes Guillain–Barré syndrome causes heart rate irregularities (lines 4–5).

Suggest and explain why.

[3 marks]

The first successful drug trial to reduce concentrations of huntingtin in the brain used single-stranded DNA molecules (lines 13–14).

Suggest and explain how this drug could cause a reduction in the concentration of the protein huntingtin.

[3 marks]

Scientists from the first successful drug trial to reduce concentrations of huntingtin (lines 9–11) reported that the drug is not a cure for Huntington’s disease.

Suggest two reasons why the drug should not be considered a cure. Do not include repeats of the drug trial in your answer.

[2 marks]

Suggest two reasons why people had the drug injected into the cerebrospinal fluid (lines 12–13) rather than taking a pill containing the drug.

[2 marks]

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