Question 1
A value for enthalpy of solution can be determined in two ways:
• from a cycle, using lattice enthalpy and enthalpies of hydration
• from the results of a calorimetry experiment.
Define the term enthalpy of lattice dissociation.
[2 marks]
The enthalpy of solution for ammonium nitrate is the enthalpy change for the reaction shown.
Draw a suitably labelled cycle and use it, with data from Table 1, to calculate the enthalpy of lattice dissociation for ammonium nitrate.
[3 marks]
A student does an experiment to determine a value for the enthalpy of solution for ammonium nitrate.
The student uses this method.
• Measure 25.0 cm3 of distilled water in a measuring cylinder.
• Pour the water into a beaker.
• Record the temperature of the water in the beaker.
• Add 4.00 g of solid NH4NO3 to the water in the beaker.
• Stir the solution and record the lowest temperature reached.
Table 2 shows the student’s results.
Calculate the enthalpy of solution, in kJ mol1, for ammonium nitrate in this experiment.
Assume that the specific heat capacity of the solution, c = 4.18 J K1 g
1
Assume that the density of the solution = 1.00 g cm3
[3 marks]
The uncertainty in each of the temperature readings from the thermometer used in this experiment is ±0.1°C
Calculate the percentage uncertainty in the temperature change in this experiment.
Percentage uncertainty
[1 mark]
Suggest a change to the student’s method, using the same apparatus, that would reduce the percentage uncertainty in the temperature change.
Give a reason for your answer.
[2 marks]
Another student obtained a value of +15 kJ mol1 using the same method.
Suggest the main reason for the difference between this experimental value for the enthalpy of solution and the correct value of +26 kJ mol1
[1 mark]
Table 3 shows some entropy data at 298 K
| Entropy S / J K1mol1 | |
| NH4NO3(s) | 151 |
| NH4 | 113 |
| NO3 | 146 |
Calculate a value for the Gibbs free-energy change (G), at 298 K, for the reaction when ammonium nitrate dissolves in water.
Use data from Table 3 and the value of H from the equation. Assume for the solvent, water, that the entropy change,
S = 0
Explain what the calculated value of G indicates about the feasibility of this reaction at 298 K
[4 marks]
Ammonium nitrate decomposes as shown.
The entropy change (S) for this reaction is +144 J K–1 mol
1
Calculate the temperature at which this reaction becomes feasible.
[2 marks]