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Maths B (MEI) · OCR H640 · Pure Mathematics and Comprehension · June 2024

OCR A Level Maths B (MEI) Pure Mathematics and Comprehension June 2024 question paper H640/03

2h 75 marks

Materials

Practise the past exam questions by topic

OCR H640 · Paper 3

18 questions
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Question 2

(a)

The function f(x) is defined by

Question 2, shown as an image

Find an expression for f-1(x) and state the domain of this inverse function.

[3]

Answer
Mark scheme for question 2(a)
(b)

Explain why g(x) = 1 + x2, with domain all real numbers, has no inverse function.

[1]

Answer
Mark scheme for question 2(b)

Question 3

In this question you must show detailed reasoning.

The diagram shows the curve with equation y = x5 and the square OABC where the points A, B and C have coordinates (1, 0), (1, 1) and (0, 1) respectively.

The curve cuts the square into two parts.

Figure for question 3

Show that the relationship between the areas of the two parts of the square is

Question 3, shown as an image

[4]

Question 9

This question is about the equation f(x) = 0, where f(x) = x4 - x - fraction Fig. 9.1 shows the curve y = f (x).

Figure for question 9
(a)

Show, by calculation, that the equation f (x) = 0 has a root between x = 1 and x = 2.

[2]

Answer
Mark scheme for question 9(a)
(b)

Fig. 9.2 shows part of a spreadsheet being used to find a root of the equation.

Figure for question 9

Write down a suitable number to use as the next value of x in the spreadsheet.

[1]

Answer
Mark scheme for question 9(b)
(c)

Determine a root of the equation f (x) = 0. Give your answer correct to 1 decimal place.

[1]

Answer
Mark scheme for question 9(c)
(d)

Fig. 9.3 shows a similar spreadsheet being used to search for another root of f (x) = 0.

Figure for question 9
(d)(i)

Explain why it looks from rows 2 and 3 of the spreadsheet as if there is a root between

0 and 1.

[1]

Answer
Mark scheme for question 9(d)(i)
(d)(ii)

Explain why this process will not find a root between 0 and 1.

[1]

Answer
Mark scheme for question 9(d)(ii)

Question 10

The diagram below shows the curve y = f (x).

Figure for question 10

Sketch the graph of the gradient function, y = f ′(x), on the copy of the diagram in the Printed

Answer Booklet.

[3]

Answer
Mark scheme for question 10

Question 11

Fig. 11.1 shows the curve with equation y = g (x) where g (x) = x sin x + cos x and the curve of the gradient function y = g ′ (x) for - 2 π ⩽ x ⩽ 2 π.

Fig. 11.1

Figure for question 11
(a)

Show that the x‑coordinates of the points on the curve y = g(x) where the gradient is 1 satisfy the equation fraction - cos x = 0.

[3]

(b)

Fig. 11.2 shows part of the curve with equation y = fraction - cos x.

Fig. 11.2

Figure for question 11

Use the Newton‑Raphson method with a suitable starting value to find the smallest positive x ‑coordinate of a point on the curve y = x sin x + cos x where the gradient is 1.

You should write down at least the following.

• The iteration you use

• The starting value

• The solution correct to 4 decimal places

[4]

(c)

Explain why x1 = 3 is not a suitable starting value for the Newton‑Raphson method in

part (b).

[1]

Question 13

Substitute appropriate values of t1 and t2 to verify that t1t2 gives the correct value for the

y ‑coordinate of the point of intersection of the tangents at the points A and B in Fig. C1.

Figure for question 13 Figure for question 13

[1]

Question 16

Question 16, shown as an image

[2]

Answer
Mark scheme for question 16

Question 18

A student is investigating the intersection points of tangents to the curve y = 6x2 - 7x + 1. She uses software to draw tangents at pairs of points with x ‑coordinates differing by 5.

Find the equation of the curve that all the intersection points lie on.

[2]

The paper as printed

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