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Edexcel A Level Physics

Topic questions Space physics Orbits of planets and satellites

Orbits of planets and satellites

12 questions · 133 marks · about 2.5 hours

Orbits of planets and satellites questions

Edexcel 9PH0 Orbits of planets and satellites 12 questions

Paper 2: Advanced Physics II June 2025, Question 17 9 marks

The asteroid Bennu is in an approximately circular orbit around the Sun. Scientists consider that Bennu may collide with Earth within the next century.

(a)

In 2060 Bennu will be 7.49×108m from the Earth.

(a)(i)

Show that the mass of Bennu is about 7.8maths symbol1010kg.

mean radius of Bennu = 245 m average density of Bennu = 1260 kg m–3

[3]
Reveal mark scheme Mark scheme for question 17(a)(i)
(a)(ii)

Calculate the magnitude of the force F between Bennu and Earth in 2060.

mass of Earth = 5.98maths symbol1024kg

[2]
Reveal mark scheme Mark scheme for question 17(a)(ii)
(b)

The orbital time of Bennu around the Sun is 1.17 years.

Calculate the mass of the Sun.

average distance of Bennu from the Sun = 1.70maths symbol1011m

Question 17, shown as an image
[4]
Reveal mark scheme Mark scheme for question 17(b)

Paper 2: Advanced Physics II June 2024, Question 2 1 mark

A satellite of mass m orbits the Earth with speed v.

What is the speed of a satellite of mass 2m orbiting at the same distance from the Earth?

Question 2, shown as an image
Question 2, shown as an image
Question 2, shown as an image
Question 2, shown as an image
[1]
Reveal mark scheme Mark scheme for question 2

Paper 2: Advanced Physics II June 2023, Question 18 14 marks

Galileo is credited with inventing the first telescope in 1610. The picture shows an early demonstration of the telescope.

Figure for question 18

(Source: © CPA Media Pte Ltd/Alamy Stock Photo)

A converging lens was positioned at one end of the telescope. A diverging lens was placed at the other end and a person looked through this lens.

(a)

The converging lens produced an image at a distance equal to the focal length of the lens.

Explain what can be concluded about the object being viewed.

[2]
Reveal mark scheme Mark scheme for question 18(a)
(b)

The final image produced by the telescope is described as virtual and upright.

State what is meant by virtual and upright.

Virtual

Upright

[2]
Reveal mark scheme Mark scheme for question 18(b)
(c)

The image, I, produced by the converging lens is at a distance from the diverging lens equal to the focal length of the diverging lens, as shown. This image acts as an object for the diverging lens.

Figure for question 18

The distance equal to the focal length on the other side of the lens is marked with F.

Draw the ray diagram for the diverging lens.

[3]
Reveal mark scheme Mark scheme for question 18(c)
(d)

Galileo’s first telescope had a magnification of 10, and a distance between the centres of the two lenses of 90 cm.

Question 18, shown as an image

Calculate the focal length of each lens.

[2]
Reveal mark scheme Mark scheme for question 18(d)
(e)

Galileo was the first person to observe Jupiter’s larger moons.

Ganymede is Jupiter’s largest moon. The distance between the centre of Ganymede and the centre of Jupiter is 1.07×106km. Ganymede takes 171 hours to complete an orbit around Jupiter.

Calculate the mass of Jupiter.

[5]
Reveal mark scheme Mark scheme for question 18(e)

Paper 2: Advanced Physics II November 2021, Question 17 11 marks

Also involves Kinetic, elastic and gravitational potential energy · Conservation and dissipation of energy

Astronomers observing stars at the centre of our galaxy have suggested that many of them are orbiting a supermassive black hole. The mass of this black hole is 9.2 maths symbol 1036kg.

(a)

Calculate the orbital period for a star in a circular orbit at a distance of 1.9 maths symbol 1014m from a black hole of this mass.

[3]
Reveal mark scheme Mark scheme for question 17(a)
(b)

The star S0-2 is in a highly elliptical orbit around the position of the black hole.

At its point of closest approach, S0-2 is at a distance of 1.8 maths symbol 1013m from the centre of the black hole.

At the most distant point of its orbit, S0-2 is 2.7 maths symbol 1014m from the black hole.

(b)(i)

Show that the change in gravitational potential between the closest and most distant points in this orbit is about 3 maths symbol 1013J kg−1.

[2]
Reveal mark scheme Mark scheme for question 17(b)(i)
(b)(ii)

At its point of closest approach, the star is travelling at a speed of 8.1 maths symbol 106m s−1.

Calculate the speed of S0-2 at the furthest point in its orbit using the change in gravitational potential.

mass of S0-2 = 2.4 maths symbol 1031kg

[3]
Reveal mark scheme Mark scheme for question 17(b)(ii)
(c)

Trigonometric parallax and Hubble’s law are two methods used to determine astronomical distances. Explain whether either of these methods is suitable to determine the distance to S0-2.

[3]
Reveal mark scheme Mark scheme for question 17(c)

Paper 2: Advanced Physics II November 2020, Question 16 12 marks

Also involves Kinetic, elastic and gravitational potential energy

Astronauts on the 1971 Apollo 14 mission to the Moon brought back many rock samples. It is now believed that one of these contains a piece of rock that originated on Earth about 4 billion years (4 × 109 years) ago.

The piece of rock is believed to have been launched into space when an asteroid struck the Earth.

(a)

The rock sample contains uranium. The radioactive decay of uranium allows it to be used to determine the time since the rock was formed on the Earth.

(a)(i)

The uranium isotope23892U becomes the lead isotope20682Pb through a series of radioactive decays.

Calculate the number of α particles and the number of β particles emitted for one nucleus of23892U to decay to become a nucleus of20682Pb.

[2]
Reveal mark scheme Mark scheme for question 16(a)(i)
(a)(ii)

The half-life of23892U is 4.47 maths symbol 109 years. The half-lives of the other stages in the decay to20682Pb are relatively so short that they can be ignored.

There was no lead in the rock when it formed, so all the20682Pb in the sample is a product of23892U decay. In the sample, for every 103 uranium nuclei present at the start, 50 are now lead nuclei.

Show that the age of the sample is about 4 × 109 years.

[3]
Reveal mark scheme Mark scheme for question 16(a)(ii)
(b)

The gravitational potential between the Earth and the Moon due to the combined effect of their gravitational fields increases to a maximum value of −1.28 MJ kg−1 at a point between them.

Calculate the minimum speed at which a rock would have to leave the Earth in order to reach the Moon.

In your calculation, you may assume the rock has zero kinetic energy when it has maximum potential energy.

mass of Earth = 5.97 maths symbol 1024kg radius of Earth = 6370 km

[4]
Reveal mark scheme Mark scheme for question 16(b)
(c)

Four billion years ago, the Moon had a different orbital period, because it was closer to the Earth than it is today.

Calculate the period of the Moon’s orbit four billion years ago, when the radius of its orbit was 1.34 maths symbol 108m.

mass of Earth = 5.97 × 1024kg

[3]
Reveal mark scheme Mark scheme for question 16(c)

Paper 2: Advanced Physics II October 2020, Question 16 12 marks

Also involves Kinetic, elastic and gravitational potential energy

Astronauts on the 1971 Apollo 14 mission to the Moon brought back many rock samples. It is now believed that one of these contains a piece of rock that originated on Earth about 4 billion years (4 × 109 years) ago.

The piece of rock is believed to have been launched into space when an asteroid struck the Earth.

(a)

The rock sample contains uranium. The radioactive decay of uranium allows it to be used to determine the time since the rock was formed on the Earth.

(a)(i)

The uranium isotope23892U becomes the lead isotope20682Pb through a series of radioactive decays.

Calculate the number of α particles and the number of β particles emitted for one nucleus of23892U to decay to become a nucleus of20682Pb.

[2]
Reveal mark scheme Mark scheme for question 16(a)(i)
(a)(ii)

The half-life of23892U is 4.47 maths symbol 109 years. The half-lives of the other stages in the decay to20682Pb are relatively so short that they can be ignored.

There was no lead in the rock when it formed, so all the20682Pb in the sample is a product of23892U decay. In the sample, for every 103 uranium nuclei present at the start, 50 are now lead nuclei.

Show that the age of the sample is about 4 × 109 years.

[3]
Reveal mark scheme Mark scheme for question 16(a)(ii)
(b)

The gravitational potential between the Earth and the Moon due to the combined effect of their gravitational fields increases to a maximum value of −1.28 MJ kg−1 at a point between them.

Calculate the minimum speed at which a rock would have to leave the Earth in order to reach the Moon.

In your calculation, you may assume the rock has zero kinetic energy when it has maximum potential energy.

mass of Earth = 5.97 maths symbol 1024kg radius of Earth = 6370 km

[4]
Reveal mark scheme Mark scheme for question 16(b)
(c)

Four billion years ago, the Moon had a different orbital period, because it was closer to the Earth than it is today.

Calculate the period of the Moon’s orbit four billion years ago, when the radius of its orbit was 1.34 maths symbol 108m.

mass of Earth = 5.97 × 1024kg

[3]
Reveal mark scheme Mark scheme for question 16(c)

Paper 3: General and Practical Principles in Physics November 2020, Question 11 18 marks

Solar panels consisting of combinations of photovoltaic cells use energy in the radiation received from the Sun to generate electricity.

(a)

An advertisement for solar panels claims that the intensity of radiation from the Sun incident at the top of the Earth’s atmosphere is more than 2 kW m−2.

Assess the validity of this claim.

radius of Sun = 6.96 × 108m

surface temperature of Sun = 5790 K

distance from Sun to Earth = 1.50 × 1011m

[4]
Reveal mark scheme Mark scheme for question 11(a)
(b)

The average intensity of radiation from the Sun incident at the Earth’s surface over a 24-hour period has been determined to be 164 W m−2.

Figure for question 11
(b)(i)

The average intensity of radiation from the Sun at the Earth’s surface is much less than the intensity incident at the top of the Earth’s atmosphere.

Explain why.

[4]
Reveal mark scheme Mark scheme for question 11(b)(i)
(b)(ii)

It is claimed that the area of solar panels needed to generate 100 GW of power is about 0.5% of the surface area of the Earth.

Assess the validity of this claim.

radius of Earth = 6.4 × 106m

typical efficiency of solar panels = 25%

[4]
Reveal mark scheme Mark scheme for question 11(b)(ii)
(c)

Scientists are developing a space station equipped with large solar panels. The space station would be located in a geostationary orbit. The space station would transfer energy to Earth as microwaves.

(c)(i)

A space station in a geostationary orbit is above the equator and has a period of 24 hours.

Explain one advantage of locating the space station in a geostationary orbit.

[2]
Reveal mark scheme Mark scheme for question 11(c)(i)
(c)(ii)

Calculate the height h of the space station above the equator when it is in a geostationary orbit.

mass of Earth = 6.00 × 1024kg

24 hours = 8.64 maths symbol 104s

[4]
Reveal mark scheme Mark scheme for question 11(c)(ii)

Paper 3: General and Practical Principles in Physics October 2020, Question 11 18 marks

Solar panels consisting of combinations of photovoltaic cells use energy in the radiation received from the Sun to generate electricity.

(a)

An advertisement for solar panels claims that the intensity of radiation from the Sun incident at the top of the Earth’s atmosphere is more than 2 kW m−2.

Assess the validity of this claim.

radius of Sun = 6.96 × 108m

surface temperature of Sun = 5790 K

distance from Sun to Earth = 1.50 × 1011m

[4]
Reveal mark scheme Mark scheme for question 11(a)
(b)

The average intensity of radiation from the Sun incident at the Earth’s surface over a 24-hour period has been determined to be 164 W m−2.

Figure for question 11
(b)(i)

The average intensity of radiation from the Sun at the Earth’s surface is much less than the intensity incident at the top of the Earth’s atmosphere.

Explain why.

[4]
Reveal mark scheme Mark scheme for question 11(b)(i)
(b)(ii)

It is claimed that the area of solar panels needed to generate 100 GW of power is about 0.5% of the surface area of the Earth.

Assess the validity of this claim.

radius of Earth = 6.4 × 106m

typical efficiency of solar panels = 25%

[4]
Reveal mark scheme Mark scheme for question 11(b)(ii)
(c)

Scientists are developing a space station equipped with large solar panels. The space station would be located in a geostationary orbit. The space station would transfer energy to Earth as microwaves.

(c)(i)

A space station in a geostationary orbit is above the equator and has a period of 24 hours.

Explain one advantage of locating the space station in a geostationary orbit.

[2]
Reveal mark scheme Mark scheme for question 11(c)(i)
(c)(ii)

Calculate the height h of the space station above the equator when it is in a geostationary orbit.

mass of Earth = 6.00 × 1024kg

24 hours = 8.64 maths symbol 104s

[4]
Reveal mark scheme Mark scheme for question 11(c)(ii)

Paper 3: General and Practical Principles in Physics June 2019, Question 6 13 marks

Also involves Telescopes

In 1990, the Hubble Space Telescope (HST) was launched into a low Earth orbit above the Earth’s atmosphere.

(a)

HST orbits the Earth in a circular orbit with a speed of 7.59 km s–1.

mass of Earth = 5.97 × 1024 kg radius of Earth = 6.37 maths symbol 106 m

(a)(i)

Show that the height of HST above the surface of the Earth is about 6 × 105 m.

[3]
Reveal mark scheme Mark scheme for question 6(a)(i)
(a)(ii)

Calculate the increase in the gravitational potential energy as HST is raised, from its initial position at the Earth’s surface, to its orbital height.

mass of HST = 11 600 kg

[2]
Reveal mark scheme Mark scheme for question 6(a)(ii)
(a)(iii)

A student suggests that giving HST more energy than that required in (ii) would result in the satellite orbiting at a greater height and with a greater speed.

Assess the validity of the student’s suggestion.

[4]
Reveal mark scheme Mark scheme for question 6(a)(iii)
(b)

The transmission of electromagnetic radiation through the atmosphere is shown on the graph.

Figure for question 6

State one advantage shown by this graph of positioning a telescope above the atmosphere.

[1]
Reveal mark scheme Mark scheme for question 6(b)
(c)

High resolution images from HST allow astronomers to make detailed measurements of very distant galaxies. The graph shows how the recessional velocities of distant galaxies depend on their distance from Earth.

Figure for question 6

Determine an age for the universe.

[3]
Reveal mark scheme Mark scheme for question 6(c)

Paper 3: General and Practical Principles in Physics June 2018, Question 11 10 marks

The International Space Station (ISS) is in a low Earth orbit. Astronauts in ISS have an apparent weight of zero. In order to determine their mass, the astronauts must secure themselves to a platform which is set into oscillation and moves with simple harmonic

Figure for question 11
(a)

Explain why the astronauts in the ISS have an apparent weight of zero.

[2]
Reveal mark scheme Mark scheme for question 11(a)
(b)

State what is meant by simple harmonic motion.

[2]
Reveal mark scheme Mark scheme for question 11(b)
(c)

Describe how, using a stopwatch and a ruler, the following quantities could be determined for the oscillating platform:

(c)(i)

the frequency of oscillation

[2]
Reveal mark scheme Mark scheme for question 11(c)(i)
(c)(ii)

the maximum speed of the platform.

[2]
Reveal mark scheme Mark scheme for question 11(c)(ii)
(d)

The platform continues to move with simple harmonic motion at the same frequency, but its amplitude is doubled.

Explain how the maximum kinetic energy of the platform will change.

[2]
Reveal mark scheme Mark scheme for question 11(d)

Paper 2: Advanced Physics II June 2017, Question 12 5 marks

Also involves Circular motion

The diagram shows two black holes, A and B, orbiting each other.

Assume that the centre of mass C of the system is the centre of a circular orbit for each black hole as shown in the diagram.

Figure for question 12

Black hole A is in an orbit of radius 2.9maths symbol1010m and black hole B is in an orbit of radius 3.6maths symbol1010m. Both orbit with the same period, so the total distance between them is 6.5maths symbol1010m.

(a)

Calculate the force between the black holes.

mass of Sun, Mmaths symbol = 1.99maths symbol1030kg mass of black hole A = 36Mmaths symbol mass of black hole B = 29Mmaths symbol

[2]
Reveal mark scheme Mark scheme for question 12(a)
(b)

By considering the orbit of one black hole about C, determine the period of the orbit.

[3]
Reveal mark scheme Mark scheme for question 12(b)

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