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Edexcel A Level Physics

Topic questions Forces Stress, strain & the Young modulus

Stress, strain & the Young modulus

13 questions · 101 marks · about 2 hours

Stress, strain and the Young modulus questions

Edexcel 9PH0 Stress, strain and the Young modulus 13 questions

Paper 2: Advanced Physics II June 2025, Question 20 11 marks

Also involves Gravity and weight

The photograph shows the Petronas Twin Towers in Kuala Lumpur, which are the world’s tallest twin buildings.

Figure for question 20
(a)

Each tower is supported by 16 cylindrical concrete columns.

Calculate the stress at the base of each cylindrical concrete column.

mass of each tower = 3.0maths symbol108kg diameter of each column = 2.4 m

[5]
Reveal mark scheme Mark scheme for question 20(a)
(b)

Tall buildings sway in the wind. The design of the Petronas Towers permits safe movement of the towers.

(b)(i)

The towers were designed to permit a maximum horizontal displacement of 0.90 m at the top of the towers. The natural frequency of each tower is 0.17 Hz.

Calculate the maximum velocity at the top of one of the towers when the tower is oscillating at its natural frequency.

[3]
Reveal mark scheme Mark scheme for question 20(b)(i)
(b)(ii)

The twin towers were linked together to improve the response of the building to strong winds.

The graph below shows how the maximum displacement x varies with the frequency f for a single tower and for two linked towers.

Figure for question 20

Explain the behaviour of a single tower compared with the behaviour of the linked towers.

[3]
Reveal mark scheme Mark scheme for question 20(b)(ii)

Paper 2: Advanced Physics II June 2024, Question 10 1 mark

A wire of length L and diameter d is fixed at one end. A force F is applied to the wire causing an extension e. A second wire, made of the same material, of length 2L and diameter fraction, is fixed in the same way. A force 2 F is applied to this wire.

What is the extension of the second wire?

Question 10, shown as an image
Question 10, shown as an image
[1]
Reveal mark scheme Mark scheme for question 10

Paper 3: General and Practical Principles in Physics June 2024, Question 1 8 marks

A student stretched a length of nylon fishing line using the apparatus shown below.

Figure for question 1
(a)

The nylon fishing line was stretched by adding masses to the mass holder. The positions of the bottom of the mass holder were measured as masses were added. For each mass, the extension of the nylon fishing line was calculated. The student recorded the results, as shown in the table.

Mass / kgExtension / cm
0.050.4
0.10.8
0.252.1
0.53.9
0.756.0
1.07.2

Criticise the recording of these results.

[2]
Reveal mark scheme Mark scheme for question 1(a)
(b)

Describe how the extension of the nylon fishing line could have been determined as accurately as possible.

[3]
Reveal mark scheme Mark scheme for question 1(b)
(c)

The strain for the nylon fishing line at its yield point is 0.04

(c)(i)

State what is meant by yield point.

[1]
Reveal mark scheme Mark scheme for question 1(c)(i)
(c)(ii)

The original length of the nylon fishing line was 2.00 m.

Determine whether the fishing line was stretched beyond its yield point.

[2]
Reveal mark scheme Mark scheme for question 1(c)(ii)

Paper 2: Advanced Physics II June 2023, Question 4 1 mark

A wire Y of cross‑sectional area A and length l is joined to a second wire Z of cross‑sectional area 2 A and length 2 l as shown. Wire Z is fixed at one end and a force F is applied to the other end of wire Y.

Figure for question 4

The wires are made of the same material.

Wire Y extends by a distance x.

Which of the following is the extension of wire Z?

Question 4, shown as an image
Question 4, shown as an image
[1]
Reveal mark scheme Mark scheme for question 4

Paper 3: General and Practical Principles in Physics June 2023, Question 5 10 marks

Figure for question 5
(a)(i)

Give one advantage of using a reference wire as well as a test wire.

[1]
Reveal mark scheme Mark scheme for question 5(a)(i)
(a)(ii)

State why a reference load was applied to the reference wire.

[1]
Reveal mark scheme Mark scheme for question 5(a)(ii)
(b)

Explain why the test wire should be both long and thin.

[3]
Reveal mark scheme Mark scheme for question 5(b)
(c)

The student varied the load F on the test wire and recorded the corresponding change in length Δ x from the vernier scale. The results are shown on the graph.

Δ x / mm

Figure for question 5

Determine a value for the Young modulus of brass.

length of wire = 2.75 m

Question 5, shown as an image
[5]
Reveal mark scheme Mark scheme for question 5(c)

Paper 2: Advanced Physics II June 2022, Question 18 9 marks

The harp is a musical instrument with many strings, as shown.

Figure for question 18

All the strings are under tension.

The strings on one type of harp are made from nylon of density 1070 kg m−3. One string has a diameter of 1.14 mm.

(a)(i)

Show that the mass per unit length μ of the string is about 1.1 maths symbol 10−3kg m−1.

[2]
Reveal mark scheme Mark scheme for question 18(a)(i)
(a)(ii)

When the middle of the string is plucked, a note of frequency 440 Hz is produced.

Calculate the tension in the string.

length of string = 41.0 cm

[4]
Reveal mark scheme Mark scheme for question 18(a)(ii)
(b)

The graph shows how the Young modulus E of the nylon varies with temperature.

Figure for question 18

When the harp is played, the temperature of the string increases.

Explain how this temperature change would affect the frequency of the note produced when the string is plucked.

[3]
Reveal mark scheme Mark scheme for question 18(b)

Paper 2: Advanced Physics II November 2021, Question 5 1 mark

Also involves Gravity and weight

A mass of 24 kg is suspended from a steel wire of length 1.5 m. The wire has cross‑sectional area 3.1 maths symbol 10−6m2.

The Young modulus of steel is 1.8 maths symbol 1011Pa.

Which of the following gives the extension of the wire?

Question 5, shown as an image
Question 5, shown as an image
Question 5, shown as an image
Question 5, shown as an image
[1]
Reveal mark scheme Mark scheme for question 5

Paper 2: Advanced Physics II November 2020, Question 15 13 marks

The photograph shows a guitar.

Figure for question 15

When a guitar string is plucked, a standing wave is created.

(a)

Explain how a standing wave is created on the string.

[3]
Reveal mark scheme Mark scheme for question 15(a)
(b)

The diagram shows a standing wave on a guitar string.

Figure for question 15

The oscillating length of the guitar string is 66 cm.

(b)(i)

State the wavelength for this standing wave.

[1]
Reveal mark scheme Mark scheme for question 15(b)(i)
(b)(ii)

Calculate the frequency of vibration for this standing wave.

tension in guitar string = 88.6 N

mass per unit length of guitar string = 4.47 maths symbol 10−3kg m−1

[3]
Reveal mark scheme Mark scheme for question 15(b)(ii)
(c)

One end of the guitar string is wrapped around a cylindrical tuning peg. Turning the peg changes the total length of the string and hence changes the tension in the string. This changes the frequency of vibration of the string.

Figure for question 15
(c)(i)

The length of one string is 68 cm.

Calculate the extension required to produce a tension of 93.4 N in the string.

Young modulus of string material = 1.8 × 109N m−2

cross-sectional area of string = 6.6 maths symbol 10−7m2

[4]
Reveal mark scheme Mark scheme for question 15(c)(i)
(c)(ii)

The vibrating length of string is unchanged by turning the tuning peg.

Explain the effect that tightening the string has on the frequency of the sound produced.

[2]
Reveal mark scheme Mark scheme for question 15(c)(ii)

Paper 2: Advanced Physics II October 2020, Question 15 13 marks

The photograph shows a guitar.

Figure for question 15

When a guitar string is plucked, a standing wave is created.

(a)

Explain how a standing wave is created on the string.

[3]
Reveal mark scheme Mark scheme for question 15(a)
(b)

The diagram shows a standing wave on a guitar string.

Figure for question 15

The oscillating length of the guitar string is 66 cm.

(b)(i)

State the wavelength for this standing wave.

[1]
Reveal mark scheme Mark scheme for question 15(b)(i)
(b)(ii)

Calculate the frequency of vibration for this standing wave.

tension in guitar string = 88.6 N

mass per unit length of guitar string = 4.47 maths symbol 10−3kg m−1

[3]
Reveal mark scheme Mark scheme for question 15(b)(ii)
(c)

One end of the guitar string is wrapped around a cylindrical tuning peg. Turning the peg changes the total length of the string and hence changes the tension in the string. This changes the frequency of vibration of the string.

Figure for question 15
(c)(i)

The length of one string is 68 cm.

Calculate the extension required to produce a tension of 93.4 N in the string.

Young modulus of string material = 1.8 × 109N m−2

cross-sectional area of string = 6.6 maths symbol 10−7m2

[4]
Reveal mark scheme Mark scheme for question 15(c)(i)
(c)(ii)

The vibrating length of string is unchanged by turning the tuning peg.

Explain the effect that tightening the string has on the frequency of the sound produced.

[2]
Reveal mark scheme Mark scheme for question 15(c)(ii)

Paper 2: Advanced Physics II June 2019, Question 16 13 marks

Question 16, shown as an image
Figure for question 16
Question 16, shown as an image
(a)
Question 16, shown as an image

Show that the length of the wire supporting the sphere is about 10m.

Question 16, shown as an image
[4]
Reveal mark scheme Mark scheme for question 16(a)
(b)
Question 16, shown as an image
(b)(i)
Question 16, shown as an image
[3]
Reveal mark scheme Mark scheme for question 16(b)(i)
(b)(ii)
Question 16, shown as an image
Question 16, shown as an image
[3]
Reveal mark scheme Mark scheme for question 16(b)(ii)
(c)
Figure for question 16 Figure for question 16 Figure for question 16
[3]
Reveal mark scheme Mark scheme for question 16(c)

Paper 3: General and Practical Principles in Physics June 2019, Question 10 8 marks

Seat belts are being tested by a car manufacturer. In the test, a car moving at a steady speed of 28 m s–1 collides with a wall and stops.

A crash-test dummy in the driving seat is wearing a seat belt made from polyester webbing. The seat belt has a cross-sectional area of 0.85 cm2 and a total length of 2.0 m. A student suggests that in the collision the seat belt absorbs all the kinetic energy of the dummy.

(a)

Show that the energy per unit volume that would have to be absorbed by the seat belt is about 2 maths symbol 108 J m–3.

mass of dummy = 75 kg

[3]
Reveal mark scheme Mark scheme for question 10(a)
(b)

The graph shows how stress varies with strain for the seat belt.

Figure for question 10
(b)(i)

Show that the area under the graph represents the energy stored per unit volume in the seat belt.

[2]
Reveal mark scheme Mark scheme for question 10(b)(i)
(b)(ii)

Use the graph to determine whether the seat belt absorbs all the kinetic energy of the dummy from part (a).

In this collision, the maximum strain of the seat belt is 0.075

[3]
Reveal mark scheme Mark scheme for question 10(b)(ii)

Paper 2: Advanced Physics II June 2017, Question 20 12 marks

In 2016 scientists at the Laser Interferometer Gravitational‑Wave Observatory (LIGO) announced that gravitational waves had been detected.

The signal they detected is shown on the graph.

Figure for question 20
(a)

Gravitational waves travel at the speed of light.

Determine the mean wavelength of the waves detected between 0.30 s and 0.35 s on the graph.

[3]
Reveal mark scheme Mark scheme for question 20(a)
(b)

Gravitational waves alternately compress and stretch matter by very small amounts as they pass through.

The LIGO detector has two arms, at 90° to each other, each 4 km long. As a gravitational wave passes the detector, the arms change length. The detector continuously compares the lengths of the two arms.

Figure for question 20
(b)(i)

An article states that ‘the maximum change in the 4 km length of the arm is about 0.001 times the diameter of a proton’.

Determine whether this statement applies to the gravitational wave shown in the graph.

diameter of proton = 8.8maths symbol10–16m

[3]
Reveal mark scheme Mark scheme for question 20(b)(i)
(b)(ii)

In the LIGO detector, any change in the lengths of the arms is detected using a laser beam and photodetector.

Figure for question 20

The laser beam is split into two at B, one beam travelling to one mirror and the other beam travelling to the other mirror. After reflection at the mirrors, the beams are recombined at B and reach the photodetector. The photodetector measures the intensity of the incident light.

The system is arranged so that when no gravitational waves are present, the beams have a path difference of half a wavelength at the photodetector.

Explain how the photodetector detects very small changes in the length of one arm, when the other arm stays the same length.

[4]
Reveal mark scheme Mark scheme for question 20(b)(ii)
(b)(iii)

The system could be arranged so that when no gravitational waves are present, the beams have zero path difference at the photodetector.

Explain whether using an initial path difference of half a wavelength is a more sensitive way of detecting changes in length than having an initial path difference of zero.

[2]
Reveal mark scheme Mark scheme for question 20(b)(iii)

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