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Further Maths B (MEI) · OCR H635 · Numerical Methods (optional - choose any two of Y411/Y412/Y413/Y414) · June 2025

OCR GCE AS Level Further Maths B (MEI) Numerical Methods (optional - choose any two of Y411/Y412/Y413/Y414) June 2025 question paper Y414

1h 15m 60 marks

OCR H635 · Unit Y414

9 questions
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Question 1

The method of interval bisection is used to find a sequence of approximations to one of the roots of the equation ex - x2 - 3x = 0.

The table shows the associated spreadsheet output.

ABCDEF
1af(a)bf(b)cf(c)
22-2.6109432.0855372.5-1.56751
32.5-1.5675132.0855372.75-0.16987
42.75-0.1698732.0855372.8750.834799
52.75-0.169872.8750.8347992.81250.303839
6
(a)

Write down a suitable formula for cell E2.

[1]

Answer
Mark scheme for question 1(a)
(b)

The formula in cell A3 is = IF (F2 < 0,E2,A2).

Write down a similar formula for cell C3.

[1]

Answer
Mark scheme for question 1(b)
(c)

Complete row 6 of the table in the Printed Answer Booklet.

[2]

Answer
Mark scheme for question 1(c)
(d)

Without doing any more calculations, write down the value of the root correct to the maximum

number of decimal places which seems justified. You must explain the precision quoted.

[1]

Answer
Mark scheme for question 1(d)

Question 2

The table gives three values of x and the associated values of y.

x-123
y-3.390.180.45

Use Lagrange’s form of the interpolating polynomial to construct a polynomial of degree 2 for the values in the table. Give your answer in the form

y = ax2 + bx + c,

where a, b and c are constants to be determined.

[4]

Answer
Mark scheme for question 2

Question 3

(a)

Find the relative error when π is chopped to 3 decimal places.

[2]

Answer
Mark scheme for question 3(a)
(b)

Find the relative error when π is rounded to 3 decimal places.

[2]

Answer
Mark scheme for question 3(b)
(c)

You are given that y = π2 - 5 and z = (π - 5)2.

You are also given the following information.

• Y is an approximation to y.

• Z is an approximation to z.

• Y and Z are found by using π = 3.14.

A student states that the relative error in using Y to approximate y is exactly the same as the relative error in using Z to approximate z, because in each case the calculation involves squaring and subtracting 5.

Without doing any calculations, explain whether the student is correct.

[1]

Answer
Mark scheme for question 3(c)

Question 4

A student is using a spreadsheet to investigate the curve y = f (x) at the point where x = 2. Some of the spreadsheet output is shown below.

Table 4.1 shows some values of x and the associated values of f (x).

Table 4.2 shows two approximations to f ′ (2) found using the same method with h = 0.001 and h = 0.01.

Figure for question 4
(a)

The formula in cell G10 is = (H5 - G5) /G9.

The formula in cell H10 is = (I 5 - G5)/ H 9.

State the method being used to find these approximations to f ′ (2).

[1]

Answer
Mark scheme for question 4(a)
(b)
Question 4, shown as an image

• Explain why your answer is not the same as the value displayed in cell G10.

[3]

Answer
Mark scheme for question 4(b)
(c)

State the value of f ′ (2) as accurately as you can. You must justify the precision quoted.

[1]

Answer
Mark scheme for question 4(c)
(d)

Hence determine an estimate for the error when f (2) is used as an approximation to f (2.1).

[2]

Answer
Mark scheme for question 4(d)
(e)

Explain whether your answer to part (d) is likely to be an over-estimate or an under-estimate.

[1]

Answer
Mark scheme for question 4(e)

Question 5

Question 5, shown as an image

Simpson’s rule.

FGHIJ
21nTnSndifferenceratio
2210.84557616
2320.881446720.89340357
2440.890666510.893739770.00034
2580.892994530.893770543.1E-050.092
26160.893578220.893772792.2E-060.073
27320.893724260.893772941.5E-070.066
28640.893760770.893772959.4E-090.063
291280.89376990.893772955.9E-100.063
(a)

Write down the value displayed in cell I25 using standard mathematical notation.

[1]

Answer
Mark scheme for question 5(a)
(b)
Question 5, shown as an image

[1]

Answer
Mark scheme for question 5(b)
(c)

Write down a suitable formula for cell H23.

[2]

Answer
Mark scheme for question 5(c)
(d)(i)

Explain what the values in column J tell you about the order of Simpson’s rule in this

case.

[2]

Answer
Mark scheme for question 5(d)(i)
(d)(ii)

Explain whether this is usual.

[1]

Answer
Mark scheme for question 5(d)(ii)

Question 6

The equation 0.5 ln x + x2 - x - 2 = 0 has a root α, such that 1 < α < 2.

A student attempts to find α using the iterative formula

xn+1 = g(xn) with x0 = 1, where g(x) = 0.5 ln x + x2 - 2.

The associated spreadsheet output is shown in the table.

KL
1nxn
201
31-1
42#NUM!
(a)

Explain why #NUM! is displayed in cell L4.

[1]

Answer
Mark scheme for question 6(a)
(b)
Figure for question 6 Figure for question 6

[1]

Answer
Mark scheme for question 6(b)
(c)

Explain why the iterative formula xn+1 = g(xn) may not be used to successfully find α,

whatever the value of x0.

[1]

Answer
Mark scheme for question 6(c)
(d)

Use the relaxed iteration

xn+1 = (1 - λ)xn + λg(xn),

with λ =-0.328 and x0 = 1, to determine the value of α correct to 6 decimal places.

[3]

Answer
Mark scheme for question 6(d)

Question 7

A student makes a cup of tea and investigates how long it takes to reach room temperature. The student places the cup of tea on a table in the kitchen and records the temperature T °C of the tea t minutes after it was made, at 5 minute intervals starting with t = 5. The data collected are shown in the table.

Figure for question 7
(a)

Show that a quadratic polynomial would be a reasonable model for these data.

[3]

Answer
Mark scheme for question 7(a)
(b)

Use Newton’s forward difference interpolation method to determine a suitable quadratic

polynomial for these data.

[4]

Answer
Mark scheme for question 7(b)
(c)

The temperature in the kitchen is 19°C. It takes one hour for the tea to cool to room temperature.

(c)(i)

Use the model to find an estimate of the temperature of the tea after 1 hour.

[1]

Answer
Mark scheme for question 7(c)(i)
(c)(ii)

Use the model to find an estimate of the temperature of the tea after an hour and a half.

[1]

Answer
Mark scheme for question 7(c)(ii)
(c)(iii)

Hence identify a limitation of the model.

[1]

Answer
Mark scheme for question 7(c)(iii)

Question 8

Table 8.1 shows some values of x and the associated values of f (x).

Table 8.1

x0.50.91.3
f(x)1.414 211.099 470.711 01
(a)

Use the central difference method to determine an approximation to f ′ (0.9).

[2]

Answer
Mark scheme for question 8(a)
(b)

Table 8.2 shows a sequence of approximations to f ′ (0.9) for different values of the step length, h together with some further analysis.

Table 8.2

h0.20.10.050.0250.0125
f ′(0.9)-0.957 844-0.977 203-0.982 021-0.983 225-0.983 525
difference-0.019 360-0.004 818-0.001 203-0.000 301
ratio0.248 8820.249 7190.249 930

Use extrapolation to determine the value of f ′ (0.9) as accurately as you can. You must justify

the precision quoted.

[5]

Answer
Mark scheme for question 8(b)

Question 9

In this question you must show detailed reasoning

The equation 0.2x4 + 0.8x - 0.2 = 0 has a root α such that 0 < α < 1.

(a)

Use the Newton-Raphson method with x0 = 1 to determine the value of α correct to

6 decimal places.

[5]

Answer
Mark scheme for question 9(a)
(b)(i)

The equation 0.2x4 + 0.8x - 0.2 = 0 has another root β such that -2 < β <-1.

The Newton-Raphson method is used to find a sequence of approximations to β. The associated spreadsheet output is shown in the table below, together with some further analysis.

ABCD
rxrdifferenceratio
0-2
1-1.750.25
2-1.6709230.0790770.3163082
3-1.6633190.0076040.096159
4-1.6632526.7E-050.0088147
5-1.6632525.18E-097.724E-05

Explain what the values in column D suggest about the order of convergence of this

sequence of approximations.

[2]

Answer
Mark scheme for question 9(b)(i)
(b)(ii)

Explain whether this is usual.

[1]

Answer
Mark scheme for question 9(b)(ii)

The paper as printed

752828-question-paper-numerical-methods-erratum

752674-question-paper-numerical-methods

752675-question-paper-numerical-methods-answer-book

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