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Further Maths B (MEI) · OCR H635 · Numerical Methods (optional - choose any two of Y411/Y412/Y413/Y414) · November 2021

OCR GCE AS Level Further Maths B (MEI) Numerical Methods (optional - choose any two of Y411/Y412/Y413/Y414) November 2021 question paper Y414

1h 15m 60 marks

OCR H635 · Unit Y414

7 questions
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Question 1

The table shows 3 values of x and the associated values of f (x).

x-112
f(x)0.7-3.56-4.94
(a)

Use Lagrange’s method to construct the interpolating polynomial of degree 2 for the values in the table, giving your answer in the form

ax2 + bx + c

where a, b and c are constants to be determined.

[4]

Answer
Mark scheme for question 1(a)
(b)

Explain why it is not possible to use Newton’s forward difference interpolation formula for

these values.

[1]

Answer
Mark scheme for question 1(b)

Question 2

The table shows 2 values of x and the associated values of (f x). The values of x are exact and the values of f(x) have been rounded to 3 decimal places.

x29.529.7
f(x)0.4920.495
(a)
Question 2, shown as an image

[4]

Answer
Mark scheme for question 2(a)
(b)

Explain why your answer to part (a) is so large.

[1]

Answer
Mark scheme for question 2(b)
(c)
Figure for question 2

[1]

Answer
Mark scheme for question 2(c)

Question 3

The table shows 3 values of x and the associated values of f (x).

x22.052.1
f(x)1.3862941.4715721.558068
(a)

Use the forward difference method to find two estimates of f ′ (2).

[3]

Answer
Mark scheme for question 3(a)
(b)

Explain why it is not possible to use the central difference method in this case.

[1]

Answer
Mark scheme for question 3(b)
(c)

Explain why it is generally preferable to use the central difference method instead of the

forward difference method.

[1]

Answer
Mark scheme for question 3(c)

Question 4

Question 4, shown as an image
Figure for question 4
Question 4, shown as an image

The Newton-Raphson method is to be used to solve the equation.

(a)

On the copy of Fig. 4.1 in the Printed Answer Booklet, illustrate how the Newton-Raphson

method finds x1 with a starting value of x0 = 1.

[1]

Answer
Mark scheme for question 4(a)
(b)

The spreadsheet output in Fig. 4.2 shows some iterates, together with some further analysis, when the Newton-Raphson method is used with a starting value of x0 = 0.5.

Figure for question 4

Determine whether α = 2.817921 correct to 6 decimal places.

[2]

Answer
Mark scheme for question 4(b)
(c)

Explain what the entries in the ratio column in Fig. 4.2 tell you about the order of convergence

of this sequence of estimates.

[2]

Answer
Mark scheme for question 4(c)
(d)

Fig. 4.3 shows the spreadsheet output when the Newton-Raphson method is used with a starting value of x0 = 0.1.

Figure for question 4

Explain why #NUM! is displayed in cell J7.

[2]

Answer
Mark scheme for question 4(d)
(e)

The method of false position is used to find β. Some spreadsheet output showing the method being applied is shown in Fig. 4.4.

Figure for question 4

Determine the values which would be displayed in row 13 of the output, giving your answers

correct to 5 decimal places where appropriate.

[4]

Answer
Mark scheme for question 4(e)
(f)

State the value of β as accurately as you can, justifying the precision quoted.

[1]

Answer
Mark scheme for question 4(f)
(g)

The formula in cell P9 is = IF(S8 > 0,R8,P8).

Give a similar formula for cell N9.

[1]

Answer
Mark scheme for question 4(g)

Question 5

Question 5, shown as an image

midpoint rule and Simpson’s rule. Some of the spreadsheet output she has generated is shown below. Some of the values are missing.

ABCDEF
1nTnMnS2ndifferenceratio
212.8888888892
322.4444444442.1621754022.256265083
442.3033099232.2248312722.250990823-0.005274
582.2640705982.250517186-0.0004740.0898
6162.2539055392.2487722982.250483378-3.38E-050.07138
7322.2513389182.2500523122.250481181-2.2E-060.06499
(a)

Use the information in the output to determine the values in cells

• D2,

• E3,

• F4,

• C5.

[5]

Answer
Mark scheme for question 5(a)
(b)
Question 5, shown as an image

[5]

Answer
Mark scheme for question 5(b)

Question 6

James is investigating relative error. He uses En = 2.718n to approximate en, and calculates the relative error for various values of n. Some of his results are shown in the spreadsheet output in Fig. 6.1.

Figure for question 6
(a)

Give a suitable formula for cell D6.

[1]

Answer
Mark scheme for question 6(a)
(b)

Let y be the relative error when En is used to approximate en, and x be the relative error when E is used to approximate e1.

Write down a formula for y in terms of x which could be used to model the relationship

between y, x and n.

[1]

Answer
Mark scheme for question 6(b)
(c)

Determine whether the model holds for n = 5.

[3]

Answer
Mark scheme for question 6(c)
(d)

James tests the model again, this time using Fn = 2.7n to approximate en. Some of his results are shown in the spreadsheet output in Fig. 6.2.

Figure for question 6

Identify a limitation of the model found in part (b).

[1]

Answer
Mark scheme for question 6(d)
(e)

James carries out some further analysis, which is shown in the spreadsheet output in Fig. 6.3.

Figure for question 6

Write - 2.592E-05 in standard mathematical notation.

[1]

Answer
Mark scheme for question 6(e)
(f)

The formula in cell E22 is = E18*$D$21.

This formula has been copied across row 22 so that equivalent formulae are in cells F22 and G22.

Explain the purpose of the $ symbols.

[1]

Answer
Mark scheme for question 6(f)
(g)
Figure for question 6

[1]

Answer
Mark scheme for question 6(g)

Question 7

The equation f(x) = 0 where f(x) = 0.9x × x2 - x - 1 has a root α, such that α ≈ 1.87.

Question 7, shown as an image
(a)

Use the central difference method with h = 0.005 to determine an estimate of g ′ (1.87).

[2]

Answer
Mark scheme for question 7(a)
(b)

Explain how your answer to part (a) would influence Sundip’s decision.

[1]

Answer
Mark scheme for question 7(b)
(c)

Sundip decides to use the iterative formula given above with x0 = 2. Her spreadsheet output, together with some further analysis, is shown.

NOPQ
10rxrdifferenceratio
1102
1211.9245009-0.0754991
1321.8925878-0.03191310.4227
1431.8790715-0.01351630.4235
1541.8733418-0.00572970.4239
1651.8709120-0.00242980.4241
1761.8698814-0.00103060.4241
1871.8694442-0.00043720.4242
1981.8692588-0.00018540.4242
2091.8691801-7.8660E-050.4242

Write down suitable cell formulae for

• cell P12,

• cell Q13.

[2]

Answer
Mark scheme for question 7(c)
(d)

Explain what the entries in column Q tell you about the order of convergence of the estimates

in column O.

[2]

Answer
Mark scheme for question 7(d)
(e)

Without doing any more calculations, state the value of α as accurately as you can, justifying

the precision quoted.

[2]

Answer
Mark scheme for question 7(e)
(f)

Use the relaxed iteration xn+1 = (1 - λ)xn + λg(xn), with λ = 1.736 and x0 = 2 to determine

the value of α correct to 8 decimal places.

[3]

Answer
Mark scheme for question 7(f)

The paper as printed

667441-question-paper-numerical-methods

667440-question-paper-numerical-methods-answer-book

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