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OCR A Level Biology

Topic questions Biological molecules Proteins

Proteins

12 questions · 101 marks · about 2 hours

Proteins questions

OCR H420 Proteins 12 questions

Biological Processes June 2025, Question 2 1 mark

Which option describes a conjugated protein?

A A globular protein with a prosthetic group

B A protein with an inorganic ion

C A protein with more than one polypeptide chain

D An enzyme with an inorganic ion

Your answer

[1]
Reveal mark scheme Mark scheme for question 2

Biological Processes June 2025, Question 21 12 marks

(a)

21

(a)(i)

Describe three ways fish gills are adapted for efficient gas exchange.

[3]
Reveal mark scheme Mark scheme for question 21(a)(i)
(a)(ii)

Explain why insects can function with open circulatory systems.

[3]
Reveal mark scheme Mark scheme for question 21(a)(ii)
(a)(iii)

The largest fish is the whale shark. Whale sharks have an average mass of 20 tonnes.

The largest marine mammal is the blue whale. Blue whales have an average mass of 150 tonnes.

Use your knowledge of gas exchange and circulatory systems to suggest why marine mammals can grow to a much larger size than fish.

[2]
Reveal mark scheme Mark scheme for question 21(a)(iii)
(b)

Explain how the structure of haemoglobin allows it to transport oxygen from the lungs to the tissues.

[4]
Reveal mark scheme Mark scheme for question 21(b)

Unified Biology June 2024, Question 5 17 marks

Type 1 diabetes mellitus is characterised by a lack of insulin production. Type 2 diabetes mellitus can involve reduced production of insulin and a decreased response to insulin.

(a)

* Scientists analysed the occurrence of diabetes in identical and non-identical twins.

Identical twins have the same DNA. Non-identical twins share approximately 50% of each other’s DNA.

The scientists selected 614 pairs of twins in which at least one of the individuals had diabetes: 109 pairs had type 1 diabetes; 505 pairs had type 2 diabetes.

The scientists calculated the percentage probability of an individual having diabetes when their twin has the disease.

The table shows the percentage probability of both individuals in a pair of twins developing either type 1 or type 2 diabetes.

pair of twins having the diseasePercentage probability of both individuals in a
Type 1 diabetesType 2 diabetes
Identical twins2334
Non-identical twins516

Explain what conclusions can be drawn from the data in the table about the influence of the environment and genetics on the probability of developing diabetes.

Extra answer space if required.

[6]
Reveal mark scheme Mark scheme for question 5(a)
(b)

Insulin is secreted from cells in the pancreas.

This is a photomicrograph of pancreatic tissue.

Figure for question 5

Identify the structures labelled A, B and C.

[3]
Reveal mark scheme Mark scheme for question 5(b)
(c)

The graph shows the changes in the rate of insulin secretion in a person with type 2 diabetes after consuming glucose.

Figure for question 5

The table shows the changes in the rate of insulin secretion in a person with normal glucose tolerance after consuming glucose.

Time (min)Rate of insulin secretion (pmol min–1 m–2)
060
40460
80365
120299
160190

Plot the data from the table on the graph and draw a line of best fit.

[2]
Reveal mark scheme Mark scheme for question 5(c)
(d)

The table lists statements about a molecule of insulin.

Complete the table by stating the level of protein structure (primary, secondary, tertiary or quaternary) to which the statement relates.

Figure for question 5
[2]
Reveal mark scheme Mark scheme for question 5(d)
(e)

Bacteria can be genetically modified to produce insulin.

(e)(i)

State how a plasmid containing the gene coding for insulin can be transferred into a bacterial cell.

[1]
Reveal mark scheme Mark scheme for question 5(e)(i)
(e)(ii)

Suggest how bacterial cells can be screened to check if they have taken up a recombinant plasmid.

[1]
Reveal mark scheme Mark scheme for question 5(e)(ii)
(f)

In the future, type 1 diabetes could be treated by giving patients new pancreatic maths symbol-cells that have been produced in a laboratory from stem cells.

(f)(i)

State a feature of stem cells that allows them to be used to produce pancreatic maths symbol-cells.

[1]
Reveal mark scheme Mark scheme for question 5(f)(i)
(f)(ii)

Future treatments for type 1 diabetes may be able to use stem cells from a patient’s body to produce new maths symbol-cells.

Explain why patients receiving these new maths symbol-cells would still need to be given immunosuppressant drugs.

[1]
Reveal mark scheme Mark scheme for question 5(f)(ii)

Biological Processes June 2023, Question 3 1 mark

Which statement about the structure of amino acids is not true?

A Amino acids contain amino and carboxyl groups.

B Amino acids contain the elements hydrogen, carbon and oxygen only.

C Each amino acid has a unique R group.

D The R groups in amino acids can be polar or non-polar.

Your answer

[1]
Reveal mark scheme Mark scheme for question 3

Biological Processes June 2023, Question 4 1 mark

Which of the options is a feature of collagen?

A It allows alveoli to recoil

B It dissolves in water

C It is flexible

D It is the main protein found in hair

Your answer

[1]
Reveal mark scheme Mark scheme for question 4

Biological Diversity June 2022, Question 8 1 mark

Which statement about the secondary structure of a protein is correct?

A maths symbol-pleated sheets contain maths symbol-glucose.

B Disulfide bonds are not involved.

C Each single polypeptide is either an maths symbol-helix or a maths symbol-pleated sheet.

D Hydrogen bonds form between the R-groups of different amino acids.

Your answer

[1]
Reveal mark scheme Mark scheme for question 8

Biological Diversity June 2022, Question 16 14 marks

Haemoglobin is a globular protein.

Fig. 16.1 shows the structure of haemoglobin.

Figure for question 16
(a)

There are four levels of protein structure.

(a)(i)

Name the bond present in the primary structure of a protein.

[1]
Reveal mark scheme Mark scheme for question 16(a)(i)
(a)(ii)

Name the structure labelled X.

[1]
Reveal mark scheme Mark scheme for question 16(a)(ii)
(a)(iii)

State one feature, visible in Fig. 16.1, that shows that haemoglobin is a globular protein.

[1]
Reveal mark scheme Mark scheme for question 16(a)(iii)
(b)

Sickle cell disease is a genetic disease that results from a substitution mutation in one of the genes that code for haemoglobin.

Fig. 16.2 below shows part of the mRNA sequence that codes for normal haemoglobin and the corresponding sequence of amino acids.

Question 16, shown as an image
Question 16, shown as an image

Fig. 16.2

Fig. 16.3 is a representation of the genetic code.

Figure for question 16
(b)(i)

Use Fig. 16.3 to identify the missing amino acids 1 and 2 in Fig. 16.2.

[2]
Reveal mark scheme Mark scheme for question 16(b)(i)
(b)(ii)

Outline the role of RNA polymerase in the production of the mRNA sequence in Fig. 16.2.

[2]
Reveal mark scheme Mark scheme for question 16(b)(ii)
(b)(iii)

In sickle cell disease, the haemoglobin contains the amino acid valine in one of the positions normally occupied by glutamic acid.

State the base sequence on the anticodon of a tRNA molecule that brings valine to the ribosome.

[1]
Reveal mark scheme Mark scheme for question 16(b)(iii)
(b)(iv)
Figure for question 16
[6]
Reveal mark scheme Mark scheme for question 16(b)(iv)

Biological Diversity June 2022, Question 21 16 marks

Microorganisms can be used to produce a variety of food products.

(a)

Microorganisms have simple nutrient requirements, which helps to reduce production costs.

List two other advantages of using microorganisms in food production.

[2]
Reveal mark scheme Mark scheme for question 21(a)
(b)

Yoghurt is a food produced from milk using microorganisms.

Yoghurt production involves two bacteria: Lactobacillus delbrueckii and Streptococcus thermophilus.

(b)(i)

The bacteria convert the lactose present in milk into lactic acid.

Lactic acid is an important contributor to the flavour of yoghurt. Lactic acid also helps to give yoghurt a longer shelf life than milk.

Suggest how lactic acid helps to extend the shelf life of yoghurt.

[2]
Reveal mark scheme Mark scheme for question 21(b)(i)
(b)(ii)

Both bacteria also break down some of the protein casein, which is present in milk.

Name the product of protein breakdown and describe the type of reaction that takes place.

[2]
Reveal mark scheme Mark scheme for question 21(b)(ii)
(c)

The microorganism that is used to produce mycoprotein is a fungus.

The diagram is of a fermenter used for mycoprotein production.

Figure for question 21
(c)(i)

Use the diagram to name the type of fermentation process used for mycoprotein production.

Justify your answer.

[1]
Reveal mark scheme Mark scheme for question 21(c)(i)
(c)(ii)

Suggest and explain why a cooling system is necessary.

[2]
Reveal mark scheme Mark scheme for question 21(c)(ii)
(c)(iii)

The air inlet provides the fungus with oxygen for respiration, and ammonia.

Suggest and explain why the fungus is provided with ammonia.

[2]
Reveal mark scheme Mark scheme for question 21(c)(iii)
(d)

Mycoprotein foods contain protein.

The presence of protein in a solution can be detected using biuret reagent.

In the presence of protein, biuret reagent turns from blue to violet.

(d)(i)

A colorimeter can be used, along with biuret reagent, to determine the concentration of protein in a solution.

Outline how to use a colorimeter to determine the concentration of protein in a solution.

[4]
Reveal mark scheme Mark scheme for question 21(d)(i)
(d)(ii)

State one alternative method for determining the concentration of protein in a solution.

[1]
Reveal mark scheme Mark scheme for question 21(d)(ii)

Biological Processes June 2019, Question 13 1 mark

Collagen is found in tendons. Tendons attach muscles to bones.

Which of the following lists of properties, A to D, makes collagen suitable for this role?

A strong, inflexible, insoluble

B strong, flexible, soluble

C strong, inflexible, soluble

D strong, flexible, insoluble

Your answer

[1]
Reveal mark scheme Mark scheme for question 13

Biological Processes June 2019, Question 20 11 marks

Rubredoxin is a protein found in bacteria. It contains around 50 amino acids. One iron ion is bound by the sulphur atoms of four cysteine amino acids.

The structure of rubredoxin is shown in Fig. 20.1.

Figure for question 20
(a)(i)

Rubredoxin is known as a conjugated protein.

Use Fig. 20.1 to explain what is meant by the term conjugated protein.

[3]
Reveal mark scheme Mark scheme for question 20(a)(i)
(a)(ii)

Using the information provided about rubredoxin, state two similarities between the structures of rubredoxin and haemoglobin.

[2]
Reveal mark scheme Mark scheme for question 20(a)(ii)
(a)(iii)

Rubredoxin and haemoglobin have different secondary and tertiary structures.

Using the information provided about rubredoxin, state two other differences between the structures of rubredoxin and haemoglobin.

[2]
Reveal mark scheme Mark scheme for question 20(a)(iii)
(b)

Ferritin is a protein that is used to regulate iron levels within plant tissues.

It is a large spherical structure which can hold many iron (Fe3+) ions at its centre.

Iron can be toxic to plant tissues. Ferritin prevents the build-up of iron.

Fig. 20.2 shows the internal structure of ferritin.

Figure for question 20
(b)(i)
Figure for question 20 Figure for question 20
[3]
Reveal mark scheme Mark scheme for question 20(b)(i)
(b)(ii)

Explain how hydrophilic and hydrophobic interactions contribute to the spherical shape of ferritin.

[1]
Reveal mark scheme Mark scheme for question 20(b)(ii)

Unified Biology June 2017, Question 1 11 marks

Fig. 1.1 shows the structure of the amino acid leucine.

(a)(i)

On Fig. 1.1, draw a circle around the R group of leucine.

Figure for question 1
[1]
Reveal mark scheme Mark scheme for question 1(a)(i)
(a)(ii)

Students used thin layer chromatography to separate leucine from other amino acids. The chromatogram they produced is shown in Fig. 1.2.

Figure for question 1

What can you conclude about the chemical properties of leucine and amino acid X?

[1]
Reveal mark scheme Mark scheme for question 1(a)(ii)
(a)(iii)

Amino acid Z was in the mixture analysed by the students. It is not shown on the chromatogram in Fig. 1.2. Amino acid Z has an Rf value that is 0.20 lower than that of amino acid Y.

Place a dot on the chromatogram in Fig. 1.2 to show the distance moved by amino acid Z.

Show your working.

[3]
Reveal mark scheme Mark scheme for question 1(a)(iii)
(b)

Thin layer chromatography can also be used to separate photosynthetic pigments.

(b)(i)

State a material that can be used as the stationary phase in thin layer chromatography.

[1]
Reveal mark scheme Mark scheme for question 1(b)(i)
(b)(ii)

State the precise location of photosynthetic pigments in a chloroplast.

[2]
Reveal mark scheme Mark scheme for question 1(b)(ii)
(c)

When sequencing DNA, fragments of DNA are separated by electrophoresis.

Describe three differences between the process of thin layer chromatography and the form of electrophoresis used to sequence DNA.

[3]
Reveal mark scheme Mark scheme for question 1(c)

Unified Biology June 2017, Question 2 15 marks

Bread contains a mixture of polypeptides known as gluten.

Gluten consists of two types of polypeptide: gliadins and glutenins.

(a)
(a)(i)

The table below contains statements about the structures of gluten polypeptides.

In the boxes next to each statement, write the level of protein structure (primary, secondary, tertiary, or quaternary) to which the statement refers.

Figure for question 2
[2]
Reveal mark scheme Mark scheme for question 2(a)(i)
(a)(ii)

Coeliac disease is caused by an immune reaction to gliadins in a person’s digestive system. The immune system produces antibodies that bind to part of the gliadin polypeptides, which causes inflammation.

Some people who stop eating foods that contain gluten still occasionally experience the symptoms of coeliac disease.

What can you conclude about:

• the structure of the antibody that causes coeliac disease; and

• what the antibody binds to when producing the symptoms of coeliac disease?

[2]
Reveal mark scheme Mark scheme for question 2(a)(ii)
(b)

Gluten helps to trap carbon dioxide within bread dough. This enables bread to rise when it is baked.

The carbon dioxide is produced by baker’s yeast, Saccharomyces cerevisiae. This species of yeast is able to convert ethanol to acetyl CoA at low glucose concentrations.

Fig. 2 shows the oxygen consumption and carbon dioxide production of a population of S. cerevisiae grown in batch culture. The population was provided with glucose as their only initial source of carbon.

Figure for question 2
Question 2, shown as an image
Question 2, shown as an image
Question 2, shown as an image
Question 2, shown as an image

Fig. 2

(b)(i)

Suggest and explain what conclusions can be drawn from Fig. 2 about the factors that affected the rate and type of respiration carried out by S. cerevisiae in this batch culture.

[3]
Reveal mark scheme Mark scheme for question 2(b)(i)
(b)(ii)

Describe two practical considerations to ensure the S. cerevisiae population grows successfully when the initial culture is established.

[2]
Reveal mark scheme Mark scheme for question 2(b)(ii)
(b)(iii)
Figure for question 2
[2]
Reveal mark scheme Mark scheme for question 2(b)(iii)
(b)(iv)

A group of students were designing an experiment to investigate the effect of temperature on the respiration rate of S. cerevisiae.

Their planned method included the following:

• S. cerevisiae yeast suspension will be divided into six equal volumes to form the experimental groups.

• Six temperatures will be tested: 15 °C, 20 °C, 25 °C, 30 °C, 35 °C and 40 °C.

• Beakers of S. cerevisiae will be placed in water baths to control the temperature.

• Respiration rate will be measured by using a pH probe to monitor changes in the pH of the suspensions.

• The experiment will be repeated four times.

Evaluate whether the students’ method is likely to produce valid results.

[3]
Reveal mark scheme Mark scheme for question 2(b)(iv)
(b)(v)

The students used a Student’s t-test to compare the results at 30 °C and 35 °C.

They calculated a t value of 2.200.

The critical value for p = 0.05 is 2.306.

Assuming their final method was valid, what can the students conclude from the result of the t-test?

[1]
Reveal mark scheme Mark scheme for question 2(b)(v)

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