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Edexcel A Level Physics

Topic questions Waves Stefan's law & Wien's displacement law

Stefan's law & Wien's displacement law

13 questions · 117 marks · about 2.5 hours

Stefan's law and Wien's displacement law questions

Edexcel 9PH0 Stefan's law and Wien's displacement law 13 questions

Paper 2: Advanced Physics II June 2025, Question 21 13 marks

All objects with a temperature above absolute zero emit a spectrum of electromagnetic radiation.

(a)

State what is meant by absolute zero.

[1]
Reveal mark scheme Mark scheme for question 21(a)
(b)

The graph shows how the intensity of radiation emitted by the Earth varied with wavelength in 2020.

Figure for question 21

Explain the differences between this graph and a graph representing the emission of radiation by the Earth in 2050. Assume that the average global temperature increases over time.

[4]
Reveal mark scheme Mark scheme for question 21(b)
(c)

At the end of the 19th century, Wien investigated the radiation emitted by hot objects and formulated a law.

The table shows data for some stars.

Starλmax / nmT / K
Bellatrix13221 500
Rigel24511 600
Sirius2879910

Deduce whether Wien’s law is confirmed by this data.

[3]
Reveal mark scheme Mark scheme for question 21(c)
(d)

The Hertzsprung–Russell diagram below shows part of the main sequence of stars. The star Sirius A is marked on the diagram.

Figure for question 21

On a website it states that the radius of Sirius A is twice the radius of the Sun. Deduce whether this statement is correct. radius of the Sun = 6.96×108m surface temperature of the Sun = 5800 K

[5]
Reveal mark scheme Mark scheme for question 21(d)

Paper 3: General and Practical Principles in Physics June 2025, Question 5 9 marks

Fuse wire is made of a metal that has a low melting point. The wire melts when the current exceeds a maximum value.

A student investigated how the cross‑sectional area affected the current at which a wire melted. She used wires of the same length and metal, but different diameters.

The student steadily increased the current through each wire and recorded the maximum current through the wire before it melted.

(a)

Describe how the student could determine an accurate value for the cross‑sectional area of a wire.

[4]
Reveal mark scheme Mark scheme for question 5(a)
(b)(i)

Explain why a current in a wire causes the resistance of the wire to change.

[3]
Reveal mark scheme Mark scheme for question 5(b)(i)
(b)(ii)

The length of a wire does not affect the value of current at which the wire melts.

Explain why. Assume the wire behaves as a black body.

[2]
Reveal mark scheme Mark scheme for question 5(b)(ii)

Paper 2: Advanced Physics II June 2024, Question 13 4 marks

Aldebaran is a red giant star.

For a black body radiator of Aldebaran’s surface temperature, the wavelength λmax at which the intensity is maximum is 7.43 × 10–7m.

Determine the luminosity of Aldebaran.

radius of Aldebaran = 3.14 × 1010m

[4]
Reveal mark scheme Mark scheme for question 13

Paper 2: Advanced Physics II June 2023, Question 17 16 marks

Also involves The life cycle of a star

Scientists can analyse light from stars that has passed through a diffraction grating.

(a)

*(a) Explain the pattern produced when a mixture of blue and red light, from the same source, passes through a diffraction grating.

[6]
Reveal mark scheme Mark scheme for question 17(a)
(b)
Figure for question 17
(b)(i)

Light interacts with atoms as it passes through the atmosphere of the star.

Explain how this leads to the formation of the dark lines within the spectrum.

[4]
Reveal mark scheme Mark scheme for question 17(b)(i)
(b)(ii)

The surface temperature of the star is 5800 K.

On the axes below, sketch a graph of the intensity of radiation against the wavelength of that radiation for this star.

Figure for question 17
[4]
Reveal mark scheme Mark scheme for question 17(b)(ii)
(b)(iii)

This star is a main sequence star.

Explain why main sequence stars do not collapse due to gravitational forces.

[2]
Reveal mark scheme Mark scheme for question 17(b)(iii)

Paper 2: Advanced Physics II November 2021, Question 15 7 marks

One of the largest stars in our galaxy is VY Canis Majoris. This star’s radius is 1420 times the radius of the Sun. The luminosity of this star is 270 000 times the luminosity of the Sun.

A student states that the surface temperature of VY Canis Majoris must be much greater than the surface temperature of the Sun.

(a)

Determine whether the student’s statement is correct.

surface temperature of Sun = 5780 K

Question 15, shown as an image
[3]
Reveal mark scheme Mark scheme for question 15(a)
(b)

Calculate the wavelength with maximum intensity in the black body radiation spectrum of VY Canis Majoris.

[2]
Reveal mark scheme Mark scheme for question 15(b)
(c)

Add the position of VY Canis Majoris to the Hertzsprung Russell diagram to determine which type of star it is.

Figure for question 15
[2]
Reveal mark scheme Mark scheme for question 15(c)

Paper 2: Advanced Physics II November 2020, Question 14 10 marks

Also involves Electrical power and energy transfers

The photograph shows a filament bulb.

Figure for question 14

The filament is an emitter with 35% of the power output of a black body radiator of the same temperature.

(a)

When a potential difference (p.d) of 2.0 V is applied across the bulb, there is a current of 0.37 A in the filament.

Calculate the temperature of the filament.

surface area of filament = 3.9 × 10−6m2

[3]
Reveal mark scheme Mark scheme for question 14(a)
(b)

In an experiment to investigate the efficiency of a filament light bulb a p.d. was applied. The p.d. and current were measured and the light bulb was observed. The p.d. was then increased and new measurements taken.

When a small p.d. is applied to the bulb, no light is visible. If the p.d. is gradually increased, the filament starts to glow and eventually appears white.

(b)(i)
Figure for question 14 Figure for question 14
[5]
Reveal mark scheme Mark scheme for question 14(b)(i)
(b)(ii)

Use your graph to explain why filament light bulbs are considered inefficient.

[2]
Reveal mark scheme Mark scheme for question 14(b)(ii)

Paper 2: Advanced Physics II October 2020, Question 14 10 marks

Also involves Electrical power and energy transfers

The photograph shows a filament bulb.

Figure for question 14

The filament is an emitter with 35% of the power output of a black body radiator of the same temperature.

(a)

When a potential difference (p.d) of 2.0 V is applied across the bulb, there is a current of 0.37 A in the filament.

Calculate the temperature of the filament.

surface area of filament = 3.9 × 10−6m2

[3]
Reveal mark scheme Mark scheme for question 14(a)
(b)

In an experiment to investigate the efficiency of a filament light bulb a p.d. was applied. The p.d. and current were measured and the light bulb was observed. The p.d. was then increased and new measurements taken.

When a small p.d. is applied to the bulb, no light is visible. If the p.d. is gradually increased, the filament starts to glow and eventually appears white.

(b)(i)
Figure for question 14 Figure for question 14
[5]
Reveal mark scheme Mark scheme for question 14(b)(i)
(b)(ii)

Use your graph to explain why filament light bulbs are considered inefficient.

[2]
Reveal mark scheme Mark scheme for question 14(b)(ii)

Paper 3: General and Practical Principles in Physics November 2020, Question 11 18 marks

Solar panels consisting of combinations of photovoltaic cells use energy in the radiation received from the Sun to generate electricity.

(a)

An advertisement for solar panels claims that the intensity of radiation from the Sun incident at the top of the Earth’s atmosphere is more than 2 kW m−2.

Assess the validity of this claim.

radius of Sun = 6.96 × 108m

surface temperature of Sun = 5790 K

distance from Sun to Earth = 1.50 × 1011m

[4]
Reveal mark scheme Mark scheme for question 11(a)
(b)

The average intensity of radiation from the Sun incident at the Earth’s surface over a 24-hour period has been determined to be 164 W m−2.

Figure for question 11
(b)(i)

The average intensity of radiation from the Sun at the Earth’s surface is much less than the intensity incident at the top of the Earth’s atmosphere.

Explain why.

[4]
Reveal mark scheme Mark scheme for question 11(b)(i)
(b)(ii)

It is claimed that the area of solar panels needed to generate 100 GW of power is about 0.5% of the surface area of the Earth.

Assess the validity of this claim.

radius of Earth = 6.4 × 106m

typical efficiency of solar panels = 25%

[4]
Reveal mark scheme Mark scheme for question 11(b)(ii)
(c)

Scientists are developing a space station equipped with large solar panels. The space station would be located in a geostationary orbit. The space station would transfer energy to Earth as microwaves.

(c)(i)

A space station in a geostationary orbit is above the equator and has a period of 24 hours.

Explain one advantage of locating the space station in a geostationary orbit.

[2]
Reveal mark scheme Mark scheme for question 11(c)(i)
(c)(ii)

Calculate the height h of the space station above the equator when it is in a geostationary orbit.

mass of Earth = 6.00 × 1024kg

24 hours = 8.64 maths symbol 104s

[4]
Reveal mark scheme Mark scheme for question 11(c)(ii)

Paper 3: General and Practical Principles in Physics October 2020, Question 11 18 marks

Solar panels consisting of combinations of photovoltaic cells use energy in the radiation received from the Sun to generate electricity.

(a)

An advertisement for solar panels claims that the intensity of radiation from the Sun incident at the top of the Earth’s atmosphere is more than 2 kW m−2.

Assess the validity of this claim.

radius of Sun = 6.96 × 108m

surface temperature of Sun = 5790 K

distance from Sun to Earth = 1.50 × 1011m

[4]
Reveal mark scheme Mark scheme for question 11(a)
(b)

The average intensity of radiation from the Sun incident at the Earth’s surface over a 24-hour period has been determined to be 164 W m−2.

Figure for question 11
(b)(i)

The average intensity of radiation from the Sun at the Earth’s surface is much less than the intensity incident at the top of the Earth’s atmosphere.

Explain why.

[4]
Reveal mark scheme Mark scheme for question 11(b)(i)
(b)(ii)

It is claimed that the area of solar panels needed to generate 100 GW of power is about 0.5% of the surface area of the Earth.

Assess the validity of this claim.

radius of Earth = 6.4 × 106m

typical efficiency of solar panels = 25%

[4]
Reveal mark scheme Mark scheme for question 11(b)(ii)
(c)

Scientists are developing a space station equipped with large solar panels. The space station would be located in a geostationary orbit. The space station would transfer energy to Earth as microwaves.

(c)(i)

A space station in a geostationary orbit is above the equator and has a period of 24 hours.

Explain one advantage of locating the space station in a geostationary orbit.

[2]
Reveal mark scheme Mark scheme for question 11(c)(i)
(c)(ii)

Calculate the height h of the space station above the equator when it is in a geostationary orbit.

mass of Earth = 6.00 × 1024kg

24 hours = 8.64 maths symbol 104s

[4]
Reveal mark scheme Mark scheme for question 11(c)(ii)

Paper 3: General and Practical Principles in Physics June 2019, Question 5 9 marks

Also involves Attenuation of X-rays

An oximeter is a device used in hospitals to monitor the oxygen level in a patient’s blood.

In an oximeter, two light-emitting diodes (LEDs) are mounted opposite light sensors in a clip and attached to the patient’s finger. One of the LEDs produces red light and the other produces infrared.

Figure for question 5

The intensity I of electromagnetic radiation received by the detector, after passing through a thickness x of blood, is given by

Question 5, shown as an image

where I0 is the intensity that would have been received if the blood were not present and maths symbol is the attenuation coefficient of blood.

The red LED emits visible light of wavelength 650 nm and the infrared LED emits infrared of wavelength 950 nm.

The graph shows how maths symbol varies with wavelength maths symbol for oxygenated blood and deoxygenated blood.

Figure for question 5
(a)

I0 for the infrared LED is 1.8 W m–2.

Calculate I for the infrared after passing through 1.4 mm of oxygenated blood.

[3]
Reveal mark scheme Mark scheme for question 5(a)
(b)

The oximeter determines I / I0 the fraction of radiation transmitted at each wavelength.

Deduce whether I / I0 will be smaller for the red or the infrared radiation if the blood is deoxygenated.

[3]
Reveal mark scheme Mark scheme for question 5(b)
(c)

It is suggested that ambient light could affect the readings produced by the oximeter.

Halogen lamps have a filament temperature of 3200 K.

Deduce whether the light from such a lamp would have a significant effect on the oximeter readings.

[3]
Reveal mark scheme Mark scheme for question 5(c)

Paper 2: Advanced Physics II June 2017, Question 7 1 mark

A black body radiator of temperature T and surface area A has a luminosity L.

Which of the following is the luminosity of a black body radiator with surface area A/2 and temperature 2 T ?

Question 7, shown as an image
Question 7, shown as an image
[1]
Reveal mark scheme Mark scheme for question 7

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