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AQA GCSE Combined Science: Synergy

Topic questions Electricity Series & parallel circuits

Series & parallel circuits

5 questions · 44 marks · about 45 minutes

Series and parallel circuits questions

AQA 8465 Series and parallel circuits 5 questions

Paper 3: Physical sciences June 2025 Foundation tier, Question 3 9 marks

A student investigated how the resistance of a light dependent resistor (LDR) varied with light intensity.

Figure 8 shows the circuit used.

Figure for question 3
3.1

The student connected cells together to make the battery.

How many 1.5 V cells did the student use to make the 6.0 V battery?

Tick (maths symbol) one box.

2 cells 3 cells 4 cells

[1]
Reveal mark scheme Mark scheme for question 3.1
3.2

When the potential difference across the LDR was 3.0 V, the resistance of the LDR was 2000 Ω.

Calculate the current in the LDR.

Use the equation:

Question 3, shown as an image
[2]
Reveal mark scheme Mark scheme for question 3.2
3.3

The resistor and the LDR were connected in series.

How does the potential difference across the battery compare with the total potential difference across the resistor and LDR?

Tick (maths symbol) one box.

The potential difference across the battery is less.

The potential difference across the battery is the same.

The potential difference across the battery is greater.

[1]
Reveal mark scheme Mark scheme for question 3.3
3.4

The potential difference across the battery was 6.0 V.

The potential difference across the LDR was 3.0 V.

How should the student calculate the potential difference across the resistor?

Tick (maths symbol) one box.

Question 3, shown as an image
[1]
Reveal mark scheme Mark scheme for question 3.4
3.5

The student plotted a graph to show how the resistance of the LDR varied with light intensity.

Figure 9 shows the results.

Figure for question 3

What was the resistance of the LDR when the light intensity was 50 arbitrary units?

[1]
Reveal mark scheme Mark scheme for question 3.5
3.6

Which two conclusions can the student make from Figure 9?

Tick (maths symbol) two boxes.

Resistance and light intensity have a non-linear relationship.

Resistance and light intensity have a positive correlation.

Resistance decreases as light intensity increases.

Resistance is directly proportional to light intensity.

Resistance is not affected by light intensity.

[2]
Reveal mark scheme Mark scheme for question 3.6
3.7

LDRs are often used in control circuits.

Which circuit would need an LDR?

Tick (maths symbol) one box.

A circuit to monitor the temperature of an oven.

A circuit to keep the contents of a fridge cold.

A circuit to switch lights on at night.

[1]
Reveal mark scheme Mark scheme for question 3.7

Paper 3: Physical sciences June 2025 Higher tier, Question 4 8 marks

A student investigated how the resistance of a light dependent resistor (LDR) varies with light intensity.

Figure 4 shows the circuit.

Figure for question 4
4.1

The potential difference across the battery was 6.0 V.

Determine the potential difference across each cell.

[1]
Reveal mark scheme Mark scheme for question 4.1
4.2

When the LDR was in a dark room, the reading on the voltmeter was 3.0 V.

What was the resistance of the LDR?

Give a reason for your answer.

Tick (maths symbol) one box.

1000 Ω 2000 Ω 4000 Ω

[2]
Reveal mark scheme Mark scheme for question 4.2
4.3

The student directed a bright light onto the LDR in the circuit.

Explain why the reading on the voltmeter decreased.

[3]
Reveal mark scheme Mark scheme for question 4.3
4.4

Another student set the circuit up incorrectly.

Figure 5 shows the incorrect circuit.

Figure for question 4

The student placed the circuit in a dark room and then directed a bright light onto the LDR.

Explain what the reading on the voltmeter would be.

[2]
Reveal mark scheme Mark scheme for question 4.4

Paper 4: Physical sciences June 2024 Foundation tier, Question 2 9 marks

A hairdryer contains a heating element and a motor.

The motor is connected to a fan.

Figure for question 2

Figure 2 shows part of the electrical circuit inside the hairdryer.

Figure for question 2
2.1

How does the current in the motor compare with the current in the heating element?

Give a reason for your answer.

Tick (✓) one box.

The current is greater in the motor.

The current in both components is the same.

The current is less in the motor.

[2]
Reveal mark scheme Mark scheme for question 2.1
2.2

The potential difference across the motor is 20 V.

What is the potential difference across the heating element?

Give a reason for your answer.

Tick (✓) one box.

20 V 50 V
210 V
230 V

[2]
Reveal mark scheme Mark scheme for question 2.2
2.3

The hairdryer transfers 460 000 J of energy in 250 seconds.

Calculate the power of the hairdryer.

Use the equation:

Question 2, shown as an image
[2]
Reveal mark scheme Mark scheme for question 2.3
2.4

The current in the hairdryer is 8.0 A.

Calculate the time taken for 1200 C of charge to flow past a point in the hairdryer circuit.

Use the equation:

Question 2, shown as an image
[2]
Reveal mark scheme Mark scheme for question 2.4
2.5

The hairdryer is connected to the mains electricity supply.

What is the frequency of the UK mains electricity supply?

Tick (✓) one box.

50 Hz 60 Hz
100 Hz
230 Hz

[1]
Reveal mark scheme Mark scheme for question 2.5

Paper 4: Physical sciences June 2024 Higher tier, Question 9 8 marks

A student investigated electrical circuits.

9.1
Figure for question 9 Figure for question 9
[4]
Reveal mark scheme Mark scheme for question 9.1
9.2

The student changed the position of the voltmeter.

Figure 14 shows the new circuit.

Figure for question 9

The student connected the voltmeter across the 15 Ω fixed resistor.

The student used the variable resistor to vary the potential difference across the fixed resistor.

The potential difference across the fixed resistor can only be varied between 6 V and 12 V using the circuit in Figure 14.

Explain why.

[3]
Reveal mark scheme Mark scheme for question 9.2
9.3

Give one way the student could vary the potential difference across the fixed resistor below 6 V.

[1]
Reveal mark scheme Mark scheme for question 9.3

Paper 4: Physical sciences June 2022 Higher tier, Question 5 10 marks

A student carried out an investigation using an electrical circuit.

Figure 8 shows the circuit used.

Figure for question 5
5.1

The student increased the resistance of the variable resistor.

Describe what happened to the potential difference across resistor R and the current in resistor R.

[2]
Reveal mark scheme Mark scheme for question 5.1
5.2

The student investigated how the current in resistor R varied with the potential difference across resistor R.

To keep the temperature of resistor R constant, the student opened the switch after taking each reading.

Figure 9 shows the results.

Figure for question 5

Explain what happens to the resistance of resistor R as the potential difference across resistor R increases.

Use information from Figure 9.

[2]
Reveal mark scheme Mark scheme for question 5.2
5.3

After the reading was taken at 4.0 V, the student did not open the switch before taking the reading at 5.0 V.

Explain why the current was lower than expected when the 5.0 V reading was taken.

[2]
Reveal mark scheme Mark scheme for question 5.3
5.4

Figure 8 is repeated below.

Figure for question 5

The student had more resistors with the same resistance as resistor R.

Describe a method to investigate how the number of resistors in parallel affects the total resistance of the resistors in parallel.

[4]
Reveal mark scheme Mark scheme for question 5.4

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