Periodic table, elements and physical chemistry June 2024, Question 18 12 marks
This question is about two oxides of sulfur: sulfur dioxide, SO2, and sulfur trioxide, SO3.
SO3 decomposes to form SO2 and O2, as shown in Equilibrium 18.1.
2.25 moles of SO3 is heated to 550 C in the presence of a catalyst and the resulting mixture allowed to reach equilibrium.
The equilibrium mixture contains 0.900 mol of SO2 and the total pressure is 2.80 atm.
Calculate the numerical value for Kp for Equilibrium 18.1 under these conditions and state the units of Kp.
Give your answer to 3 significant figures.
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The numerical values of Kp for Equilibrium 18.1 at temperatures T1 and T2 are shown below.
| Temperature | Kp |
| T1 | 3.3 Γ 10β5 |
| T2 | 7.7 Γ 10β2 |
Explain why T2 is a higher temperature than T1.
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Suggest how the value of Kp would change if the reaction was repeated with no catalyst added and the pressure of the system increased.
Tick (β) one box in each row.
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SO2 and SO3 both have molecules with sulfur in the centre and bond angles of approximately 120.
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Explain why the bond angles in SO3 are 120.
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Explain why both SO2 and SO3 have polar bonds, but only SO2 has polar molecules.
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