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OCR A Level Chemistry

Topic questions Bonding, structure and the properties of matter Condensation polymerisation

Condensation polymerisation

16 questions · 168 marks · about 4 hours

Condensation polymerisation questions

OCR H432 Condensation polymerisation 16 questions

Synthesis and analytical techniques June 2025, Question 7 1 mark

What are the organic products of the acid hydrolysis of CH3CH2CONHCH3?

A CH3CH2COO– + CH3NH3+

B CH3CH2COOH + CH3NH3+

C CH3CH2COOH + CH3NH2

D CH3CH2COO– + CH3NH2

Question 7, shown as an image
[1]
Reveal mark scheme Mark scheme for question 7

Synthesis and analytical techniques June 2025, Question 18 8 marks

Figure for question 18
(a)

1-Chlorobut-2-ene and 3-hydroxybutanoic acid can both form polymers.

Draw two repeat units of each of the polymers formed.

State the type of polymerisation reaction that takes place for each compound.

Figure for question 18
[4]
Reveal mark scheme Mark scheme for question 18(a)
(b)

The disposal of polymers containing chlorine is a major challenge.

(b)(i)

Suggest why a polymer made from monomers containing chlorine, such as 1-chlorobut-2-ene, is difficult to dispose of by incineration.

[1]
Reveal mark scheme Mark scheme for question 18(b)(i)
(b)(ii)

The polymer formed from 3-hydroxybutanoic acid can be hydrolysed. This makes the polymer biodegradable.

Suggest what feature in the structure of this polymer allows this hydrolysis.

[1]
Reveal mark scheme Mark scheme for question 18(b)(ii)
(c)
Figure for question 18 Figure for question 18
[2]
Reveal mark scheme Mark scheme for question 18(c)

Synthesis and analytical techniques June 2024, Question 12 1 mark

1,6-Diaminohexane, H2N(CH2)6NH2, reacts with hexanedioyl dichloride, Cl OC(CH2)4COCl to form a polyamide and one other product.

What is the other product formed in this reaction?

A HC l

B H2O

C CO

D NH3

Question 12, shown as an image
[1]
Reveal mark scheme Mark scheme for question 12

Synthesis and analytical techniques June 2024, Question 20 13 marks

This question is about carboxylic acids and esters.

(a)

Short-chain carboxylic acids, such as methanoic acid, HCOOH, are soluble in water.

Explain, with a labelled diagram, how HCOOH interacts with water when it dissolves.

[2]
Reveal mark scheme Mark scheme for question 20(a)
(b)

Ester F has the structure shown below.

Figure for question 20
(b)(i)

What is the systematic name for this ester?

[1]
Reveal mark scheme Mark scheme for question 20(b)(i)
(b)(ii)

Ester F can be prepared from a carboxylic acid in two steps.

Step 1 The carboxylic acid is converted into an acyl chloride.

Step 2 The acyl chloride is converted into ester F.

Write equations for Step 1 and Step 2.

Show organic compounds as structures.

Step 1

Step 2

[4]
Reveal mark scheme Mark scheme for question 20(b)(ii)
(c)

The repeat unit of a polyester is shown below.

Figure for question 20

Draw the structures of monomers required to form this polyester.

[2]
Reveal mark scheme Mark scheme for question 20(c)
(d)

The compound below contains an ester and an amide group.

Figure for question 20

Draw the structures of the organic products formed by the complete alkaline hydrolysis of this compound using NaOH(aq).

[4]
Reveal mark scheme Mark scheme for question 20(d)

Synthesis and analytical techniques June 2024, Question 22 6 marks

maths symbol-Amino acids have the general formula RCH(NH2)COOH.

The R group in an maths symbol-amino acid contains C and H only.

This R group has a molar mass of 91 g mol–1.

(a)

A polymer is formed from 500 molecules of this maths symbol-amino acid.

Determine the molar mass of this polymer.

Give your answer to the nearest whole number.

molar mass of polymer =........ g mol–1

[3]
Reveal mark scheme Mark scheme for question 22(a)
(b)
Figure for question 22
[3]
Reveal mark scheme Mark scheme for question 22(b)

Synthesis and analytical techniques June 2023, Question 20 10 marks

This question is about aromatic compounds containing the –COOH and –OH functional groups.

(a)

Salicylic acid, shown below, is used in the manufacture of some important medicines.

Figure for question 20

Salicylic acid

Complete the flowchart for reactions of salicylic acid, by adding the organic products in each

Figure for question 20
[4]
Reveal mark scheme Mark scheme for question 20(a)
(b)

PAS, shown below, is an antibiotic used to treat several diseases including tuberculosis (TB).

Figure for question 20
(b)(i)

A student predicts that PAS could polymerise to form a polymer containing both ester and amide linkages.

Draw a section of this polymer.

The section should contain one amide and one ester linkage, which should be displayed.

[3]
Reveal mark scheme Mark scheme for question 20(b)(i)
(b)(ii)

For the treatment of TB, the maximum daily dosage of PAS that should be prescribed is 300 mg per kg of body mass.

A child weighs 20.0 kg.

Calculate the number of PAS molecules in the maximum daily dosage of PAS for this child.

[3]
Reveal mark scheme Mark scheme for question 20(b)(ii)

Synthesis and analytical techniques June 2023, Question 21 9 marks

This question is about maths symbol-amino acids.

(a)

The general formula of an maths symbol-amino acid is RCH(NH2)COOH.

Most maths symbol-amino acids show optical isomerism.

Explain the term optical isomerism.

[1]
Reveal mark scheme Mark scheme for question 21(a)
(b)

The maths symbol-amino acid valine has the R group of –CH(CH3)2.

(b)(i)

What is the systematic name of valine?

[1]
Reveal mark scheme Mark scheme for question 21(b)(i)
(b)(ii)

Draw diagrams to show 3D structures of the optical isomers of valine.

Figure for question 21
[2]
Reveal mark scheme Mark scheme for question 21(b)(ii)
(c)
Figure for question 21
(c)(i)

How many optical isomers are possible for compound E ?

[1]
Reveal mark scheme Mark scheme for question 21(c)(i)
(c)(ii)

A student hydrolyses compound E with dilute hydrochloric acid, HC l (aq).

Draw the structures of the organic products formed by this hydrolysis.

[4]
Reveal mark scheme Mark scheme for question 21(c)(ii)

Synthesis and analytical techniques June 2022, Question 19 22 marks

This question is about compounds that contain the carboxylic acid functional group.

(a)

Carboxylic acids react with alkalis, metals and carbonates to form salts.

Write full equations for the following three reactions. Show structures for organic compounds.

β€’ the reaction of propanoic acid with aqueous potassium hydroxide:

β€’ the reaction of aqueous methanoic acid with magnesium:

β€’ the reaction of the maths symbol–amino acid, aspartic acid (R=CH2COOH), with an excess of aqueous sodium carbonate, Na2CO3:

[4]
Reveal mark scheme Mark scheme for question 19(a)
(b)
Figure for question 19
[4]
Reveal mark scheme Mark scheme for question 19(b)
(c)

This part is about polymers derived from carboxylic acid monomers.

(c)(i)

Poly(pent-3-enoic acid) is an addition polymer.

Draw the structure of pent-3-enoic acid and two repeat units of this polymer.

Figure for question 19
[2]
Reveal mark scheme Mark scheme for question 19(c)(i)
(c)(ii)

Butanedicarboxylic acid and 1,4-dihydroxy-2-methylbenzene react to form a condensation polymer.

Draw one repeat unit of this condensation polymer.

[2]
Reveal mark scheme Mark scheme for question 19(c)(ii)
(c)(iii)

Three repeat units of a condensation polymer are shown below.

Figure for question 19

Draw the structure of the monomer required to form this polymer.

[1]
Reveal mark scheme Mark scheme for question 19(c)(iii)
(d)

A polymer is formed from 400 molecules of 2-aminopropanoic acid.

(d)(i)

Draw one repeat unit of this polymer.

[1]
Reveal mark scheme Mark scheme for question 19(d)(i)
(d)(ii)

What is the relative molecular mass, Mr, of the polymer?

[2]
Reveal mark scheme Mark scheme for question 19(d)(ii)
(e)
Figure for question 19
[6]
Reveal mark scheme Mark scheme for question 19(e)

Synthesis and analytical techniques November 2021, Question 17 10 marks

This question is about haloalkanes and polymers.

(a)

Freon-13, is a CFC with the molecular formula CCl F3. In the upper atmosphere, the presence of Freon-13 can lead to ozone depletion.

Explain, with the aid of equations, how Freon-13 can lead to this ozone depletion.

Use β€˜dots’ (β€’) to show the position of unpaired electrons.

[3]
Reveal mark scheme Mark scheme for question 17(a)
(b)

An oligomer is a polymer with a low molecular mass and a small number of repeat units.

An oligomer made from 2-chloro-1,1,2-trifluoroethene is used as a lubricating oil.

(b)(i)

Draw the repeat unit of this oligomer.

[1]
Reveal mark scheme Mark scheme for question 17(b)(i)
(b)(ii)

The boiling point of the lubricating oil can be increased by increasing the number of repeat units.

Explain this statement.

[2]
Reveal mark scheme Mark scheme for question 17(b)(ii)
(c)

A polymer can be made from the monomers:

β€’ 1,4-diaminobutane

β€’ benzene-1,4-diacyl dichloride.

Draw the structures of these monomers and one repeat unit of the polymer.

Figure for question 17
[4]
Reveal mark scheme Mark scheme for question 17(c)

Synthesis and analytical techniques November 2020, Question 18 11 marks

Also involves Biodegradability and disposal of polymers

Alcohols can be used to prepare organic compounds with different functional groups.

(a)

HO(CH2)4OH can be oxidised to form HOOC(CH2)2COOH.

(a)(i)

State the reagents and conditions and write an equation for this oxidation.

In the equation, use [O] for the oxidising agent.

Reagents and conditions:........

Equation:

[3]
Reveal mark scheme Mark scheme for question 18(a)(i)
(a)(ii)

HOOC(CH2)2COOH is soluble in water.

Explain, using a labelled diagram, why HOOC(CH2)2COOH is soluble in water.

[2]
Reveal mark scheme Mark scheme for question 18(a)(ii)
(b)

HOOC(CH2)2COOH and HO(CH2)4OH react together to form polymer E.

(b)(i)

Draw one repeat unit of polymer E.

The functional groups should be clearly displayed.

[2]
Reveal mark scheme Mark scheme for question 18(b)(i)
(b)(ii)

Governments are encouraging the development of biodegradable polymers to reduce dependency on persistent plastic waste derived from fossil fuels.

Polymer E is a biodegradable polymer.

Suggest why polymer E is able to biodegrade.

[1]
Reveal mark scheme Mark scheme for question 18(b)(ii)
(b)(iii)
Figure for question 18
[3]
Reveal mark scheme Mark scheme for question 18(b)(iii)

Synthesis and analytical techniques June 2019, Question 18 22 marks

This question is about esters.

(a)

The structure of ester A is shown below.

Figure for question 18
(a)(i)

What is the systematic name of ester A ?

[1]
Reveal mark scheme Mark scheme for question 18(a)(i)
(a)(ii)
Figure for question 18
[5]
Reveal mark scheme Mark scheme for question 18(a)(ii)
(a)(iii)

Name the type of reactions of ester A shown in (ii).

[1]
Reveal mark scheme Mark scheme for question 18(a)(iii)
(b)
Figure for question 18
[4]
Reveal mark scheme Mark scheme for question 18(b)
(c)
Figure for question 18
[1]
Reveal mark scheme Mark scheme for question 18(c)
(d)

A polyester is formed from 200 molecules of 4-hydroxybenzoic acid.

What is the relative molecular mass, Mr, of the polyester?

Mr =........ g molβˆ’1

[2]
Reveal mark scheme Mark scheme for question 18(d)
(e)

* A student intends to synthesise ester C.

Figure for question 18
(e)(i)

Plan a two-stage synthesis to prepare 12.75 g of ester C starting from 2-methylpropanal, (CH3)2CHCHO. Assume the overall percentage yield of ester C from 2-methylpropanal is 40%.

In your answer include the mass of 2-methylpropanal required, reagents, conditions and equations where appropriate.

Purification details are not required.

[6]
Reveal mark scheme Mark scheme for question 18(e)(i)
(e)(ii)
Figure for question 18
[2]
Reveal mark scheme Mark scheme for question 18(e)(ii)

Synthesis and analytical techniques June 2019, Question 19 21 marks

This question is about benzene.

(a)

Over time, the KekulΓ© and delocalised models have been used to describe the bonding and structure of a benzene molecule.

(a)(i)

Describe, in terms of orbital overlap, the similarities and differences between the bonding in the KekulΓ© model and the delocalised model of benzene.

[3]
Reveal mark scheme Mark scheme for question 19(a)(i)
(a)(ii)

Experimental evidence led to the general acceptance of the delocalised model over the KekulΓ© model.

Describe two pieces of evidence to support the delocalised model of benzene.

[2]
Reveal mark scheme Mark scheme for question 19(a)(ii)
(b)

Benzene can be used as the starting material for the synthesis of compounds D and E, shown below.

In the diagrams C6H5 is a phenyl group.

Figure for question 19

Compounds D and E can be converted into polymers.

(b)(i)

Draw two repeat units of these polymers.

Two repeat units of polymer formed from D

Two repeat units of polymer formed from E

[3]
Reveal mark scheme Mark scheme for question 19(b)(i)
(b)(ii)

State the type of polymer formed from compounds D and E.

From compound D........

From compound E........

[1]
Reveal mark scheme Mark scheme for question 19(b)(ii)
(b)(iii)

In the synthesis of compounds D and E, benzene is first reacted with ethanoyl chloride, CH3COCl, to form phenylethanone, shown below.

Figure for question 19

The reaction takes place in the presence of aluminium chloride, Al Cl3, which acts as a catalyst.

In the mechanism for this reaction,

β€’ ethanoyl chloride first reacts with aluminium chloride to form the CH3–C+=O cation

β€’ the CH3–C+=O cation then behaves as an electrophile.

Complete the mechanism for the reaction.

Include equations to show the role of the Al Cl3 catalyst, relevant curly arrows and the structure of the intermediate.

Formation of electrophile........

Question 19, shown as an image
Figure for question 19

Regeneration of catalyst........

[5]
Reveal mark scheme Mark scheme for question 19(b)(iii)
(b)(iv)

Complete the flowchart for the synthesis of compounds D and E from phenylethanone.

Figure for question 19
[7]
Reveal mark scheme Mark scheme for question 19(b)(iv)

Synthesis and analytical techniques June 2018, Question 17 7 marks

The general formula of an maths symbol-amino acid is RCH(NH2)COOH.

(a)

The maths symbol-amino acid cysteine (R = CH2SH) shows optical isomerism.

Draw 3-D diagrams to show the optical isomers of cysteine.

[2]
Reveal mark scheme Mark scheme for question 17(a)
(b)

The maths symbol-amino acid lysine (R = (CH2)4NH2) reacts with an excess of dilute hydrochloric acid to form a salt.

Draw the structure of the salt formed in this reaction.

[2]
Reveal mark scheme Mark scheme for question 17(b)
(c)

maths symbol-Amino acids can react to form proteins.

A short section of a protein chain is shown below.

Figure for question 17

A student hydrolyses the protein with hot NaOH(aq).

Draw the structures of the organic products formed from this section of the protein.

[3]
Reveal mark scheme Mark scheme for question 17(c)

Synthesis and analytical techniques June 2018, Question 21 12 marks

This question is about aromatic carboxylic acids and their derivatives.

(a)
Figure for question 21
[3]
Reveal mark scheme Mark scheme for question 21(a)
(b)
Figure for question 21
[4]
Reveal mark scheme Mark scheme for question 21(b)
(c)
Figure for question 21
(c)(i)

The concentration of ester K in the cosmetic product is 9.13 Γ— 10βˆ’2 g dmβˆ’3.

Using the results, calculate the concentration, in mol dmβˆ’3, of ester M in the cosmetic product.

Give your answer to two significant figures.

concentration of ester M =........ mol dmβˆ’3

[2]
Reveal mark scheme Mark scheme for question 21(c)(i)
(c)(ii)
Figure for question 21 Figure for question 21
[3]
Reveal mark scheme Mark scheme for question 21(c)(ii)

Synthesis and analytical techniques June 2017, Question 18 14 marks

Also involves Biodegradability and disposal of polymers

This question is about organic compounds containing nitrogen.

(a)

Sodium cyanide, NaCN, can be reacted with many organic compounds to increase the length of a carbon chain.

(a)(i)

1-Chloropropane, CH3CH2CH2Cl, reacts with ethanolic sodium cyanide by nucleophilic substitution.

Outline the mechanism for this reaction.

Include curly arrows, relevant dipoles and the structure of the organic product.

[3]
Reveal mark scheme Mark scheme for question 18(a)(i)
(a)(ii)

Compound G is used to synthesise compounds H and I as shown in the flowchart below.

Complete the flowchart showing the structure of compound G and the formulae of the reagents for Reaction 2 and Reaction 3.

Figure for question 18
[3]
Reveal mark scheme Mark scheme for question 18(a)(ii)
(a)(iii)

Compound H reacts with dilute hydrochloric acid to form a salt.

Explain why compound H can react with dilute hydrochloric acid and suggest a structure for the salt formed.

Explanation........

Structure

[2]
Reveal mark scheme Mark scheme for question 18(a)(iii)
(a)(iv)

Compound I is the monomer for the biodegradable polymer J.

Draw two repeat units of polymer J and suggest a reason why it is biodegradable.

[3]
Reveal mark scheme Mark scheme for question 18(a)(iv)
(b)

The repeat unit of Nylon 6,6 is shown below.

Figure for question 18
(b)(i)

Draw the structures of two monomers that can be used to form Nylon 6,6.

[2]
Reveal mark scheme Mark scheme for question 18(b)(i)
(b)(ii)

A sample of Nylon 6,6 has a relative molecular mass of 21500.

Estimate the number of repeat units in the sample.

Give your answer as a whole number.

[1]
Reveal mark scheme Mark scheme for question 18(b)(ii)

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