Periodic table, elements and physical chemistry June 2025, Question 17 16 marks
This question is about carbon monoxide and carbon as reducing agents in industry.
Iron(III) oxide, Fe2O3, can be reduced by carbon monoxide to form iron.
Some standard enthalpy change of formation, fH
, and standard entropy, S
, values are shown in the table.
| Substance | Fe2O3(s) | CO(g) | Fe(s) | CO2(g) |
| Ξf H | β824 | β111 | 0 | β394 |
| S | 87 | 198 | To calculate in part (a)(iv) | 214 |
Explain why the standard enthalpy change of formation of Fe has a value of 0 kJ molβ1.
Reveal mark scheme
Calculate the enthalpy change, rH, for the forward reaction in Equilibrium 17.1.
H =........ kJ molβ1
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Explain why the standard entropy of CO2 is greater than the standard entropy of Fe2O3.
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The standard entropy change, S
, for the forward reaction in Equilibrium 17.1 has a value of +15 J Kβ1 molβ1.
Use data from the table to calculate the standard entropy, S, of Fe.
S =........ J Kβ1 molβ1
Reveal mark scheme
Carbon can also reduce Fe2O3(s) to iron as shown in Equilibrium 17.2.
The forward reaction is only feasible at high temperatures.
β’ Show that the forward reaction is not feasible at 100 Β°C.
β’ Calculate the minimum temperature, in K, for the forward reaction to be feasible.
Give the minimum temperature to the nearest whole number.
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Steam can be reduced by carbon monoxide in a reversible reaction.
At 700 K the value of Kp is 8.13.
Explain why Kp for Equilibrium 17.3 has no units.
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An equal number of moles of steam and carbon monoxide are left at 700 K in a sealed container until equilibrium is reached.
At equilibrium, both H2 and CO2 have a partial pressure of 211 kPa.
Calculate the partial pressures of H2O and CO at equilibrium.
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At a second temperature the value of Kp for Equilibrium 17.3 is 129.
Explain whether the second temperature is higher or lower than 700 K.
Reveal mark scheme