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Further Maths A · OCR H245 · Additional Pure Mathematics (optional - choose any two of Y542/Y543/Y544/Y545) · June 2025

OCR A Level Further Maths A Additional Pure Mathematics (optional - choose any two of Y542/Y543/Y544/Y545) June 2025 question paper Y545

1h 30m 75 marks

Practise the past exam questions by topic

OCR H245 · Unit Y545

8 questions
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Question 1

(a)

A student claims that the order of 5 modulo 37 is 5.

Without calculation, explain why this student’s claim must be incorrect.

[1]

Answer
Mark scheme for question 1(a)
(b)

Show that the order of 5 modulo 37 is 36.

[3]

Answer
Mark scheme for question 1(b)

Question 2

The points P, Q, R and S have coordinates (1, 2, 4), (3, 1, 6), (4, 8, - 2) and (5, 5, 5) respectively.

(a)

Find, in exact form, the area of triangle PQR.

[3]

(b)

Find, in exact form, the volume of tetrahedron PQRS.

[3]

(c)

Use your answers to part (a) and part (b) to deduce the shortest distance from S to the plane containing P, Q and R. Give your answer in exact form.

[You may use the formula V = fraction Ah, where V is the volume of a pyramid, A is the area of one

of its bases and h is the height relative to the base.]

[2]

Question 4

In this question you must show detailed reasoning.

The surface S is given by the equation z = 4x2y - 3xy2 - 5x for all real values of x and y.

(a)

The point P (1, 1, - 4) lies on S.

Find the equation of the tangent plane to S at P.

[4]

(b)

The point Q is a stationary point of S with positive x - and y-coordinates.

(b)(i)

Find, in exact form, the coordinates of Q.

[5]

(b)(ii)

Find the value of the determinant of H, the Hessian matrix of S, at Q.

[4]

(b)(iii)

Deduce the nature of the stationary point Q.

[1]

Question 5

(a)

Determine the solution of the linear congruence 3 x ≡ 7 (mod 13). Give your answer in the

form x ≡ a (mod 13), where 0 ⩽ a < 13.

[2]

Answer
Mark scheme for question 5(a)
(b)

Hence or otherwise, determine the solution of the simultaneous linear congruences

3 x ≡ 7 (mod 13), 7 x ≡ 3 (mod 31).

[4]

Answer
Mark scheme for question 5(b)

Question 6

In this question, the set S is {2, 4, 6, 8}, and ×10 is the operation of multiplication modulo 10.

(a)

The group G consists of the set S, under the operation ×10.

(a)(i)

Complete the Cayley table for G given in the Printed Answer Booklet.

[1]

(a)(ii)

State the identity element of G.

[1]

(a)(iii)

State the order of each non-identity element of G.

[2]

(b)
Figure for question 6
(b)(i)

State, with justification, the order of H.

[2]

(b)(ii)

State also the identity element of H.

[1]

(b)(iii)

State all the elements of H of order 2.

[2]

(b)(iv)

Using the result of part (a)(iii), or otherwise, explain why all the (non-identity) elements

which do not have order 2 must have order 4.

[3]

(b)(v)

State whether or not H is cyclic. You must give a reason for your answer.

[1]

Question 7

In this question you must show detailed reasoning.

A curve is defined parametrically by x = cos3t, y = sin3t, for 0 ⩽ t ⩽ fraction. When the curve is rotated through 2π about the x-axis, a surface of revolution is formed with surface area A.

Determine the exact value of A.

[8]

Answer
Mark scheme for question 7

Question 8

(a)(i)

Determine, in terms of q, the general solution of the first-order recurrence relation.

[3]

(a)(ii)

Hence explain why, when q is close to zero, Gn is approximately constant and equal to

1.25.

[2]

(a)(iii)

In the case where G1 = 1.22 and G2 = 1.2378, find the values of q and G0.

[3]

(b)

The population of a species of fish Fn is being modelled by the second-order recurrence relation

Fn+2 = 1.25Fn+1 - rFn+1Fn,

where r is a positive constant and n is the number of weeks since the start of the breeding season.

You are given that the value of r is such that the model predicts that the population approaches a limiting value, L.

(b)(i)

Determine L in terms of r.

[2]

(b)(ii)

Determine what happens if a term of the sequence is greater than fraction

[2]

(b)(iii)

Explain why the modified recurrence relation Fn+2 = INT(1.25Fn+1 - rFn+1Fn) may be

preferable when modelling this fish population.

[1]

(b)(iv)

When r = 0.0001, both Fn+2 = 1.25Fn+1 - rFn+1Fn and Fn+2 = INT(1.25Fn+1 - rFn+1Fn) predict that the fish population approaches a limiting value.

By finding the limiting value for each model, when F0 = 2450 and F1 = 2475, compare

the two models for the fish population.

[3]

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