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Biology A (Gateway) · OCR J247 · Paper 2 · Foundation · June 2018

OCR GCSE Biology A (Gateway) Paper 2 Foundation June 2018 question paper J247/02

1h 45m 90 marks

OCR J247 · Paper 2

24 questions
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Question 1

Which process in the carbon cycle takes in carbon dioxide from the air?

A Combustion

B Decomposition

C Photosynthesis

D Respiration

Question 1, shown as an image

[1]

Answer
Mark scheme for question 1

Question 2

The diagram shows a pyramid of biomass.

Figure for question 2

Which trophic level is X ?

A Primary consumers

B Producers

C Secondary consumers

D Tertiary consumers

Question 2, shown as an image

[1]

Answer
Mark scheme for question 2

Question 3

There are two main types of reproduction, sexual and asexual.

Which is an advantage of sexual reproduction?

A Creates more variation

B Produces larger numbers of offspring

C Produces offspring that are all identical so well adapted

D Only needs one parent

Question 3, shown as an image

[1]

Answer
Mark scheme for question 3

Question 4

What did Gregor Mendel discover?

A A theory for how life on Earth started

B How characteristics are inherited in pea plants

C The shape of the DNA molecule

D The theory of natural selection

Question 4, shown as an image

[1]

Answer
Mark scheme for question 4

Question 5

Tears and stomach juices are important in the body’s response to pathogens.

TearsStomach juices
AAcidAntibiotics
BAntibioticsAntibodies
CAntibodiesLysozyme
DLysozymeAcid

Which row of the table correctly describes what substances are found in tears and stomach juices?

Question 5, shown as an image

[1]

Answer
Mark scheme for question 5

Question 6

Which statement describes how vaccines work?

A Cause the body to produce antibodies.

B Cause the release of antigens.

C Contain antiviral drugs.

D Make platelets more active.

Question 6, shown as an image

[1]

Answer
Mark scheme for question 6

Question 7

A scientist was studying a population of snails.

He caught 60 snails in the first sample. He marked them and released them.

He caught 50 snails in the second sample. 20 of the snails were marked.

Question 7, shown as an image

What is the estimated population?

A 150

B 2400

C 3000

D 60 000

Question 7, shown as an image

[1]

Answer
Mark scheme for question 7

Question 8

A gardener releases spiders into a greenhouse. They eat the insects which are eating her plants.

What is this an example of?

A Biological control

B Gene technology

C Homeostasis

D Parasitism

Question 8, shown as an image

[1]

Answer
Mark scheme for question 8

Question 9

In selective breeding which organisms breed?

A Humans choose which organisms breed.

B Organisms that are best suited to their environment will breed.

C Random organisms will breed.

D The youngest organisms will breed.

Question 9, shown as an image

[1]

Answer
Mark scheme for question 9

Question 10

A scientist is estimating the number of rabbits in a field.

He has eight different estimates, 12, 12, 13, 15, 17, 19, 22 and 26.

Which is the median value for his estimates?

A 8

B 12

C 16

D 17

Question 10, shown as an image

[1]

Answer
Mark scheme for question 10

Question 11

Strains of bacteria are now becoming resistant to antibiotics.

Which process is causing this resistance?

A Genetic modification

B Natural classification

C Natural selection

D Selective breeding

Question 11, shown as an image

[1]

Answer
Mark scheme for question 11

Question 12

Plants can be grown in water.

What is the name of this growth method?

A Active transport

B Germination

C Hypothermia

D Hydroponics

Question 12, shown as an image

[1]

Answer
Mark scheme for question 12

Question 13

An organism has the genotype TT.

Which term describes this organism?

A Heterozygous dominant

B Heterozygous recessive

C Homozygous dominant

D Homozygous recessive

Question 13, shown as an image

[1]

Answer
Mark scheme for question 13

Question 14

Which process produces gametes?

A Diffusion

B Fertilisation

C Meiosis

D Mitosis

Question 14, shown as an image

[1]

Answer
Mark scheme for question 14

Question 15

Which is a chemical defence of plants?

A Antimicrobial substances

B Cell walls

C Leaf cuticles

D Thorns

Question 15, shown as an image

[1]

Answer
Mark scheme for question 15

Question 16

(a)
Figure for question 16

[2]

Answer
Mark scheme for question 16(a)
(b)

Identical twins occur when an embryo splits into two.

In the diagram below, some of the chromosome numbers in the different cells have been given to you.

Figure for question 16

Cell in Twin A’s body
Cell in Twin B’s body

Complete the diagram to show the number of chromosomes in:

• The sperm cell

• The zygote

• The cell in Twin B’s body.

[3]

Answer
Mark scheme for question 16(b)

Question 17

A student investigates the effect of acid rain on seed growth.

• She soaks cotton wool in a solution with a pH value of 7.0.

• She puts 20 mustard seeds onto the cotton wool and places it inside a flask.

• She adds the same solution to the flask.

• She then repeats this four times using solutions with different pH values.

One of the flasks is shown in the diagram.

Figure for question 17

After 8 days she counts how many of the seeds are growing.

The table shows her results.

pH of solutionNumber of the 20 seeds that are growing after 8 days
7.017
6.518
6.016
5.56
5.02

The student used 20 seeds in each flask.

(a)

Write down one other factor that the student should have kept the same in this investigation.

[1]

Answer
Mark scheme for question 17(a)
(b)

Describe what this investigation shows about the effect of acid rain on seed growth.

[2]

Answer
Mark scheme for question 17(b)
(c)

One way to compare the growth of seeds is to use a germination index (GI).

Question 17, shown as an image
(c)(i)

For the seeds at pH 6.0, the mean root length was 5 mm.

Calculate the GI for these seeds.

[2]

Answer
Mark scheme for question 17(c)(i)
(c)(ii)

Look at the equation for GI.

This is a better way of measuring the effect of acid rain on seed growth than just counting the number of seeds growing.

Explain why.

[1]

Answer
Mark scheme for question 17(c)(ii)

Question 18

(a)

The sex chromosomes determine the sex of a baby.

What are the sex chromosomes of a male and of a female?

[2]

Answer
Mark scheme for question 18(a)
(b)

The data in the table shows the ratio of males to females in England and Wales.

Ratio of males to females in England and Wales
At birth105 males : 100 females
Average over the whole population98 males : 100 females
Answer
Mark scheme for question 18(b)
(b)(i)

What percentage of babies are male at birth?

[1]

Answer
Mark scheme for question 18(b)(i)
(b)(ii)

In a hospital 410 babies are born in a week.

Calculate how many of them are likely to be male.

[1]

Answer
Mark scheme for question 18(b)(ii)
(b)(iii)

On average, men do not live as long as women.

How does the data in the table show this?

[2]

Answer
Mark scheme for question 18(b)(iii)

Question 19

A gardener buys a composter to decay plant material as quickly as possible.

The composter has three sections.

Figure for question 19
Question 19, shown as an image

She designs an experiment to see if watering makes the plant material decay faster.

She waters:

• Section A once a week

• Section B once a month

• Section C is not watered.

(a)

The gardener wants valid results. Explain one factor that the gardener should keep constant.

[2]

Answer
Mark scheme for question 19(a)
(b)

The gardener measures the temperature in each section for five months.

She knows that heat is given off when plant material decays.

The graph shows her results.

Figure for question 19
(b)(i)

Write down two differences between the change in temperature in Section A and the change in temperature in Section C.

[2]

Answer
Mark scheme for question 19(b)(i)
(b)(ii)

The gardener decides that she should water all sections every week.

Explain why she decides this.

[1]

Answer
Mark scheme for question 19(b)(ii)
(c)

Each section of the composter has holes in it to let oxygen in.

Explain why this helps the material to decay.

[2]

Answer
Mark scheme for question 19(c)

Question 20

Retinitis pigmentosa is a genetic condition.

It is caused by a mutation to a gene. This mutation produces a recessive allele.

If people have retinitis pigmentosa then the cells in their retina are damaged.

(a)

Explain the meaning of these terms.

Mutation........

Gene........

[2]

Answer
Mark scheme for question 20(a)
(b)

If a person has two alleles for retinitis pigmentosa, they will not be able to see properly.

(b)(i)

Why does a person need two affected alleles to have the condition?

[1]

Answer
Mark scheme for question 20(b)(i)
(b)(ii)

Why does the condition affect the ability to see properly?

[1]

Answer
Mark scheme for question 20(b)(ii)
(c)

Two people are heterozygous for retinitis pigmentosa and are expecting a baby.

Complete the genetic diagram to work out the probability that the baby will have the condition.

R is the normal allele and r is the allele for retinitis pigmentosa.

Figure for question 20

[3]

Answer
Mark scheme for question 20(c)
(d)(i)

Scientists want to use stem cells as a treatment for this condition.

Why might stem cells be able to repair the retina?

[2]

Answer
Mark scheme for question 20(d)(i)
(d)(ii)

Write down two reasons why medical treatments are tested on animals first.

[2]

Answer
Mark scheme for question 20(d)(ii)

Question 21

The diagram shows the flow of biomass through an agricultural food chain.

Figure for question 21
(a)(i)

Calculate how much biomass is lost between the plants and humans.

[1]

Answer
Mark scheme for question 21(a)(i)
(a)(ii)

One way biomass is lost from the food chain is by insects eating the leaves of plants.

Write down one other way that biomass is lost from the food chain.

[1]

Answer
Mark scheme for question 21(a)(ii)
(b)

The plants grown for cattle food often have their leaves eaten by insects.

Scientists have produced genetically modified (GM) plants that make insecticide in their leaves.

(b)(i)

* Explain why these GM plants would make more biomass available to humans.

In your answer use the diagram of the agricultural food chain and ideas about photosynthesis.

[6]

Answer
Mark scheme for question 21(b)(i)
(b)(ii)

Suggest two reasons why some people are against this type of genetic engineering.

[2]

Answer
Mark scheme for question 21(b)(ii)

Question 22

Figure for question 22
(a)

In angina the heart muscle starts to carry out anaerobic respiration.

Explain why this happens.

Use the information in the diagram and your biological knowledge.

[3]

Answer
Mark scheme for question 22(a)
(b)

Angina is often the first sign of a disease called coronary heart disease (CHD).

The table is used to estimate the risk of getting CHD. The more points a person scores, then the higher the risk of getting CHD.

Risk factorNumber of points
123
Age in years<2021–3031–40
Blood cholesterol levelLowMediumHigh
Number of cigarettes smoked per day01–1011–20
MassBelow averageAverageAbove average
Number of parents with coronary heart disease (CHD)012
(b)(i)

How many points are scored by smoking 20 cigarettes a day?

[1]

Answer
Mark scheme for question 22(b)(i)
(b)(ii)

What is the effect of age on the chance of getting CHD?

[1]

Answer
Mark scheme for question 22(b)(ii)
(b)(iii)
Figure for question 22

[3]

Answer
Mark scheme for question 22(b)(iii)
(c)

There are several treatments for coronary heart disease (CHD).

One of these is an operation.

In this operation, doctors insert a metal grid called a stent into the artery.

Figure for question 22
(c)(i)

Look at the diagram.

Why does using a stent help treat CHD?

[2]

Answer
Mark scheme for question 22(c)(i)
(c)(ii)

Taking a drug called statins is a treatment for CHD.

The drug is taken every day and lowers the level of cholesterol in a person’s blood.

Suggest one advantage and one disadvantage of taking statins.

Advantage........

Disadvantage........

[2]

Answer
Mark scheme for question 22(c)(ii)

Question 23

Figure for question 23
(a)

How many secondary consumers are shown in this food web?

[1]

Answer
Mark scheme for question 23(a)
(b)

A survey was set up to see if the number of badgers and hedgehogs has changed in the UK.

The number of badgers and hedgehogs were counted in different areas each year from 2003 to 2012.

The graph shows the results.

Figure for question 23

Use the food web to suggest an explanation for the change in the number of hedgehogs shown in the graph.

[2]

Answer
Mark scheme for question 23(b)
(c)

Hedgehogs are covered in small spines.

When they are frightened they often roll up into a ball and keep still.

Figure for question 23
(c)(i)

In country areas, where badgers live, this is an advantage to the hedgehogs.

In cities, where there are many roads, this is a disadvantage.

Explain these two conclusions.

[2]

Answer
Mark scheme for question 23(c)(i)
(c)(ii)

Scientists have noticed that a new type of hedgehog is increasing in numbers in cities.

These hedgehogs do not roll up. They run away when frightened. The scientists think that genes control this behaviour.

Explain how this type of hedgehog may become more common in cities.

Use ideas about natural selection.

[4]

Answer
Mark scheme for question 23(c)(ii)

Question 24

A student investigates plants growing underneath a tree.

Figure for question 24

He lays out a tape measure on the ground, starting at the tree. He then places a quadrat on the ground.

He measures the percentage of the ground in the quadrat that is covered by plants. He repeats this every metre away from the tree.

The table shows his results.

Distance from the tree(m)Percentage of ground covered by plants (%)
110
215
318
422
550
658
762
864
(a)

Plot a graph of the student’s results and draw a line of best fit.

[5]

Answer
Mark scheme for question 24(a)
(b)

The student thinks that shade from the tree is affecting the plants.

Explain how the student’s results show this.

[4]

Answer
Mark scheme for question 24(b)

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