BREAKING
Mole Day revealed to be a lie, chemists demand refund★Student titrates to pale pink, class gives standing ovation★Bunsen left on yellow flame, teacher sighs for 3rd week★
  1. Home
  2. IGCSE
  3. Chemistry
  4. Edexcel
  5. Catalysts

Edexcel IGCSE Chemistry

Topic questions The rate and extent of chemical change Catalysts

Catalysts

15 questions · 171 marks · about 3 hours

Catalysts questions

Edexcel 4CH1 Catalysts 15 questions

Chemistry Paper 1 November 2024, Question 5 11 marks

Also involves Rate of reaction

Hydrogen peroxide decomposes to form water and oxygen.

This decomposition is shown in the equation.

(a)

Give the test for oxygen gas.

[1]
Reveal mark scheme Mark scheme for question 5(a)
(b)

The rate of reaction is increased by adding a suitable catalyst.

Describe how a catalyst increases the rate of a reaction.

[2]
Reveal mark scheme Mark scheme for question 5(b)
(c)

A student uses this apparatus to investigate the rate of decomposition of hydrogen peroxide solution.

Figure for question 5

The student adds 100 cm3 of hydrogen peroxide solution at 20 °C to the apparatus labelled A.

The student records the volume of oxygen gas collected every minute for 16 minutes.

The graph shows the student’s results.

Figure for question 5
(c)(i)

Name the pieces of apparatus labelled A and B.

[2]
Reveal mark scheme Mark scheme for question 5(c)(i)
(c)(ii)

Determine the volume of oxygen gas produced in the first 4 minutes.

Show on the graph how you obtain your answer.

[2]
Reveal mark scheme Mark scheme for question 5(c)(ii)
(c)(iii)

Determine the rate of reaction at 8 minutes by drawing a suitable tangent to the curve.

Include the units for the rate of reaction.

[4]
Reveal mark scheme Mark scheme for question 5(c)(iii)

Chemistry Paper 1 June 2024 (R), Question 10 6 marks

This is the equation for the decomposition of hydrogen peroxide.

Question 10, shown as an image

The rate of reaction increases when a catalyst of manganese(IV) oxide is added.

(a)

Describe how a catalyst increases the rate of a reaction.

[2]
Reveal mark scheme Mark scheme for question 10(a)
(b)

A student adds 50 cm3 of hydrogen peroxide solution to a glass container and then adds 1.0 g of manganese(IV) oxide.

The diagram shows the apparatus the student uses.

Figure for question 10
(b)(i)

Name the glass container the student uses.

[1]
Reveal mark scheme Mark scheme for question 10(b)(i)
(b)(ii)

The student waits until the hydrogen peroxide solution completely decomposes.

Describe how the student could then show that the manganese(IV) oxide was a catalyst and not a reactant.

[3]
Reveal mark scheme Mark scheme for question 10(b)(ii)

Chemistry Paper 1 November 2023, Question 6 12 marks

A student uses this apparatus to investigate the decomposition of hydrogen peroxide solution.

Figure for question 6

This is the equation for the reaction.

(a)

Give the test for oxygen.

[1]
Reveal mark scheme Mark scheme for question 6(a)
(b)

Complete the dot‑and‑cross diagram for a molecule of hydrogen peroxide.

Show outer electrons only.

[2]
Reveal mark scheme Mark scheme for question 6(b)
(c)

H O O H

The student measures the volume of oxygen collected at regular intervals until the reaction stops.

The table shows the student’s results.

Figure for question 6
(c)(i)

Plot the student’s results on the grid.

[1]
Reveal mark scheme Mark scheme for question 6(c)(i)
(c)(ii)

Draw a curve of best fit.

Figure for question 6
[1]
Reveal mark scheme Mark scheme for question 6(c)(ii)
(d)
(d)(i)

Explain in terms of particle collision theory how decreasing the concentration affects the rate of a reaction.

[3]
Reveal mark scheme Mark scheme for question 6(d)(i)
(d)(ii)

The student repeats the experiment using the same volume of hydrogen peroxide solution but with half the original concentration.

All other conditions are kept the same.

On the grid, draw the curve you would expect the student to obtain.

[2]
Reveal mark scheme Mark scheme for question 6(d)(ii)
(e)

In this reaction, the manganese(IV) oxide acts as a catalyst.

Explain how a catalyst works.

[2]
Reveal mark scheme Mark scheme for question 6(e)

Chemistry Paper 1 June 2023 (R), Question 6 10 marks

A student uses this apparatus to investigate the rate of reaction when hydrogen peroxide solution decomposes.

Figure for question 6

This is the equation for the reaction.

Question 6, shown as an image
(a)

Give a reason why the gas that collects in the gas syringe is not pure oxygen.

[1]
Reveal mark scheme Mark scheme for question 6(a)
(b)

The rate of reaction can be increased by adding a catalyst to the hydrogen peroxide solution.

Describe how a catalyst increases the rate of a reaction.

[2]
Reveal mark scheme Mark scheme for question 6(b)
(c)

These solids catalyse the decomposition of hydrogen peroxide solution.

• lead(IV) oxide

• manganese(IV) oxide

Describe a method that the student could use to find out which solid is the more effective catalyst.

[5]
Reveal mark scheme Mark scheme for question 6(c)
(d)

A student investigates the decomposition of a solution of hydrogen peroxide at different temperatures.

The graph shows how the total volume of oxygen collected in the syringe changes with time when the solution is at a temperature of 20 °C.

Figure for question 6

On the grid, draw the curve the student would obtain at a temperature of 40 °C when all other conditions are kept the same.

[2]
Reveal mark scheme Mark scheme for question 6(d)

Chemistry Paper 1 June 2023, Question 10 12 marks

Also involves Limiting reactants

Zinc reacts with dilute hydrochloric acid to form zinc chloride and hydrogen gas.

This is the equation for the reaction.

Question 10, shown as an image
(a)

In an experiment, 20 cm3 of hydrochloric acid containing 0.0036 mol are reacted with 1.3 g of zinc granules at a temperature of 30 °C.

(a)(i)

Show by calculation that the zinc is in excess.

[2]
Reveal mark scheme Mark scheme for question 10(a)(i)
(a)(ii)

The volume of hydrogen collected is measured at regular time intervals.

Curve A shows the results of this experiment.

Figure for question 10

The experiment is repeated using 1.3 g of zinc powder instead of zinc granules.

All other conditions are kept the same.

On the grid, draw the curve you would expect to obtain.

[2]
Reveal mark scheme Mark scheme for question 10(a)(ii)
(b)

In the original experiment, 20 cm3 of hydrochloric acid containing 0.0036 mol were reacted with 1.3 g of zinc granules at a temperature of 30 °C and curve A was obtained.

The student does two more experiments and obtains curves B and C.

Figure for question 10
(b)(i)

In one of these experiments the student repeats the original method but at a temperature of 20 °C.

Explain in terms of particle collision theory why the curve obtained could be curve B.

[4]
Reveal mark scheme Mark scheme for question 10(b)(i)
(b)(ii)

In the other experiment the student repeats the original method but uses 20 cm3 of hydrochloric acid containing 0.0018 mol.

Explain why curve C shows the results the student obtained.

[2]
Reveal mark scheme Mark scheme for question 10(b)(ii)
(c)

Catalysts can be used to speed up reactions.

Describe how a catalyst works.

[2]
Reveal mark scheme Mark scheme for question 10(c)

Chemistry Paper 2 January 2023, Question 6 13 marks

When ethanoic acid reacts with ethanol in the presence of concentrated sulfuric acid, one of the products is ester A.

This is the equation for the reaction.

Question 6, shown as an image
Question 6, shown as an image
Question 6, shown as an image

ethanoic acid
ethanol
water

(a)(i)

Draw a circle around the functional group in ethanoic acid.

[1]
Reveal mark scheme Mark scheme for question 6(a)(i)
(a)(ii)

Give the displayed formula of ester A.

[2]
Reveal mark scheme Mark scheme for question 6(a)(ii)
(a)(iii)

Name ester A.

[1]
Reveal mark scheme Mark scheme for question 6(a)(iii)
(b)

The reaction mixture is kept in a sealed container until dynamic equilibrium is reached.

State what is meant by the term dynamic equilibrium.

[2]
Reveal mark scheme Mark scheme for question 6(b)
(c)

During the reaction, the number of moles of ethanoic acid in the reaction mixture decreases, but the number of moles of concentrated sulfuric acid does not change.

(c)(i)

Give a reason why the number of moles of concentrated sulfuric acid does not change.

[1]
Reveal mark scheme Mark scheme for question 6(c)(i)
(c)(ii)

A student does a titration to find the accurate volume of sodium hydroxide solution needed for complete neutralisation.

The student starts by using a pipette to transfer 25.0 cm3 of the reaction mixture to a conical flask.

Describe how the student should complete the titration.

[6]
Reveal mark scheme Mark scheme for question 6(c)(ii)

Chemistry Paper 1 June 2022 (R), Question 9 10 marks

This question is about rates of reaction.

(a)

A student uses this method to investigate the rate of reaction between iron(III) nitrate solution and sodium thiosulfate solution.

• pour 50 cm3 of iron(III) nitrate solution into a conical flask

• add one drop of catalyst solution

• add 50 cm3 of sodium thiosulfate solution to the conical flask

• record the time for the mixture to become colourless

The student repeats the method using different catalysts and also with no catalyst.

The table shows the student’s results.

CatalystTime for mixture to become colourless in s
no catalyst55
cobalt(II) chloride solution32
copper(II) sulfate solution8
iron(II) sulfate solution27
zinc nitrate solution75
(a)(i)

Explain which is the best catalyst for the reaction.

[2]
Reveal mark scheme Mark scheme for question 9(a)(i)
(a)(ii)

Explain how a catalyst increases the rate of a reaction.

[2]
Reveal mark scheme Mark scheme for question 9(a)(ii)
(b)

The rate of a reaction can also be altered by changing the temperature or by changing the concentration of solutions.

(b)(i)

Explain, using the particle collision theory, how increasing the temperature affects the rate of a reaction.

[4]
Reveal mark scheme Mark scheme for question 9(b)(i)
(b)(ii)

Explain why using a solution of a lower concentration decreases the rate of reaction.

[2]
Reveal mark scheme Mark scheme for question 9(b)(ii)

Chemistry Paper 2 June 2022 (R), Question 7 15 marks

Also involves Limiting reactants · Percentage yield · The Haber process

In the presence of an iron catalyst, nitrogen reacts with hydrogen to form ammonia.

The reaction conditions used are a temperature of 450maths symbolC and a pressure of 200 atmospheres.

This is the equation for the reaction.

Question 7, shown as an image
(a)(i)

State what the symbol maths symbol represents.

[1]
Reveal mark scheme Mark scheme for question 7(a)(i)
(a)(ii)

Give the reason for using a catalyst.

[1]
Reveal mark scheme Mark scheme for question 7(a)(ii)
(b)(i)

The reaction mixture is kept at a pressure of 200 atmospheres, but the

Question 7, shown as an image

Explain the effect of this change on the yield of ammonia at equilibrium.

[2]
Reveal mark scheme Mark scheme for question 7(b)(i)
(b)(ii)

The reaction mixture is kept at a temperature of 450maths symbolC, but the pressure is increased to 300 atmospheres.

Explain the effect of this change on the yield of ammonia at equilibrium.

[2]
Reveal mark scheme Mark scheme for question 7(b)(ii)
(c)

Draw an energy level diagram for the reaction between nitrogen and hydrogen.

Include the reactants, products and Δ H in your diagram.

Figure for question 7
[3]
Reveal mark scheme Mark scheme for question 7(c)
(d)

QUESTION 7 CONTINUES ON NEXT PAGE

At the start of the reaction, 48 dm3 of nitrogen is added to 120 dm3 of hydrogen at rtp.

Question 7, shown as an image

[molar volume of any gas at rtp = 24 dm3]

(d)(i)

Show by calculation that the nitrogen is in excess.

[3]
Reveal mark scheme Mark scheme for question 7(d)(i)
(d)(ii)

The yield of ammonia at equilibrium is 20 %.

Calculate the volume, in dm3, of ammonia formed from 120 dm3 of hydrogen.

[3]
Reveal mark scheme Mark scheme for question 7(d)(ii)

Chemistry Paper 2 January 2022, Question 5 8 marks

Hydrogen peroxide solution decomposes to give water and oxygen gas.

The equation for this reaction is

Question 5, shown as an image
(a)

Three different solids are catalysts for the decomposition of hydrogen peroxide solution.

A student is given hydrogen peroxide solution and a sample of each of the solid catalysts.

The student has a timer, a measuring cylinder, a balance and the apparatus shown in the diagram.

Describe a method the student could use to find which of the three solids is the most effective catalyst for the decomposition of hydrogen peroxide solution.

[5]
Reveal mark scheme Mark scheme for question 5(a)
(b)

The diagram shows the reaction profile for the decomposition of hydrogen peroxide without a catalyst.

Figure for question 5
(b)(i)

Label the diagram to show the activation energy (Ea) and the enthalpy change (Δ H) for this reaction.

[2]
Reveal mark scheme Mark scheme for question 5(b)(i)
(b)(ii)

On the diagram, draw a curve to show the reaction profile for the same reaction when a catalyst is used.

[1]
Reveal mark scheme Mark scheme for question 5(b)(ii)

Chemistry Paper 2 January 2022 (R), Question 5 12 marks

Also involves Percentage yield

This question is about three stages in the manufacture of sulfuric acid.

(a)

In stage 1, sulfur is burned in oxygen to form sulfur dioxide gas.

Question 5, shown as an image
(a)(i)

State one environmental problem caused by the release of sulfur dioxide into the atmosphere.

[1]
Reveal mark scheme Mark scheme for question 5(a)(i)
(a)(ii)

A mass of 6.4 tonnes of sulfur is burned to produce sulfur dioxide gas.

Calculate the maximum volume, in dm3, of sulfur dioxide gas that can be produced at rtp.

[molar volume of sulfur dioxide gas at rtp = 24 dm3]

[1 tonne = 106g]

Give your answer in standard form.

[3]
Reveal mark scheme Mark scheme for question 5(a)(ii)
(b)

In stage 2, sulfur dioxide is reacted with oxygen to form sulfur trioxide gas.

Question 5, shown as an image

The yield of sulfur trioxide is approximately 98%.

(b)(i)

A catalyst is used in this reaction.

Explain how a catalyst increases the rate of a reaction.

[2]
Reveal mark scheme Mark scheme for question 5(b)(i)
(b)(ii)

The temperature is kept constant.

Give a reason why increasing the pressure would increase the yield of sulfur trioxide.

[1]
Reveal mark scheme Mark scheme for question 5(b)(ii)
(b)(iii)

Suggest why it is not necessary to increase the pressure in stage 2.

[1]
Reveal mark scheme Mark scheme for question 5(b)(iii)
(c)

In stage 3, the sulfur trioxide is reacted with concentrated sulfuric acid to form a liquid called oleum, H2S2O7

The oleum is then added to water to form concentrated sulfuric acid.

Complete the chemical equations for these two reactions.

Question 5, shown as an image
[2]
Reveal mark scheme Mark scheme for question 5(c)
(d)

Sulfuric acid reacts with ammonia to form ammonium sulfate, (NH4)2SO4

Calculate the percentage by mass of nitrogen in ammonium sulfate.

[Mr of (NH4)2SO4 = 132]

[2]
Reveal mark scheme Mark scheme for question 5(d)

Chemistry Paper 2 January 2021 (R), Question 5 13 marks

Hydrogen peroxide solution decomposes slowly at room temperature to form water and oxygen.

The equation for the reaction is

Question 5, shown as an image
(a)

A catalyst increases the rate of this reaction.

State one other property of a catalyst.

[1]
Reveal mark scheme Mark scheme for question 5(a)
(b)

A student has samples of three solids, X, Y and Z.

The student uses this apparatus to find out which solids act as catalysts in the decomposition of hydrogen peroxide solution.

Figure for question 5

Describe the method that the student should use to find out which solids act as catalysts.

[6]
Reveal mark scheme Mark scheme for question 5(b)
(c)

The decomposition of hydrogen peroxide solution is exothermic.

On the diagram, draw and label the reaction profiles for the reaction

maths symbol without a catalyst

maths symbol with a catalyst

Figure for question 5
[2]
Reveal mark scheme Mark scheme for question 5(c)
(d)

The equation for the reaction can be shown using displayed formulae.

Question 5, shown as an image

The table gives the bond energies for two of the bonds.

BondBond energy in kJ/mol
H O463
O O146
(d)(i)

Use this information to calculate the total amount of energy needed to break all the bonds in two moles of H2O2

[1]
Reveal mark scheme Mark scheme for question 5(d)(i)
(d)(ii)

Use this information to calculate the total amount of energy released when all the bonds in two moles of H2O are formed.

[1]
Reveal mark scheme Mark scheme for question 5(d)(ii)
(d)(iii)

Use the value of ΔH and your answers for (i) and (ii) to calculate the bond energy, in kJ/mol, for the O fraction O bond.

bond energy =........ kJ/mol

[2]
Reveal mark scheme Mark scheme for question 5(d)(iii)

Chemistry Paper 1 November 2020 (R), Question 4 14 marks

Also involves Chemical measurements and uncertainty

A solution of hydrogen peroxide decomposes when a catalyst of manganese(IV) oxide is added.

The products of the reaction are water and oxygen.

(a)

Complete the chemical equation for this reaction.

Question 4, shown as an image
[1]
Reveal mark scheme Mark scheme for question 4(a)
(b)

Give a test for oxygen.

[1]
Reveal mark scheme Mark scheme for question 4(b)
(c)

State the reason for adding a catalyst.

[1]
Reveal mark scheme Mark scheme for question 4(c)
(d)

A student investigates how changing the concentration of the hydrogen peroxide solution affects the rate of this reaction.

She uses this apparatus.

Figure for question 4

The student records the volume of oxygen that collects every 2 minutes for 16 minutes.

The table shows her results.

Figure for question 4
(d)(i)

Plot the student’s results on the grid.

[1]
Reveal mark scheme Mark scheme for question 4(d)(i)
(d)(ii)

Draw a circle on the grid around the anomalous result.

[1]
Reveal mark scheme Mark scheme for question 4(d)(ii)
(d)(iii)

Draw a curve of best fit through the points, ignoring the anomalous result.

Figure for question 4
[1]
Reveal mark scheme Mark scheme for question 4(d)(iii)
(d)(iv)

Suggest a mistake that the student might have made to cause the anomalous result.

[1]
Reveal mark scheme Mark scheme for question 4(d)(iv)
(d)(v)

Determine the volume of oxygen collected during the first 3 minutes.

Show on your graph how you obtain your answer.

Question 4, shown as an image
[2]
Reveal mark scheme Mark scheme for question 4(d)(v)
(e)

The student repeats the experiment using hydrogen peroxide solution of half the concentration of the original solution.

She keeps the volume of the hydrogen peroxide solution and all other conditions the same.

(e)(i)

Draw on the grid the curve you would expect the student to obtain.

[2]
Reveal mark scheme Mark scheme for question 4(e)(i)
(e)(ii)

Explain how using hydrogen peroxide solution of half the concentration affects the rate of the reaction.

Refer to particle collision theory in your answer.

[3]
Reveal mark scheme Mark scheme for question 4(e)(ii)

Chemistry Paper 1 January 2020, Question 10 12 marks

Also involves Moles and amount of substance

Figure for question 10
(a)(i)

Complete the chemical equation for the reaction in stage 1.

Question 10, shown as an image
[1]
Reveal mark scheme Mark scheme for question 10(a)(i)
(a)(ii)

Give the meaning of the symbol maths symbol

[1]
Reveal mark scheme Mark scheme for question 10(a)(ii)
(a)(iii)

State the purpose of the platinum catalyst.

[1]
Reveal mark scheme Mark scheme for question 10(a)(iii)
(b)

Give a chemical equation for the reaction of nitrogen monoxide and oxygen in stage 2.

[1]
Reveal mark scheme Mark scheme for question 10(b)
(c)
(c)(i)

The equation for the reaction in stage 3 is

Question 10, shown as an image

Calculate the maximum mass, in tonnes, of nitric acid that could be produced in this reaction from 11.5 tonnes of nitrogen dioxide.

Question 10, shown as an image

mass of nitric acid =........ tonnes

[4]
Reveal mark scheme Mark scheme for question 10(c)(i)
(c)(ii)

Suggest what use can be made of the nitrogen monoxide gas formed in stage 3.

[1]
Reveal mark scheme Mark scheme for question 10(c)(ii)
(d)

When copper(II) oxide reacts with dilute nitric acid, copper(II) nitrate is produced.

The equation for the reaction is

Question 10, shown as an image

0.200 mol of nitric acid reacts with excess copper(II) oxide.

A mass of 15.3 g of copper(II) nitrate is produced.

Calculate the percentage yield of copper(II) nitrate.

[Mr of copper(II) nitrate = 187.5]

[3]
Reveal mark scheme Mark scheme for question 10(d)

Chemistry Paper 2 January 2020, Question 5 8 marks

Oxygen can be prepared from hydrogen peroxide using a catalyst.

(a)

Which is a correct statement about oxygen?

Question 5, shown as an image
[1]
Reveal mark scheme Mark scheme for question 5(a)
(b)

Explain how a catalyst increases the rate of a reaction.

[2]
Reveal mark scheme Mark scheme for question 5(b)
(c)

The equation for the preparation of oxygen from hydrogen peroxide is

This equation can also be written using displayed formulae to show all the covalent bonds in the molecules.

Question 5, shown as an image

The table gives the bond energies for these bonds.

BondH OO OO O
Bond energy in kJ/mol463143498
(c)(i)

Use the values in the table to calculate the enthalpy change, Δ H, for the reaction.

Include a sign in your answer.

[3]
Reveal mark scheme Mark scheme for question 5(c)(i)
(c)(ii)

Complete the energy level diagram to show the position of the products and the enthalpy change, Δ H, for the reaction.

Figure for question 5
[2]
Reveal mark scheme Mark scheme for question 5(c)(ii)

Chemistry Paper 2 January 2020 (R), Question 6 15 marks

This question is about ethane and ethene.

(a)

Ethane can be obtained from crude oil.

Describe the industrial process used to separate crude oil into fractions.

[4]
Reveal mark scheme Mark scheme for question 6(a)
(b)

The equation for the reaction between ethene gas and hydrogen gas is

Question 6, shown as an image

The rate of this reaction can be increased by increasing the pressure.

(b)(i)

Explain why increasing the pressure increases the rate of this reaction.

[2]
Reveal mark scheme Mark scheme for question 6(b)(i)
(b)(ii)

The rate of this reaction can also be increased by using a catalyst.

Explain how using a catalyst increases the rate of a reaction.

[2]
Reveal mark scheme Mark scheme for question 6(b)(ii)
(b)(iii)

Give one other way that the rate of reaction between ethene gas and hydrogen gas can be increased.

[1]
Reveal mark scheme Mark scheme for question 6(b)(iii)
(b)(iv)

The reaction between ethene and hydrogen is exothermic.

Complete the reaction profile diagram, including labels for the activation energy and the enthalpy change, maths symbolH.

Question 6, shown as an image
[3]
Reveal mark scheme Mark scheme for question 6(b)(iv)
(c)

The reaction between ethene and hydrogen can be represented using displayed formulae.

H H H H

Question 6, shown as an image
Figure for question 6

Use the bond energies in the table to calculate the enthalpy change, maths symbolH, in kJ/mol for this reaction.

maths symbolH =........ kJ/mol

[3]
Reveal mark scheme Mark scheme for question 6(c)

Report a problem with a question on this page
What is wrong?

Goes to whoever maintains the question split. No account needed and nothing is published on this page.

Memes

Certified Chemistry memes. Peer-reviewed by nobody.

Laugh now. Cry in the exam hall later. Then come back and do a past paper.

Do the mole calculation
Write ‘exothermic’ and pray
Me on the 6-marker about electrolysis
Knowing water is H₂O
Balancing an equation first try
Getting two concordant titres
Realising nobody actually knows what a mole is
Chemistry enlightenment, ranked

Mum 💖

how's chemistry going love?? 🥰

we're doing bonding rn

aww that's lovely 💕

📱 Screen time this week · TikTok6h 2m

Zero bonds were formed

Chemistry starter pack

Goggles that fog instantlyBunsen on the orange flameBurette that's always leakingThis website
Goggles on, collect all four