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Edexcel IGCSE Chemistry

Topic questions Quantitative chemistry Percentage yield

Percentage yield

13 questions · 161 marks · about 3 hours

Percentage yield questions

Edexcel 4CH1 Percentage yield 13 questions

Chemistry Paper 1 June 2025, Question 6 13 marks

(a)

When iron rusts, iron(III) oxide forms.

State two conditions needed for iron to rust.

[2]
Reveal mark scheme Mark scheme for question 6(a)
(b)

What is the name of the process used to coat iron with zinc?

Question 6, shown as an image
[1]
Reveal mark scheme Mark scheme for question 6(b)
(c)

What is the correct order of reactivity of these four metals?

Question 6, shown as an image
Question 6, shown as an image
[1]
Reveal mark scheme Mark scheme for question 6(c)
(d)

Describe a test to show that a solution contains Fe3+ ions.

test

[2]
Reveal mark scheme Mark scheme for question 6(d)
(e)

result

A sample of iron(III) oxide reacts with excess carbon monoxide.

This is the equation for the reaction.

Question 6, shown as an image
(e)(i)

Explain why this is a redox reaction.

[2]
Reveal mark scheme Mark scheme for question 6(e)(i)
(e)(ii)

Calculate the minimum mass of iron(III) oxide needed to produce a theoretical yield of 28 g of iron.

[for Fe2O3 Mr = 160]

[3]
Reveal mark scheme Mark scheme for question 6(e)(ii)
(e)(iii)

The actual yield of iron from this sample is 21 g.

Calculate the percentage yield of iron.

[2]
Reveal mark scheme Mark scheme for question 6(e)(iii)

Chemistry Paper 2 June 2025 (R), Question 6 15 marks

Also involves Amounts of substance in equations

A student does a titration to find the volume of phosphoric acid solution (H3PO4) needed to neutralise a sample of potassium hydroxide solution (KOH).

One of the products of the reaction is potassium phosphate.

This is the student’s method.

• use a measuring cylinder to transfer 25 cm3 of potassium hydroxide solution to a conical flask

• add two drops of an indicator

• fill a burette with phosphoric acid solution and record the initial reading on the burette

• add the acid to the conical flask

• record the final burette reading when the indicator changes colour

This is the equation for the reaction.

Question 6, shown as an image
(a)

Explain two improvements to the student’s method that would give more accurate results.

[4]
Reveal mark scheme Mark scheme for question 6(a)
(b)

The student repeats the titration correctly.

The potassium hydroxide solution has a concentration of 0.150 mol / dm3.

The phosphoric acid solution has a concentration of 0.0400 mol / dm3.

Calculate the volume, in cm3, of phosphoric acid solution needed to neutralise 25.0 cm3 of 0.150 mol / dm3 potassium hydroxide solution.

Give your answer to three significant figures.

[4]
Reveal mark scheme Mark scheme for question 6(b)
(c)

Potassium phosphate solution reacts with calcium chloride solution.

One of the products is the insoluble solid, calcium phosphate.

(c)(i)

Complete the equation for the reaction.

Question 6, shown as an image
[1]
(c)(ii)

The student reacts a solution containing 0.0400 mol of potassium phosphate with an excess of calcium chloride solution.

The student obtains 5.70 g of calcium phosphate.

Show that the percentage yield for the reaction is about 90%

[for Ca3(PO4)2 Mr = 310]

[3]
Reveal mark scheme Mark scheme for question 6(c)(ii)
(c)(iii)

Describe how the student can obtain a pure, dry sample of calcium phosphate from the mixture at the end of the reaction.

[3]
Reveal mark scheme Mark scheme for question 6(c)(iii)

Chemistry Paper 2 June 2024 (R), Question 4 8 marks

Also involves Moles and amount of substance

This question is about the manufacture of ethanol by the fermentation of glucose.

(a)

Fermentation needs to be done in the absence of air.

Give two other conditions needed for fermentation.

[2]
Reveal mark scheme Mark scheme for question 4(a)
(b)

Explain why fermentation needs to be done in the absence of air.

[2]
Reveal mark scheme Mark scheme for question 4(b)
(c)
(c)(i)

Complete the equation for fermentation.

Question 4, shown as an image
[1]
Reveal mark scheme Mark scheme for question 4(c)(i)
(c)(ii)

A mixture containing 500 mol of glucose is fermented.

A mass of 5750 g of ethanol is obtained.

Calculate the percentage yield.

[for ethanol, Mr = 46]

[3]
Reveal mark scheme Mark scheme for question 4(c)(ii)

Chemistry Paper 1 November 2023, Question 10 9 marks

Also involves Moles and amount of substance

This method is used in an experiment to produce hydrated zinc nitrate crystals.

• pour 50 cm3 of dilute nitric acid into a beaker

• add a spatula of zinc powder to the acid

• add more zinc until it is in excess

• filter the mixture

• obtain crystals of zinc nitrate from the filtrate

(a)

State why the mixture is filtered.

[1]
Reveal mark scheme Mark scheme for question 10(a)
(b)

Describe how a pure, dry sample of hydrated zinc nitrate crystals could be obtained from the filtrate.

[4]
Reveal mark scheme Mark scheme for question 10(b)
(c)

This equation represents the formation of hydrated zinc nitrate in the experiment.

Question 10, shown as an image
(c)(i)

In another experiment, 9.75 g of zinc is completely reacted with nitric acid.

Show that the maximum possible mass of hydrated zinc nitrate crystals that could be formed is approximately 45 g.

[for Zn(NO3)2.6H2O, Mr = 297]

[2]
Reveal mark scheme Mark scheme for question 10(c)(i)
(c)(ii)

The actual yield of hydrated zinc nitrate crystals is 36.4 g.

Calculate the percentage yield of hydrated zinc nitrate crystals.

[2]
Reveal mark scheme Mark scheme for question 10(c)(ii)

Chemistry Paper 2 June 2023 (R), Question 5 13 marks

Also involves Moles and amount of substance · Electrolysis of molten ionic compounds

This question is about the insoluble salt, lead(II) bromide.

Lead(II) bromide can be made by a precipitation reaction.

This is the equation for the reaction.

Pb(NO3)2(aq) + 2KBr(aq) maths symbol PbBr2(s) + 2KNO3(aq)

(a)

Describe how solutions of lead nitrate and potassium bromide can be used to make a pure, dry sample of lead(II) bromide.

[4]
Reveal mark scheme Mark scheme for question 5(a)
(b)

A solution containing 0.150 mol of lead(II) nitrate is reacted with an excess of potassium bromide solution.

A mass of 49.6 g of pure, dry lead(II) bromide is produced.

Show, by calculation, that the percentage yield of lead(II) bromide is 90.1%.

[for PbBr2, Mr = 367]

[2]
Reveal mark scheme Mark scheme for question 5(b)
(c)

A student investigates the change in electrical conductivity as dilute lead(II) nitrate solution is added to dilute potassium bromide solution.

This is the student’s method.

Step 1add 50 cm3 of potassium bromide solution to a beaker

Step 2 measure the electrical conductivity of the solution

Step 3add 10 cm3 of lead(II) nitrate solution to the beaker

Step 4 stir the mixture

Step 5 measure the electrical conductivity of the mixture

Repeat steps 3, 4 and 5 until a total of 50 cm3 of lead(II) nitrate solution has been added.

The table shows the student’s results.

Total volume of lead(II) nitrate solution added in cm3Electrical conductivity in arbitrary units
010.00
109.80
209.77
309.40
409.20
509.00
(c)(i)

Plot the student’s results on the grid.

[1]
Reveal mark scheme Mark scheme for question 5(c)(i)
(c)(ii)

Draw a line of best fit, ignoring the anomalous result.

Figure for question 5

Total volume of lead(II) nitrate in cm3

[1]
(c)(iii)

Explain the shape of the graph.

[2]
Reveal mark scheme Mark scheme for question 5(c)(iii)
(c)(iv)

Suggest a mistake the student could have made to cause the anomalous result.

[1]
Reveal mark scheme Mark scheme for question 5(c)(iv)
(c)(v)

Further 10 cm3 volumes of lead(II) nitrate are added to the beaker so the lead(II) nitrate is in excess.

Predict what will happen to the conductivity of the mixture when the lead(II) nitrate is in excess.

[1]
Reveal mark scheme Mark scheme for question 5(c)(v)
(d)

The diagram shows the electrolysis of molten lead(II) bromide, PbBr2

Figure for question 5
Question 5, shown as an image

This is the ionic half‑equation for the formation of bromine at electrode A.

Question 5, shown as an image

Give a reason why this half‑equation shows oxidation.

[1]
Reveal mark scheme Mark scheme for question 5(d)

Chemistry Paper 1 June 2022 (R), Question 11 10 marks

Also involves Hazard symbols and risk assessment

Figure for question 11
(a)

A teacher uses this apparatus to reduce tungsten oxide.

Figure for question 11

This is the teacher’s method.

• record the mass of a weighing boat

• add tungsten oxide and record the mass again

• heat the weighing boat and tungsten oxide strongly for two minutes and then allow to cool

• record the mass of the weighing boat and its contents

(a)(i)

Complete the equation by adding the state symbols.

Question 11, shown as an image
[2]
Reveal mark scheme Mark scheme for question 11(a)(i)
(a)(ii)

Give an addition to the method to check that the tungsten oxide has been completely reduced.

[1]
Reveal mark scheme Mark scheme for question 11(a)(ii)
(a)(iii)

The table shows the teacher’s results.

Mass in g
empty weighing boat14.72
weighing boat and tungsten oxide17.04
weighing boat and tungsten16.56

Use the teacher’s results to show that the empirical formula of tungsten oxide is WO3

[for tungsten, Ar = 184 for oxygen, Ar = 16]

[3]
Reveal mark scheme Mark scheme for question 11(a)(iii)
(a)(iv)

The teacher wears eye protection and a lab coat during the experiment.

Give one other safety precaution the teacher should take.

[1]
Reveal mark scheme Mark scheme for question 11(a)(iv)
(b)

In industry, tungsten oxide is reduced on a large scale using hydrogen.

The percentage yield of tungsten is 73.5%

This is the equation for the reaction.

Question 11, shown as an image

Calculate the mass, in tonnes, of tungsten that is produced when 2784 tonnes of tungsten oxide are reacted with an excess of hydrogen.

[1 tonne = 1maths symbol106g]

[for tungsten, Ar = 184 for oxygen, Ar = 16]

mass of tungsten =........ tonnes

[3]
Reveal mark scheme Mark scheme for question 11(b)

Chemistry Paper 1 January 2022, Question 11 12 marks

A student uses this apparatus to heat crystals of hydrated zinc sulfate and collect the liquid produced.

Figure for question 11
(a)(i)

Describe a chemical test to show that the colourless liquid contains water.

[2]
Reveal mark scheme Mark scheme for question 11(a)(i)
(a)(ii)

Describe a physical test to show the colourless liquid is pure water.

[2]
Reveal mark scheme Mark scheme for question 11(a)(ii)
(b)

The equation for the decomposition of hydrated zinc sulfate is

Question 11, shown as an image

The student records these masses.

mass of boiling tube = 41.64 g

mass of boiling tube + ZnSO4·7H2O = 54.46 g

Calculate the maximum volume, in cm3, of pure water that could be produced.

Give your answer to 1 decimal place.

[1.00 cm3 of pure water has a mass of 1.00 g]

[Mr of ZnSO4·7H2O = 287 Mr of H2O = 18]

[5]
Reveal mark scheme Mark scheme for question 11(b)
(c)

In an experiment using a different mass of ZnSO4·7H2O the maximum volume of pure water that could be produced is 8.5 cm3.

The student collected the pure water and calculated the percentage yield to be 20.3 %.

(c)(i)

Calculate the volume, in cm3, of pure water collected.

[1]
Reveal mark scheme Mark scheme for question 11(c)(i)
(c)(ii)

Explain an improvement to the apparatus that would increase the percentage yield of pure water.

[2]
Reveal mark scheme Mark scheme for question 11(c)(ii)

Chemistry Paper 1 January 2021 (R), Question 10 15 marks

This question is about salts.

(a)

Soluble salts can be prepared by the reaction between a metal oxide and an acid.

The equation for this type of reaction is

metal oxide + acid maths symbol salt + water

(a)(i)

State the name given to this type of reaction.

[1]
Reveal mark scheme Mark scheme for question 10(a)(i)
(a)(ii)

State, in terms of protons, what happens in this reaction.

[1]
Reveal mark scheme Mark scheme for question 10(a)(ii)
(b)(i)

A student is given 50 cm3 of dilute sulfuric acid and a bottle of solid copper(II) carbonate.

Describe the method that the student should use to prepare a saturated solution of copper(II) sulfate.

In your answer, refer to the pieces of apparatus that the student should use.

[5]
Reveal mark scheme Mark scheme for question 10(b)(i)
(b)(ii)

The student produces dry crystals of hydrated copper(II) sulfate from the saturated solution.

He calculates that 6.40 g of dry crystals should be formed.

The mass of dry crystals he actually obtains is 1.80 g less than he calculated.

Calculate the student’s percentage yield.

Give your answer to one decimal place.

[3]
Reveal mark scheme Mark scheme for question 10(b)(ii)
(c)
(c)(i)

Gypsum is hydrated calcium sulfate.

A sample of gypsum contains 79% of calcium sulfate by mass.

Calculate the value of x in CaSO4.xH2O

Question 10, shown as an image
[3]
Reveal mark scheme Mark scheme for question 10(c)(i)
(c)(ii)

Describe a test for calcium ions in the sample of gypsum.

[2]
Reveal mark scheme Mark scheme for question 10(c)(ii)

Chemistry Paper 2 January 2021, Question 6 15 marks

Also involves Limiting reactants

This question is about the insoluble salt silver chloride (AgC l).

Silver chloride can be made by the reaction between copper(II) chloride and silver nitrate.

(a)

Describe how a student could prepare a pure, dry sample of silver chloride starting with copper(II) chloride solution and silver nitrate solution.

[4]
Reveal mark scheme Mark scheme for question 6(a)
(b)

A student investigates the quantity of silver chloride produced when different volumes of silver nitrate solution are added to copper(II) chloride solution.

This is the student’s method. maths symbol pour 5.0 cm3 of copper(II) chloride solution into a test tube maths symbol add 1.0 cm3 of silver nitrate solution to the test tube

maths symbol allow the silver chloride precipitate to settle

maths symbol measure the height of the precipitate

The student repeats the method using different volumes of silver nitrate solution.

The table shows the student’s results.

Volume of silver nitrate added in cm3Height of precipitate in cm
0.00.0
1.00.5
2.01.0
3.01.2
4.02.0
5.02.5
6.03.0
7.03.0
8.03.0
(b)(i)

Plot the student’s results.

[2]
Reveal mark scheme Mark scheme for question 6(b)(i)
(b)(ii)

Draw two straight lines of best fit, ignoring the anomalous result.

Figure for question 6

Volume of silver nitrate added in cm3

[1]
Reveal mark scheme Mark scheme for question 6(b)(ii)
(b)(iii)

Suggest a mistake the student made to cause the anomalous result.

[1]
Reveal mark scheme Mark scheme for question 6(b)(iii)
(b)(iv)

Give a reason why the last three heights are the same.

[1]
Reveal mark scheme Mark scheme for question 6(b)(iv)
(c)

The equation for the reaction between copper(II) chloride and silver nitrate is

CuCl2(aq) + 2AgNO3(aq) maths symbol 2AgCl(s) + Cu(NO3)2(aq)

A student measures 25.0 cm3 of 0.500 mol/dm3 copper(II) chloride solution and reacts it with silver nitrate solution.

(c)(i)

Name a piece of apparatus suitable for measuring 25.0 cm3 of copper(II) chloride solution.

[1]
Reveal mark scheme Mark scheme for question 6(c)(i)
(c)(ii)

Calculate the maximum mass, in grams, of silver chloride that could be produced.

[Mr of AgCl = 143.5]

[3]
Reveal mark scheme Mark scheme for question 6(c)(ii)
(c)(iii)

In an experiment using different solutions, the mass of silver chloride produced is 0.744 g.

The maximum mass of silver chloride that could be produced is 0.850 g.

Calculate the percentage yield.

[2]
Reveal mark scheme Mark scheme for question 6(c)(iii)

Chemistry Paper 1 November 2020 (R), Question 7 13 marks

A student uses the reaction between zinc and dilute sulfuric acid to prepare some zinc sulfate crystals.

(a)(i)

Complete the equation for this reaction by giving the correct state symbols.

Question 7, shown as an image
[1]
Reveal mark scheme Mark scheme for question 7(a)(i)
(a)(ii)

State what would be observed during this reaction.

[1]
Reveal mark scheme Mark scheme for question 7(a)(ii)
(b)

The student adds excess zinc to a beaker of dilute sulfuric acid.

(b)(i)

Explain why it is necessary to add excess zinc.

[2]
Reveal mark scheme Mark scheme for question 7(b)(i)
(b)(ii)

Draw a diagram of the apparatus the student should use to remove the unreacted zinc and collect the zinc sulfate solution.

[2]
Reveal mark scheme Mark scheme for question 7(b)(ii)
(c)

The student obtains a pure, dry sample of zinc sulfate crystals.

The formula of zinc sulfate crystals is ZnSO4.7H2O

(c)(i)

Calculate the relative molecular mass (Mr) of zinc sulfate crystals.

[2]
Reveal mark scheme Mark scheme for question 7(c)(i)
(c)(ii)

The student uses 0.0200 mol of dilute sulfuric acid in her preparation.

Show that the maximum mass of zinc sulfate crystals that the student could obtain is about 6 g.

[2]
Reveal mark scheme Mark scheme for question 7(c)(ii)
(c)(iii)

The student obtains a mass of 4.28 g of zinc sulfate crystals.

Calculate the percentage yield of the zinc sulfate crystals.

Give your answer to three significant figures.

[3]
Reveal mark scheme Mark scheme for question 7(c)(iii)

Chemistry Paper 1 November 2020, Question 9 12 marks

Also involves Conservation of mass and balanced equations

Sodium hydrogencarbonate (NaHCO3) is also known as baking soda.

Baking soda can be used to make cakes increase in size in an oven.

This is the equation for the reaction that takes place when baking soda is heated.

Question 9, shown as an image
(a)(i)

What type of reaction is this?

Question 9, shown as an image
[1]
Reveal mark scheme Mark scheme for question 9(a)(i)
(a)(ii)

Suggest why the reaction makes the cakes increase in size.

[1]
Reveal mark scheme Mark scheme for question 9(a)(ii)
(b)

A student uses this apparatus to investigate the reaction that takes place when sodium hydrogencarbonate is heated.

Figure for question 9

This is the student’s method.

● weigh a crucible and record the mass

● add some sodium hydrogencarbonate to the crucible, reweigh it and record the mass

● heat the crucible and contents for five minutes, then allow to cool before weighing and recording the mass

● heat the crucible and contents again for a further three minutes, then allow to cool before weighing and recording the mass

(b)(i)

Give a reason why the crucible and contents are heated for a further three minutes.

[1]
Reveal mark scheme Mark scheme for question 9(b)(i)
(b)(ii)

The student considered using a lid on the crucible in the experiment.

Suggest an advantage and a disadvantage of using a lid on the crucible.

[2]
Reveal mark scheme Mark scheme for question 9(b)(ii)
(c)

The table shows some of the student’s results.

Figure for question 9
(c)(i)

Calculate the mass of sodium hydrogencarbonate that the student uses.

[1]
Reveal mark scheme Mark scheme for question 9(c)(i)
(c)(ii)

Using this equation, calculate the maximum mass of sodium carbonate (Na2CO3) that could form in the student’s reaction.

Question 9, shown as an image

[Mr of NaHCO3 = 84 Mr of Na2CO3 = 106]

[3]
Reveal mark scheme Mark scheme for question 9(c)(ii)
(d)

In a second experiment, the student uses a larger mass of sodium hydrogencarbonate.

She calculates that she should obtain 4.8 g of sodium carbonate.

She actually obtains 4.2 g of sodium carbonate.

(d)(i)

Calculate the percentage yield from the student’s experiment.

[2]
Reveal mark scheme Mark scheme for question 9(d)(i)
(d)(ii)

Other than spillages, suggest a possible reason why the student’s actual yield is less than expected.

[1]
Reveal mark scheme Mark scheme for question 9(d)(ii)

Chemistry Paper 1 January 2020, Question 10 12 marks

Also involves Moles and amount of substance

Figure for question 10
(a)(i)

Complete the chemical equation for the reaction in stage 1.

Question 10, shown as an image
[1]
Reveal mark scheme Mark scheme for question 10(a)(i)
(a)(ii)

Give the meaning of the symbol maths symbol

[1]
Reveal mark scheme Mark scheme for question 10(a)(ii)
(a)(iii)

State the purpose of the platinum catalyst.

[1]
Reveal mark scheme Mark scheme for question 10(a)(iii)
(b)

Give a chemical equation for the reaction of nitrogen monoxide and oxygen in stage 2.

[1]
Reveal mark scheme Mark scheme for question 10(b)
(c)
(c)(i)

The equation for the reaction in stage 3 is

Question 10, shown as an image

Calculate the maximum mass, in tonnes, of nitric acid that could be produced in this reaction from 11.5 tonnes of nitrogen dioxide.

Question 10, shown as an image

mass of nitric acid =........ tonnes

[4]
Reveal mark scheme Mark scheme for question 10(c)(i)
(c)(ii)

Suggest what use can be made of the nitrogen monoxide gas formed in stage 3.

[1]
Reveal mark scheme Mark scheme for question 10(c)(ii)
(d)

When copper(II) oxide reacts with dilute nitric acid, copper(II) nitrate is produced.

The equation for the reaction is

Question 10, shown as an image

0.200 mol of nitric acid reacts with excess copper(II) oxide.

A mass of 15.3 g of copper(II) nitrate is produced.

Calculate the percentage yield of copper(II) nitrate.

[Mr of copper(II) nitrate = 187.5]

[3]
Reveal mark scheme Mark scheme for question 10(d)

Chemistry Paper 2 January 2020 (R), Question 7 14 marks

Also involves Exothermic and endothermic reactions · Enzymes and drug design

(a) Ethanol, C2H5OH, can be produced by the fermentation of glucose, C6H12O6

(a)
(a)(i)

Complete the equation for the fermentation of glucose.

Question 7, shown as an image
[1]
Reveal mark scheme Mark scheme for question 7(a)(i)
(a)(ii)

State why it is necessary for fermentation to be done in the absence of air.

[1]
Reveal mark scheme Mark scheme for question 7(a)(ii)
(a)(iii)

Explain why the temperature should not be higher than 40 °C.

[2]
Reveal mark scheme Mark scheme for question 7(a)(iii)
(a)(iv)

When 4 mol of glucose is fermented, a mass of 55.2 g of ethanol is produced.

Show that the percentage yield of ethanol is 15%.

[Mr of C2H5OH = 46]

[2]
Reveal mark scheme Mark scheme for question 7(a)(iv)
(b)

Ethanol can also be produced by the reaction between ethene and steam.

The equation for the reaction is

Question 7, shown as an image
(b)(i)

This reaction is in dynamic equilibrium.

Give two features of a reaction in dynamic equilibrium.

[2]
Reveal mark scheme Mark scheme for question 7(b)(i)
(b)(ii)

When the equilibrium mixture is heated, the yield of ethanol decreases.

Explain whether the forward reaction is exothermic or endothermic.

[2]
Reveal mark scheme Mark scheme for question 7(b)(ii)
(c)

Carboxylic acids react with alcohols to form esters.

The displayed formula of an ester is

H H O

Question 7, shown as an image
Question 7, shown as an image

H H H H

(c)(i)

Carboxylic acid A and alcohol B react to produce this ester.

Give the displayed formula of carboxylic acid A and of alcohol B.

Figure for question 7
[2]
Reveal mark scheme Mark scheme for question 7(c)(i)
(c)(ii)

Indicators can be used to test for carboxylic acids.

Describe a different chemical test for a carboxylic acid.

[2]
Reveal mark scheme Mark scheme for question 7(c)(ii)

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