Chemistry Paper 2 June 2024, Question 6 14 marks
A scientist reacts lead(II) nitrate solution with sodium bromide solution.
This is the equation for the reaction.
Pb(NO3)2(aq) + 2NaBr(aq) PbBr2(s) + 2NaNO3(aq)
Describe how the scientist could obtain a pure dry sample of lead(II) bromide (PbBr2) from the reaction mixture.
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The scientist reacts an excess of lead(II) nitrate solution with 25 cm3 of sodium bromide solution of concentration 2.0 mol/dm3.
Show that the amount of sodium bromide used is 0.050 mol.
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Show that the maximum theoretical mass of lead(II) bromide is approximately 9 g.
[for PbBr2 Mr = 367]
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The scientist electrolyses molten lead(II) bromide using this apparatus.
Explain why lead(II) bromide needs to be molten rather than solid for electrolysis to occur.
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The electrolyte is at a temperature of 400C.
Explain a suitable material for the electrodes.
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Give the half‑equation that occurs at the negative electrode.
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Bromine forms at the positive electrode.
This is the half‑equation for the reaction at the positive electrode.
State what is observed at the positive electrode.
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State why the half‑equation represents an oxidation reaction.
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