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Edexcel IGCSE Chemistry

Topic questions Chemical changes Titrations

Titrations

15 questions · 178 marks · about 3 hours

Titrations questions

Edexcel 4CH1 Titrations 15 questions

Chemistry Paper 2 June 2025 (R), Question 6 15 marks

Also involves Amounts of substance in equations

A student does a titration to find the volume of phosphoric acid solution (H3PO4) needed to neutralise a sample of potassium hydroxide solution (KOH).

One of the products of the reaction is potassium phosphate.

This is the student’s method.

• use a measuring cylinder to transfer 25 cm3 of potassium hydroxide solution to a conical flask

• add two drops of an indicator

• fill a burette with phosphoric acid solution and record the initial reading on the burette

• add the acid to the conical flask

• record the final burette reading when the indicator changes colour

This is the equation for the reaction.

Question 6, shown as an image
(a)

Explain two improvements to the student’s method that would give more accurate results.

[4]
Reveal mark scheme Mark scheme for question 6(a)
(b)

The student repeats the titration correctly.

The potassium hydroxide solution has a concentration of 0.150 mol / dm3.

The phosphoric acid solution has a concentration of 0.0400 mol / dm3.

Calculate the volume, in cm3, of phosphoric acid solution needed to neutralise 25.0 cm3 of 0.150 mol / dm3 potassium hydroxide solution.

Give your answer to three significant figures.

[4]
Reveal mark scheme Mark scheme for question 6(b)
(c)

Potassium phosphate solution reacts with calcium chloride solution.

One of the products is the insoluble solid, calcium phosphate.

(c)(i)

Complete the equation for the reaction.

Question 6, shown as an image
[1]
(c)(ii)

The student reacts a solution containing 0.0400 mol of potassium phosphate with an excess of calcium chloride solution.

The student obtains 5.70 g of calcium phosphate.

Show that the percentage yield for the reaction is about 90%

[for Ca3(PO4)2 Mr = 310]

[3]
Reveal mark scheme Mark scheme for question 6(c)(ii)
(c)(iii)

Describe how the student can obtain a pure, dry sample of calcium phosphate from the mixture at the end of the reaction.

[3]
Reveal mark scheme Mark scheme for question 6(c)(iii)

Chemistry Paper 2 November 2024, Question 5 13 marks

Also involves Chemical measurements and uncertainty · Concentration of solutions

A student does some titrations to find the volume of dilute nitric acid needed to exactly neutralise 25.0 cm3 of sodium hydroxide solution.

This is the student’s method.

Step 1 add 25.0 cm3 of sodium hydroxide solution to a conical flask

Step 2 add three drops of methyl orange indicator

Step 3 fill a burette with the acid

Step 4 add acid from the burette until the indicator changes colour

Step 5 record the volume of acid added

(a)
(a)(i)

Give the name of the apparatus that the student should use to measure the volume of sodium hydroxide solution in step 1.

[1]
Reveal mark scheme Mark scheme for question 5(a)(i)
(a)(ii)

Give the colour change seen in step 4.

[1]
Reveal mark scheme Mark scheme for question 5(a)(ii)
(a)(iii)

Give a reason why the student does not use universal indicator in this titration.

[1]
Reveal mark scheme Mark scheme for question 5(a)(iii)
(b)

The student completes a rough titration and four accurate titrations.

The diagram shows the burette readings from the rough titration.

Figure for question 5

The table shows the student’s results.

Rough titrationTitration 1Titration 2Titration 3Titration 4
Burette reading at end in cm321.8022.8521.7524.10
Burette reading at start in cm30.500.150.250.10
Volume added in cm321.3022.7021.5024.00
(b)(i)

Complete the table by adding the results from the rough titration.

Record the volumes to the nearest 0.05 cm3

[2]
Reveal mark scheme Mark scheme for question 5(b)(i)
(b)(ii)

Concordant results are results within 0.20 cm3 of each other.

Use the concordant results from the table to calculate the mean volume of acid added.

[3]
Reveal mark scheme Mark scheme for question 5(b)(ii)
(c)

This is the equation for the reaction between dilute nitric acid and sodium hydroxide solution.

HNO3(aq) + NaOH(aq) maths symbol NaNO3(aq) + H2O(l)

After the titration, the student knows the volume of acid needed to neutralise 25.0 cm3 of the sodium hydroxide solution.

Sodium nitrate decomposes at high temperatures.

Describe how the student could obtain pure, dry crystals of sodium nitrate from dilute nitric acid and sodium hydroxide solution.

[5]
Reveal mark scheme Mark scheme for question 5(c)

Chemistry Paper 2 June 2024 (R), Question 5 14 marks

Also involves Moles and amount of substance

Sodium sulfate can be prepared by the reaction between sodium hydroxide solution and sodium hydrogensulfate (NaHSO4) solution.

This is the equation for the reaction.

Question 5, shown as an image

Sodium hydrogensulfate solution is acidic.

A student adds 25.0 cm3 of sodium hydroxide solution to a conical flask and adds two drops of indicator.

The student does a titration.

(a)
(a)(i)

Name a piece of apparatus that should be used to add 25.0 cm3 of sodium hydroxide solution to the conical flask.

[1]
Reveal mark scheme Mark scheme for question 5(a)(i)
(a)(ii)

Describe the method the student should use to find the accurate volume of sodium hydrogensulfate solution needed to neutralise the 25.0 cm3 of sodium hydroxide solution.

[5]
Reveal mark scheme Mark scheme for question 5(a)(ii)
(b)

The student repeats the titration without the indicator and forms a solution of sodium sulfate.

Describe how the student can obtain pure, dry crystals of hydrated sodium sulfate from the solution.

[4]
Reveal mark scheme Mark scheme for question 5(b)
(c)

Crystals of hydrated sodium sulfate decompose when heated.

This is the equation for the decomposition.

Question 5, shown as an image

A student uses this apparatus to find the value of x.

Figure for question 5

The student heats the crystals until the decomposition is complete.

The table shows the student’s results.

Figure for question 5

Use the results to calculate the value of x.

[for Na2SO4, Mr = 142 for H2O, Mr = 18]

[4]
Reveal mark scheme Mark scheme for question 5(c)

Chemistry Paper 2 November 2023, Question 6 11 marks

(a)

The diagram shows two pieces of apparatus used in a titration.

Figure for question 6

Give the names of these pieces of apparatus.

[2]
Reveal mark scheme Mark scheme for question 6(a)
(b)

Give the name of a suitable indicator that can be used in an acid-alkali titration.

[1]
Reveal mark scheme Mark scheme for question 6(b)
(c)

A student does a titration using sodium carbonate solution and dilute nitric acid.

This is the equation for the reaction.

Question 6, shown as an image

The table shows the concentrations of the two solutions and the volume of sodium carbonate used in the titration.

Figure for question 6

Use the equation and the data in the table to answer these questions.

(c)(i)

Calculate the volume of dilute nitric acid that the student would need to neutralise the sodium carbonate solution.

[3]
Reveal mark scheme Mark scheme for question 6(c)(i)
(c)(ii)

Calculate the volume, in cm3, of carbon dioxide gas at rtp that would be produced from the 25.0 cm3 of the sodium carbonate solution.

[at rtp, molar volume = 24 000 cm3]

[2]
Reveal mark scheme Mark scheme for question 6(c)(ii)
(d)

Describe a test to show that sodium carbonate solution contains carbonate ions.

[3]
Reveal mark scheme Mark scheme for question 6(d)

Chemistry Paper 2 June 2023, Question 4 11 marks

A student does a titration to find the concentration of potassium hydroxide solution.

This is the student’s method.

• add 25.0 cm3 of the potassium hydroxide solution to a conical flask

• add a few drops of methyl orange indicator to the conical flask

• fill a burette with dilute sulfuric acid and record the initial burette reading

• place the conical flask on a white tile

• add the acid from the burette to the mixture in the conical flask, swirling the flask continuously

• when the indicator changes colour at the end point, record the final burette reading

Repeat the titration to obtain concordant results.

(a)

Give the name of the most suitable piece of apparatus to measure out 25.0 cm3 of potassium hydroxide solution.

[1]
Reveal mark scheme Mark scheme for question 4(a)
(b)

Give the colour of methyl orange in potassium hydroxide solution and in dilute sulfuric acid.

colour in potassium hydroxide solution

colour in dilute sulfuric acid

[2]
Reveal mark scheme Mark scheme for question 4(b)
(c)

State why the student places the conical flask on a white tile.

[1]
Reveal mark scheme Mark scheme for question 4(c)
(d)

State why the student swirls the flask continuously.

[1]
Reveal mark scheme Mark scheme for question 4(d)
(e)

State what is meant by the term concordant results.

[1]
Reveal mark scheme Mark scheme for question 4(e)
(f)

The student finds that 15.00 cm3 of sulfuric acid of concentration 0.180 mol / dm3 neutralises 25.0 cm3 of potassium hydroxide solution.

This is the equation for the reaction.

Question 4, shown as an image

Calculate the concentration of the potassium hydroxide solution.

concentration =........ mol / dm

[3]
Reveal mark scheme Mark scheme for question 4(f)
(g)

This is the ionic equation for the reaction between an acid and an alkali.

Question 4, shown as an image

Explain why the OH− ion is a proton acceptor in this reaction.

[2]
Reveal mark scheme Mark scheme for question 4(g)

Chemistry Paper 2 January 2023, Question 6 13 marks

When ethanoic acid reacts with ethanol in the presence of concentrated sulfuric acid, one of the products is ester A.

This is the equation for the reaction.

Question 6, shown as an image
Question 6, shown as an image
Question 6, shown as an image

ethanoic acid
ethanol
water

(a)(i)

Draw a circle around the functional group in ethanoic acid.

[1]
Reveal mark scheme Mark scheme for question 6(a)(i)
(a)(ii)

Give the displayed formula of ester A.

[2]
Reveal mark scheme Mark scheme for question 6(a)(ii)
(a)(iii)

Name ester A.

[1]
Reveal mark scheme Mark scheme for question 6(a)(iii)
(b)

The reaction mixture is kept in a sealed container until dynamic equilibrium is reached.

State what is meant by the term dynamic equilibrium.

[2]
Reveal mark scheme Mark scheme for question 6(b)
(c)

During the reaction, the number of moles of ethanoic acid in the reaction mixture decreases, but the number of moles of concentrated sulfuric acid does not change.

(c)(i)

Give a reason why the number of moles of concentrated sulfuric acid does not change.

[1]
Reveal mark scheme Mark scheme for question 6(c)(i)
(c)(ii)

A student does a titration to find the accurate volume of sodium hydroxide solution needed for complete neutralisation.

The student starts by using a pipette to transfer 25.0 cm3 of the reaction mixture to a conical flask.

Describe how the student should complete the titration.

[6]
Reveal mark scheme Mark scheme for question 6(c)(ii)

Chemistry Paper 2 January 2023 (R), Question 7 11 marks

Also involves Amounts of substance in equations

A student is asked to find the concentration of a solution of nitric acid by doing a titration.

The student is provided with sodium hydroxide solution with a concentration of 0.350 mol/dm3

These are the first four steps in the student’s method.

• use a pipette to add exactly 25.0 cm3 of the nitric acid solution to a conical flask placed on a white tile

• add a few drops of indicator to the flask

• use a burette to add sodium hydroxide solution to the flask until the indicator has changed colour

• record the volume needed for the indicator to change colour

(a)

Give the reason for using the white tile.

[1]
Reveal mark scheme Mark scheme for question 7(a)
(b)

Universal indicator is not a suitable indicator to use in a titration.

Complete the table to show the name of a suitable indicator and its final colour in this titration.

Figure for question 7
[2]
Reveal mark scheme Mark scheme for question 7(b)
(c)

The student wants to obtain an accurate value for the volume of sodium hydroxide solution needed to neutralise the 25.0 cm3 of nitric acid.

Describe all the further steps the student should take.

[5]
Reveal mark scheme Mark scheme for question 7(c)
(d)

This is a summary of the student’s results.

volume of HNO3 used = 25.0 cm3

concentration of NaOH solution = 0.350 mol/dm3

volume of NaOH solution needed for neutralisation = 18.80 cm3

The equation for the reaction is

HNO3 + NaOH maths symbol NaNO3 + H2O

(d)(i)

Calculate the amount, in moles, of NaOH that reacts.

[1]
Reveal mark scheme Mark scheme for question 7(d)(i)
(d)(ii)

Determine the amount, in moles, of HNO3 that reacts.

amount of HNO3 =........

[1]
(d)(iii)

Calculate the concentration, in mol/dm3, of the HNO3

concentration =........ mol/dm

[1]
Reveal mark scheme Mark scheme for question 7(d)(iii)

Chemistry Paper 2 June 2022, Question 2 9 marks

Also involves Amounts of substance in equations

(a)

The diagram shows two pieces of apparatus, X and Y.

Figure for question 2
(a)(i)

Give the name of each piece of apparatus.

[2]
Reveal mark scheme Mark scheme for question 2(a)(i)
(a)(ii)

In a titration, a student adds 25.0 cm3 of barium hydroxide solution to a conical flask.

Give a reason why it is better to use Y rather than X.

[1]
Reveal mark scheme Mark scheme for question 2(a)(ii)
(b)

The student uses methyl orange indicator in the titration.

(b)(i)

State the colour of methyl orange in barium hydroxide solution.

[1]
Reveal mark scheme Mark scheme for question 2(b)(i)
(b)(ii)

Give a reason why universal indicator is not suitable for use in a titration.

[1]
Reveal mark scheme Mark scheme for question 2(b)(ii)
(c)

The student adds some dilute nitric acid to a burette and does the titration.

The equation for the reaction is

Question 2, shown as an image

The student finds that 21.50 cm3 of nitric acid of concentration 0.600 mol/dm3 neutralises 25.0 cm3 of barium hydroxide solution.

Calculate the concentration, in mol/dm3, of the barium hydroxide solution.

concentration =........ mol/dm

[3]
Reveal mark scheme Mark scheme for question 2(c)
(d)

State why sulfuric acid would not be a suitable acid to use in this titration.

[1]
Reveal mark scheme Mark scheme for question 2(d)

Chemistry Paper 2 June 2022 (R), Question 6 12 marks

A student uses this method to do a titration.

• use a measuring cylinder to obtain 25 cm3 of sodium hydroxide solution

• transfer the solution to a conical flask

• add a few drops of universal indicator to the flask

• fill a burette with dilute sulfuric acid and record the initial burette reading

• add the acid to the flask, swirling the flask continuously

• add the acid slowly near the end‑point

• record the final burette reading at the end‑point

The student repeats the titration until at least two concordant results are obtained.

(a)

State what is meant by concordant results.

[1]
Reveal mark scheme Mark scheme for question 6(a)
(b)

Explain two improvements to the student’s method so that more accurate results are obtained.

[4]
Reveal mark scheme Mark scheme for question 6(b)
(c)

The student makes the improvements and repeats the titration.

The sulfuric acid has a concentration of 0.600 mol/dm3.

The sodium hydroxide solution has a concentration of 1.50 mol/dm3.

This is the equation for the reaction.

Question 6, shown as an image

Calculate the volume, in cm3, of sulfuric acid that the student needs to completely react with 25.0 cm3 of the sodium hydroxide solution.

[3]
Reveal mark scheme Mark scheme for question 6(c)
(d)

The student plans to obtain pure dry crystals of hydrated sodium sulfate.

They add the calculated volume of sulfuric acid to 25.0 cm3 of the sodium hydroxide solution to form sodium sulfate solution.

Describe what the student should do to obtain pure dry crystals of hydrated sodium sulfate from the solution.

[4]
Reveal mark scheme Mark scheme for question 6(d)

Chemistry Paper 2 January 2022 (R), Question 3 11 marks

Also involves Amounts of substance in equations

A student does a titration to find the concentration of a solution of dilute sulfuric acid.

The student uses these solutions and this apparatus.

• dilute sulfuric acid

• potassium hydroxide solution of concentration 0.240 mol / dm3

• methyl orange indicator

Figure for question 3
(a)

The student wants to find the volume of sulfuric acid needed to neutralise 25.0 cm3 of the potassium hydroxide solution.

Describe how the student should do this titration.

Assume that all pieces of apparatus are clean and dry.

[6]
Reveal mark scheme Mark scheme for question 3(a)
(b)

The student needs 15.00 cm3 of sulfuric acid to neutralise 25.0 cm3 of the potassium hydroxide solution.

This is the equation for the reaction.

Question 3, shown as an image
(b)(i)

Calculate the amount, in moles, of KOH in 25.0 cm3 of potassium hydroxide solution of concentration 0.240 mol / dm3.

[2]
Reveal mark scheme Mark scheme for question 3(b)(i)
(b)(ii)

Calculate the amount, in moles, of H2SO4 in 15.00 cm3 of the sulfuric acid.

amount of H2SO4 =........

[1]
(b)(iii)

Calculate the concentration, in mol / dm3, of the sulfuric acid.

concentration of sulfuric acid =........ mol / dm

[2]
Reveal mark scheme Mark scheme for question 3(b)(iii)

Chemistry Paper 2 January 2021 (R), Question 6 10 marks

Also involves Amounts of substance in equations

A student does a titration using dilute sulfuric acid to find the concentration of a solution of potassium hydroxide.

The student adds 25.0 cm3 of the potassium hydroxide solution to a conical flask. He then adds a few drops of methyl orange indicator.

The student does the titration four times.

(a)(i)

Name the piece of apparatus the student should use to add the potassium hydroxide solution.

[1]
Reveal mark scheme Mark scheme for question 6(a)(i)
(a)(ii)

What is the colour of methyl orange in an alkaline solution?

Question 6, shown as an image
[1]
Reveal mark scheme Mark scheme for question 6(a)(ii)
(b)

The table shows the student’s results.

titration1234
volume of acid added in cm320.6520.6020.9020.55
concordant results

Concordant results are those within 0.20 cm3 of each other.

(b)(i)

Place ticks (✓) in the table to show which results are concordant.

[1]
Reveal mark scheme Mark scheme for question 6(b)(i)
(b)(ii)

Use the concordant results to calculate the mean (average) volume of acid added.

[2]
Reveal mark scheme Mark scheme for question 6(b)(ii)
(c)

This table shows the student’s results for another titration.

Figure for question 6

The equation for the reaction is

(c)(i)

Calculate the amount, in moles, of KOH in 25.0 cm3 of the potassium hydroxide solution.

[2]
Reveal mark scheme Mark scheme for question 6(c)(i)
(c)(ii)

Calculate the amount, in moles, of H2SO4 in 21.20 cm3 of sulfuric acid.

Question 6, shown as an image
[1]
Reveal mark scheme Mark scheme for question 6(c)(ii)
(c)(iii)

Calculate the concentration, in mol/dm3, of the sulfuric acid.

concentration of sulfuric acid =........ mol/dm

[2]
Reveal mark scheme Mark scheme for question 6(c)(iii)

Chemistry Paper 2 November 2020, Question 6 11 marks

Also involves Amounts of substance in equations

A student is provided with a bottle containing a colourless solution X.

Solution X is thought to be dilute sulfuric acid of concentration 0.10 mol/dm3.

The student does some experiments on samples of solution X to try to show that it is dilute sulfuric acid.

The student adds a few drops of litmus to a sample of solution X.

The litmus turns red.

(a)

The student knows that the products of the electrolysis of dilute sulfuric acid are hydrogen and oxygen.

She carries out the electrolysis using this apparatus.

Figure for question 6
(a)(i)

Suggest why the student does not use zinc electrodes in her experiment.

[1]
Reveal mark scheme Mark scheme for question 6(a)(i)
(a)(ii)

State what is observed at both the anode and the cathode during the electrolysis.

[1]
Reveal mark scheme Mark scheme for question 6(a)(ii)
(a)(iii)

Which of these tests shows that the gas formed at the cathode is hydrogen?

Question 6, shown as an image
[1]
Reveal mark scheme Mark scheme for question 6(a)(iii)
(b)

Describe a test to show that solution X contains sulfate ions.

[2]
Reveal mark scheme Mark scheme for question 6(b)
(c)

The student then does a titration to see if the concentration of the dilute sulfuric acid is 0.10 mol/dm3.

She measures 25.0 cm3 of potassium hydroxide solution into a conical flask, and then adds a few drops of indicator solution.

(c)(i)

Name the piece of apparatus the student should use to measure 25.0 cm3 of the potassium hydroxide solution.

[1]
(c)(ii)

The concentration of potassium hydroxide in the solution is 0.125 mol/dm3.

Calculate the amount, in mol, of KOH in 25.0 cm3 of this solution.

[2]
Reveal mark scheme Mark scheme for question 6(c)(ii)
(c)(iii)

The equation for the reaction in the titration is

Question 6, shown as an image

Calculate the volume, in cm3, of 0.10 mol/dm3 sulfuric acid needed to neutralise 25.0 cm3 of the potassium hydroxide solution.

[3]
Reveal mark scheme Mark scheme for question 6(c)(iii)

Chemistry Paper 2 November 2020 (R), Question 6 13 marks

A student wants to prepare sodium chloride crystals from sodium hydroxide solution and dilute hydrochloric acid.

He does a titration to find the volume of dilute hydrochloric acid needed to neutralise the sodium hydroxide solution.

This is his method.

● add 25.0 cm3 of sodium hydroxide solution to a conical flask

● add a few drops of phenolphthalein indicator to the conical flask

● titrate the solution with the hydrochloric acid

(a)

Name a suitable piece of apparatus that the student should use to measure 25.0 cm3 of sodium hydroxide solution.

[1]
(b)(i)

Give the colour of the phenolphthalein indicator in sodium hydroxide solution and in hydrochloric acid.

colour in sodium hydroxide solution........

colour in hydrochloric acid........

[2]
Reveal mark scheme Mark scheme for question 6(b)(i)
(b)(ii)

Suggest why universal indicator is never used in a titration.

[1]
Reveal mark scheme Mark scheme for question 6(b)(ii)
(c)

The student finds that 21.50 cm3 of hydrochloric acid is needed to neutralise 25.0 cm3 of sodium hydroxide solution.

(c)(i)

Describe what the student should do next to prepare a pure solution of sodium chloride.

[2]
Reveal mark scheme Mark scheme for question 6(c)(i)
(c)(ii)

Describe how the student could obtain dry crystals of sodium chloride from the pure sodium chloride solution.

[4]
Reveal mark scheme Mark scheme for question 6(c)(ii)
(d)

The student needs 21.50 cm3 of hydrochloric acid to neutralise 25.0 cm3 of sodium hydroxide solution of concentration 0.800 mol/dm3.

The equation for the reaction is

Question 6, shown as an image

Calculate the concentration, in mol/dm3, of the hydrochloric acid.

concentration =........ mol/dm

[3]
Reveal mark scheme Mark scheme for question 6(d)

Chemistry Paper 2 January 2020, Question 4 9 marks

Also involves Amounts of substance in equations

A student investigates the reaction between sodium hydroxide solution and dilute sulfuric acid.

He does a titration to find the concentration of the sulfuric acid.

This is his plan for the titration. There are some mistakes and omissions in his plan.

● rinse a conical flask with the sodium hydroxide solution

● use a measuring cylinder to measure out 25 cm3 of the sodium hydroxide solution and add it to the conical flask

● add a few drops of methyl orange indicator to the conical flask

● rinse a burette with water and then fill it with the sulfuric acid

● add the acid from the burette to the conical flask until the indicator changes colour at the end‑point of the titration

● record the final burette reading

(a)

Give the colour change of the methyl orange indicator at the end‑point.

[2]
Reveal mark scheme Mark scheme for question 4(a)
(b)

Describe four changes that the student could make to improve his plan.

[4]
Reveal mark scheme Mark scheme for question 4(b)
(c)

The student then does the titration correctly.

He finds that 16.70 cm3 of the dilute sulfuric acid neutralises 25.0 cm3 of sodium hydroxide solution of concentration 0.200 mol/dm3

The equation for the reaction is

Question 4, shown as an image

Calculate the concentration, in mol/dm3, of the sulfuric acid.

concentration of sulfuric acid =........ mol/dm

[3]
Reveal mark scheme Mark scheme for question 4(c)

Chemistry Paper 2 June 2019 (R), Question 6 15 marks

Also involves Amounts of substance in equations

When a bottle of wine is left open for several days, some of the ethanol in the wine turns to ethanoic acid, CH3COOH

(a)

A scientist uses a titration method to investigate how much ethanoic acid is formed if a bottle of white wine is left open for one week.

She uses this method.

● fill a burette with the white wine and record the reading

● add 25.0 cm3 of sodium hydroxide solution to a conical flask

● add a few drops of phenolphthalein indicator to the flask

● swirl the flask continuously while adding wine from the burette

● add the wine drop by drop near the end point

● record the reading at the end point

(a)(i)

Name the piece of apparatus that would be most suitable for measuring the 25.0 cm3 of sodium hydroxide solution.

[1]
Reveal mark scheme Mark scheme for question 6(a)(i)
(a)(ii)

Suggest why red wine would not be suitable to use for this investigation.

[1]
Reveal mark scheme Mark scheme for question 6(a)(ii)
(a)(iii)

State why she swirls the flask continuously.

[1]
Reveal mark scheme Mark scheme for question 6(a)(iii)
(a)(iv)

State why she adds the wine drop by drop near the end point.

[1]
Reveal mark scheme Mark scheme for question 6(a)(iv)
(b)

The diagram shows the burette readings at the start and end of one of the titrations.

Figure for question 6
Question 6, shown as an image

Use the readings to complete the table.

Give your values to the nearest 0.05 cm3.

Figure for question 6
[3]
Reveal mark scheme Mark scheme for question 6(b)
(c)

The scientist repeats the titration four more times.

The table shows her results for these four titrations.

titration number1234
volume of wine added in cm320.4020.1020.3520.45
concordant results

Concordant results are those within 0.20 cm3 of each other.

(c)(i)

Add ticks (maths symbol) to the table to show the concordant results.

[1]
Reveal mark scheme Mark scheme for question 6(c)(i)
(c)(ii)

Use your ticked results to calculate the mean (average) volume of wine added.

[2]
Reveal mark scheme Mark scheme for question 6(c)(ii)
(d)

Another scientist repeats the titration with a different bottle of white wine that has been left open for a week.

The equation for the reaction that occurs in this titration is

CH3COOH + NaOH maths symbol CH3COONa + H2O

The mean volume of wine added is 19.50 cm3.

(d)(i)

The concentration of the sodium hydroxide solution is 0.0500 mol/dm3.

Calculate the amount, in moles, of NaOH in 25.0 cm3 of sodium hydroxide solution.

[2]
Reveal mark scheme Mark scheme for question 6(d)(i)
(d)(ii)

Deduce the amount, in moles, of CH3COOH in 19.50 cm3 of the wine.

[1]
Reveal mark scheme Mark scheme for question 6(d)(ii)
(d)(iii)

Calculate the concentration, in mol/dm3, of CH3COOH in the wine.

concentration of CH3COOH =........ mol/dm3

[2]
Reveal mark scheme Mark scheme for question 6(d)(iii)

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we're doing bonding rn

aww that's lovely 💕

📱 Screen time this week · TikTok6h 2m

Zero bonds were formed

Chemistry starter pack

Goggles that fog instantlyBunsen on the orange flameBurette that's always leakingThis website
Goggles on, collect all four