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OCR A Level Chemistry

Topic questions Quantitative chemistry Percentage yield

Percentage yield

18 questions · 167 marks · about 3.5 hours

Percentage yield questions

OCR H432 Percentage yield 18 questions

Unified chemistry June 2025, Question 5 16 marks

This question is about two metal hydrides, lithium aluminium hydride, LiAl H4, and sodium borohydride, NaBH4. Both hydrides are used as reducing agents in organic chemistry.

(a)
Figure for question 5
(a)(i)

What is the systematic name of the alcohol C6H5CH2OH?

[1]
Reveal mark scheme Mark scheme for question 5(a)(i)
(a)(ii)

Calculate the mass of LiAl H4 that the student should use in Step 2 and the percentage yield of pure C6H5CH2OH obtained in Step 4.

Give the mass of LiAl H4 and the percentage yield of pure C6H5CH2OH to 3 significant figures.

Percentage yield of pure C6H5CH2OH =........ %

[4]
Reveal mark scheme Mark scheme for question 5(a)(ii)
(a)(iii)

In the preparation, LiAl H4 behaves as a nucleophile.

What is meant by the term nucleophile ?

[1]
Reveal mark scheme Mark scheme for question 5(a)(iii)
(a)(iv)

The mechanism for Step 2 in the reduction of C6H5COOC2H5 is shown below. In the mechanism, LiAl H4 can be represented as H–.

Complete the mechanism by adding curly arrows to the three boxes.

Figure for question 5
[4]
Reveal mark scheme Mark scheme for question 5(a)(iv)
(a)(v)

Suggest why the student heated the mixture from Step 2 with dilute aqueous acid in Step 3.

[1]
Reveal mark scheme Mark scheme for question 5(a)(v)
(b)

NaBH4 contains Na+ and BH4– ions.

Draw a β€˜dot‑and‑cross’ diagram for NaBH4.

Use a different symbol for the electrons from each element.

Show outer electrons only.

[2]
Reveal mark scheme Mark scheme for question 5(b)
(c)

NaBH4/ O2 cells are being investigated as potential fuel cells.

β€’ The positive electrode contains O2.

β€’ The negative electrode contains NaBH4.

The reaction at the positive electrode and the overall cell reaction for a NaBH4/ O2 fuel cell are shown below.

Question 5, shown as an image

Overall cell reaction: NaBH4 + 2O2 fraction NaBO2 + 2H2O E fraction = 1.64 V

(c)(i)

What is the standard electrode potential of the negative electrode in this cell?

[1]
Reveal mark scheme Mark scheme for question 5(c)(i)
(c)(ii)

Construct the equation for the reaction at the negative electrode of this cell.

[2]
Reveal mark scheme Mark scheme for question 5(c)(ii)

Synthesis and analytical techniques June 2024, Question 23 12 marks

Oil of wintergreen is a liquid used in medicine to relieve muscle pain.

Compound H is a component in oil of wintergreen and can be synthesised from compound G, as shown below. The boiling point and density of compound H are stated.

Figure for question 23

Compound G
Compound H boiling point = 222 Β°C density = 1.174 g cmβˆ’3

A student prepares a sample of compound H by the method below.

Step 1 Reflux 8.97 g of compound G for 30 minutes with an excess of methanol in the presence of a small amount of sulfuric acid as a catalyst.

Step 2 Add an excess of aqueous sodium carbonate, Na2CO3(aq). Two layers are obtained.

Step 3 Purify the impure compound H that forms from the resulting mixture.

The student follows this method and obtains 5.32 g of pure compound H.

(a)

Why does the student use reflux in Step 1 ?

[1]
Reveal mark scheme Mark scheme for question 23(a)
(b)
(b)(i)

In Step 2, Na2CO3(aq) removes the sulfuric acid catalyst and any unreacted compound G from the mixture.

Write equations for this removal.

Removal of sulfuric acid

Removal of unreacted compound G

Figure for question 23

Compound G

[3]
Reveal mark scheme Mark scheme for question 23(b)(i)
(b)(ii)

Another student suggests that adding aqueous sodium hydroxide would be more effective in removing the sulfuric acid catalyst than Na2CO3(aq).

Comment on whether the student’s suggestion is an improvement for the preparation of compound H.

[1]
Reveal mark scheme Mark scheme for question 23(b)(ii)
(c)

Calculate the percentage yield of compound H.

Give your answer to three significant figures.

[3]
Reveal mark scheme Mark scheme for question 23(c)
(d)

Describe how to purify the impure compound H from the two layers in Step 2.

[4]
Reveal mark scheme Mark scheme for question 23(d)

Synthesis and analytical techniques June 2023, Question 18 11 marks

Figure for question 18
(a)

Outline the mechanism for this reaction, including the role of H2SO4 as a catalyst.

[5]
Reveal mark scheme Mark scheme for question 18(a)
(b)

Determine the percentage yield of 1,3-dinitrobenzene.

Give your answer to 3 significant figures.

[3]
Reveal mark scheme Mark scheme for question 18(b)
(c)

Describe how to purify the impure crystals in Step 3.

[3]
Reveal mark scheme Mark scheme for question 18(c)

Synthesis and analytical techniques June 2022, Question 19 22 marks

This question is about compounds that contain the carboxylic acid functional group.

(a)

Carboxylic acids react with alkalis, metals and carbonates to form salts.

Write full equations for the following three reactions. Show structures for organic compounds.

β€’ the reaction of propanoic acid with aqueous potassium hydroxide:

β€’ the reaction of aqueous methanoic acid with magnesium:

β€’ the reaction of the maths symbol–amino acid, aspartic acid (R=CH2COOH), with an excess of aqueous sodium carbonate, Na2CO3:

[4]
Reveal mark scheme Mark scheme for question 19(a)
(b)
Figure for question 19
[4]
Reveal mark scheme Mark scheme for question 19(b)
(c)

This part is about polymers derived from carboxylic acid monomers.

(c)(i)

Poly(pent-3-enoic acid) is an addition polymer.

Draw the structure of pent-3-enoic acid and two repeat units of this polymer.

Figure for question 19
[2]
Reveal mark scheme Mark scheme for question 19(c)(i)
(c)(ii)

Butanedicarboxylic acid and 1,4-dihydroxy-2-methylbenzene react to form a condensation polymer.

Draw one repeat unit of this condensation polymer.

[2]
Reveal mark scheme Mark scheme for question 19(c)(ii)
(c)(iii)

Three repeat units of a condensation polymer are shown below.

Figure for question 19

Draw the structure of the monomer required to form this polymer.

[1]
Reveal mark scheme Mark scheme for question 19(c)(iii)
(d)

A polymer is formed from 400 molecules of 2-aminopropanoic acid.

(d)(i)

Draw one repeat unit of this polymer.

[1]
Reveal mark scheme Mark scheme for question 19(d)(i)
(d)(ii)

What is the relative molecular mass, Mr, of the polymer?

[2]
Reveal mark scheme Mark scheme for question 19(d)(ii)
(e)
Figure for question 19
[6]
Reveal mark scheme Mark scheme for question 19(e)

Unified chemistry June 2022, Question 3 10 marks

Also involves Nucleophilic substitution

Information about 1-bromobutane and butan-1-ol is shown in the table.

CompoundMelting point / Β°CBoiling point / Β°CDensity / g cm–3
1-bromobutane–1131021.268
butan-1-ol–901180.810

A student prepares a sample of 1-bromobutane by refluxing 9.25 g of butan-1-ol with sodium bromide and sulfuric acid.

After reflux, the reaction mixture is purified.

The student obtains 6.10 cm3 of pure 1-bromobutane.

(a)

* Draw a diagram to show how the student would have carried out the reflux and calculate the percentage yield of 1-bromobutane that the student obtains.

Describe how the student could have obtained pure 1-bromobutane from the reaction

mixture obtained after reflux.

[6]
Reveal mark scheme Mark scheme for question 3(a)
(b)

Butan-1-ol reacts with sodium bromide and sulfuric acid to form 1-bromobutane by nucleophilic substitution.

The mechanism for this reaction takes place by two steps.

Step 1 The oxygen atom of the alcohol group accepts a proton to form a positively-charged intermediate.

Step 2 Bromide ions react with the intermediate from Step 1 by nucleophilic substitution to form 1-bromobutane.

Show both steps in this mechanism.

[4]
Reveal mark scheme Mark scheme for question 3(b)

Synthesis and analytical techniques November 2021, Question 19 14 marks

This question is about organic synthesis.

(a)

Prenal, shown below, is used in the synthesis of some pharmaceuticals.

Figure for question 19
(a)(i)

What is the systematic name for prenal?

[1]
Reveal mark scheme Mark scheme for question 19(a)(i)
(a)(ii)
Figure for question 19
[7]
Reveal mark scheme Mark scheme for question 19(a)(ii)
(b)

* A student intends to synthesise compound A using the two-stage route below.

Figure for question 19

(chloromethyl)benzene Compound A

Plan a two-stage synthesis to prepare 5.44 g of compound A starting from (chloromethyl)benzene, C6H5CH2Cl. Assume that the overall percentage yield of compound A from (chloromethyl)benzene is 25%.

In your answer, include the mass of C6H5CH2Cl required, reagents, and equations where appropriate.

Purification details are not required.

[6]
Reveal mark scheme Mark scheme for question 19(b)

Synthesis and analytical techniques November 2020, Question 20 8 marks

Cyclopentanol can be reacted to form cyclopentene. Cyclopentene is a liquid with a boiling point of 44 Β°C and a density of 0.74 g cmβˆ’3.

A student plans to prepare 4.00 g of cyclopentene by reacting cyclopentanol (boiling point 140 Β°C) with an acid catalyst.

Figure for question 20

The expected percentage yield of cyclopentene is 64.0%.

Method The student carries out the preparation using apparatus set up for distillation, as shown below.

1 The reaction mixture is heated gently, and a distillate containing impure cyclopentene is collected.

Figure for question 20

2 The distillate has an aqueous layer and an organic layer. The student purifies the cyclopentene from the distillate.

(a)

* Calculate the mass of cyclopentanol that the student should use and explain how pure

cyclopentene could be obtained from the distillate.

[6]
Reveal mark scheme Mark scheme for question 20(a)
(b)
Figure for question 20
[2]
Reveal mark scheme Mark scheme for question 20(b)

Synthesis and analytical techniques June 2019, Question 11 1 mark

A student reacts 4.50 g of C6H5NH2 with excess CH3COCl in the reaction below.

C6H5NH2 + CH3COCl β†’ C6H5NHCOCH3 + HCl

Mr = 93.0 Mr = 135.0

The reaction produces 3.25 g of C6H5NHCOCH3.

What is the percentage yield of C6H5NHCOCH3?

A 49.8

B 68.9

C 72.2

D 95.4

Question 11, shown as an image
[1]
Reveal mark scheme Mark scheme for question 11

Synthesis and analytical techniques June 2019, Question 18 22 marks

This question is about esters.

(a)

The structure of ester A is shown below.

Figure for question 18
(a)(i)

What is the systematic name of ester A ?

[1]
Reveal mark scheme Mark scheme for question 18(a)(i)
(a)(ii)
Figure for question 18
[5]
Reveal mark scheme Mark scheme for question 18(a)(ii)
(a)(iii)

Name the type of reactions of ester A shown in (ii).

[1]
Reveal mark scheme Mark scheme for question 18(a)(iii)
(b)
Figure for question 18
[4]
Reveal mark scheme Mark scheme for question 18(b)
(c)
Figure for question 18
[1]
Reveal mark scheme Mark scheme for question 18(c)
(d)

A polyester is formed from 200 molecules of 4-hydroxybenzoic acid.

What is the relative molecular mass, Mr, of the polyester?

Mr =........ g molβˆ’1

[2]
Reveal mark scheme Mark scheme for question 18(d)
(e)

* A student intends to synthesise ester C.

Figure for question 18
(e)(i)

Plan a two-stage synthesis to prepare 12.75 g of ester C starting from 2-methylpropanal, (CH3)2CHCHO. Assume the overall percentage yield of ester C from 2-methylpropanal is 40%.

In your answer include the mass of 2-methylpropanal required, reagents, conditions and equations where appropriate.

Purification details are not required.

[6]
Reveal mark scheme Mark scheme for question 18(e)(i)
(e)(ii)
Figure for question 18
[2]
Reveal mark scheme Mark scheme for question 18(e)(ii)

Unified chemistry June 2019, Question 2 8 marks

Figure for question 2
(a)

In Step 1, sodium carbonate, Na2CO3, makes the reaction mixture alkaline.

Write an ionic equation to show how carbonate ions form an alkaline solution in water.

[1]
Reveal mark scheme Mark scheme for question 2(a)
(b)

In Step 2, explain why the mixture must be acidified so that crystals of benzoic acid appear.

[1]
Reveal mark scheme Mark scheme for question 2(b)
(c)

Write the overall equation for the preparation of benzoic acid from phenylmethanol.

Use [O] for the oxidising agent.

[1]
Reveal mark scheme Mark scheme for question 2(c)
(d)

Calculate the percentage yield of benzoic acid.

Give your answer to 3 significant figures.

[3]
Reveal mark scheme Mark scheme for question 2(d)
(e)

In Step 3, describe how the student can recrystallise the impure crystals to obtain pure benzoic acid.

[2]
Reveal mark scheme Mark scheme for question 2(e)

Synthesis and analytical techniques June 2018, Question 7 1 mark

Ethanol can be prepared by different reactions.

Which reaction has the lowest atom economy?

A C6H12O6 β†’ 2C2H5OH + 2CO2

B C2H4 + H2O β†’ C2H5OH

C C2H5Br + H2O β†’ C2H5OH + HBr

D CH3COOC2H5 + H2O β†’ C2H5OH + CH3COOH

Question 7, shown as an image
[1]
Reveal mark scheme Mark scheme for question 7

Unified chemistry June 2018, Question 4 11 marks

This question is about two compounds used in medicine.

(a)

Cis-platin, PtCl2(NH3)2, is a complex of platinum which is used in cancer treatment.

(a)(i)

What is the oxidation number of platinum in cis-platin?

[1]
Reveal mark scheme Mark scheme for question 4(a)(i)
(a)(ii)

Cis-platin is prepared in a ligand substitution reaction which takes place in multiple steps.

The equation for the final step forming cis-platin is shown below.

Question 4, shown as an image

cis-platin

In the box, outline the mechanism for the formation of cis-platin from [PtCl3(NH3)]–. Use curly arrows and lone pairs where appropriate.

Question 4, shown as an image

cis-platin

[2]
Reveal mark scheme Mark scheme for question 4(a)(ii)
(b)

Paracetamol is a solid organic compound used in tablets as a painkiller.

Figure for question 4
(b)(i)

Name the functional groups present in paracetamol.

[2]
Reveal mark scheme Mark scheme for question 4(b)(i)
(b)(ii)
Figure for question 4
[6]
Reveal mark scheme Mark scheme for question 4(b)(ii)

Synthesis and analytical techniques June 2017, Question 17 21 marks

This question is about the chemistry of aromatic compounds.

(a)

Benzoic acid can be nitrated by concentrated nitric acid in the presence of concentrated sulfuric acid as a catalyst, as shown in Equation 17.1.

The organic product of this reaction is 3-nitrobenzoic acid.

Figure for question 17
(a)(i)

Outline the mechanism for this nitration of benzoic acid.

Show how H2SO4 behaves as a catalyst.

[5]
Reveal mark scheme Mark scheme for question 17(a)(i)
(a)(ii)

* A chemist carries out the reaction in Equation 17.1 using 4.97 g of benzoic acid.

The chemist obtains 3-nitrobenzoic acid as an impure solid.

The chemist purifies the solid to obtain 4.85 g of 3-nitrobenzoic acid.

Describe a method to obtain a pure sample of 3-nitrobenzoic acid from the impure solid, determine the percentage yield and check its purity.

[6]
Reveal mark scheme Mark scheme for question 17(a)(ii)
(b)

A student investigates the relative ease of nitration of phenol, benzene, and benzoic acid.

Figure for question 17

The student finds that the conditions required for the nitration of each compound are different, as shown in Table 17.1.

Figure for question 17
(b)(i)

State the trend in the relative ease of nitration of phenol, benzene, and benzoic acid.

[1]
Reveal mark scheme Mark scheme for question 17(b)(i)
(b)(ii)

Apply your knowledge of the bonding in arenes to explain the trend in part (b)(i).

[3]
Reveal mark scheme Mark scheme for question 17(b)(ii)
(c)

A student synthesises 3-bromophenylamine, shown below, starting from nitrobenzene.

(c)(i)

Complete the flowchart showing the structure of the intermediate and the formulae the reagents for each stage.

Figure for question 17
[3]
Reveal mark scheme Mark scheme for question 17(c)(i)
(c)(ii)

Another student attempts the same synthesis but carries out reduction before bromination. The student was surprised to find that two structural isomers of 3-bromophenylamine had been formed instead of the desired organic product.

Explain this result and suggest the structures of the two isomers that formed.

Explanation........

Structures

[3]
Reveal mark scheme Mark scheme for question 17(c)(ii)

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