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Edexcel GCSE Chemistry

Topic questions Chemical changes Making soluble salts

Making soluble salts

16 questions · 166 marks · about 3 hours

Making soluble salts questions

Edexcel 1CH0 Making soluble salts 16 questions

Paper 1 June 2025 Foundation tier, Question 9 11 marks

Also involves Hazard symbols and risk assessment

Silver nitrate and potassium chloride are ionic compounds that are soluble in water.

(a)

When potassium chloride solution is added to a solution of silver nitrate, a white precipitate forms.

(a)(i)

Complete the equation for this reaction, including the missing state symbol.

Question 9, shown as an image
[2]
Reveal mark scheme Mark scheme for question 9(a)(i)
(a)(ii)

Give the name of the white precipitate that forms.

[1]
Reveal mark scheme Mark scheme for question 9(a)(ii)
(a)(iii)

State and explain how the white precipitate can be separated from the reaction mixture.

[3]
Reveal mark scheme Mark scheme for question 9(a)(iii)
(b)

Silver nitrate solution conducts electricity. Solid silver also conducts electricity.

Describe how silver nitrate solution conducts electricity and how solid silver conducts electricity.

[3]
Reveal mark scheme Mark scheme for question 9(b)
(c)

A bottle containing an unknown solution is labelled with the two hazard symbols shown in Figure 16.

Figure for question 9
(c)(i)

What are the meanings of these two symbols?

Question 9, shown as an image
[1]
Reveal mark scheme Mark scheme for question 9(c)(i)
(c)(ii)

State a safety step that should be taken when using the unknown solution.

[1]
Reveal mark scheme Mark scheme for question 9(c)(ii)

Paper 1 June 2025 Higher tier, Question 3 9 marks

Silver nitrate and potassium chloride are ionic compounds that are soluble in water.

(a)

When potassium chloride solution is added to a solution of silver nitrate, a white precipitate forms.

(a)(i)

Complete the equation for this reaction, including the missing state symbol.

Question 3, shown as an image
[2]
Reveal mark scheme Mark scheme for question 3(a)(i)
(a)(ii)

Give the name of the white precipitate that forms.

[1]
Reveal mark scheme Mark scheme for question 3(a)(ii)
(a)(iii)

State and explain how the white precipitate can be separated from the reaction mixture.

[3]
Reveal mark scheme Mark scheme for question 3(a)(iii)
(b)

Silver nitrate solution conducts electricity. Solid silver also conducts electricity.

Describe how silver nitrate solution conducts electricity and how solid silver conducts electricity.

[3]
Reveal mark scheme Mark scheme for question 3(b)

Paper 1 June 2024 Foundation tier, Question 6 11 marks

(a)

A 250 cm3 solution of copper sulfate contains 6.52 g of dissolved solid.

Calculate the concentration of this copper sulfate solution in g dm–3.

Question 6, shown as an image

concentration =........ g dm

[2]
Reveal mark scheme Mark scheme for question 6(a)
(b)

Sodium hydroxide solution and copper sulfate solution were reacted together completely.

The result was a mixture of a precipitate of copper hydroxide in a solution of sodium sulfate.

Describe how to obtain

β€’ a pure sample of solid copper hydroxide from the mixture

β€’ a pure sample of solid sodium sulfate from the mixture.

[4]
Reveal mark scheme Mark scheme for question 6(b)
(c)

Figure 9 shows the equipment used to electrolyse a sample of sodium sulfate solution.

Figure for question 6
Question 6, shown as an image

Graphite electrodes are used in the electrolysis.

(c)(i)

Give two reasons why graphite is a suitable material for the electrodes.

[2]
Reveal mark scheme Mark scheme for question 6(c)(i)
(c)(ii)

Sodium sulfate solution contains ions.

Which ions are attracted to the positive electrode during the electrolysis?

Question 6, shown as an image
[1]
Reveal mark scheme Mark scheme for question 6(c)(ii)
(c)(iii)

Draw one straight line from each electrode to the product formed at that electrode during the electrolysis of sodium sulfate solution.

Figure for question 6
[2]
Reveal mark scheme Mark scheme for question 6(c)(iii)

Paper 1 June 2024 Higher tier, Question 6 10 marks

Titration can be used to find the volume of dilute hydrochloric acid needed to neutralise 25.0 cm3 of barium hydroxide solution.

(a)

Before the titration is carried out, the pipette and conical flask are rinsed out with pure water.

Explain the effect, if any, that traces of water in the pipette and conical flask after rinsing could have on the titration result.

pipette

[4]
Reveal mark scheme Mark scheme for question 6(a)
(b)

conical flask

In the titration, a few drops of phenolphthalein indicator are added to the barium hydroxide solution.

(b)(i)

State the change in colour of phenolphthalein at the end point, when the barium hydroxide solution has just been neutralised.

[1]
Reveal mark scheme Mark scheme for question 6(b)(i)
(b)(ii)

Write the ionic equation for the neutralisation reaction that occurs when hydrochloric acid is added to barium hydroxide solution.

[2]
Reveal mark scheme Mark scheme for question 6(b)(ii)
(c)

When barium hydroxide solution is neutralised by dilute sulfuric acid, a white precipitate of barium sulfate is formed in the conical flask.

Describe an experiment to obtain a sample of pure, dry barium sulfate from the contents of the conical flask.

[3]
Reveal mark scheme Mark scheme for question 6(c)

Paper 1 June 2023 Foundation tier, Question 5 9 marks

Also involves Hazard symbols and risk assessment

(a)

When lead nitrate solution and potassium chloride solution are mixed, potassium nitrate and a precipitate of lead chloride are formed.

(a)(i)

Complete the word equation for this reaction.

lead nitrate +........ maths symbol........ + lead chloride

[1]
Reveal mark scheme Mark scheme for question 5(a)(i)
(a)(ii)

Lead nitrate is toxic.

Which hazard symbol should be on a container of lead nitrate?

Figure for question 5
[1]
Reveal mark scheme Mark scheme for question 5(a)(ii)
(b)

A student put 5 cm3 of potassium carbonate solution into a test tube and added 2 cm3 of calcium nitrate solution.

A precipitate formed and was allowed to settle as shown in Figure 7.

The height of the precipitate was measured.

Figure for question 5
(b)(i)

Give the name of the piece of apparatus the student should use to find the volume of the potassium carbonate solution.

[1]
Reveal mark scheme Mark scheme for question 5(b)(i)
(b)(ii)

The student repeated the experiment.

The results are shown in Figure 8.

Figure for question 5

Use the data in Figure 8 to calculate the mean height of the precipitate.

[2]
Reveal mark scheme Mark scheme for question 5(b)(ii)
(b)(iii)

Describe how a pure, dry sample of the precipitate could be obtained from the mixture in the test tube.

[3]
Reveal mark scheme Mark scheme for question 5(b)(iii)
(b)(iv)

The student investigated whether increasing the volume of calcium nitrate solution increased the height of the precipitate formed.

They repeated the experiment using different volumes of calcium nitrate.

State one variable that should be controlled in this investigation.

[1]
Reveal mark scheme Mark scheme for question 5(b)(iv)

Paper 1 June 2023 Higher tier, Question 8 11 marks

Also involves Reactions of acids

Crystals of copper sulfate are prepared by reacting copper oxide, a base, with dilute sulfuric acid.

(a)

Name the other product of this reaction.

[1]
Reveal mark scheme Mark scheme for question 8(a)
(b)

During the experiment, a spatula measure of copper oxide, a black powder, is added to warm, dilute sulfuric acid in a beaker.

When the mixture is stirred, the black powder disappears and the mixture turns pale blue.

The student then adds more copper oxide until the maximum amount of copper sulfate is formed without wasting copper oxide.

Explain how the student knows when to stop adding copper oxide.

[3]
Reveal mark scheme Mark scheme for question 8(b)
(c)

The reaction produces an aqueous solution of copper sulfate.

What is the best way to obtain crystals of copper sulfate from an aqueous solution?

Question 8, shown as an image
[1]
Reveal mark scheme Mark scheme for question 8(c)
(d)

When some water is removed from the aqueous solution of copper sulfate, crystals of copper sulfate are made.

Describe how the arrangement and movement of the particles change as crystals are formed from a solution.

[3]
Reveal mark scheme Mark scheme for question 8(d)
(e)

In this reaction, copper oxide, CuO, forms copper sulfate, CuSO4.

Explain, in terms of electrons, whether the copper in copper oxide has been oxidised, has been reduced, or has not been oxidised or reduced.

[2]
Reveal mark scheme Mark scheme for question 8(e)
(f)

In another experiment, a copper sulfate solution with a concentration of 39.875 g dm–3 is used.

Calculate the mass of copper sulfate dissolved in 0.300 dm3 of this solution.

[1]
Reveal mark scheme Mark scheme for question 8(f)

Paper 1 June 2022 Foundation tier, Question 6 11 marks

(a)

3.14 g of solid copper sulfate was dissolved in water and made up to 250 cm3 of solution.

Question 6, shown as an image

Calculate the concentration of this copper sulfate solution in g dmβˆ’3.

concentration =........ g dm

[2]
Reveal mark scheme Mark scheme for question 6(a)
(b)

Sodium hydroxide solution was added to a solution of copper sulfate. A precipitate of copper hydroxide and a solution of sodium sulfate were formed.

(b)(i)

State what would be seen in the reaction.

[1]
Reveal mark scheme Mark scheme for question 6(b)(i)
(b)(ii)

Complete the balanced equation for the reaction by adding a number in front of NaOH.

Question 6, shown as an image
[1]
Reveal mark scheme Mark scheme for question 6(b)(ii)
(b)(iii)

Describe how to obtain a pure, dry sample of the precipitate of copper hydroxide from the reaction mixture.

[3]
Reveal mark scheme Mark scheme for question 6(b)(iii)
(c)
Figure for question 6
(c)(i)

Figure 11 shows the ions in the sodium sulfate solution.

Draw a circle around each of the ions in Figure 11 that are attracted to the negative graphite electrode during the electrolysis.

Figure for question 6
[1]
Reveal mark scheme Mark scheme for question 6(c)(i)
(c)(ii)

State why it is important that the electrodes are inert.

[1]
Reveal mark scheme Mark scheme for question 6(c)(ii)
(c)(iii)

Explain, in terms of its structure, how graphite conducts electricity.

[2]
Reveal mark scheme Mark scheme for question 6(c)(iii)

Paper 1 June 2022 Higher tier, Question 9 13 marks

(a)

A student carried out an investigation to determine the order of reactivity of four metals, W, X, Y and Z. A piece of metal W was added to a test tube containing excess dilute hydrochloric acid. This was repeated with the other three metals, X, Y and Z. In each case, the size of each piece of metal was the same. The student recorded observations on each reaction for three minutes.

The observations obtained are shown in Figure 8.

Figure for question 9
(a)(i)

Use the information in Figure 8 to place the metals in order of reactivity from the least reactive to the most reactive.

Question 9, shown as an image
Figure for question 9
[2]
Reveal mark scheme Mark scheme for question 9(a)(i)
(a)(ii)

The experiment was repeated using an excess of dilute sulfuric acid in place of the dilute hydrochloric acid.

metal + sulfuric acid maths symbol metal sulfate + hydrogen

When metal Y reacts with dilute sulfuric acid, bubbles form quickly at first and then the reaction stops. Most of the solid metal remains.

Explain why the reaction between metal Y and excess dilute sulfuric acid stopped even though there was solid metal Y left.

[2]
Reveal mark scheme Mark scheme for question 9(a)(ii)
(a)(iii)

The reactions between metals and dilute ethanoic acid are slower than reactions between metals and dilute hydrochloric acid. This is because ethanoic acid is a weak acid.

Explain the meaning of the term weak acid.

[2]
Reveal mark scheme Mark scheme for question 9(a)(iii)
(b)

The formula of aluminium sulfate is Al2(SO4)3.

Calculate the total number of atoms that combine to form 5.13 g of aluminium sulfate.

(relative atomic masses: O = 16.0, A l = 27.0, S = 32.0 Avogadro number = 6.02maths symbol1023)

number of atoms =........

[4]
Reveal mark scheme Mark scheme for question 9(b)
(c)

Iron is more reactive than lead. Iron reacts with lead nitrate solution to form solid lead. Two possible balanced equations for the reaction are

Equation 1 Fe + Pb(NO3)2 maths symbol Fe(NO3)2 + Pb

Equation 2 2Fe + 3Pb(NO3)2 maths symbol 2Fe(NO3)3 + 3Pb

In one experiment, it was found that 4.48 g of iron reacted with excess lead nitrate solution to form 24.84 g of lead.

Carry out a calculation, using the information above, to show which equation represents the reaction taking place.

(relative atomic masses: Fe = 56.0, Pb = 207)

[3]
Reveal mark scheme Mark scheme for question 9(c)

Paper 1 November 2021 Higher tier, Question 6 9 marks

Also involves Amounts of substance in equations

(a)

Copper carbonate reacts with dilute nitric acid.

(a)(i)

During the reaction the copper carbonate powder completely disappears.

State what can be deduced about the amount of acid used.

[1]
Reveal mark scheme Mark scheme for question 6(a)(i)
(a)(ii)

During the reaction, the pH of the mixture changed from 2 to 6.

By what factor has the concentration of the hydrogen ions in the mixture changed?

Question 6, shown as an image
Question 6, shown as an image
[1]
Reveal mark scheme Mark scheme for question 6(a)(ii)
(b)

Using different reactants, a solution of copper sulfate was prepared.

Describe what should be done to obtain copper sulfate crystals from this copper sulfate solution.

[2]
Reveal mark scheme Mark scheme for question 6(b)
(c)

When chloride ions are added to a pale blue solution containing copper ions, the mixture turns yellow.

This is a reversible reaction.

pale blue solution + chloride ions maths symbolmaths symbol yellow solution + water

What effect does the removal of chloride ions have on the colour of the yellow mixture?

Question 6, shown as an image
[1]
Reveal mark scheme Mark scheme for question 6(c)
(d)

Hydrated copper sulfate has the formula CuSO4.5H2O. The formula tells us that each mole of copper sulfate contains 5 moles of water.

A sample of CuSO4.5H2O was heated gently until all the water was removed to form anhydrous copper sulfate, CuSO4.

Question 6, shown as an image

The mass of water formed was 4.5 g.

Calculate the mass of hydrated copper sulfate that was heated.

(relative atomic masses: H = 1.0, O = 16.0; relative formula mass: CuSO4.5H2O = 249.5)

mass of CuSO4.5H2O =........

[4]
Reveal mark scheme Mark scheme for question 6(d)

Paper 1 November 2020 Foundation tier, Question 9 13 marks

Also involves Conservation of mass and balanced equations

The word equation for the reaction between copper carbonate and dilute sulfuric acid is

copper sulfuric copper carbon

Question 9, shown as an image
(a)(i)

Complete the balanced equation for this reaction.

Question 9, shown as an image
[2]
Reveal mark scheme Mark scheme for question 9(a)(i)
(a)(ii)

Calculate the relative formula mass of copper carbonate, CuCO3. (relative atomic masses: C = 12.0, O = 16.0, Cu = 63.5)

relative formula mass of CuCO3 =........

[2]
Reveal mark scheme Mark scheme for question 9(a)(ii)
(a)(iii)

What is the chemical test to show that a gas is carbon dioxide?

Question 9, shown as an image
[1]
Reveal mark scheme Mark scheme for question 9(a)(iii)
(b)

Figure 12 shows a conical flask containing dilute sulfuric acid. Copper carbonate is added to the acid in the flask. The copper carbonate is added one spatula measure at a time until the reaction has finished.

Figure for question 9
(b)(i)

State two observations that would show the reaction has finished.

[2]
Reveal mark scheme Mark scheme for question 9(b)(i)
(b)(ii)

*(ii) Describe how you would obtain a solution of copper sulfate from the mixture and how you would obtain pure, dry copper sulfate crystals from this solution.

Your description should include the apparatus you would use.

You may wish to use diagrams in your answer.

[6]
Reveal mark scheme Mark scheme for question 9(b)(ii)

Paper 1 November 2020 Foundation tier, Question 10 11 marks

Potassium hydroxide reacts with hydrochloric acid to form potassium chloride and water.

potassium hydroxide + hydrochloric acid maths symbol potassium chloride + water

(a)

A student carried out a titration to find the exact volume of dilute hydrochloric acid that reacted with 25.0 cm3 of potassium hydroxide solution.

There were five steps in the titration. The steps shown are not in the correct order.

step J pour the potassium hydroxide solution into a conical flask and add a few drops of indicator to this solution step K fill a burette with the dilute hydrochloric acid and record the initial reading from the burette step L use a measuring cylinder to obtain 25 cm3 of potassium hydroxide solution step M take a final reading from the burette and calculate the volume of the dilute hydrochloric acid reacted step N run the dilute hydrochloric acid from the burette into the conical flask until the indicator changes colour

(a)(i)

Write the steps in the correct order.

Some of the steps have been completed for you.

first step last step

Figure for question 10
[1]
Reveal mark scheme Mark scheme for question 10(a)(i)
(a)(ii)

Suggest an alternative piece of apparatus that could be used in step L to obtain exactly 25.0 cm3 of potassium hydroxide solution.

[1]
Reveal mark scheme Mark scheme for question 10(a)(ii)
(b)

A student was then asked to produce a pure sample of solid potassium chloride.

After finding the volume of acid reacted in step M, the student added this volume of acid to a fresh 25.0 cm3 sample of the potassium hydroxide solution. This mixture was then evaporated.

(b)(i)

Explain why this new mixture was evaporated rather than the original mixture from the titration, to produce a pure sample of solid potassium chloride.

[2]
Reveal mark scheme Mark scheme for question 10(b)(i)
(b)(ii)

After evaporation, the mass of the potassium chloride was determined.

The theoretical yield of the experiment was 0.70 g. The actual yield was 0.84 g.

This gave a percentage yield greater than 100%.

Calculate the percentage yield of this experiment.

percentage yield =........

[2]
Reveal mark scheme Mark scheme for question 10(b)(ii)
(b)(iii)

Suggest a reason why the actual yield was greater than the theoretical yield.

[1]
Reveal mark scheme Mark scheme for question 10(b)(iii)
(b)(iv)

The equation for the reaction between potassium hydroxide solution and dilute hydrochloric acid is

Question 10, shown as an image

Calculate the atom economy for the production of potassium chloride from potassium hydroxide and hydrochloric acid. (relative formula masses: KOH = 56.0, HCl = 36.5, KCl = 74.5, H2O = 18.0)

Give your answer to one decimal place.

atom economy =........

[4]
Reveal mark scheme Mark scheme for question 10(b)(iv)

Paper 1 November 2020 Higher tier, Question 3 9 marks

Also involves Conservation of mass and balanced equations

The word equation for the reaction between copper carbonate and dilute sulfuric acid is

copper sulfuric copper carbon

Question 3, shown as an image
(a)(i)

Complete the balanced equation for this reaction.

Question 3, shown as an image
[2]
Reveal mark scheme Mark scheme for question 3(a)(i)
(a)(ii)

Calculate the relative formula mass of copper carbonate, CuCO3. (relative atomic masses: C = 12.0, O = 16.0, Cu = 63.5)

relative formula mass of CuCO3 =........

[2]
Reveal mark scheme Mark scheme for question 3(a)(ii)
(a)(iii)

What is the chemical test to show that a gas is carbon dioxide?

Question 3, shown as an image
[1]
Reveal mark scheme Mark scheme for question 3(a)(iii)
(b)

Figure 4 shows a conical flask containing dilute sulfuric acid. Copper carbonate is added to the acid in the flask. The copper carbonate is added one spatula measure at a time until the reaction has finished.

Figure for question 3

State two observations that would show the reaction has finished.

[2]
Reveal mark scheme Mark scheme for question 3(b)
(c)

The electronic configuration of carbon is 2.4 The electronic configuration of oxygen is 2.6

Draw a dot and cross diagram for a molecule of carbon dioxide.

Show outer electrons only.

[2]
Reveal mark scheme Mark scheme for question 3(c)

Paper 1 June 2019 Higher tier, Question 3 8 marks

(a) Water, acidified with sulfuric acid, is decomposed by electrolysis. The water is decomposed to produce hydrogen and oxygen.

(a)
(a)(i)

A sample of hydrogen is mixed with air and ignited.

State what would happen.

[1]
Reveal mark scheme Mark scheme for question 3(a)(i)
(a)(ii)

Throughout the experiment the volume of hydrogen and the volume of oxygen are measured at two-minute intervals.

The results are shown in Figure 2.

time in minutesvolume of hydrogen inΒ cm3volume of oxygen inΒ cm3
000
242
484
6126
8168
Question 3, shown as an image

Describe, using the data in Figure 2, what the results show about the volumes of hydrogen and of oxygen produced in this experiment.

[2]
Reveal mark scheme Mark scheme for question 3(a)(ii)
(b)

Molten lead bromide is electrolysed.

The products of this electrolysis are

Question 3, shown as an image
[1]
Reveal mark scheme Mark scheme for question 3(b)
(c)

Calcium nitrate and calcium carbonate are both ionic compounds.

Calcium nitrate mixed with water behaves as an electrolyte. Calcium carbonate mixed with water does not behave as an electrolyte.

Explain, in terms of solubility and movement of ions, this difference in behaviour.

[2]
Reveal mark scheme Mark scheme for question 3(c)
(d)

When molten zinc chloride is electrolysed, zinc ions, Zn2+, form zinc atoms.

Write the half equation for this reaction.

[2]
Reveal mark scheme Mark scheme for question 3(d)

Paper 1 June 2018 Foundation tier, Question 5 10 marks

Also involves Hazard symbols and risk assessment

Two compounds of barium are barium sulfide and barium chloride.

(a)

The hazard symbol shown in Figure 5 is on bottles containing barium metal.

Figure for question 5

State the meaning of this hazard symbol.

[1]
Reveal mark scheme Mark scheme for question 5(a)
(b)

Give the names of the elements combined in barium sulfide.

[1]
Reveal mark scheme Mark scheme for question 5(b)
(c)

Barium chloride is toxic.

Explain one safety precaution that should be taken when using barium chloride.

[2]
Reveal mark scheme Mark scheme for question 5(c)
(d)(i)

A beaker of barium chloride solution and a beaker of dilute sulfuric acid were placed on a balance, as shown in Figure 6.

Figure for question 5

The total mass reading on the balance was 25.7 g.

The dilute sulfuric acid was poured into the barium chloride solution and the beaker replaced on the balance, as shown in Figure 7.

Figure for question 5

Figure 7

The mixture formed contained a white precipitate.

State the total mass reading on the balance after the reaction.

[1]
Reveal mark scheme Mark scheme for question 5(d)(i)
(d)(ii)

Give the name of the white precipitate formed by the reaction of barium chloride solution with dilute sulfuric acid.

[1]
Reveal mark scheme Mark scheme for question 5(d)(ii)
(e)

Solid sodium chloride is dissolved in water.

The sodium chloride solution is electrolysed in the apparatus shown in Figure 8.

Figure for question 5
(e)(i)

State why sodium chloride solution, rather than solid sodium chloride, must be used in this experiment.

[1]
Reveal mark scheme Mark scheme for question 5(e)(i)
(e)(ii)

The formulae of the ions present in the sodium chloride solution are

Question 5, shown as an image

Circle the ions that would be attracted to the anode.

[1]
Reveal mark scheme Mark scheme for question 5(e)(ii)
(e)(iii)

Molten lead bromide can be electrolysed to form molten lead and bromine gas.

Explain how a student could modify the apparatus shown in Figure 8 to carry out this electrolysis.

[2]
Reveal mark scheme Mark scheme for question 5(e)(iii)

Paper 1 June 2018 Foundation tier, Question 8 12 marks

Also involves Subatomic particles

(a)

State two characteristic properties of metals.

[2]
Reveal mark scheme Mark scheme for question 8(a)
(b)

Acids are used to make salts.

Give the name of the acid used to make chlorides.

[1]
Reveal mark scheme Mark scheme for question 8(b)
(c)

Salts of metals can be prepared by reacting the metal with an acid to produce the salt and hydrogen.

(c)(i)

Describe the test to show that the gas is hydrogen.

[2]
Reveal mark scheme Mark scheme for question 8(c)(i)
(c)(ii)

Nickel is a metal.

Explain how the structure of a nickel atom, Ni, changes when it forms a nickel ion, Ni2+

[2]
Reveal mark scheme Mark scheme for question 8(c)(ii)
(d)

A nickel sulfate solution is made by dissolving 23.5 g of nickel sulfate to make 250 cm3 of solution.

Calculate the concentration of the solution in g dm–3.

concentration =........ g dm

[2]
Reveal mark scheme Mark scheme for question 8(d)
(e)

Excess solid nickel carbonate is added to dilute sulfuric acid in a beaker.

nickel sulfuric nickel carbon

Question 8, shown as an image

Nickel sulfate is formed in solution.

Describe how a sample of pure, dry nickel sulfate crystals can be obtained from the mixture of nickel sulfate solution and excess solid nickel carbonate in the beaker.

[3]
Reveal mark scheme Mark scheme for question 8(e)

Paper 1 June 2018 Higher tier, Question 2 9 marks

(a) Salts of metals can be prepared by reacting the metal with an acid to produce the salt and hydrogen.

(a)
(a)(i)

Describe the test to show the gas is hydrogen.

[2]
Reveal mark scheme Mark scheme for question 2(a)(i)
(a)(ii)

Nickel is a metal.

Explain how the structure of a nickel atom, Ni, changes when it forms a nickel ion, Ni2+.

[2]
Reveal mark scheme Mark scheme for question 2(a)(ii)
(b)

A nickel sulfate solution is made by dissolving 23.5 g of nickel sulfate to make 250 cm3 of solution.

Calculate the concentration of the solution in g dmβˆ’3.

concentration =........ g dm

[2]
Reveal mark scheme Mark scheme for question 2(b)
(c)

Excess solid nickel carbonate is added to dilute sulfuric acid in a beaker.

nickel sulfuric nickel carbon

Question 2, shown as an image

Nickel sulfate is formed in solution.

Describe how a sample of pure, dry nickel sulfate crystals can be obtained from the mixture of nickel sulfate solution and excess solid nickel carbonate in the beaker.

[3]
Reveal mark scheme Mark scheme for question 2(c)

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