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OCR GCSE Combined Science

Topic questions Cell biology Enzyme action

Enzyme action

20 questions · 126 marks · about 2.5 hours

Enzyme action questions

OCR J250 Enzyme action 20 questions

Biology Paper 7 June 2025 Higher tier, Question 7 1 mark

A scientist is investigating the action of amylase enzymes on the digestion of starch into maltose.

What would increase the rate of reaction?

A Decreasing the enzyme concentration

B Decreasing the pH to 2

C Increasing the pH to 7

D Increasing the temperature to 70 maths symbolC

Question 7, shown as an image
[1]
Reveal mark scheme Mark scheme for question 7

Biology Paper 7 June 2025 Higher tier, Question 14 8 marks

Many biological processes involve enzymes.

(a)

Explain how enzymes increase the rate of biological processes.

[3]
Reveal mark scheme Mark scheme for question 14(a)
(b)

Explain how temperature affects the progress of an enzyme-controlled reaction.

[3]
Reveal mark scheme Mark scheme for question 14(b)
(c)

Many lizards have a body temperature that matches the external temperature.

In the morning, these lizards often lie in the sun before they can become active and hunt.

Explain why they need to lie in the sun before they can hunt.

[2]
Reveal mark scheme Mark scheme for question 14(c)

Biology Paper 1 June 2024 Foundation tier, Question 4 1 mark

The graph shows the effect of pH on the activity of two enzymes.

Identify the pH where both enzymes are active.

Figure for question 4
Question 4, shown as an image
[1]
Reveal mark scheme Mark scheme for question 4

Biology Paper 1 June 2024 Foundation tier, Question 6 1 mark

The diagrams show stages in the hypothesis used to explain the mechanism of enzyme action.

Figure for question 6

Which term describes this hypothesis?

A Active site

B Denaturing

C Enzyme specificity

D Lock and key

Question 6, shown as an image
[1]
Reveal mark scheme Mark scheme for question 6

Biology Paper 2 June 2024 Foundation tier, Question 13 5 marks

New medicines are developed all the time.

(a)

Insulin is a protein used to treat diabetes. The human stomach contains an enzyme that is specific to proteins like insulin.

Suggest why it is difficult to develop an insulin medicine that is swallowed.

[2]
Reveal mark scheme Mark scheme for question 13(a)
(b)

Which type of medicine has been developed to treat HIV?

Question 13, shown as an image

antibiotic antigen antiseptic antiviral

[1]
Reveal mark scheme Mark scheme for question 13(b)
(c)

Some diseases are treated by changes to lifestyle.

Complete these sentences about cardiovascular disease.

The risk of cardiovascular disease is reduced by a........ low in saturated fat.

This reduces the risk of blocked arteries therefore allowing more oxygen to be transported to the

........ muscle in the ventricle wall.

[2]
Reveal mark scheme Mark scheme for question 13(c)

Biology Paper 7 June 2024 Higher tier, Question 4 1 mark

The diagrams show stages in the hypothesis used to explain the mechanism of enzyme action.

Which term describes the molecule labelled M?

Figure for question 4

A Active site

B Enzyme

C Lock and key

D Substrate

Question 4, shown as an image
[1]
Reveal mark scheme Mark scheme for question 4

Biology Paper 7 June 2024 Higher tier, Question 10 1 mark

The pH inside the small intestine of the human digestive system is between pH 7 and pH 8.

The pH inside the stomach of the human digestive system is between pH 1 and pH 2.

The graph shows the effect of pH on the activity of two enzymes.

Figure for question 10

Which statement about the enzymes is correct?

A Both enzymes would be denatured inside the small intestine.

B Enzyme Q would be more efficient inside the small intestine compared to enzyme P.

C Neither enzyme would work at its highest activity inside the stomach or small intestine.

D Only enzyme P would be active in the stomach.

Question 10, shown as an image
[1]
Reveal mark scheme Mark scheme for question 10

Biology Paper 8 June 2024 Higher tier, Question 13 12 marks

The picture shows the plant pathogen that causes powdery mildew.

Figure for question 13
(a)

Describe how powdery mildew is spread from one plant to another.

[2]
Reveal mark scheme Mark scheme for question 13(a)
(b)

Powdery mildew reduces the efficiency of chloroplasts.

Explain how this might reduce the rate of respiration in a plant.

[3]
Reveal mark scheme Mark scheme for question 13(b)
(c)

Plants resistant to powdery mildew are developed by genetic engineering.

(c)(i)

Complete the sentences about genetic engineering.

The gene for resistance is cut out of DNA using a........ enzyme.

The gene is then joined to bacterial DNA using a........ enzyme.

To find out if the bacteria contain the gene, scientists use........

[3]
Reveal mark scheme Mark scheme for question 13(c)(i)
(c)(ii)

Explain why the process of cutting the DNA is prevented by high temperatures.

Use your knowledge of enzymes.

[2]
Reveal mark scheme Mark scheme for question 13(c)(ii)
(d)

Powdery mildew can be controlled using chemicals.

Producing plants resistant to powdery mildew is better for biodiversity compared to using chemicals.

Suggest two reasons why.

[2]
Reveal mark scheme Mark scheme for question 13(d)

Biology Paper 1 June 2023 Foundation tier, Question 2 1 mark

The graph shows the effect of pH on enzyme activity.

What is the pH when enzyme activity is highest ?

Figure for question 2
Question 2, shown as an image
[1]
Reveal mark scheme Mark scheme for question 2

Biology Paper 1 June 2023 Foundation tier, Question 16, also on the Higher paper 12 marks

A scientist investigates the effect of temperature on anaerobic respiration in yeast.

The diagram shows the apparatus they use.

Figure for question 16

This is the method they follow:

โ€ข Collect the gas produced by the yeast for five minutes.

โ€ข Increase the temperature of the water bath.

โ€ข Repeat the investigation with fresh sugar solution.

โ€ข Do each temperature three times.

(a)(i)

Suggest why the scientist used fresh sugar solution each time.

[1]
Reveal mark scheme Mark scheme for question 16(a)(i)
(a)(ii)

Identify one variable the scientist should keep constant throughout the experiment.

Tick (โœ“) one box.

Question 16, shown as an image
[1]
Reveal mark scheme Mark scheme for question 16(a)(ii)
(a)(iii)

Which gas is collected by the scientist in the gas syringe?

[1]
Reveal mark scheme Mark scheme for question 16(a)(iii)
(b)
Figure for question 16
(b)(i)

When calculating the mean for 55 ยฐC, they did not include Trial 1.

Give the reason why.

[1]
Reveal mark scheme Mark scheme for question 16(b)(i)
(b)(ii)

Plot the mean values from the table on the graph.

[3]
Reveal mark scheme Mark scheme for question 16(b)(ii)
(b)(iii)

Draw a curve of best fit.

Figure for question 16
[1]
Reveal mark scheme Mark scheme for question 16(b)(iii)
(b)(iv)

Anaerobic respiration is an enzyme-controlled reaction.

Explain the results between 15 ยฐC and 35 ยฐC. Include ideas about enzyme particles.

[2]
Reveal mark scheme Mark scheme for question 16(b)(iv)
(b)(v)

The scientist concludes that the best temperature for anaerobic respiration is approximately 40 ยฐC.

How could they alter their investigation to identify a more accurate temperature?

[2]
Reveal mark scheme Mark scheme for question 16(b)(v)

Biology Paper 7 June 2023 Higher tier, Question 11, also on the Foundation paper 12 marks

A scientist investigates the effect of temperature on anaerobic respiration in yeast.

The diagram shows the apparatus they use.

Figure for question 11

This is the method they follow:

โ€ข Collect the gas produced by the yeast for five minutes.

โ€ข Increase the temperature of the water bath.

โ€ข Repeat the investigation with fresh sugar solution.

โ€ข Do each temperature three times.

(a)(i)

Suggest why the scientist used fresh sugar solution each time.

[1]
Reveal mark scheme Mark scheme for question 11(a)(i)
(a)(ii)

Identify one variable the scientist should keep constant throughout the experiment.

Tick (โœ“) one box.

Question 11, shown as an image
[1]
Reveal mark scheme Mark scheme for question 11(a)(ii)
(a)(iii)

Which gas is collected by the scientist in the gas syringe?

[1]
Reveal mark scheme Mark scheme for question 11(a)(iii)
(b)
Figure for question 11
(b)(i)

When calculating the mean for 55 ยฐC, they did not include Trial 1.

Give the reason why.

[1]
Reveal mark scheme Mark scheme for question 11(b)(i)
(b)(ii)

Plot the mean values from the table on the graph.

[3]
Reveal mark scheme Mark scheme for question 11(b)(ii)
(b)(iii)

Draw a curve of best fit.

Figure for question 11
[1]
Reveal mark scheme Mark scheme for question 11(b)(iii)
(b)(iv)

Anaerobic respiration is an enzyme-controlled reaction.

Explain the results between 15 ยฐC and 35 ยฐC. Include ideas about enzyme particles.

[2]
Reveal mark scheme Mark scheme for question 11(b)(iv)
(b)(v)

The scientist concludes that the best temperature for anaerobic respiration is approximately 40 ยฐC.

How could they alter their investigation to identify a more accurate temperature?

[2]
Reveal mark scheme Mark scheme for question 11(b)(v)

Biology Paper 8 June 2023 Higher tier, Question 13 6 marks

13* The pH of a soil will affect the crops that grow in the soil. When the soil pH is suitable, more crops will grow. This results in a higher yield (mass of crops).

The table shows data about the yield of four different crops, A, B, C and D, when grown in soils of different pH.

pH rangeYield as a percentage of the highest yield obtained (%)
of soilcrop Acrop Bcrop Ccrop D
4 โ€“ 4.92531465
5 โ€“ 5.97483475
6 โ€“ 6.910098100100

A farmer measures the pH of the soil in their field. The soil is pH 4.5.

Which crop should the farmer grow in the field?

Explain your choice and give reasons why pH 4.5 prevents growth in some crops. Include ideas about enzymes and their function in plants.

[6]
Reveal mark scheme Mark scheme for question 13

Biology Paper 1 June 2022 Foundation tier, Question 12 13 marks

(a)
Figure for question 12
[3]
Reveal mark scheme Mark scheme for question 12(a)
(b)
Figure for question 12
[2]
Reveal mark scheme Mark scheme for question 12(b)
(c)
Figure for question 12
(c)(i)

*(i) Describe and explain the pattern in the results.

Use ideas about the lock and key hypothesis in your answer.

[6]
Reveal mark scheme Mark scheme for question 12(c)(i)
(c)(ii)

Describe how the student could improve their investigation to find a more accurate optimum pH for the enzyme.

[2]
Reveal mark scheme Mark scheme for question 12(c)(ii)

Biology Paper 1 November 2021 Foundation tier, Question 15 12 marks

Catalase is an enzyme found in potato. Catalase breaks down hydrogen peroxide to form water and oxygen.

A student investigates the activity of catalase.

This is the method they follow: โ€“ Cut equal sized pieces of potato. โ€“ Put one piece of potato into a conical flask. โ€“ Add 50 cm3 of dilute hydrogen peroxide. โ€“ Collect the oxygen produced in 15 minutes using a measuring cylinder full of water.

Fig. 15.1 shows the set-up of their investigation.

Figure for question 15

The student then repeats the investigation, increasing the number of potato pieces each time.

(a)(i)

Each time the student repeats the investigation they use 50 cm3 of new dilute hydrogen (a) (i) peroxide.

Explain why they need to replace the dilute hydrogen peroxide.

[2]
Reveal mark scheme Mark scheme for question 15(a)(i)
(a)(ii)

Explain why the student does not need to replace the potato pieces already in the flask when repeating the investigation.

[1]
Reveal mark scheme Mark scheme for question 15(a)(ii)
(b)
Figure for question 15
(b)(i)

Plot a graph of the results and draw a line of best fit.

[4]
Reveal mark scheme Mark scheme for question 15(b)(i)
(b)(ii)

Use the graph to find the expected volume of oxygen produced when 4 pieces of potato are used.

[1]
Reveal mark scheme Mark scheme for question 15(b)(ii)
(b)(iii)

Use the data in the table to calculate the rate of reaction when the student used 6 pieces of potato.

Give your answer to 2 significant figures.

Rate of reaction =........ cm3 / min

[3]
Reveal mark scheme Mark scheme for question 15(b)(iii)
(c)

The reaction is exothermic.

Suggest how the student could improve their investigation to control the temperature.

[1]
Reveal mark scheme Mark scheme for question 15(c)

Biology Paper 7 November 2020 Higher tier, Question 15 9 marks

Figure for question 15
(a)

Explain why the student leaves the test tubes in the water bath for 5 minutes before mixing them.

[1]
Reveal mark scheme Mark scheme for question 15(a)
(b)

The table shows the studentโ€™s results.

Temperature of water bath (ยฐC)Time when indicator stays orange (seconds)
20568
30360
4060
50340
60Indicator still changes colour after 600
(b)(i)

Explain the result for 20 ยฐC.

[2]
Reveal mark scheme Mark scheme for question 15(b)(i)
(b)(ii)

Explain why amylase works slowly at 50 ยฐC but no longer works at 60 ยฐC.

[2]
Reveal mark scheme Mark scheme for question 15(b)(ii)
(c)

The student has investigated the effect of temperature on the activity of amylase.

Describe how they could develop their investigation to find the effect of pH on the activity of amylase.

[4]
Reveal mark scheme Mark scheme for question 15(c)

Biology Paper 7 June 2019 Higher tier, Question 15 4 marks

Figure for question 15
(a)

What type of molecules are Q and R ?

Molecule Q........

Molecule R........

[1]
Reveal mark scheme Mark scheme for question 15(a)
(b)

Look at the graph. It shows the effect of pH on the activity of lipase enzyme.

Figure for question 15
(b)(i)

Human lipase is most active in the small intestine.

The pH of the small intestine is pH7.5.

The lipase used to produce the results in the graph is not human lipase.

How can you tell this from the graph?

[1]
Reveal mark scheme Mark scheme for question 15(b)(i)
(b)(ii)

The lock and key hypothesis can explain the pattern in the graph.

Explain the lock and key hypothesis for enzyme specificity.

[2]
Reveal mark scheme Mark scheme for question 15(b)(ii)

Biology Paper 8 June 2019 Higher tier, Question 15 6 marks

The diagram in Fig. 15.1 shows events that occur during human sperm production.

Figure for question 15
(a)(i)

Cells in the germinal epithelium have the ability to turn into sperm cells.

Which term describes cells that have the ability to turn into specialised cells?

[1]
Reveal mark scheme Mark scheme for question 15(a)(i)
(a)(ii)

Compare the number of chromosomes in human germinal epithelium cells and human mature sperm cells.

[1]
Reveal mark scheme Mark scheme for question 15(a)(ii)
(b)

Describe the events that occur at Stage 1 and Stage 2 in Fig. 15.1.

[2]
Reveal mark scheme Mark scheme for question 15(b)
(c)

Sperm production occurs best at 35.0 ยฐC due to the enzymes involved.

Explain why the testes are positioned outside of the body cavity.

[2]
Reveal mark scheme Mark scheme for question 15(c)

Biology Paper 1 June 2018 Foundation tier, Question 15 14 marks

Figure for question 15
(a)

Which gas makes the bubbles?

[1]
Reveal mark scheme Mark scheme for question 15(a)
(b)

* The students think they could improve their method.

They will count the bubbles three times at each temperature. This would show up any anomalous results.

Describe other ways they could improve their method to obtain more precise and repeatable results.

For each improvement explain why it is needed.

[6]
Reveal mark scheme Mark scheme for question 15(b)
(c)

The students count the bubbles three times at each temperature. They then calculate the mean number of bubbles at each temperature.

The table shows their results.

Temperature (ยฐC)Mean number of bubbles per minute
103
206
3011
405
502
601
(c)(i)

Plot the results on the grid.

Figure for question 15
[2]
Reveal mark scheme Mark scheme for question 15(c)(i)
(c)(ii)

Draw a line of best fit.

[1]
Reveal mark scheme Mark scheme for question 15(c)(ii)
(d)

Respiration is an enzyme controlled reaction.

Use ideas about enzymes to explain the pattern in the results.

[4]
Reveal mark scheme Mark scheme for question 15(d)

Biology Paper 7 June 2018 Higher tier, Question 16 6 marks

The diagram shows the position of the pituitary gland and hypothalamus in the body.

Figure for question 16
(a)(i)

Two hormones released by the pituitary are involved in controlling the menstrual cycle.

Write down the names of these two hormones.

[1]
Reveal mark scheme Mark scheme for question 16(a)(i)
(a)(ii)

The graph shows the levels of these two hormones during the menstrual cycle.

Figure for question 16

Use the graph to explain how these two hormones work together to cause ovulation.

[2]
Reveal mark scheme Mark scheme for question 16(a)(ii)
(b)

The hypothalamus is involved in the regulation of body temperature.

Explain why this function of the hypothalamus is important to the role of enzymes.

[3]
Reveal mark scheme Mark scheme for question 16(b)

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