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OCR A Level Chemistry

Topic questions Organic chemistry Electrophilic substitution

Electrophilic substitution

13 questions · 170 marks · about 4 hours

Electrophilic substitution questions

OCR H432 Electrophilic substitution 13 questions

Synthesis and analytical techniques June 2025, Question 20 17 marks

This question is about aromatic compounds.

(a)

The diagrams show the Kekulé and delocalised models of benzene.

Figure for question 20

Kekulé Delocalised

One piece of evidence for the delocalised model is that benzene does not decolourise aqueous bromine.

Suggest two other pieces of evidence which support the delocalised model of benzene.

[2]
Reveal mark scheme Mark scheme for question 20(a)
(b)

A student investigates the reactions of benzene and phenol with excess bromine.

The student’s observations are given in Table 20.1.

Table 20.1

Figure for question 20
(b)(i)

Explain the difference in the relative reactivities of benzene and phenol with bromine.

[3]
Reveal mark scheme Mark scheme for question 20(b)(i)
(b)(ii)

The white precipitate has a relative molecular mass of 330.7.

Construct an equation for the reaction of phenol with excess bromine shown in Table 20.1.

Show the structure of the organic species.

[2]
Reveal mark scheme Mark scheme for question 20(b)(ii)
(c)

Compound G is an organic compound used in the production of pesticides.

Compound G can be synthesised from benzene in the two-stage process shown.

Synthesis 1

Figure for question 20

Benzene
Methylbenzene
Compound G

(c)(i)

Suggest a reagent and halogen carrier that could be used in Stage 1 of Synthesis 1.

[1]
Reveal mark scheme Mark scheme for question 20(c)(i)
(c)(ii)

Stage 2 of Synthesis 1 is the conversion of methylbenzene to compound G.

Outline the mechanism for the reaction in Stage 2.

Show the role of H2SO4 as a catalyst.

[5]
Reveal mark scheme Mark scheme for question 20(c)(ii)
(c)(iii)

A student suggested an alternative two-stage synthesis of compound G from benzene.

Synthesis 2

Figure for question 20

Benzene
Nitrobenzene
Compound G

When Synthesis 2 is attempted, the synthesis is not successful and a different organic compound from compound G is produced.

• Suggest why Synthesis 1 is successful but Synthesis 2 is not successful.

• Suggest the structure of the different organic compound that is formed in Synthesis 2.

[2]
Reveal mark scheme Mark scheme for question 20(c)(iii)
(c)(iv)

In the production of a pesticide, compound G is reduced to amine H.

Suggest suitable reagents and complete the equation for this reduction.

Reagents........

Equation:

Figure for question 20

Compound G
Amine H

[2]
Reveal mark scheme Mark scheme for question 20(c)(iv)

Synthesis and analytical techniques June 2024, Question 21 14 marks

This question is about aromatic compounds.

Reveal mark scheme Mark scheme for question 21
(a)

Ethylbenzene, C6H5CH2CH3, can be prepared by reacting benzene with chloroethane, CH3CH2Cl, in the presence of Al Cl3. The Al Cl3 acts as a halogen carrier.

Figure for question 21

Ethylbenzene

In the mechanism, chloroethane reacts with the halogen carrier to form a carbocation, which acts as the electrophile.

(a)(i)

What is meant by the term electrophile ?

[1]
Reveal mark scheme Mark scheme for question 21(a)(i)
(a)(ii)

Outline the mechanism for this reaction, including the role of Al Cl3 as a halogen carrier.

[5]
Reveal mark scheme Mark scheme for question 21(a)(ii)
(b)

The table shows directing effects for different groups in the electrophilic substitution of aromatic compounds.

Directing effect2- and 4- directing3-directing
–OH–NO2
Group–NH2–COCH3
–NHCOCH3–CN
(b)(i)
Figure for question 21
[3]
Reveal mark scheme Mark scheme for question 21(b)(i)
(b)(ii)

The reactions of C6H5NH2 are similar to the reactions of phenol.

Write an equation for the tri-substitution of C6H5NH2 with chlorine.

[2]
Reveal mark scheme Mark scheme for question 21(b)(ii)
(b)(iii)

Explain why chlorine reacts much more readily with C6H5NH2 than with benzene.

[3]
Reveal mark scheme Mark scheme for question 21(b)(iii)

Synthesis and analytical techniques June 2023, Question 18 11 marks

Figure for question 18
(a)

Outline the mechanism for this reaction, including the role of H2SO4 as a catalyst.

[5]
Reveal mark scheme Mark scheme for question 18(a)
(b)

Determine the percentage yield of 1,3-dinitrobenzene.

Give your answer to 3 significant figures.

[3]
Reveal mark scheme Mark scheme for question 18(b)
(c)

Describe how to purify the impure crystals in Step 3.

[3]
Reveal mark scheme Mark scheme for question 18(c)

Synthesis and analytical techniques June 2022, Question 20 22 marks

This question is about the chemistry of aromatic compounds.

(a)
Figure for question 20
(a)(i)

What chemical test(s) could be used to confirm the presence of the phenol group in compounds K and L ?

[1]
Reveal mark scheme Mark scheme for question 20(a)(i)
(a)(ii)

A student thought that13C NMR spectroscopy could be used to distinguish between compounds J, K and L.

Explain, with reasoning, whether the student is correct.

[3]
Reveal mark scheme Mark scheme for question 20(a)(ii)
(a)(iii)

Compound J is substituted at the 2-and 4-positions by chlorine in the presence of a catalyst.

Outline the mechanism for the 4 substitution of compound J by chlorine in the presence of a catalyst.

Show the role of the catalyst.

[4]
Reveal mark scheme Mark scheme for question 20(a)(iii)
(b)

Compounds K and L react with chlorine much more readily than compound J.

Explain why.

[3]
Reveal mark scheme Mark scheme for question 20(b)
(c)

Compound J, C6H5CH2CH2OH, is reacted with acidified potassium dichromate(VI) under reflux to form organic product M.

Write an equation for this reaction.

Use [O] to represent the oxidising agent and show the structure of M.

[2]
Reveal mark scheme Mark scheme for question 20(c)
(d)

A two-stage synthesis of an amine from compound J is shown below.

(d)(i)

Add the reagents for each stage of this synthesis.

Figure for question 20

Compound J

Figure for question 20
[2]
Reveal mark scheme Mark scheme for question 20(d)(i)
(d)(ii)
Figure for question 20
[1]
Reveal mark scheme Mark scheme for question 20(d)(ii)
(e)
Figure for question 20 Figure for question 20
[4]
Reveal mark scheme Mark scheme for question 20(e)
(f)
Figure for question 20
[2]
Reveal mark scheme Mark scheme for question 20(f)

Synthesis and analytical techniques November 2021, Question 20 20 marks

This question is about reactions of phenol.

(a)
Figure for question 20
(a)(i)

Complete the mechanism below for Stage 1 and Stage 2.

Show curly arrows, the structure of the intermediate and the missing formulae on the dotted lines.

Figure for question 20
[6]
Reveal mark scheme Mark scheme for question 20(a)(i)
(a)(ii)
Figure for question 20
[2]
Reveal mark scheme Mark scheme for question 20(a)(ii)
(a)(iii)

Two molecules of salicylic acid can react together in the presence of an acid catalyst to form compound B.

Compound B has three rings and a molecular formula of C14H8O4.

Write the equation for this reaction showing the structures of organic compounds.

[3]
Reveal mark scheme Mark scheme for question 20(a)(iii)
(b)

A student reacts phenol with nitric acid and sulfuric acid at 100 °C to form impure crystals of an organic compound, C. The student purifies the crystals by recrystallisation.

(b)(i)

Describe how the student could recrystallise the impure crystals to obtain a pure sample of C.

[3]
Reveal mark scheme Mark scheme for question 20(b)(i)
(b)(ii)

The pure sample of C is analysed to give the following results.

Percentage composition by mass: C, 31.44%; H, 1.31%; N, 18.34%; O, 48.91%.

The mass spectrum of C shows a molecular ion peak at m / z = 229.0

The13C NMR spectrum of C is shown below.

Figure for question 20

The table shows directing effects for different groups in the electrophilic substitution of aromatic compounds.

Directing effect2- and 4- directing3-directing
Group–OH–NO2
–NH2

Analyse all the information to suggest the structure for C.

Show all your reasoning.

compound C

[6]
Reveal mark scheme Mark scheme for question 20(b)(ii)

Synthesis and analytical techniques November 2020, Question 17 20 marks

Compounds B and C, shown below, are unsaturated hydrocarbons containing nine carbon atoms.

Figure for question 17
(a)

Compound B reacts with chlorine at room temperature, but compound C requires the presence of a halogen carrier.

In both reactions, the organic compound reacts with chlorine in a 1:1 molar ratio.

(a)(i)

Draw the structures of the organic product of each reaction.

Figure for question 17
[2]
Reveal mark scheme Mark scheme for question 17(a)(i)
(a)(ii)
Figure for question 17
[3]
Reveal mark scheme Mark scheme for question 17(a)(ii)
(a)(iii)

Outline the mechanism for the reaction of compound C with chlorine.

Show the role of the halogen carrier.

[5]
Reveal mark scheme Mark scheme for question 17(a)(iii)
(b)

Compound C can be prepared by ‘trimerisation’ of propanone using concentrated sulfuric acid as a catalyst.

Suggest an equation for this reaction, using molecular formulae.

[3]
Reveal mark scheme Mark scheme for question 17(b)
(c)

An organic chemist is investigating compound D for possible use as a medicine.

The chemist proposes a synthesis of compound D from compound C.

Figure for question 17
(c)(i)
Figure for question 17
[2]
Reveal mark scheme Mark scheme for question 17(c)(i)
(c)(ii)

The chemist develops a three-stage synthesis of compound D from compound C.

Complete the flowchart. Show structures for organic compounds.

Figure for question 17
[5]
Reveal mark scheme Mark scheme for question 17(c)(ii)

Synthesis and analytical techniques June 2019, Question 19 21 marks

This question is about benzene.

(a)

Over time, the Kekulé and delocalised models have been used to describe the bonding and structure of a benzene molecule.

(a)(i)

Describe, in terms of orbital overlap, the similarities and differences between the bonding in the Kekulé model and the delocalised model of benzene.

[3]
Reveal mark scheme Mark scheme for question 19(a)(i)
(a)(ii)

Experimental evidence led to the general acceptance of the delocalised model over the Kekulé model.

Describe two pieces of evidence to support the delocalised model of benzene.

[2]
Reveal mark scheme Mark scheme for question 19(a)(ii)
(b)

Benzene can be used as the starting material for the synthesis of compounds D and E, shown below.

In the diagrams C6H5 is a phenyl group.

Figure for question 19

Compounds D and E can be converted into polymers.

(b)(i)

Draw two repeat units of these polymers.

Two repeat units of polymer formed from D

Two repeat units of polymer formed from E

[3]
Reveal mark scheme Mark scheme for question 19(b)(i)
(b)(ii)

State the type of polymer formed from compounds D and E.

From compound D........

From compound E........

[1]
Reveal mark scheme Mark scheme for question 19(b)(ii)
(b)(iii)

In the synthesis of compounds D and E, benzene is first reacted with ethanoyl chloride, CH3COCl, to form phenylethanone, shown below.

Figure for question 19

The reaction takes place in the presence of aluminium chloride, Al Cl3, which acts as a catalyst.

In the mechanism for this reaction,

• ethanoyl chloride first reacts with aluminium chloride to form the CH3–C+=O cation

• the CH3–C+=O cation then behaves as an electrophile.

Complete the mechanism for the reaction.

Include equations to show the role of the Al Cl3 catalyst, relevant curly arrows and the structure of the intermediate.

Formation of electrophile........

Question 19, shown as an image
Figure for question 19

Regeneration of catalyst........

[5]
Reveal mark scheme Mark scheme for question 19(b)(iii)
(b)(iv)

Complete the flowchart for the synthesis of compounds D and E from phenylethanone.

Figure for question 19
[7]
Reveal mark scheme Mark scheme for question 19(b)(iv)

Synthesis and analytical techniques June 2018, Question 10 1 mark

Benzene reacts with an organic reagent in the presence of a halogen carrier to form phenylethanone.

Figure for question 10

Which organic reagent is required?

A CH3CH2OH

B CH3CHO

C CH3COCl

D CH3COOH

Question 10, shown as an image
[1]
Reveal mark scheme Mark scheme for question 10

Synthesis and analytical techniques June 2018, Question 18 9 marks

This question is about aromatic compounds.

(a)

Phenol undergoes nitration more readily than benzene.

(a)(i)

A student carries out the nitration of phenol with dilute nitric acid to produce 2-nitrophenol and 4-nitrophenol.

A small amount of 3-nitrophenol is also produced.

Figure for question 18

2-nitrophenol 3-nitrophenol 4-nitrophenol

The student thought that13C NMR spectroscopy could be used to distinguish between these three nitrophenols.

Explain whether the student is correct.

[3]
Reveal mark scheme Mark scheme for question 18(a)(i)
(a)(ii)

Explain why phenol is nitrated more readily than benzene.

[3]
Reveal mark scheme Mark scheme for question 18(a)(ii)
(b)

Methylbenzene reacts with sulfur trioxide, SO3, to form D, shown below.

Figure for question 18

The electrophile in this reaction is SO3.

Complete the mechanism for the formation of D. Show curly arrows and the structure of the intermediate.

Figure for question 18
[3]
Reveal mark scheme Mark scheme for question 18(b)

Unified chemistry June 2018, Question 6 12 marks

This question is about organic reactions.

(a)
Figure for question 6
(a)(i)

Give the systematic name for compound A.

[1]
Reveal mark scheme Mark scheme for question 6(a)(i)
(a)(ii)

What type of reaction has taken place?

[1]
Reveal mark scheme Mark scheme for question 6(a)(ii)
(a)(iii)
Figure for question 6
[3]
Reveal mark scheme Mark scheme for question 6(a)(iii)
(a)(iv)

A similar reaction takes place when propanone, (CH3)2CO, is mixed with OH–(aq) ions.

Draw the structure of the organic product of this reaction.

[1]
Reveal mark scheme Mark scheme for question 6(a)(iv)
(b)

* Many organic reactions use electrophiles as reagents.

Explain the role of electrophiles in organic chemistry.

Your answer should include one reaction of an aliphatic compound and one reaction of an

aromatic compound, including relevant mechanisms.

[6]
Reveal mark scheme Mark scheme for question 6(b)

Synthesis and analytical techniques June 2017, Question 17 21 marks

This question is about the chemistry of aromatic compounds.

(a)

Benzoic acid can be nitrated by concentrated nitric acid in the presence of concentrated sulfuric acid as a catalyst, as shown in Equation 17.1.

The organic product of this reaction is 3-nitrobenzoic acid.

Figure for question 17
(a)(i)

Outline the mechanism for this nitration of benzoic acid.

Show how H2SO4 behaves as a catalyst.

[5]
Reveal mark scheme Mark scheme for question 17(a)(i)
(a)(ii)

* A chemist carries out the reaction in Equation 17.1 using 4.97 g of benzoic acid.

The chemist obtains 3-nitrobenzoic acid as an impure solid.

The chemist purifies the solid to obtain 4.85 g of 3-nitrobenzoic acid.

Describe a method to obtain a pure sample of 3-nitrobenzoic acid from the impure solid, determine the percentage yield and check its purity.

[6]
Reveal mark scheme Mark scheme for question 17(a)(ii)
(b)

A student investigates the relative ease of nitration of phenol, benzene, and benzoic acid.

Figure for question 17

The student finds that the conditions required for the nitration of each compound are different, as shown in Table 17.1.

Figure for question 17
(b)(i)

State the trend in the relative ease of nitration of phenol, benzene, and benzoic acid.

[1]
Reveal mark scheme Mark scheme for question 17(b)(i)
(b)(ii)

Apply your knowledge of the bonding in arenes to explain the trend in part (b)(i).

[3]
Reveal mark scheme Mark scheme for question 17(b)(ii)
(c)

A student synthesises 3-bromophenylamine, shown below, starting from nitrobenzene.

(c)(i)

Complete the flowchart showing the structure of the intermediate and the formulae the reagents for each stage.

Figure for question 17
[3]
Reveal mark scheme Mark scheme for question 17(c)(i)
(c)(ii)

Another student attempts the same synthesis but carries out reduction before bromination. The student was surprised to find that two structural isomers of 3-bromophenylamine had been formed instead of the desired organic product.

Explain this result and suggest the structures of the two isomers that formed.

Explanation........

Structures

[3]
Reveal mark scheme Mark scheme for question 17(c)(ii)

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