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OCR A Level Chemistry

Topic questions Organic chemistry Phenols

Phenols

15 questions · 166 marks · about 3.5 hours

Phenols questions

OCR H432 Phenols 15 questions

Synthesis and analytical techniques June 2025, Question 20 17 marks

This question is about aromatic compounds.

(a)

The diagrams show the Kekulé and delocalised models of benzene.

Figure for question 20

Kekulé Delocalised

One piece of evidence for the delocalised model is that benzene does not decolourise aqueous bromine.

Suggest two other pieces of evidence which support the delocalised model of benzene.

[2]
Reveal mark scheme Mark scheme for question 20(a)
(b)

A student investigates the reactions of benzene and phenol with excess bromine.

The student’s observations are given in Table 20.1.

Table 20.1

Figure for question 20
(b)(i)

Explain the difference in the relative reactivities of benzene and phenol with bromine.

[3]
Reveal mark scheme Mark scheme for question 20(b)(i)
(b)(ii)

The white precipitate has a relative molecular mass of 330.7.

Construct an equation for the reaction of phenol with excess bromine shown in Table 20.1.

Show the structure of the organic species.

[2]
Reveal mark scheme Mark scheme for question 20(b)(ii)
(c)

Compound G is an organic compound used in the production of pesticides.

Compound G can be synthesised from benzene in the two-stage process shown.

Synthesis 1

Figure for question 20

Benzene
Methylbenzene
Compound G

(c)(i)

Suggest a reagent and halogen carrier that could be used in Stage 1 of Synthesis 1.

[1]
Reveal mark scheme Mark scheme for question 20(c)(i)
(c)(ii)

Stage 2 of Synthesis 1 is the conversion of methylbenzene to compound G.

Outline the mechanism for the reaction in Stage 2.

Show the role of H2SO4 as a catalyst.

[5]
Reveal mark scheme Mark scheme for question 20(c)(ii)
(c)(iii)

A student suggested an alternative two-stage synthesis of compound G from benzene.

Synthesis 2

Figure for question 20

Benzene
Nitrobenzene
Compound G

When Synthesis 2 is attempted, the synthesis is not successful and a different organic compound from compound G is produced.

• Suggest why Synthesis 1 is successful but Synthesis 2 is not successful.

• Suggest the structure of the different organic compound that is formed in Synthesis 2.

[2]
Reveal mark scheme Mark scheme for question 20(c)(iii)
(c)(iv)

In the production of a pesticide, compound G is reduced to amine H.

Suggest suitable reagents and complete the equation for this reduction.

Reagents........

Equation:

Figure for question 20

Compound G
Amine H

[2]
Reveal mark scheme Mark scheme for question 20(c)(iv)

Unified chemistry June 2025, Question 2 14 marks

This question is about different compounds that each contain O and H atoms covalently bonded together.

(a)

The alcohol 2,3‑dimethylhexan‑1‑ol has the molecular formula C8H18O.

(a)(i)

Draw the skeletal formula of 2,3‑dimethylhexan‑1‑ol.

[1]
Reveal mark scheme Mark scheme for question 2(a)(i)
(a)(ii)

What is the number of H atoms in 8.45 g of 2,3‑dimethylhexan‑1‑ol?

Give your answer to 3 significant figures and in standard form.

[3]
Reveal mark scheme Mark scheme for question 2(a)(ii)
(b)
Figure for question 2
(b)(i)

Why does paracetamol not react with Na2CO3(aq)?

[1]
Reveal mark scheme Mark scheme for question 2(b)(i)
(b)(ii)

The student uses the reaction of nuromol tablets with Na2CO3(aq) to determine the mass of ibuprofen and the mass of paracetomol in one nuromol tablet.

The student’s method is outlined below.

• Weigh four nuromol tablets.

• Add the tablets to an excess of aqueous sodium carbonate.

• Collect the gas produced and measure its volume.

Results Mass of four nuromol tablets = 2.80 g Volume of gas collected at RTP = 48.0 cm3

Assume that ibuprofen is the only compound in nuromol tablets that reacts with Na2CO3(aq).

Determine the mass of ibuprofen and the mass of paracetomol, in mg, in one nuromol tablet.

[4]
Reveal mark scheme Mark scheme for question 2(b)(ii)
(c)

Barium hydroxide, Ba(OH)2, is an alkali. A student is supplied with a solution of Ba(OH)2 with a concentration of 46.80 g dm–3 at 25 °C.

The student dilutes 20.0 cm3 of this solution of Ba(OH)2 with water and the solution is made up to 100.0 cm3 at 25 °C.

Calculate the pH of the diluted solution of Ba(OH)2 at 25 °C.

Give your answer to 2 decimal places.

[5]
Reveal mark scheme Mark scheme for question 2(c)

Synthesis and analytical techniques June 2024, Question 21 14 marks

This question is about aromatic compounds.

Reveal mark scheme Mark scheme for question 21
(a)

Ethylbenzene, C6H5CH2CH3, can be prepared by reacting benzene with chloroethane, CH3CH2Cl, in the presence of Al Cl3. The Al Cl3 acts as a halogen carrier.

Figure for question 21

Ethylbenzene

In the mechanism, chloroethane reacts with the halogen carrier to form a carbocation, which acts as the electrophile.

(a)(i)

What is meant by the term electrophile ?

[1]
Reveal mark scheme Mark scheme for question 21(a)(i)
(a)(ii)

Outline the mechanism for this reaction, including the role of Al Cl3 as a halogen carrier.

[5]
Reveal mark scheme Mark scheme for question 21(a)(ii)
(b)

The table shows directing effects for different groups in the electrophilic substitution of aromatic compounds.

Directing effect2- and 4- directing3-directing
–OH–NO2
Group–NH2–COCH3
–NHCOCH3–CN
(b)(i)
Figure for question 21
[3]
Reveal mark scheme Mark scheme for question 21(b)(i)
(b)(ii)

The reactions of C6H5NH2 are similar to the reactions of phenol.

Write an equation for the tri-substitution of C6H5NH2 with chlorine.

[2]
Reveal mark scheme Mark scheme for question 21(b)(ii)
(b)(iii)

Explain why chlorine reacts much more readily with C6H5NH2 than with benzene.

[3]
Reveal mark scheme Mark scheme for question 21(b)(iii)

Synthesis and analytical techniques June 2024, Question 23 12 marks

Oil of wintergreen is a liquid used in medicine to relieve muscle pain.

Compound H is a component in oil of wintergreen and can be synthesised from compound G, as shown below. The boiling point and density of compound H are stated.

Figure for question 23

Compound G
Compound H boiling point = 222 °C density = 1.174 g cm−3

A student prepares a sample of compound H by the method below.

Step 1 Reflux 8.97 g of compound G for 30 minutes with an excess of methanol in the presence of a small amount of sulfuric acid as a catalyst.

Step 2 Add an excess of aqueous sodium carbonate, Na2CO3(aq). Two layers are obtained.

Step 3 Purify the impure compound H that forms from the resulting mixture.

The student follows this method and obtains 5.32 g of pure compound H.

(a)

Why does the student use reflux in Step 1 ?

[1]
Reveal mark scheme Mark scheme for question 23(a)
(b)
(b)(i)

In Step 2, Na2CO3(aq) removes the sulfuric acid catalyst and any unreacted compound G from the mixture.

Write equations for this removal.

Removal of sulfuric acid

Removal of unreacted compound G

Figure for question 23

Compound G

[3]
Reveal mark scheme Mark scheme for question 23(b)(i)
(b)(ii)

Another student suggests that adding aqueous sodium hydroxide would be more effective in removing the sulfuric acid catalyst than Na2CO3(aq).

Comment on whether the student’s suggestion is an improvement for the preparation of compound H.

[1]
Reveal mark scheme Mark scheme for question 23(b)(ii)
(c)

Calculate the percentage yield of compound H.

Give your answer to three significant figures.

[3]
Reveal mark scheme Mark scheme for question 23(c)
(d)

Describe how to purify the impure compound H from the two layers in Step 2.

[4]
Reveal mark scheme Mark scheme for question 23(d)

Synthesis and analytical techniques June 2023, Question 20 10 marks

This question is about aromatic compounds containing the –COOH and –OH functional groups.

(a)

Salicylic acid, shown below, is used in the manufacture of some important medicines.

Figure for question 20

Salicylic acid

Complete the flowchart for reactions of salicylic acid, by adding the organic products in each

Figure for question 20
[4]
Reveal mark scheme Mark scheme for question 20(a)
(b)

PAS, shown below, is an antibiotic used to treat several diseases including tuberculosis (TB).

Figure for question 20
(b)(i)

A student predicts that PAS could polymerise to form a polymer containing both ester and amide linkages.

Draw a section of this polymer.

The section should contain one amide and one ester linkage, which should be displayed.

[3]
Reveal mark scheme Mark scheme for question 20(b)(i)
(b)(ii)

For the treatment of TB, the maximum daily dosage of PAS that should be prescribed is 300 mg per kg of body mass.

A child weighs 20.0 kg.

Calculate the number of PAS molecules in the maximum daily dosage of PAS for this child.

[3]
Reveal mark scheme Mark scheme for question 20(b)(ii)

Unified chemistry June 2023, Question 5 11 marks

Aspirin tablets are used for pain relief.

The structure of aspirin is shown below.

Figure for question 5
(a)

A student uses the reaction of aspirin with cold NaOH(aq) to determine the mass of aspirin in one tablet.

In this reaction, 1 mol of aspirin reacts with 1 mol of cold NaOH(aq).

The student’s method is outlined below.

Step 1 The student reacts three aspirin tablets with 100 cm3 of 0.500 mol dm–3 NaOH(aq). The NaOH is in excess. A colourless solution forms.

Step 2 The colourless solution from Step 1 is made up to 250.0 cm3 with distilled water.

Step 3 A 25.00 cm3 sample of the diluted solution from Step 2 is titrated with 0.200 mol dm–3 HCl(aq) in the burette.

The HC l (aq) reacts with excess NaOH(aq) that remains in Step 1:

Question 5, shown as an image

The student repeats the titration to obtain concordant (consistent) titres.

Titration results The trial titre has been omitted.

The burette readings have been read to the nearest 0.05 cm3.

123
Final reading / cm323.1045.4027.40
Initial reading / cm30.0023.105.00

Analysis of results From the results, the student can determine the following.

1. The amount, in mol, of excess NaOH(aq) that remains after the reaction of aspirin with NaOH(aq).

2. The amount, in mol, of NaOH(aq) that reacted with the aspirin.

Use the results to determine the mass, in mg, of aspirin in one aspirin tablet.

[6]
Reveal mark scheme Mark scheme for question 5(a)
(b)

Aspirin reacts with hot NaOH(aq), under reflux.

(b)(i)

Draw a labelled diagram of suitable apparatus for reflux.

[2]
Reveal mark scheme Mark scheme for question 5(b)(i)
(b)(ii)

In this reaction, 1 mol of aspirin reacts with 3 mol of hot NaOH(aq).

Complete the equation for the reaction of aspirin with an excess of hot NaOH(aq).

Show structures for organic compounds.

Figure for question 5
[3]
Reveal mark scheme Mark scheme for question 5(b)(ii)

Synthesis and analytical techniques June 2022, Question 20 22 marks

This question is about the chemistry of aromatic compounds.

(a)
Figure for question 20
(a)(i)

What chemical test(s) could be used to confirm the presence of the phenol group in compounds K and L ?

[1]
Reveal mark scheme Mark scheme for question 20(a)(i)
(a)(ii)

A student thought that13C NMR spectroscopy could be used to distinguish between compounds J, K and L.

Explain, with reasoning, whether the student is correct.

[3]
Reveal mark scheme Mark scheme for question 20(a)(ii)
(a)(iii)

Compound J is substituted at the 2-and 4-positions by chlorine in the presence of a catalyst.

Outline the mechanism for the 4 substitution of compound J by chlorine in the presence of a catalyst.

Show the role of the catalyst.

[4]
Reveal mark scheme Mark scheme for question 20(a)(iii)
(b)

Compounds K and L react with chlorine much more readily than compound J.

Explain why.

[3]
Reveal mark scheme Mark scheme for question 20(b)
(c)

Compound J, C6H5CH2CH2OH, is reacted with acidified potassium dichromate(VI) under reflux to form organic product M.

Write an equation for this reaction.

Use [O] to represent the oxidising agent and show the structure of M.

[2]
Reveal mark scheme Mark scheme for question 20(c)
(d)

A two-stage synthesis of an amine from compound J is shown below.

(d)(i)

Add the reagents for each stage of this synthesis.

Figure for question 20

Compound J

Figure for question 20
[2]
Reveal mark scheme Mark scheme for question 20(d)(i)
(d)(ii)
Figure for question 20
[1]
Reveal mark scheme Mark scheme for question 20(d)(ii)
(e)
Figure for question 20 Figure for question 20
[4]
Reveal mark scheme Mark scheme for question 20(e)
(f)
Figure for question 20
[2]
Reveal mark scheme Mark scheme for question 20(f)

Synthesis and analytical techniques November 2021, Question 20 20 marks

This question is about reactions of phenol.

(a)
Figure for question 20
(a)(i)

Complete the mechanism below for Stage 1 and Stage 2.

Show curly arrows, the structure of the intermediate and the missing formulae on the dotted lines.

Figure for question 20
[6]
Reveal mark scheme Mark scheme for question 20(a)(i)
(a)(ii)
Figure for question 20
[2]
Reveal mark scheme Mark scheme for question 20(a)(ii)
(a)(iii)

Two molecules of salicylic acid can react together in the presence of an acid catalyst to form compound B.

Compound B has three rings and a molecular formula of C14H8O4.

Write the equation for this reaction showing the structures of organic compounds.

[3]
Reveal mark scheme Mark scheme for question 20(a)(iii)
(b)

A student reacts phenol with nitric acid and sulfuric acid at 100 °C to form impure crystals of an organic compound, C. The student purifies the crystals by recrystallisation.

(b)(i)

Describe how the student could recrystallise the impure crystals to obtain a pure sample of C.

[3]
Reveal mark scheme Mark scheme for question 20(b)(i)
(b)(ii)

The pure sample of C is analysed to give the following results.

Percentage composition by mass: C, 31.44%; H, 1.31%; N, 18.34%; O, 48.91%.

The mass spectrum of C shows a molecular ion peak at m / z = 229.0

The13C NMR spectrum of C is shown below.

Figure for question 20

The table shows directing effects for different groups in the electrophilic substitution of aromatic compounds.

Directing effect2- and 4- directing3-directing
Group–OH–NO2
–NH2

Analyse all the information to suggest the structure for C.

Show all your reasoning.

compound C

[6]
Reveal mark scheme Mark scheme for question 20(b)(ii)

Synthesis and analytical techniques June 2018, Question 18 9 marks

This question is about aromatic compounds.

(a)

Phenol undergoes nitration more readily than benzene.

(a)(i)

A student carries out the nitration of phenol with dilute nitric acid to produce 2-nitrophenol and 4-nitrophenol.

A small amount of 3-nitrophenol is also produced.

Figure for question 18

2-nitrophenol 3-nitrophenol 4-nitrophenol

The student thought that13C NMR spectroscopy could be used to distinguish between these three nitrophenols.

Explain whether the student is correct.

[3]
Reveal mark scheme Mark scheme for question 18(a)(i)
(a)(ii)

Explain why phenol is nitrated more readily than benzene.

[3]
Reveal mark scheme Mark scheme for question 18(a)(ii)
(b)

Methylbenzene reacts with sulfur trioxide, SO3, to form D, shown below.

Figure for question 18

The electrophile in this reaction is SO3.

Complete the mechanism for the formation of D. Show curly arrows and the structure of the intermediate.

Figure for question 18
[3]
Reveal mark scheme Mark scheme for question 18(b)

Synthesis and analytical techniques June 2018, Question 21 12 marks

This question is about aromatic carboxylic acids and their derivatives.

(a)
Figure for question 21
[3]
Reveal mark scheme Mark scheme for question 21(a)
(b)
Figure for question 21
[4]
Reveal mark scheme Mark scheme for question 21(b)
(c)
Figure for question 21
(c)(i)

The concentration of ester K in the cosmetic product is 9.13 × 10−2 g dm−3.

Using the results, calculate the concentration, in mol dm−3, of ester M in the cosmetic product.

Give your answer to two significant figures.

concentration of ester M =........ mol dm−3

[2]
Reveal mark scheme Mark scheme for question 21(c)(i)
(c)(ii)
Figure for question 21 Figure for question 21
[3]
Reveal mark scheme Mark scheme for question 21(c)(ii)

Synthesis and analytical techniques June 2017, Question 17 21 marks

This question is about the chemistry of aromatic compounds.

(a)

Benzoic acid can be nitrated by concentrated nitric acid in the presence of concentrated sulfuric acid as a catalyst, as shown in Equation 17.1.

The organic product of this reaction is 3-nitrobenzoic acid.

Figure for question 17
(a)(i)

Outline the mechanism for this nitration of benzoic acid.

Show how H2SO4 behaves as a catalyst.

[5]
Reveal mark scheme Mark scheme for question 17(a)(i)
(a)(ii)

* A chemist carries out the reaction in Equation 17.1 using 4.97 g of benzoic acid.

The chemist obtains 3-nitrobenzoic acid as an impure solid.

The chemist purifies the solid to obtain 4.85 g of 3-nitrobenzoic acid.

Describe a method to obtain a pure sample of 3-nitrobenzoic acid from the impure solid, determine the percentage yield and check its purity.

[6]
Reveal mark scheme Mark scheme for question 17(a)(ii)
(b)

A student investigates the relative ease of nitration of phenol, benzene, and benzoic acid.

Figure for question 17

The student finds that the conditions required for the nitration of each compound are different, as shown in Table 17.1.

Figure for question 17
(b)(i)

State the trend in the relative ease of nitration of phenol, benzene, and benzoic acid.

[1]
Reveal mark scheme Mark scheme for question 17(b)(i)
(b)(ii)

Apply your knowledge of the bonding in arenes to explain the trend in part (b)(i).

[3]
Reveal mark scheme Mark scheme for question 17(b)(ii)
(c)

A student synthesises 3-bromophenylamine, shown below, starting from nitrobenzene.

(c)(i)

Complete the flowchart showing the structure of the intermediate and the formulae the reagents for each stage.

Figure for question 17
[3]
Reveal mark scheme Mark scheme for question 17(c)(i)
(c)(ii)

Another student attempts the same synthesis but carries out reduction before bromination. The student was surprised to find that two structural isomers of 3-bromophenylamine had been formed instead of the desired organic product.

Explain this result and suggest the structures of the two isomers that formed.

Explanation........

Structures

[3]
Reveal mark scheme Mark scheme for question 17(c)(ii)

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