Unit 1: Non-calculator June 2025 Intermediate tier, Question 19, also on the Higher paper 2 marks
The length of each side of a square is 15 cm, correct to the nearest 1 cm.
Calculate the greatest possible perimeter of this square.
Reveal mark scheme
WJEC GCSE Maths
Topic questions Number Limits of accuracy and bounds
24 questions · 71 marks · about 1.5 hours
The length of each side of a square is 15 cm, correct to the nearest 1 cm.
Calculate the greatest possible perimeter of this square.
The length of each side of a square is 15 cm, correct to the nearest 1 cm.
Calculate the greatest possible perimeter of this square.
The table below shows the value of g and the value of h.
It also shows the degree of accuracy of each value.
| Value | Degree of accuracy |
| g = 8 | 1 significant figure |
| h =⋅1 7 | 1 decimal place |
Use the formula
to calculate the greatest possible value of f.
You must show all your working.
The values e = 7·1, f = 73·9 and g = 65·7 are each given correct to 1 decimal place.
The value of h is found using the formula.h
Calculate the greatest value of h. Give your answer correct to four decimal places.
You must show all your working.
7 cubes are stacked on top of each other. Each of these cubes has edges of length 60 mm, measured correct to the nearest millimetre.
Calculate the greatest possible height of this stack of 7 cubes.
7 cubes are stacked on top of each other. Each of these cubes has edges of length 60 mm, measured correct to the nearest millimetre.
Calculate the greatest possible height of this stack of 7 cubes.
The values b = 23, c = 0·73 and d = 8·3 are each given correct to 2 significant figures.
Use the formula
to calculate the greatest possible value of a. Give your answer correct to 2 decimal places.
You must show all your working.
Two time periods are measured as 4 hours 40 minutes and 2 hours 50 minutes.
Each measurement is correct to the nearest 10 minutes.
What is the least possible sum of these two time periods?
Give your answer in hours and minutes.
Answer =........ hours........ minutes
Two time periods are measured as 4 hours 40 minutes and 2 hours 50 minutes.
Each measurement is correct to the nearest 10 minutes.
What is the least possible sum of these two time periods?
Give your answer in hours and minutes.
Answer =........ hours........ minutes
Two times are recorded correct to the nearest 0·1 second.
Calculate the greatest possible difference between these times.
Two times are recorded correct to the nearest 0·1 second.
Calculate the greatest possible difference between these times.
The table below shows the value of d and the value of e.
It also shows the degree of accuracy of each value.
| Value | Degree of accuracy |
| d = 64 | Nearest whole number |
| e = 8·6 | 1 decimal place |
Use the formula
to calculate the least possible value of c.
You must show all your working.
The lengths of the sides of a rectangle are given as 24 cm and 15 cm.
Each measurement is given correct to the nearest centimetre.
Calculate the difference between the greatest possible perimeter of the rectangle and the least
possible perimeter of the rectangle.
The lengths of the sides of a rectangle are given as 24 cm and 15 cm.
Each measurement is given correct to the nearest centimetre.
Calculate the difference between the greatest possible perimeter of the rectangle and the least
possible perimeter of the rectangle.
An amount written correct to the nearest £10 is £7180. This amount is increased by 23·5%, correct to the nearest 0·1%. Calculate the least possible value of the increased amount.
Give your answer correct to the nearest pound.
Write down the greatest possible value of length a.
Give your answer in mm.
Calculate the greatest possible value of length b.
Give your answer in mm.
Calculate the least possible value of length c.
Give your answer in mm.
Write down the greatest possible value of length a.
Give your answer in mm.
Calculate the greatest possible value of length b.
Give your answer in mm.
Calculate the least possible value of length c.
Give your answer in mm.
A mass is written as 430 kg, correct to the nearest 10 kg.
Circle the least possible value of this mass.
420 kg 425 kg 429·5 kg 426 kg 424·9 kg
A time period is written as 22 seconds, correct to the nearest second.
Circle the least possible value of this time period.
22 s 20 s 21 s 21·5 s 21·4 s
A population is written as 85 people, correct to the nearest five people.
Circle the least possible value of this population.
83 people 81 people 84 people 82 people 80 people
A mass is written as 430 kg, correct to the nearest 10 kg.
Circle the least possible value of this mass.
420 kg 425 kg 429·5 kg 426 kg 424·9 kg
A time period is written as 22 seconds, correct to the nearest second.
Circle the least possible value of this time period.
22 s 20 s 21 s 21·5 s 21·4 s
A population is written as 85 people, correct to the nearest five people.
Circle the least possible value of this population.
83 people 81 people 84 people 82 people 80 people
Also involves Compound measures
A car travels 300 km, measured correct to the nearest 5 km.
It travels this distance in 6 hours, measured correct to the nearest hour. Calculate the least possible average speed of the car.
Give your answer in km/h, correct to 2 decimal places.
The area of a rectangle is 137 cm2, correct to the nearest cm2.
Its width is 11 cm, correct to the nearest cm.
Calculate the greatest possible length of the rectangle.
Give your answer correct to 3 significant figures.
Also involves Area and perimeter
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