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Edexcel IGCSE Biology

Topic questions Cell biology Enzyme action

Enzyme action

6 questions · 69 marks · about 1 hour

Enzyme action questions

Edexcel 4BI1 Enzyme action 6 questions

Biology Paper 2 November 2023, Question 2 12 marks

Catalase is an enzyme found in many cells. This enzyme controls the breakdown of hydrogen peroxide into water and oxygen.

Question 2, shown as an image

hydrogen water oxygen peroxide A teacher uses this method to investigate the effect of pH on catalase. Step 1 maths symbol cut a cylinder of potato tissue into six equal sized discs Step 2 maths symbol measure 10 cm33 of hydrogen peroxide solution and place into a boiling tube Step 3 a maths symbol dd a pH buffer solution to the tube to keep the pH at 7 Step 4 a maths symbol dd the six potato discs to the boiling tube Step 5 c maths symbol ollect the gas given off by the reaction in an inverted

Question 2, shown as an image

Step 6 maths symbol measure the total volume of gas collected after five minutes Repeat steps 1 to 6 using four different pH buffers (pH 4, pH 5, pH 6 and pH 8). The diagram shows the teacher’s apparatus.

Figure for question 2
(a)

State what is meant by the term enzyme.

[1]
Reveal mark scheme Mark scheme for question 2(a)
(b)

Suggest why each potato cylinder was cut into six discs rather than left as one cylinder.

[1]
Reveal mark scheme Mark scheme for question 2(b)
(c)
(c)(i)

Give the dependent variable in this experiment.

[1]
Reveal mark scheme Mark scheme for question 2(c)(i)
(c)(ii)

The teacher controls the time for gas collection and also the volume of hydrogen peroxide used. State two other abiotic variables the teacher should control in this experiment.

[2]
Reveal mark scheme Mark scheme for question 2(c)(ii)
(d)

The table shows the teacher’s results.

pH of solutionVolume of oxygen after 5 minutes in cm3Mean rate of reaction in cm3 per minute
440.8
561.2
671.4
7122.4
830.6
(d)(i)

Calculate the percentage change in the mean rate of reaction as the pH is changed from pH 4 to pH 7.

percentage change =........

[2]
Reveal mark scheme Mark scheme for question 2(d)(i)
(d)(ii)

The teacher calculated the mean rate of reaction by collecting the oxygen released for the first five minutes of the reaction. Explain why the mean rate of reaction changes beyond the first five minutes.

[2]
Reveal mark scheme Mark scheme for question 2(d)(ii)
(d)(iii)

Explain the effect of changing pH on an enzyme-controlled reaction.

[3]
Reveal mark scheme Mark scheme for question 2(d)(iii)

Biology Paper 2 June 2022, Question 5 11 marks

Pineapple juice contains a protease called bromelain.

A student uses this method to investigate the digestion of solid gelatine protein by bromelain.

• place solid gelatine protein into a test tube up to a height of 5 cm

• mix 5 cm3 pineapple juice with 1 cm3 of pH 4 buffer

• place 1 cm3 of the pineapple juice and buffer solution on top of the gelatine

• leave for one hour in a water bath set to 37 °C

• measure the height of the solid gelatine and use it to calculate the volume of gelatine that has been digested

Repeat the method three more times.

The diagram shows part of the student’s method.

Figure for question 5
(a)

The table shows the student’s results for the volumes of gelatine digested at pH 4.

Tube numberVolume of gelatine digested in cm3
10.55
21.89
30.54
40.61
(a)(i)

Calculate the mean volume of gelatine digested in cm3.

Give your answer to two decimal places.

mean volume =........ 3

[3]
Reveal mark scheme Mark scheme for question 5(a)(i)
(a)(ii)

State what substances are produced when the gelatine protein is digested.

[1]
Reveal mark scheme Mark scheme for question 5(a)(ii)
(b)

The student repeats the investigation with different pH buffers.

The table shows their results.

pHMean volume of gelatine digested in cm3
30.32
50.98
70.51
90.33
110.01
(b)(i)

Give two variables the student should control.

[2]
Reveal mark scheme Mark scheme for question 5(b)(i)
(b)(ii)

Explain the effect of changing the pH on the mean volume of gelatine digested.

[3]
Reveal mark scheme Mark scheme for question 5(b)(ii)
(c)

Describe how to test for the presence of protein.

[2]
Reveal mark scheme Mark scheme for question 5(c)

Biology Paper 1 January 2022, Question 6 10 marks

The diagram shows part of the gut of a rabbit. The rabbit is a primary consumer and eats mainly grass and other vegetable material.

Figure for question 6
(a)

Name the parts labelled A, B, C and D.

[4]
Reveal mark scheme Mark scheme for question 6(a)
(b)

The gut of a rabbit has a large caecum and appendix. These contain bacteria that are able to produce the enzyme cellulase. Explain how these bacteria help the rabbits with their diet of plant material.

[3]
Reveal mark scheme Mark scheme for question 6(b)
(c)

The human gut has a caecum and appendix but they are much smaller than those in the rabbit.

(c)(i)

Suggest why the human gut only has a small caecum and appendix.

[1]
Reveal mark scheme Mark scheme for question 6(c)(i)
(c)(ii)

In humans the appendix also acts as a store of useful bacteria. Scientists have discovered that patients who have had their appendix removed are more likely to develop infections of the colon. Explain how having no appendix may increase the likelihood of bacterial infections of the colon.

[2]
Reveal mark scheme Mark scheme for question 6(c)(ii)

Biology Paper 2 January 2021, Question 6 12 marks

Also involves Factors affecting enzyme activity

Catalase is an enzyme found in many cells.

It speeds up the breakdown of hydrogen peroxide into water and oxygen.

The equation for the reaction is

Question 6, shown as an image

A teacher demonstrates the effect of increasing catalase concentration on the initial rate of the reaction.

This is the teacher’s method.

• cut five equal size discs from a potato, each 0.2 mm thick

• place the discs in a boiling tube with 5 cm3 of buffer solution

• add 5 cm3 of hydrogen peroxide solution to the boiling tube

• place a bung and delivery tube firmly into the boiling tube

• position the other end of the delivery tube under an inverted measuring cylinder

• start a timer as soon as the first bubble of oxygen enters the measuring cylinder

• measure the volume of oxygen produced in one minute

Repeat this method three times.

Figure for question 6

The teacher uses this method with different numbers of potato discs, making sure that other conditions are unchanged.

(a)

Give the expected relationship between the named independent variable and the named dependent variable in this demonstration.

[2]
Reveal mark scheme Mark scheme for question 6(a)
(b)

Give two variables that the teacher controls in this demonstration.

[2]
Reveal mark scheme Mark scheme for question 6(b)
(c)

The table shows the teacher’s results.

EnzymeVolume of oxygen produced in one minute in cm3
concentration in number of discsReading 1Reading 2Reading 3Reading 4Mean reading
51.21.50.01.5
103.54.56.05.54.9
156.57.07.58.07.3
209.08.58.07.58.3
2515.011.011.512.012.4
(c)(i)

Calculate the mean volume of oxygen produced in one minute using 5 potato discs.

[2]
Reveal mark scheme Mark scheme for question 6(c)(i)
(c)(ii)

Calculate the percentage increase in mean volume of oxygen produced in one minute as the concentration of enzyme changes from 15 to 20 discs.

[2]
Reveal mark scheme Mark scheme for question 6(c)(ii)
(c)(iii)

Explain the relationship between the concentration of enzyme and mean volume of oxygen produced in one minute.

[2]
Reveal mark scheme Mark scheme for question 6(c)(iii)
(d)

Suggest why the teacher measures the volume of oxygen after the first minute of the reaction rather than after 10 minutes.

[2]
Reveal mark scheme Mark scheme for question 6(d)

Biology Paper 2 November 2020 (R), Question 6 10 marks

Variation in a population can have different causes.

(a)

Which of these will not lead to an increase in genetic variation in a population of plants?

Question 6, shown as an image
[1]
Reveal mark scheme Mark scheme for question 6(a)
(b)

Explain how a change in the DNA of a microorganism can reduce its ability to digest a substance.

[5]
Reveal mark scheme Mark scheme for question 6(b)
(c)

Explain why a change in DNA may not affect the phenotype of an organism.

[4]
Reveal mark scheme Mark scheme for question 6(c)

Biology Paper 1 January 2020, Question 4 14 marks

Also involves Factors affecting enzyme activity

Enzymes are biological molecules that act as catalysts in metabolic reactions.

(a)(i)

State what is meant by the term catalyst.

[1]
Reveal mark scheme Mark scheme for question 4(a)(i)
(a)(ii)

State what is meant by the term metabolic.

[1]
Reveal mark scheme Mark scheme for question 4(a)(ii)
(b)

A teacher investigates the effect of enzyme concentration on the rate of a reaction.

He uses the enzyme catalase, which is found in potato.

He changes the enzyme concentration by adding different numbers of potato discs.

Catalase breaks down hydrogen peroxide solution into water and oxygen.

This is his method.

● cut same-sized discs from a potato

● put 5 cm3 of hydrogen peroxide solution into each of five test tubes

● add a different number of potato discs to the hydrogen peroxide

● measure the volume of oxygen gas produced in three minutes

The teacher repeats each test four times for each concentration.

He then calculates the mean rate of oxygen production for each concentration.

The table shows his results.

Enzyme concentration (number of potato discs)Mean rate of oxygen production in cm3 per minute
22.0
44.4
67.0
88.2
108.2
(b)(i)

Plot a line graph to show the effect of enzyme concentration on the mean rate of oxygen production.

Use a ruler to join the points with straight lines.

[5]
Reveal mark scheme Mark scheme for question 4(b)(i)
(b)(ii)

Explain the effect of increasing enzyme concentration on the rate of oxygen production.

[3]
Reveal mark scheme Mark scheme for question 4(b)(ii)
(b)(iii)

Name a piece of apparatus suitable for measuring the volume of oxygen produced.

[1]
Reveal mark scheme Mark scheme for question 4(b)(iii)
(b)(iv)

Explain why it is important for the teacher to keep the volume and concentration of the hydrogen peroxide constant.

[2]
Reveal mark scheme Mark scheme for question 4(b)(iv)
(b)(v)

Name another variable the teacher should keep constant in his investigation.

[1]
Reveal mark scheme Mark scheme for question 4(b)(v)

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