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Edexcel IGCSE Maths

Topic questions Pure mathematics Quadratic equations

Quadratic equations

55 questions · 304 marks · about 6 hours

Quadratic equations questions

Edexcel 4MA1 Quadratic equations 55 questions

Paper 1F June 2025 Foundation tier, Question 23, also on the Higher paper 6 marks

(a)
Question 23, shown as an image

Show clear algebraic working.

[3]
Reveal mark scheme Mark scheme for question 23(a)
(b)(i)

Factorise y2 โ€“ 11y + 30

[2]
Reveal mark scheme Mark scheme for question 23(b)(i)
(b)(ii)

Hence solve y2 โ€“ 11y + 30 = 0

[1]
Reveal mark scheme Mark scheme for question 23(b)(ii)

Paper 1F June 2025 (R) Foundation tier, Question 23 8 marks

(a)

Expand x(x maths symbol 3)

[1]
(b)
Question 23, shown as an image
[2]
Reveal mark scheme Mark scheme for question 23(b)
(c)

Simplify a6 maths symbol a10

[1]
(d)

Simplify c30 maths symbol c12

[1]
(e)(i)

Factorise y2 maths symbol 10y maths symbol 21

[2]
Reveal mark scheme Mark scheme for question 23(e)(i)
(e)(ii)

Hence, solve y2 maths symbol 10y maths symbol 21 maths symbol 0

[1]
Reveal mark scheme Mark scheme for question 23(e)(ii)

Paper 1H June 2025 Higher tier, Question 6, also on the Foundation paper 6 marks

(a)
6 Question 6, shown as an image

Show clear algebraic working.

[3]
Reveal mark scheme Mark scheme for question 6(a)
(b)(i)

Factorise y2 โ€“ 11y + 30

[2]
Reveal mark scheme Mark scheme for question 6(b)(i)
(b)(ii)

Hence solve y2 โ€“ 11y + 30 = 0

[1]
Reveal mark scheme Mark scheme for question 6(b)(ii)

Paper 1H June 2025 (R) Higher tier, Question 8 5 marks

(a)

Simplify a6 maths symbol a10

[1]
(b)

Simplify c30 maths symbol c12

[1]
(c)(i)

Factorise y2 maths symbol 10y maths symbol 21

[2]
Reveal mark scheme Mark scheme for question 8(c)(i)
(c)(ii)

Hence, solve y2 maths symbol 10y maths symbol 21 maths symbol 0

[1]
Reveal mark scheme Mark scheme for question 8(c)(ii)

Paper 2H June 2025 Higher tier, Question 19 3 marks

19Solve the inequality 4x2 maths symbol 4x maths symbol15 maths symbol 0 Show clear algebraic working.

[3]
Reveal mark scheme Mark scheme for question 19

Paper 2H June 2025 Higher tier, Question 21 3 marks

Also involves Forming and solving equations

The diagram shows a cuboid.

Figure for question 21

The cuboid measures 3x cm by 2x cm by y cm

The volume of the cuboid is 1014cmยณ The total surface area of the cuboid is A cmยฒ

Question 21, shown as an image

You must show all the stages of your working.

[3]
Reveal mark scheme Mark scheme for question 21

Paper 1F November 2024 Foundation tier, Question 25 6 marks

(a)(i)

Factorise x2 maths symbol 5x maths symbol 24

[2]
Reveal mark scheme Mark scheme for question 25(a)(i)
(a)(ii)

Hence, solve x2 maths symbol 5x maths symbol 24 maths symbol 0

[1]
Reveal mark scheme Mark scheme for question 25(a)(ii)
(b)

Solve the inequality 3y maths symbol 5 maths symbol 7y maths symbol 10

Show clear algebraic working.

[3]
Reveal mark scheme Mark scheme for question 25(b)

Paper 1F June 2024 (R) Foundation tier, Question 22, also on the Higher paper 9 marks

(a)

Simplify g9 maths symbol g2

[1]
(b)

Expand 5k2(k3 + 4)

[2]
Reveal mark scheme Mark scheme for question 22(b)
(c)(i)

Factorise x2 maths symbol 2x maths symbol 63

[2]
Reveal mark scheme Mark scheme for question 22(c)(i)
(c)(ii)

Hence, solve x2 maths symbol 2x maths symbol 63 = 0

[1]
(d)

Solve the inequality 7 maths symbol 2y maths symbol 3y maths symbol 12

[3]
Reveal mark scheme Mark scheme for question 22(d)

Paper 1H June 2024 (R) Higher tier, Question 7, also on the Foundation paper 9 marks

(a)

Simplify g9 maths symbol g2

[1]
(b)

Expand 5k2(k3 + 4)

[2]
Reveal mark scheme Mark scheme for question 7(b)
(c)(i)

Factorise x2 maths symbol 2x maths symbol 63

[2]
Reveal mark scheme Mark scheme for question 7(c)(i)
(c)(ii)

Hence, solve x2 maths symbol 2x maths symbol 63 = 0

[1]
(d)

Solve the inequality 7 maths symbol 2y maths symbol 3y maths symbol 12

[3]
Reveal mark scheme Mark scheme for question 7(d)

Paper 1H June 2024 (R) Higher tier, Question 21 5 marks

Also involves Forming and solving equations

There are 25 counters in a bag such that

6 counters are blue x counters are orange, where x > 9 the rest of the counters are pink

Maalam takes at random two of the counters from the bag. The probability that Maalam takes one orange counter and one pink counter is fraction Calculate the probability that Maalam takes 2 pink counters from the bag. Show clear algebraic working.

[5]
Reveal mark scheme Mark scheme for question 21

Paper 1H June 2024 Higher tier, Question 24 6 marks

24A polygon has n sides, where n maths symbol 5

The interior angles of the polygon form an arithmetic sequence.

The smallest angle of the polygon is 84ยฐ The common difference of the sequence is 4ยฐ

Work out the sum of the interior angles of the polygon. Show clear algebraic working.

[6]
Reveal mark scheme Mark scheme for question 24

Paper 2H November 2023 Higher tier, Question 10 5 marks

Also involves Area and perimeter

The diagram shows a hexagon ABCDEF

Question 10, shown as an image
Figure for question 10
Question 10, shown as an image

AB = 25 cm BC = (x + 2) cm CD = 8 cm EF = 7 cm AF = (x + 6) cm

The area of hexagon ABCDEF is 258 cmยฒ

Work out the value of x

[5]
Reveal mark scheme Mark scheme for question 10

Paper 1F June 2023 Foundation tier, Question 21, also on the Higher paper 8 marks

(a)

Simplify (2c4d7)3

[2]
(b)

Find the value of 5y0 where y maths symbol 0

[1]
(c)

Factorise fully 16a2b3 + 20a3b

[2]
Reveal mark scheme Mark scheme for question 21(c)
(d)(i)

Factorise x2 + 9x โ€“ 22

[2]
Reveal mark scheme Mark scheme for question 21(d)(i)
(d)(ii)

Hence solve x2 + 9x โ€“ 22 = 0

[1]
Reveal mark scheme Mark scheme for question 21(d)(ii)

Paper 1H June 2023 Higher tier, Question 6, also on the Foundation paper 8 marks

(a)

Simplify (2c4d7)3

[2]
(b)

Find the value of 5y0 where y maths symbol 0

[1]
(c)

Factorise fully 16a2b3 + 20a3b

[2]
Reveal mark scheme Mark scheme for question 6(c)
(d)(i)

Factorise x2 + 9x โ€“ 22

[2]
Reveal mark scheme Mark scheme for question 6(d)(i)
(d)(ii)

Hence solve x2 + 9x โ€“ 22 = 0

[1]
Reveal mark scheme Mark scheme for question 6(d)(ii)

Paper 1H June 2023 Higher tier, Question 17 4 marks

The functions g and h are such that

Question 17, shown as an image

h(x) = x2 + 4 x maths symbol 0

(a)

What value of x must be excluded from any domain of g?

[1]
Reveal mark scheme Mark scheme for question 17(a)
(b)

Solve gh(x) = 1

[3]
Reveal mark scheme Mark scheme for question 17(b)

Paper 1H June 2023 (R) Higher tier, Question 20 7 marks

Also involves Completing the square

Curve C has equation y = f (x) The graph of curve C has one maximum point. The coordinates of this maximum point are (3, 5)

(a)

Write down the coordinates of the maximum point on the curve with equation

(a)(i)

y = 2f (x)

[1]
(a)(ii)

y = f (x) โ€“ 7

[1]
(a)(iii)

y = f (โ€“x)

Curve L has equation y = x2 + 7x + 20

Question 20, shown as an image
[1]
(b)

Find an equation for S Give your answer in the form y = ax2 + bx + c

[4]
Reveal mark scheme Mark scheme for question 20(b)

Paper 1H June 2023 (R) Higher tier, Question 24 5 marks

Also involves The discriminant

Given that

2n = 2x2 maths symbol 16x ร— 8

and

x maths symbol 0

find an expression for x in terms of n State any restrictions on n

[5]
Reveal mark scheme Mark scheme for question 24

Paper 1F January 2023 (R) Foundation tier, Question 23, also on the Higher paper 5 marks

(a)

Factorise fully 18c3d2 โ€“ 21c2

[2]
Reveal mark scheme Mark scheme for question 23(a)
(b)(i)

Factorise y2 โ€“ 3y โ€“ 18

[2]
Reveal mark scheme Mark scheme for question 23(b)(i)
(b)(ii)

Hence, solve y2 โ€“ 3y โ€“ 18 = 0

[1]
Reveal mark scheme Mark scheme for question 23(b)(ii)

Paper 1H January 2023 (R) Higher tier, Question 8, also on the Foundation paper 5 marks

(a)

Factorise fully 18c3d2 โ€“ 21c2

[2]
Reveal mark scheme Mark scheme for question 8(a)
(b)(i)

Factorise y2 โ€“ 3y โ€“ 18

[2]
Reveal mark scheme Mark scheme for question 8(b)(i)
(b)(ii)

Hence, solve y2 โ€“ 3y โ€“ 18 = 0

[1]
Reveal mark scheme Mark scheme for question 8(b)(ii)

Paper 2H January 2023 Higher tier, Question 22 3 marks

22Solve the inequality 6x2 + 37x maths symbol 35 Show clear algebraic working.

[3]
Reveal mark scheme Mark scheme for question 22

Paper 2H January 2023 (R) Higher tier, Question 23 5 marks

Also involves Sine and cosine rules

AEC and BED are chords of a circle.

Figure for question 23

AE = (x + 5) cm BE = xcm CE = (5x โ€“ 12) cm DE = (x + 12) cm

Angle DAE = 48ยฐ

Work out the size of angle ADE Give your answer correct to one decimal place.

[5]
Reveal mark scheme Mark scheme for question 23

Paper 1H June 2022 (R) Higher tier, Question 5 5 marks

(a)

Expand 3c3(c + 4)

[2]
Reveal mark scheme Mark scheme for question 5(a)
(b)(i)

Factorise x2 + 8x โ€“ 9

[2]
Reveal mark scheme Mark scheme for question 5(b)(i)
(b)(ii)

Hence, solve x2 + 8x โ€“9 = 0

[1]
Reveal mark scheme Mark scheme for question 5(b)(ii)

Paper 1H June 2022 Higher tier, Question 19 5 marks

Figure for question 19

OAB is a sector S of a circle with centre O and radius (r + 7) metres. Angle AOB = 45ยฐ

A circle C has radius (r โˆ’ 2) metres.

The area of sector S is twice the area of circle C

Find the value of r Show your working clearly.

[5]
Reveal mark scheme Mark scheme for question 19

Paper 1H June 2022 Higher tier, Question 23 6 marks

Also involves Forming and solving equations

23A polygon has n sides, where n maths symbol 5

When arranged in order of size, starting with the largest number, the sizes of the interior angles of the polygon, in degrees, are the terms of an arithmetic sequence.

Here are the first five terms of this sequence.

177 175 173 171 169

Find the value of n Show clear algebraic working.

[6]

Paper 1H June 2022 (R) Higher tier, Question 24 5 marks

Also involves Forming and solving equations

Elliot has x counters.

Each counter has one red face and one green face.

Elliot spreads all the counters out on a table and sees that the number of counters showing a red face is 5

Elliot then picks at random one of the counters and turns the counter over. He then picks at random a second counter and turns the counter over. The probability that there are still 5 counters showing a red face is fraction

Work out the value of x Show clear algebraic working.

[5]
Reveal mark scheme Mark scheme for question 24

Paper 2H June 2022 (R) Higher tier, Question 19 4 marks

19f(x) = x2 โ€“ 4

g(x) = 2x + 1

Solve fg(x) maths symbol 0 Show clear algebraic working.

[4]
Reveal mark scheme Mark scheme for question 19

Paper 1F January 2022 Foundation tier, Question 21, also on the Higher paper 5 marks

(a)

Solve the inequality 5x โ€“ 7 โ‰ค 2

[2]
Reveal mark scheme Mark scheme for question 21(a)
(b)(i)

Factorise y2 โ€“ 2y โ€“ 35

[2]
Reveal mark scheme Mark scheme for question 21(b)(i)
(b)(ii)

Hence, solve y2 โ€“ 2y โ€“ 35 = 0

[1]
Reveal mark scheme Mark scheme for question 21(b)(ii)

Paper 1H January 2022 Higher tier, Question 6, also on the Foundation paper 5 marks

(a)

Solve the inequality 5x โ€“ 7 โ‰ค 2

[2]
Reveal mark scheme Mark scheme for question 6(a)
(b)(i)

Factorise y2 โ€“ 2y โ€“ 35

[2]
Reveal mark scheme Mark scheme for question 6(b)(i)
(b)(ii)

Hence, solve y2 โ€“ 2y โ€“ 35 = 0

[1]
Reveal mark scheme Mark scheme for question 6(b)(ii)

Paper 1F January 2021 Foundation tier, Question 25, also on the Higher paper 5 marks

(a)

Simplify (2x3y5)4

[2]
Reveal mark scheme Mark scheme for question 25(a)
(b)(i)

Factorise x2 + 5x โ€“ 36

[2]
Reveal mark scheme Mark scheme for question 25(b)(i)
(b)(ii)

Hence, solve x2 + 5x โ€“ 36 = 0

[1]
Reveal mark scheme Mark scheme for question 25(b)(ii)

Paper 1H January 2021 Higher tier, Question 9, also on the Foundation paper 5 marks

(a)

Simplify (2x3y5)4

[2]
Reveal mark scheme Mark scheme for question 9(a)
(b)(i)

Factorise x2 + 5x โ€“ 36

[2]
Reveal mark scheme Mark scheme for question 9(b)(i)
(b)(ii)

Hence, solve x2 + 5x โ€“ 36 = 0

[1]
Reveal mark scheme Mark scheme for question 9(b)(ii)

Paper 2H January 2021 (R) Higher tier, Question 21 6 marks

Also involves Probability

A bag contains n beads. 6 of the beads are red and the rest are blue.

Ravi is going to take at random 2 beads from the bag. The probability that the 2 beads will be of the same colour is fraction

Using algebra, and showing each stage of your working, calculate the value of n.

[6]
Reveal mark scheme Mark scheme for question 21

Paper 1F November 2020 Foundation tier, Question 20, also on the Higher paper 8 marks

(a)

Solve 5(4 โ€“ x) = 7 โ€“ 3 x Show clear algebraic working.

[3]
Reveal mark scheme Mark scheme for question 20(a)
(b)

Factorise fully 16m3g3 + 24m2g5

[2]
Reveal mark scheme Mark scheme for question 20(b)
(c)(i)

Factorise y2 โ€“ 2y โ€“ 48

[2]
Reveal mark scheme Mark scheme for question 20(c)(i)
(c)(ii)

Hence, solve y2 โ€“ 2y โ€“ 48 = 0

[1]
Reveal mark scheme Mark scheme for question 20(c)(ii)

Paper 1H November 2020 Higher tier, Question 7, also on the Foundation paper 8 marks

(a)

Solve 5(4 โ€“ x) = 7 โ€“ 3x Show clear algebraic working.

[3]
Reveal mark scheme Mark scheme for question 7(a)
(b)

Factorise fully 16m3g3 + 24m2g5

[2]
Reveal mark scheme Mark scheme for question 7(b)
(c)(i)

Factorise y2 โ€“ 2y โ€“ 48

[2]
Reveal mark scheme Mark scheme for question 7(c)(i)
(c)(ii)

Hence, solve y2 โ€“ 2y โ€“ 48 = 0

[1]

Paper 1H November 2020 (R) Higher tier, Question 23 4 marks

In a bag, there are only

3 blue beads 4 white beads and x orange beads.

Jean is going to take at random two beads from the bag. The probability that Jean will take two beads of the same colour is fraction Find the total number of beads in the bag. Show clear algebraic working.

[4]
Reveal mark scheme Mark scheme for question 23

Paper 2H November 2020 Higher tier, Question 17 5 marks

The diagram shows a rectangle.

Figure for question 17

The area of the rectangle is Acm2

Given that A maths symbol 3x + 27 find the range of possible values for x.

[5]
Reveal mark scheme Mark scheme for question 17

Paper 2H November 2020 Higher tier, Question 20 5 marks

Also involves Probability ยท Forming and solving equations

A bag contains X counters.

There are only red counters and blue counters in the bag.

There are 4 more blue counters than red counters in the bag.

Finty takes at random 2 counters from the bag. The probability that Finty takes 2 blue counters from the bag is fraction Work out the value of X. Show clear algebraic working.

[5]
Reveal mark scheme Mark scheme for question 20

Paper 1H January 2020 Higher tier, Question 20 4 marks

Also involves Quadratic graphs

Figure for question 20
[4]
Reveal mark scheme Mark scheme for question 20
(i)

the coordinates of any points of intersection of C with the coordinate axes,

(ii)

the coordinates of the turning point.

Figure for question 20

Paper 1H January 2020 (R) Higher tier, Question 23 6 marks

Also involves Differentiation

A particle moves along a straight line. The fixed point O lies on this line. The displacement of the particle from O at time t seconds, t maths symbol0, is s metres where

At time T seconds the velocity of P is V m/s where V maths symbolโˆ’5 Find an expression for T in terms of V.

Question 23, shown as an image
[6]
Reveal mark scheme Mark scheme for question 23

Paper 2F January 2020 Foundation tier, Question 23 5 marks

(a)

Solve the inequality 2x + 7 maths symbol 4

[2]
Reveal mark scheme Mark scheme for question 23(a)
(b)

Solve x2 โ€“ 3x โ€“ 40 = 0 Show clear algebraic working.

[3]
Reveal mark scheme Mark scheme for question 23(b)

Paper 2H January 2020 (R) Higher tier, Question 19 6 marks

(a)
Question 19, shown as an image

Show clear algebraic working.

[3]
Reveal mark scheme Mark scheme for question 19(a)
(b)

Solve the inequality 5y2 โ€“ 17y maths symbol 40

[3]
Reveal mark scheme Mark scheme for question 19(b)

Paper 2H June 2019 Higher tier, Question 23 5 marks

Also involves Conditional probability

Boris has a bag that only contains red sweets and green sweets.

Boris takes at random 2 sweets from the bag. The probability that Boris takes exactly 1 red sweet from the bag is fraction Originally there were 3 red sweets in the bag.

Work out how many green sweets there were originally in the bag. Show your working clearly.

[5]
Reveal mark scheme Mark scheme for question 23

Paper 2H June 2019 (R) Higher tier, Question 24 5 marks

A box contains marbles.

4 of the marbles are red. The rest of the marbles are yellow.

Antonia takes at random a marble from the box and does not replace it. Sergio then takes at random a marble from the box.

The probability that Antonia and Sergio both take a yellow marble is 0.7

Work out how many marbles were originally in the box. Show your working clearly.

[5]
Reveal mark scheme Mark scheme for question 24

Paper 1F June 2018 Foundation tier, Question 16 9 marks

(a)

Simplify y5 ร— y9

[1]
(b)

Simplify (2m3)4

[2]
(c)

Solve 5(x + 3) = 3xmaths symbol Show clear algebraic working.

[3]
Reveal mark scheme Mark scheme for question 16(c)
(d)(i)

Factorise x2 + 2xmaths symbol

[2]
Reveal mark scheme Mark scheme for question 16(d)(i)
(d)(ii)

Hence, solve x2 + 2xmaths symbol

[1]

Paper 1H June 2018 Higher tier, Question 3 9 marks

(a)

Simplify y5maths symboly9

[1]
(b)

Simplify (2m3)4

[2]
(c)

Solve 5(x + 3) = 3 x โ€“ 4 Show clear algebraic working.

[3]
Reveal mark scheme Mark scheme for question 3(c)
(d)(i)

Factorise x2 + 2x โ€“ 24

[2]
Reveal mark scheme Mark scheme for question 3(d)(i)
(d)(ii)

Hence, solve x2 + 2x โ€“ 24 = 0

[1]

Paper 1H June 2018 Higher tier, Question 11 6 marks

(a)

Expand and simplify (2 x โ€“ 1)(x + 3)(x โ€“ 5)

[3]
Reveal mark scheme Mark scheme for question 11(a)
(b)

Solve 3x2 + 6x โ€“ 5 = 0 Show your working clearly. Give your solutions correct to 3 significant figures.

[3]
Reveal mark scheme Mark scheme for question 11(b)

Paper 1H June 2018 (R) Higher tier, Question 16 7 marks

Figure for question 16

The points B, C, Y and X lie on a circle.

AXY and ABC are straight lines.

AX = 12 cm XY = x cm AB = x cm BC = 4 cm

(a)

Show that x2maths symbolxmaths symbol

[3]
Reveal mark scheme Mark scheme for question 16(a)
(b)

Find the length of AC. Show your working clearly. Give your answer correct to 3 significant figures.

[4]
Reveal mark scheme Mark scheme for question 16(b)

Paper 2H June 2018 (R) Higher tier, Question 24 6 marks

Also involves Coordinate geometry

(a)

Express 7 โ€“ 4x โ€“ x2 in the form p โ€“ (x + q)2 where p and q are constants.

[2]
Reveal mark scheme Mark scheme for question 24(a)
(b)

Use your answer to part (a) to solve the equation 7 โ€“ 4(y + 3) โ€“ (y + 3)2 = 0

Question 24, shown as an image
[3]
Reveal mark scheme Mark scheme for question 24(b)
(c)

The curve C has equation y = 3 โ€“ 5(x + 1)2 The point A is the maximum point on C.

Write down the coordinates of A.

[1]
Reveal mark scheme Mark scheme for question 24(c)

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