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OCR GCSE Maths

Topic questions Pure mathematics Iteration

Iteration

8 questions · 55 marks · about 50 minutes

Iteration questions

OCR J560 Iteration 8 questions

Paper 6 June 2025 Higher tier, Question 24 7 marks

Also involves Locating roots by change of sign · Rounding

(a)

Show that the equation x4 + 3x2 - 2x - 5 = 0 has a solution between x = 1 and x = 2.

[3]
Reveal mark scheme Mark scheme for question 24(a)
(b)

Find this solution correct to 1 decimal place. You must show calculations to support your answer.

[4]
Reveal mark scheme Mark scheme for question 24(b)

Paper 4 November 2024 Higher tier, Question 20 8 marks

Also involves Locating roots by change of sign · Rounding · Substitution into formulae

(a)

Show that the equation x3 - 3x - 4 = 0 has a solution between x = 2 and x = 3.

[3]
Reveal mark scheme Mark scheme for question 20(a)
(b)

Use x = 2.5 to find a smaller interval for the solution to x3 - 3x - 4 = 0. You must show your working.

[2]
Reveal mark scheme Mark scheme for question 20(b)
(c)

Find this solution correct to 1 decimal place. You must show your working.

[3]
Reveal mark scheme Mark scheme for question 20(c)

Paper 6 November 2023 Higher tier, Question 16 6 marks

Also involves Locating roots by change of sign · Substitution into formulae

The graph of y = x5 - 70x - 150 is sketched below. The root of the equation x5 - 70x - 150 = 0 is p.

Figure for question 16
(a)

Show that 3 < p < 4.

[3]
Reveal mark scheme Mark scheme for question 16(a)
(b)

Find a smaller interval that contains the value of p. You must show calculations to support your answer.

[3]
Reveal mark scheme Mark scheme for question 16(b)

Paper 4 June 2023 Higher tier, Question 18 7 marks

Also involves Locating roots by change of sign · Rounding · Substitution into formulae

(a)

Show that the equation x3 + x2 - 5 = 0 has a solution between x = 1 and x = 2.

[3]
Reveal mark scheme Mark scheme for question 18(a)
(b)

Find this solution correct to 1 decimal place. You must show calculations to support your answer.

[4]
Reveal mark scheme Mark scheme for question 18(b)

Paper 5 June 2022 Higher tier, Question 13 7 marks

Also involves Completing the square · Locating roots by change of sign

The graph of y = x2 + 6x - 2 is shown below. The roots of the equation x2 + 6x - 2 = 0 are at p and q.

Figure for question 13
(a)(i)

Calculate y when x = 1.

[1]
Reveal mark scheme Mark scheme for question 13(a)(i)
(a)(ii)

Without solving the equation, explain why q must lie between 0 and 1.

[2]
Reveal mark scheme Mark scheme for question 13(a)(ii)
(a)(iii)

Explain why using a method of iteration is not the most appropriate way of finding a solution to this equation.

[1]
Reveal mark scheme Mark scheme for question 13(a)(iii)
(b)
Question 13, shown as an image
Question 13, shown as an image
[3]
Reveal mark scheme Mark scheme for question 13(b)

Paper 6 November 2021 Higher tier, Question 15 7 marks

Also involves Locating roots by change of sign · Using a calculator

(a)

Show that the equation x3 - 5x - 1 = 0 has a solution between x = 2 and x = 3.

[3]
Reveal mark scheme Mark scheme for question 15(a)
(b)

Find this solution correct to 1 decimal place. You must show your working.

[4]
Reveal mark scheme Mark scheme for question 15(b)

Paper 6 June 2019 Higher tier, Question 20 7 marks

Also involves Locating roots by change of sign · Rounding

(a)

Show that the equation x4 - x2 - 9 = 0 has a solution between x = 1 and x = 2.

[3]
Reveal mark scheme Mark scheme for question 20(a)
(b)

Find this solution correct to 1 decimal place. Show your working.

[4]
Reveal mark scheme Mark scheme for question 20(b)

Paper 6 June 2018 Higher tier, Question 9 6 marks

The graph of y = x3 - 7x - 12 is shown below. The root of the equation x3 - 7x - 12 = 0 is p.

Figure for question 9
(a)

Calculate y when x = 3.

[1]
Reveal mark scheme Mark scheme for question 9(a)
(b)

Show that 3 < p < 4.

[2]
Reveal mark scheme Mark scheme for question 9(b)
(c)

Find a smaller interval that contains the value of p. You must show calculations to support your answer.

[3]
Reveal mark scheme Mark scheme for question 9(c)

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