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OCR GCSE Maths

Topic questions Pure mathematics Rearranging formulae

Rearranging formulae

31 questions · 135 marks · about 2 hours

Rearranging formulae questions

OCR J560 Rearranging formulae 31 questions

Paper 2 June 2025 Foundation tier, Question 12 4 marks

(a)

A straight line has equation y = 5 x + 2.

(a)(i)

Write down the gradient of the line.

[1]
Reveal mark scheme Mark scheme for question 12(a)(i)
(a)(ii)

Find the value of y when x = 7.

[1]
Reveal mark scheme Mark scheme for question 12(a)(ii)
(b)

Make x the subject of y = 5 x + 2.

[2]
Reveal mark scheme Mark scheme for question 12(b)

Paper 3 June 2025 Foundation tier, Question 21 4 marks

The diagram shows a sphere with radius r cm.

Figure for question 21

The sphere has a circumference of 50 cm.

Work out the surface area of the sphere.

[The surface area, A, of a sphere with radius r is A = 4πr2.]

[4]
Reveal mark scheme Mark scheme for question 21

Paper 6 June 2025 Higher tier, Question 10 5 marks

Also involves Powers and roots · Area and perimeter

The diagram shows a sphere with radius 3 cm and a cube with side length x cm.

Figure for question 10

The surface area of the sphere is equal to the surface area of the cube.

Work out the side length, x cm, of the cube. You must show your working.

[The surface area, A, of a sphere with radius r is A = 4πr2.]

[5]
Reveal mark scheme Mark scheme for question 10

Paper 3 November 2024 Foundation tier, Question 7 2 marks

(a)

Rearrange this formula to make x the subject.

y = x + 3

[1]
Reveal mark scheme Mark scheme for question 7(a)
(b)

Rearrange this formula to make w the subject.

p = 3 w

[1]
Reveal mark scheme Mark scheme for question 7(b)

Paper 5 June 2024 Higher tier, Question 18 4 marks

Also involves Indices

A sphere has radius x cm. A cone has radius R cm and height 2 R cm.

The volume of the sphere is equal to the volume of the cone.

Write R in terms of x.

Question 18, shown as an image
[4]
Reveal mark scheme Mark scheme for question 18

Paper 6 June 2024 Higher tier, Question 5 9 marks

The diagram shows a regular pentagon made using ten congruent right-angled triangles. The length of one side of the pentagon is 12 cm.

Figure for question 5
(a)

Show that the area of the pentagon is 247.75 cm2, correct to 2 decimal places.

[6]
Reveal mark scheme Mark scheme for question 5(a)
(b)

The regular pentagon is the base of a pyramid.

The pyramid has volume 450 cm3. The perpendicular height of the pyramid is h cm.

Calculate the value of h. [The volume of a pyramid is fraction × area of base × perpendicular height.]

[3]
Reveal mark scheme Mark scheme for question 5(b)

Paper 2 November 2023 Foundation tier, Question 13 5 marks

(a)

Work out.

34

[2]
Reveal mark scheme Mark scheme for question 13(a)
(b)

Simplify. 5x2 x

[1]
Reveal mark scheme Mark scheme for question 13(b)
(c)

Rearrange this formula to make x the subject.

Question 13, shown as an image
[2]
Reveal mark scheme Mark scheme for question 13(c)

Paper 3 November 2023 Foundation tier, Question 14 3 marks

(a)

Show that the formula v = u + at can be rearranged to a = fraction

[1]
Reveal mark scheme Mark scheme for question 14(a)
(b)

Use the formula

Question 14, shown as an image

to find the acceleration, am/s2, when a particle takes 4 seconds to increase from an initial velocity of 3 m/s to a final velocity of 9 m/s.

[2]
Reveal mark scheme Mark scheme for question 14(b)

Paper 1 June 2023 Foundation tier, Question 10 2 marks

(a)

Finley is asked to solve the equation 5 x + 4 = 19.

Finley’s working is shown below.

Figure for question 10

Write down the error that Finley has made.

[1]
Reveal mark scheme Mark scheme for question 10(a)
(b)

Charlie is asked to use the formula

v = u + at

to find the initial velocity, when

• the acceleration is 5 m/s2

• the final velocity is 29 m/s

• the time is 3 seconds.

Charlie’s working is shown below.

Figure for question 10

Write down the error that Charlie has made.

[1]
Reveal mark scheme Mark scheme for question 10(b)

Paper 6 June 2023 Higher tier, Question 2 5 marks

Also involves Substitution into formulae · Converting between units

(a)

Rearrange this formula to make u the subject.

Question 2, shown as an image
[2]
Reveal mark scheme Mark scheme for question 2(a)
(b)

A rocket accelerates at 90 m / s2 and travels 270 km. The rocket’s final velocity is 8000 m / s.

Using part (a), or otherwise, calculate the rocket’s initial velocity in m / s.

[3]
Reveal mark scheme Mark scheme for question 2(b)

Paper 6 June 2023 Higher tier, Question 11 5 marks

The diagram shows a quadrilateral, PQRS.

Figure for question 11

PS = 10 cm. Angle QPS = Angle PSR = 90°.

SR is 6 cm longer than PQ. The area of quadrilateral PQRS is A cm2.

Write a simplified expression for the length PQ in terms of A. You must show your working.

[5]
Reveal mark scheme Mark scheme for question 11

Paper 1 November 2022 Foundation tier, Question 16 4 marks

(a)

Rearrange this formula to make d the subject.

f = 5 d + 4

[2]
Reveal mark scheme Mark scheme for question 16(a)
(b)

Use the formula

v = u + at

to find the final velocity, when

• the initial velocity is 5 m/s

• the acceleration is 7.5 m/s2

• the time is 6 seconds.

[2]
Reveal mark scheme Mark scheme for question 16(b)

Paper 4 November 2022 Higher tier, Question 9 4 marks

Here are two pieces of work.

For each one, describe the error in the method and give the correct answer.

(a)
Figure for question 9
[2]
Reveal mark scheme Mark scheme for question 9(a)
(b)
Figure for question 9
[2]
Reveal mark scheme Mark scheme for question 9(b)

Paper 4 November 2022 Higher tier, Question 12 6 marks

Also involves Forming and solving equations

The diagram shows a sphere and a cone.

Figure for question 12

The sphere has radius 4 cm. The cone has radius 15 cm and height 30 cm.

The sphere is completely filled with water. The same amount of water is poured into the cone.

Work out the depth, d cm, of the water in the cone. You must show your working. [The volume V of a sphere with radius r is V = fraction r3. The volume V of a cone with radius r and height h is V = fraction r2h.]

[6]
Reveal mark scheme Mark scheme for question 12

Paper 6 November 2022 Higher tier, Question 13 5 marks

(a)

Here is a function.

Figure for question 13

When the input is 6, the output is 18.

Find the value of t.

[3]
Reveal mark scheme Mark scheme for question 13(a)
(b)

Here is another function. When the input is x, the output is y.

Figure for question 13

Write an algebraic expression for x in terms of y.

[2]
Reveal mark scheme Mark scheme for question 13(b)

Paper 2 June 2022 Foundation tier, Question 7 3 marks

(a)

Multiply out.

5 (x + 2)

[1]
Reveal mark scheme Mark scheme for question 7(a)
(b)

Rearrange this formula to make r the subject.

p = 3 r - 5

[2]
Reveal mark scheme Mark scheme for question 7(b)

Paper 5 June 2022 Higher tier, Question 7 7 marks

(a)

A car accelerates at 4.06 m/s2 for 10.1 seconds from an initial velocity of 2.93 m/s.

Harper rounds each value to 1 significant figure. Harper uses the rounded values and the formula

Question 7, shown as an image

to estimate the distance travelled in the 10.1 seconds. Harper’s answer is 430 metres.

Using Harper’s method, show that their answer is wrong.

[4]
Reveal mark scheme Mark scheme for question 7(a)
(b)

Rearrange this formula to make t the subject.

Question 7, shown as an image
[3]
Reveal mark scheme Mark scheme for question 7(b)

Paper 3 November 2021 Foundation tier, Question 12 2 marks

Rearrange this formula to make w the subject.

P = 2 w + 2 h

[2]
Reveal mark scheme Mark scheme for question 12

Paper 5 November 2021 Higher tier, Question 20 4 marks

x2 - 2y = 5 and 4y + z = 7.

Write z in terms of x. Give your answer in its simplest form.

[4]
Reveal mark scheme Mark scheme for question 20

Paper 1 November 2020 Foundation tier, Question 12 4 marks

(a)

A train is travelling with a velocity of 15 m / s. It then accelerates at 0.5 m / s2 for 6 seconds.

Use the formula v = u + at to calculate the velocity of the train after the 6 seconds.

[2]
Reveal mark scheme Mark scheme for question 12(a)
(b)

Rearrange the formula v = u + at to make a the subject.

[2]
Reveal mark scheme Mark scheme for question 12(b)

Paper 2 June 2019 Foundation tier, Question 10 6 marks

(a)

Simplify fully.

(a)(i)

3 t + 5 u - 2 t + 3 u

[2]
Reveal mark scheme Mark scheme for question 10(a)(i)
(a)(ii)

6a × 2a2

[2]
Reveal mark scheme Mark scheme for question 10(a)(ii)
(b)

Make x the subject of the formula y = x2 - 1.

[2]
Reveal mark scheme Mark scheme for question 10(b)

Paper 2 November 2018 Foundation tier, Question 9 2 marks

(a)

Rearrange this formula to make x the subject.

y = x - 2

[1]
Reveal mark scheme Mark scheme for question 9(a)
(b)

Rearrange this formula to make d the subject.

C = π d

[1]
Reveal mark scheme Mark scheme for question 9(b)

Paper 3 June 2018 Foundation tier, Question 6 3 marks

You are given that 5 y = 4 x.

(a)

Find the value of y when x = 10.

[2]
Reveal mark scheme Mark scheme for question 6(a)
(b)

Write y in terms of x.

[1]
Reveal mark scheme Mark scheme for question 6(b)

Paper 1 November 2017 Foundation tier, Question 6 7 marks

(a)

Simplify.

(a)(i)

2 p + 5 p - 3 p

[1]
Reveal mark scheme Mark scheme for question 6(a)(i)
(a)(ii)

6 j + 3 k - j - 5 k

[2]
Reveal mark scheme Mark scheme for question 6(a)(ii)
(b)

Find the value of 10 h + 6 t when h = 12 and t = 4.

[2]
Reveal mark scheme Mark scheme for question 6(b)
(c)

Rearrange this formula to make d the subject.

e = f - 7 d

[2]
Reveal mark scheme Mark scheme for question 6(c)

Paper 6 November 2017 Higher tier, Question 1 4 marks

Question 1, shown as an image
(a)

Calculate s when u = 5, t = 10 and a = 3.

[2]
Reveal mark scheme Mark scheme for question 1(a)
(b)

Make a the subject of the formula.

[2]
Reveal mark scheme Mark scheme for question 1(b)

Paper 2 June 2017 Foundation tier, Question 17, also on the Higher paper 5 marks

(a)

Rearrange the equation to make x the subject.

y = 7 x - 3

[2]
Reveal mark scheme Mark scheme for question 17(a)
(b)

Factorise.

(b)(i)

x2 - xy

[1]
Reveal mark scheme Mark scheme for question 17(b)(i)
(b)(ii)

x2 + 8x + 12

[2]
Reveal mark scheme Mark scheme for question 17(b)(ii)

Paper 3 June 2017 Foundation tier, Question 5 5 marks

(a)

Find the value of 3 a + 2 b when a = 16 and b = 7.

[2]
Reveal mark scheme Mark scheme for question 5(a)
(b)

Use the formula

v = u + at

to find the final velocity, when

• the initial velocity is 2 m/s

• the acceleration is 1.5 m/s2

• the time is 6 seconds.

[2]
Reveal mark scheme Mark scheme for question 5(b)
(c)

Make d the subject of this formula.

c = 7 d

[1]
Reveal mark scheme Mark scheme for question 5(c)

Paper 5 June 2017 Higher tier, Question 5, also on the Foundation paper 5 marks

(a)

Rearrange the equation to make x the subject.

y = 7 x - 3

[2]
Reveal mark scheme Mark scheme for question 5(a)
(b)

Factorise.

(b)(i)

x2 - xy

[1]
Reveal mark scheme Mark scheme for question 5(b)(i)
(b)(ii)

x2 + 8x + 12

[2]
Reveal mark scheme Mark scheme for question 5(b)(ii)

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