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OCR GCSE Maths

Topic questions Pure mathematics Quadratic equations

Quadratic equations

38 questions · 217 marks · about 3.5 hours

Quadratic equations questions

OCR J560 Quadratic equations 38 questions

Paper 3 June 2025 Foundation tier, Question 26, also on the Higher paper 6 marks

(a)

Solve.

8 x - 11 = 6 x + 3

[3]
Reveal mark scheme Mark scheme for question 26(a)
(b)

Solve by factorising.

x2 + 15x - 16 = 0

[3]
Reveal mark scheme Mark scheme for question 26(b)

Paper 6 June 2025 Higher tier, Question 9, also on the Foundation paper 6 marks

(a)

Solve.

8 x - 11 = 6 x + 3

[3]
Reveal mark scheme Mark scheme for question 9(a)
(b)

Solve by factorising.

x2 + 15x - 16 = 0

[3]
Reveal mark scheme Mark scheme for question 9(b)

Paper 2 June 2024 Foundation tier, Question 27 8 marks

Also involves Area and perimeter

In this question, all lengths are in centimetres.

Figure for question 27

The area of the rectangle is 70 cm2.

(a)

Show that x2 + 5x - 84 = 0.

[4]
Reveal mark scheme Mark scheme for question 27(a)
(b)(i)

Solve by factorising.

Question 27, shown as an image

(b)(i) x =........ or x =........

[3]
Reveal mark scheme Mark scheme for question 27(b)(i)
(b)(ii)

Find the length of the longer side of the rectangle.

[1]
Reveal mark scheme Mark scheme for question 27(b)(ii)

Paper 4 June 2024 Higher tier, Question 15 10 marks

(a)

Solve by factorisation.

Question 15, shown as an image
[3]
Reveal mark scheme Mark scheme for question 15(a)
(b)

Write x2 + 8x + 11 in the form (x + a)2 - b.

[3]
Reveal mark scheme Mark scheme for question 15(b)
(c)(i)

Write down the coordinates of the turning point of the graph y = (x - 3)2 + 8.

[2]
Reveal mark scheme Mark scheme for question 15(c)(i)
(c)(ii)

Describe the single transformation which maps the graph of y = x2 onto the graph of y = (x - 3)2 + 8.

[2]
Reveal mark scheme Mark scheme for question 15(c)(ii)

Paper 6 June 2024 Higher tier, Question 14 5 marks

Also involves Coordinates

The sketch shows the coordinate axes and the point (0, 10).

Figure for question 14

The distance from the point (0, 10) to a point (12, t) is 12.5 units.

Work out the two possible values of t. You must show your working and you may use the sketch to help.

[5]
Reveal mark scheme Mark scheme for question 14

Paper 1 November 2023 Foundation tier, Question 16 7 marks

(a)

Multiply out.

5 a (2 - a)

[2]
(b)

Solve.

5 x + 9 > 12

[2]
Reveal mark scheme Mark scheme for question 16(b)
(c)

Solve by factorising.

x2 + 7x + 12 = 0

[3]
Reveal mark scheme Mark scheme for question 16(c)

Paper 4 November 2023 Higher tier, Question 18 4 marks

Solve this quadratic equation by factorisation.

2x2 - 6x - 24 = 5x - 3

[4]
Reveal mark scheme Mark scheme for question 18

Paper 6 November 2023 Higher tier, Question 15 5 marks

Also involves Rounding

(a)

Sasha and Taylor are asked to find how many solutions the equation 5(x + 2)2 = 45 has.

Here is Sasha’s answer.
Here is Taylor’s answer.

Figure for question 15

Decide who is correct, Sasha or Taylor, and give the reason for your decision.

........ is correct because........

[1]
Reveal mark scheme Mark scheme for question 15(a)
(b)

Solve this equation algebraically. Give your answers correct to 2 decimal places. You must show your working.

x2 - 5x + 3 = 0

[4]
Reveal mark scheme Mark scheme for question 15(b)

Paper 2 June 2023 Foundation tier, Question 20, also on the Higher paper 3 marks

Also involves Volume and surface area

The diagram shows a prism of length 10 cm.

Figure for question 20

The cross-section of the prism is a right-angled triangle. The base, b cm, is 2 cm longer than the height, h cm. The volume of the prism is 240 cm3.

A student is explaining how they worked out the value of b.

They say

b is 6 because that means h is 4 and 6 × 4 × 10 = 240.

Describe the student’s error and find the correct value of b.

[3]
Reveal mark scheme Mark scheme for question 20

Paper 2 June 2023 Foundation tier, Question 23 3 marks

(a)

Factorise x2 + 10x + 24.

[2]
Reveal mark scheme Mark scheme for question 23(a)
(b)

Write down the solutions to x2 + 10x + 24 = 0.

[1]
Reveal mark scheme Mark scheme for question 23(b)

Paper 4 June 2023 Higher tier, Question 13 2 marks

Here are two pieces of work.

Each shows a question and the first line of an incorrect solution.

For each part, describe the error made in the first line of the solution. You do not need to complete the solution.

(a)
Figure for question 13
[1]
Reveal mark scheme Mark scheme for question 13(a)
(b)
Figure for question 13
[1]
Reveal mark scheme Mark scheme for question 13(b)

Paper 5 June 2023 Higher tier, Question 4, also on the Foundation paper 3 marks

Also involves Forming and solving equations

The diagram shows a prism of length 10 cm.

Figure for question 4

The cross-section of the prism is a right-angled triangle. The base, b cm, is 2 cm longer than the height, h cm. The volume of the prism is 240 cm3.

A student is explaining how they worked out the value of b.

They say

b is 6 because that means h is 4 and 6 × 4 × 10 = 240.

Describe the student’s error and find the correct value of b.

[3]
Reveal mark scheme Mark scheme for question 4

Paper 5 June 2023 Higher tier, Question 15 9 marks

(a)

Factorise.

9x2 - 4

[2]
Reveal mark scheme Mark scheme for question 15(a)
(b)

Solve by factorisation.

3x2 - 2x - 8 = 0

[3]
Reveal mark scheme Mark scheme for question 15(b)
(c)

Solve.

Question 15, shown as an image
[4]
Reveal mark scheme Mark scheme for question 15(c)

Paper 5 November 2022 Higher tier, Question 18 8 marks

(a)

By factorising, find the roots of y = x2 + 18x + 77.

(a) x =........ and x =........

[3]
Reveal mark scheme Mark scheme for question 18(a)
(b)(i)

Write y = x2 + 18x + 77 in the form y = (x + a)2 - b.

[3]
Reveal mark scheme Mark scheme for question 18(b)(i)
(b)(ii)

Write down the coordinates of the turning point of the graph of y = x2 + 18x + 77.

[2]
Reveal mark scheme Mark scheme for question 18(b)(ii)

Paper 2 June 2022 Foundation tier, Question 21 5 marks

(a)
Figure for question 21

Darcy says that the statement in the box is an equation. Ellis says that the statement in the box is an identity. One of them is correct.

Explain which one of Darcy or Ellis is correct.

........ is correct because........

[2]
Reveal mark scheme Mark scheme for question 21(a)
(b)

Solve by factorising.

x2 + 4x - 12 = 0

[3]
Reveal mark scheme Mark scheme for question 21(b)

Paper 5 June 2022 Higher tier, Question 13 7 marks

Also involves Completing the square · Locating roots by change of sign

The graph of y = x2 + 6x - 2 is shown below. The roots of the equation x2 + 6x - 2 = 0 are at p and q.

Figure for question 13
(a)(i)

Calculate y when x = 1.

[1]
Reveal mark scheme Mark scheme for question 13(a)(i)
(a)(ii)

Without solving the equation, explain why q must lie between 0 and 1.

[2]
Reveal mark scheme Mark scheme for question 13(a)(ii)
(a)(iii)

Explain why using a method of iteration is not the most appropriate way of finding a solution to this equation.

[1]
Reveal mark scheme Mark scheme for question 13(a)(iii)
(b)
Question 13, shown as an image
Question 13, shown as an image
[3]
Reveal mark scheme Mark scheme for question 13(b)

Paper 5 June 2022 Higher tier, Question 17 6 marks

Charlie is making some wooden frames. Charlie has a strip of wood 1.6 m long and 2 cm wide.

Not to scale

Question 17, shown as an image

Each frame will be made from four pieces of wood cut from the strip to form a rectangle, as shown below.

Figure for question 17
Question 17, shown as an image

The width of each frame is x cm. The length of each frame is 2 x cm. The area enclosed by each frame must be 96 cm2.

Work out the maximum number of frames Charlie can make from the 1.6 m length of wood. You must show your working.

[6]
Reveal mark scheme Mark scheme for question 17

Paper 6 June 2022 Higher tier, Question 19 5 marks

Also involves Surds

(a)

Write x2 - 8x + 9 in the form maths symbolx - amaths symbol2 - b.

[3]
Reveal mark scheme Mark scheme for question 19(a)
(b)

Use your answer from part (a) to solve.

x2 - 8x + 9 = 0

Give your answers in exact form. You must show your working.

[2]
Reveal mark scheme Mark scheme for question 19(b)

Paper 3 November 2021 Foundation tier, Question 22 9 marks

Also involves Area and perimeter

In this question, all measurements are in centimetres.

Figure for question 22

The square and the rectangle have the same area.

(a)

Show that x2 - 8x - 20 = 0.

[3]
Reveal mark scheme Mark scheme for question 22(a)
(b)

Solve x2 - 8x - 20 = 0.

[3]
Reveal mark scheme Mark scheme for question 22(b)
(c)

Explain why one of the answers in part (b) is not possible in the context of the question.

[1]
Reveal mark scheme Mark scheme for question 22(c)
(d)

Write down the following.

(d)(i)

The area of the square.

[1]
Reveal mark scheme Mark scheme for question 22(d)(i)
(d)(ii)

The length of the rectangle.

[1]
Reveal mark scheme Mark scheme for question 22(d)(ii)

Paper 6 November 2021 Higher tier, Question 16 9 marks

The following kinematics formulas may be used in this question.

v = u + at

Question 16, shown as an image

v2 = u2 + 2as

The initial velocity of a particle is 20 m/s. The acceleration of the particle is -8 m/s2. After t seconds, the particle has travelled 25 m.

(a)

Show that 4t2 - 20t + 25 = 0.

[3]
Reveal mark scheme Mark scheme for question 16(a)
(b)

Solve 4t2 - 20t + 25 = 0.

[3]
Reveal mark scheme Mark scheme for question 16(b)
(c)

Show that the particle is stationary when it has travelled 25 m.

[3]
Reveal mark scheme Mark scheme for question 16(c)

Paper 1 November 2020 Foundation tier, Question 15 7 marks

(a)

Solve.

Question 15, shown as an image
[2]
Reveal mark scheme Mark scheme for question 15(a)
(b)

Factorise.

5a2 - 10a

[2]
Reveal mark scheme Mark scheme for question 15(b)
(c)

Solve by factorising.

x2 + 15x + 56 = 0

[3]
Reveal mark scheme Mark scheme for question 15(c)

Paper 4 November 2020 Higher tier, Question 15 6 marks

Here are two pieces of work.

For each one, describe the error made and give the complete correct solution.

(a)
Figure for question 15

Correct solution:

[3]
Reveal mark scheme Mark scheme for question 15(a)
(b)
Figure for question 15

Correct solution:

[3]
Reveal mark scheme Mark scheme for question 15(b)

Paper 4 June 2019 Higher tier, Question 19 4 marks

Solve this equation algebraically. Give your solutions correct to 2 decimal places.

Question 19, shown as an image
[4]
Reveal mark scheme Mark scheme for question 19

Paper 2 November 2018 Foundation tier, Question 15 11 marks

(a)

Multiply out.

Question 15, shown as an image

Give your answer in its simplest form.

[3]
Reveal mark scheme Mark scheme for question 15(a)
(b)

3maths symbol2x + dmaths symbol + cmaths symbolx + 5maths symbol = 10x + 17

Work out the value of c and the value of d.

[5]
Reveal mark scheme Mark scheme for question 15(b)
(c)

Solve by factorising.

Question 15, shown as an image
[3]
Reveal mark scheme Mark scheme for question 15(c)

Paper 5 November 2018 Higher tier, Question 18 10 marks

Also involves Surds

(a)(i)

Write x2 + 4x - 16 in the form (x + a)2 - b.

[3]
Reveal mark scheme Mark scheme for question 18(a)(i)
(a)(ii)

Solve the equation x2 + 4x - 16 = 0. Give your answers in surd form as simply as possible.

(ii) x =........ or x =........

[4]
Reveal mark scheme Mark scheme for question 18(a)(ii)
(b)

Sketch the graph of y = x2 + 4x - 16, showing clearly the coordinates of any turning points.

Figure for question 18
[3]
Reveal mark scheme Mark scheme for question 18(b)

Paper 6 November 2018 Higher tier, Question 12 6 marks

In the diagram, the square and the trapezium share a common side of length x cm.

Figure for question 12

The area of the square is equal to the area of the trapezium.

Work out the value of x.

[6]
Reveal mark scheme Mark scheme for question 12

Paper 1 June 2018 Foundation tier, Question 7 7 marks

(a)

Solve.

(a)(i)

4 x = 56

[1]
Reveal mark scheme Mark scheme for question 7(a)(i)
(a)(ii)
Question 7, shown as an image
[1]
Reveal mark scheme Mark scheme for question 7(a)(ii)
(a)(iii)

8 x - 6 = 46

[2]
Reveal mark scheme Mark scheme for question 7(a)(iii)
(b)

Solve by factorising.

Question 7, shown as an image
[3]
Reveal mark scheme Mark scheme for question 7(b)

Paper 4 November 2017 Higher tier, Question 18 4 marks

Also involves Rounding

Solve this equation algebraically. Give your solutions correct to 2 decimal places.

3x2 + 5x - 1 = 0

[4]
Reveal mark scheme Mark scheme for question 18

Paper 1 June 2017 Foundation tier, Question 7 6 marks

(a)

Simplify.

7 t - 6 u + 5 t - 4 u

[2]
Reveal mark scheme Mark scheme for question 7(a)
(b)

Factorise.

5 v + 20 w

[1]
Reveal mark scheme Mark scheme for question 7(b)
(c)

Solve by factorising.

Question 7, shown as an image
[3]
Reveal mark scheme Mark scheme for question 7(c)

Paper 4 June 2017 Higher tier, Question 18 6 marks

Also involves Rounding

(a)

Solve by factorisation.

Question 18, shown as an image
[3]
Reveal mark scheme Mark scheme for question 18(a)
(b)

Solve this equation. Give each value correct to 2 decimal places.

Question 18, shown as an image
[3]
Reveal mark scheme Mark scheme for question 18(b)

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