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Edexcel GCSE Combined Science

Topic questions Cell biology Enzymes

Enzymes

6 questions · 57 marks · about 1 hour

Enzymes questions

Edexcel 1SC0 Enzymes 6 questions

Paper 1: Biology 1 June 2024 Higher tier, Question 1 9 marks

(a)

Pepsin and trypsin are enzymes that break down proteins.

Figure 1 shows the results of an investigation into the activity of pepsin and trypsin at different pH levels.

Figure for question 1
(a)(i)

Which molecules are produced when a protein is broken down?

Question 1, shown as an image
[1]
Reveal mark scheme Mark scheme for question 1(a)(i)
(a)(ii)

Describe the trend in the graph for the enzyme pepsin.

Use data from the graph to support your answer.

[3]
Reveal mark scheme Mark scheme for question 1(a)(ii)
(a)(iii)

State the optimum pH for the enzyme trypsin.

[1]
Reveal mark scheme Mark scheme for question 1(a)(iii)
(a)(iv)

Explain why there is no trypsin activity at pH 5.

[3]
Reveal mark scheme Mark scheme for question 1(a)(iv)
(a)(v)

Temperature is a variable that should be controlled in this investigation.

Give one way the temperature could be controlled.

[1]
Reveal mark scheme Mark scheme for question 1(a)(v)

Paper 1: Biology 1 June 2022 Higher tier, Question 4 9 marks

A student investigated the fat content of two types of milk: milk A and milk B.

Before starting the investigation, the student added a drop of oil from a pipette into a test tube of water as shown in Figure 3.

The drop of oil rose to the surface of the water.

Figure for question 4
(a)

The student then placed a drop of milk A into one test tube of water and a drop of milk B into a different test tube of water.

The drop of milk A sank to the bottom and the drop of milk B rose to the surface.

Give one reason for the drop of milk B rising to the surface.

[1]
Reveal mark scheme Mark scheme for question 4(a)
(b)

5 cm3 of milk B and 1 cm3 of lipase were added to a different test tube.

The pH of this mixture was pH 7.

This test tube was placed in a water bath for 10 minutes.

The pH of the mixture changed from pH 7 to pH 5.

(b)(i)

Explain what caused this change in pH.

[3]
Reveal mark scheme Mark scheme for question 4(b)(i)
(b)(ii)

This procedure was repeated with milk A.

There was no change in the pH of this mixture after 10 minutes.

Explain why there was no change in the pH of the mixture containing milk A.

[2]
Reveal mark scheme Mark scheme for question 4(b)(ii)
(b)(iii)

The student repeated this procedure with lipase that had been boiled and left to cool.

This was added to another sample of milk B.

Describe why the pH did not change in this mixture.

[3]
Reveal mark scheme Mark scheme for question 4(b)(iii)

Paper 1: Biology 1 November 2020 Foundation tier, Question 4 10 marks

(a)

A student investigated the activity of a human enzyme at different temperatures.

The student measured the mass of product formed after 10 minutes at different temperatures.

Figure 5 shows the results of this investigation.

Figure for question 4
(a)(i)

Describe the trends shown in Figure 5.

[2]
Reveal mark scheme Mark scheme for question 4(a)(i)
(a)(ii)

Explain the results obtained for temperatures from 40 ยฐC to 60 ยฐC.

[2]
Reveal mark scheme Mark scheme for question 4(a)(ii)
(b)

Some enzymes are involved in the breakdown of food substances.

(b)(i)

Draw one straight line from each food group to the products of digestion for that food group.

Figure for question 4
[2]
Reveal mark scheme Mark scheme for question 4(b)(i)
(b)(ii)

Which enzyme breaks down fat?

Question 4, shown as an image
[1]
Reveal mark scheme Mark scheme for question 4(b)(ii)
(c)

Figure 6 shows an enzyme and two substrates, P and Q.

Figure for question 4

Explain the reason why no product will be formed if the enzyme is mixed with substrate Q.

[3]
Reveal mark scheme Mark scheme for question 4(c)

Paper 2: Biology 2 November 2020 Higher tier, Question 2 9 marks

A slide of potato cells was viewed using a light microscope.

Figure 3 is a drawing of the slide showing starch grains in the potato cells.

Figure for question 2
(a)(i)

Calculate the mean number of starch grains in potato cells P, Q and R.

[1]
Reveal mark scheme Mark scheme for question 2(a)(i)
(a)(ii)

Which structures are found in plant cells but are not found in animal cells?

Question 2, shown as an image
[1]
Reveal mark scheme Mark scheme for question 2(a)(ii)
(b)

A scientist investigated how the length of starch grains in potatoes changed when the potatoes were stored in the dark.

Figure 4 shows a potato after being stored in the dark.

Figure for question 2

Figure 4

Three potatoes were used in the investigation.

The length of starch grains in potato 1 were measured at the start.

The length of starch grains in potato 2 were measured after 5 weeks in the dark.

The length of starch grains in potato 3 were measured after 10 weeks in the dark.

Figure 5 shows the results.

Figure for question 2
(b)(i)

Calculate the percentage difference in the mean length of starch grains in potato 2 at 5 weeks and in potato 3 at 10 weeks.

[2]
Reveal mark scheme Mark scheme for question 2(b)(i)
(b)(ii)

State two variables the scientist should have controlled to improve this investigation.

[2]
Reveal mark scheme Mark scheme for question 2(b)(ii)
(b)(iii)

The starch grains in the potatoes became smaller as the starch was converted into glucose.

State why the potatoes need glucose.

[1]
Reveal mark scheme Mark scheme for question 2(b)(iii)
(b)(iv)

Describe how starch is broken down into glucose.

[2]
Reveal mark scheme Mark scheme for question 2(b)(iv)

Paper 2: Biology 2 November 2020 Higher tier, Question 3 11 marks

Trypsin is a protease enzyme used in the manufacture of food for babies.

(a)(i)

Which food group is digested by trypsin?

Question 3, shown as an image
[1]
Reveal mark scheme Mark scheme for question 3(a)(i)
(a)(ii)

The food is mashed before the trypsin is added.

Explain the advantage of mashing the food before adding the trypsin.

[2]
Reveal mark scheme Mark scheme for question 3(a)(ii)
(b)

A manufacturer of baby food wanted to find out the optimum pH for trypsin.

Equal volumes of different pH solutions were placed in six separate test tubes.

5 cm3 of 1% trypsin solution was added to each test tube.

1.5 g of mashed food was placed in each test tube.

The time taken to digest the food was recorded.

(b)(i)

State one other variable that should be controlled in this investigation.

[1]
Reveal mark scheme Mark scheme for question 3(b)(i)
(b)(ii)

State how this variable could be controlled.

[1]
Reveal mark scheme Mark scheme for question 3(b)(ii)
(c)

The results are shown in Figure 6.

Figure for question 3
(c)(i)

Describe the trends shown in this data.

[2]
Reveal mark scheme Mark scheme for question 3(c)(i)
(c)(ii)

At pH 4, the trypsin digested 1.5 g of mashed food at a rate of 0.8 g per minute.

Calculate the rate of digestion at pH 1.

Give your answer to one significant figure.

[2]
Reveal mark scheme Mark scheme for question 3(c)(ii)
(c)(iii)

Explain the difference in the rate of reaction at pH 1 and the rate of reaction at pH 4.

[2]
Reveal mark scheme Mark scheme for question 3(c)(iii)

Paper 1: Biology 1 June 2019 Foundation tier, Question 3 9 marks

(a)

Figure 3 shows the activity of the enzymes pepsin and trypsin at different pH

Figure for question 3
(a)(i)

Describe the trend in the graph for the enzyme trypsin.

Use data from the graph to support your answer.

[4]
Reveal mark scheme Mark scheme for question 3(a)(i)
(a)(ii)

State the optimum pH for the enzyme pepsin.

[1]
Reveal mark scheme Mark scheme for question 3(a)(ii)
(a)(iii)

Pepsin only works effectively in the stomach.

Describe the conditions in the stomach that allow pepsin to work effectively.

[2]
Reveal mark scheme Mark scheme for question 3(a)(iii)
(b)

At high pH values the active site of the enzyme pepsin changes shape.

When the active site of the enzyme changes shape, the enzyme is

Question 3, shown as an image
[1]
Reveal mark scheme Mark scheme for question 3(b)
(c)

State what is produced when proteins are digested.

[1]
Reveal mark scheme Mark scheme for question 3(c)

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