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Edexcel GCSE Biology

Topic questions Cell biology Enzymes

Enzymes

13 questions · 123 marks · about 2 hours

Enzymes questions

Edexcel 1BI0 Enzymes 13 questions

Paper 1 June 2025 Higher tier, Question 1 7 marks

(a)

Figure 1 shows a percentile chart for the height of boys from age 2 to age 16.

Figure for question 1
(a)(i)

Which is the height of an 8-year-old boy on the 10th percentile?

Question 1, shown as an image
[1]
Reveal mark scheme Mark scheme for question 1(a)(i)
(a)(ii)

The height of a 4-year-old boy was 94 cm.

Two years later, his height was 106 cm.

Using Figure 1, explain the conclusion that can be made about the growth of this child.

[2]
Reveal mark scheme Mark scheme for question 1(a)(ii)
(b)

Fats are needed for energy.

(b)(i)

Describe how a sample of food can be tested to show that it contains fat.

[2]
Reveal mark scheme Mark scheme for question 1(b)(i)
(b)(ii)

Which is produced when fats are digested?

Question 1, shown as an image
[1]
Reveal mark scheme Mark scheme for question 1(b)(ii)
(c)

State what calorimetry is used to measure.

[1]
Reveal mark scheme Mark scheme for question 1(c)

Paper 2 June 2025 Higher tier, Question 1 7 marks

(a)

As bananas ripen, they change colour and taste sweeter.

Figure 1 shows two bunches of bananas.

Figure for question 1

Unripe bananas contain more starch.

Describe the chemical test for starch.

[2]
Reveal mark scheme Mark scheme for question 1(a)
(b)

As bananas ripen the starch is converted to glucose.

Describe how bananas can be tested for the presence of glucose.

[3]
Reveal mark scheme Mark scheme for question 1(b)
(c)

A banana with green skin tested positive for starch and negative for glucose.

A banana with yellow skin tested positive for both starch and glucose.

Explain why there was glucose in the yellow banana.

[2]
Reveal mark scheme Mark scheme for question 1(c)

Paper 1 June 2024 Higher tier, Question 2 9 marks

(a)

Pepsin and trypsin are enzymes that break down proteins.

Figure 3 shows the results of an investigation into the activity of pepsin and trypsin at different pH levels.

Figure for question 2
(a)(i)

Which molecules are produced when a protein is broken down?

Question 2, shown as an image
[1]
Reveal mark scheme Mark scheme for question 2(a)(i)
(a)(ii)

Describe the trend in the graph for the enzyme pepsin.

Use data from the graph to support your answer.

[3]
Reveal mark scheme Mark scheme for question 2(a)(ii)
(a)(iii)

State the optimum pH for the enzyme trypsin.

[1]
Reveal mark scheme Mark scheme for question 2(a)(iii)
(a)(iv)

Explain why there is no trypsin activity at pH 5.

[3]
Reveal mark scheme Mark scheme for question 2(a)(iv)
(a)(v)

Temperature is a variable that should be controlled in this investigation.

Give one way the temperature could be controlled.

[1]
Reveal mark scheme Mark scheme for question 2(a)(v)

Paper 1 June 2022 Higher tier, Question 6 9 marks

Also involves Lipids

A student investigated the fat content of two types of milk: milk A and milk B.

Before starting the investigation, the student added a drop of oil from a pipette into a test tube of water as shown in Figure 5.

The drop of oil rose to the surface of the water.

Figure for question 6
(a)

The student then placed a drop of milk A into one test tube of water and a drop of milk B into a different test tube of water.

The drop of milk A sank to the bottom and the drop of milk B rose to the surface.

Give one reason for the drop of milk B rising to the surface.

[1]
Reveal mark scheme Mark scheme for question 6(a)
(b)

5 cm3 of milk B and 1 cm3 of lipase were added to a different test tube.

The pH of this mixture was pH 7.

This test tube was placed in a water bath for 10 minutes.

The pH of the mixture changed from pH 7 to pH 5.

(b)(i)

Explain what caused this change in pH.

[3]
Reveal mark scheme Mark scheme for question 6(b)(i)
(b)(ii)

This procedure was repeated with milk A.

There was no change in the pH of this mixture after 10 minutes.

Explain why there was no change in the pH of the mixture containing milk A.

[2]
Reveal mark scheme Mark scheme for question 6(b)(ii)
(b)(iii)

The student repeated this procedure with lipase that had been boiled and left to cool.

This was added to another sample of milk B.

Describe why the pH did not change in this mixture.

[3]
Reveal mark scheme Mark scheme for question 6(b)(iii)

Paper 1 November 2021 Foundation tier, Question 6 10 marks

(a)

6 (a) Why are enzymes called biological catalysts?

Question 6, shown as an image
[1]
Reveal mark scheme Mark scheme for question 6(a)
(b)

(b) Many cells contain an enzyme called catalase. Catalase breaks down hydrogen peroxide into water and oxygen. A scientist investigated the effect of hydrogen peroxide concentration on the time taken to produce 20 cm of oxygen. time taken to produce 20 cm3 of oxygen. Figure 12 shows the equipment used.

Figure for question 6
Question 6, shown as an image
(b)(i)

(i) State how the scientist could control the temperature of the flask.

[1]
Reveal mark scheme Mark scheme for question 6(b)(i)
(b)(ii)

(ii) Explain why the temperature should be controlled in this investigation.

[3]
Reveal mark scheme Mark scheme for question 6(b)(ii)
(b)(iii)

(iii) This investigation used five different concentrations of hydrogen peroxide. Figure 13 shows the results of this investigation.

Figure for question 6

Figure 13

Complete the graph by plotting the points and drawing a line to show the trend in the data. The first point has been plotted for you.

35 X

time taken to 20 collect 20 cm of oxygen in seconds

Question 6, shown as an image

concentration of hydrogen peroxide in arbitrary units

[2]
Reveal mark scheme Mark scheme for question 6(b)(iii)
(b)(iv)

(iv) Describe the trend shown in the graph. Use data from the table in Figure 13 to support your answer.

[3]
Reveal mark scheme Mark scheme for question 6(b)(iv)

Paper 1 November 2020 Foundation tier, Question 6 10 marks

Also involves Digestion

(a)

A student investigated the activity of a human enzyme at different temperatures.

The student measured the mass of product formed after 10 minutes at different temperatures.

Figure 10 shows the results of this investigation.

Figure for question 6
(a)(i)

Describe the trends shown in Figure 10.

[2]
Reveal mark scheme Mark scheme for question 6(a)(i)
(a)(ii)

Explain the results obtained for temperatures from 40 Β°C to 60 Β°C.

[2]
Reveal mark scheme Mark scheme for question 6(a)(ii)
(b)

Some enzymes are involved in the breakdown of food substances.

(b)(i)

Draw one straight line from each food group to the products of digestion for that food group.

Figure for question 6
[2]
Reveal mark scheme Mark scheme for question 6(b)(i)
(b)(ii)

Which enzyme breaks down fat?

Question 6, shown as an image
[1]
Reveal mark scheme Mark scheme for question 6(b)(ii)
(c)

Figure 11 shows an enzyme and two substrates, P and Q.

Figure for question 6

Explain the reason why no product will be formed if the enzyme is mixed with substrate Q.

[3]
Reveal mark scheme Mark scheme for question 6(c)

Paper 1 November 2020 Higher tier, Question 6 10 marks

Also involves Digestion

(a)

A maths symbol student mixed 10 cm33 of starch solution with 5 cm3 of amylase solution and kept the tube in a water bath at 25 Β°C.

The student tested the solution for starch and for glucose every 30 seconds.

Figure 6 shows the results.

time in secondsstarch detectedglucose detected
0YesNo
30YesNo
60YesYes
90YesYes
120YesYes
150NoYes
180NoYes
Question 6, shown as an image
(a)(i)

Give one reason for the result at 150 seconds.

[1]
Reveal mark scheme Mark scheme for question 6(a)(i)
(a)(ii)

Another student repeated the investigation with the same volumes of solutions and at the same temperature of 25 Β°C.

Give two other variables that would need to be controlled in the investigation.

[2]
Reveal mark scheme Mark scheme for question 6(a)(ii)
(a)(iii)

Both students also included a tube containing 10 cm3 of starch solution with 5 cm3 of distilled water instead of 5 cm3 of amylase solution.

They tested the solution for starch and for glucose every 30 seconds.

Give one reason why this tube was included in their investigations.

[1]
Reveal mark scheme Mark scheme for question 6(a)(iii)
(b)

Amylase has an optimum pH of 6.8.

Devise a method the students could use to confirm the optimum pH for amylase.

[3]
Reveal mark scheme Mark scheme for question 6(b)
(c)

Amylase is produced by salivary glands and the pancreas.

Explain why amylase is not produced in the stomach.

[3]
Reveal mark scheme Mark scheme for question 6(c)

Paper 2 November 2020 Higher tier, Question 3 9 marks

A slide of potato cells was viewed using a light microscope.

Figure 4 is a drawing of the slide showing starch grains in the potato cells.

Figure for question 3
(a)(i)

Calculate the mean number of starch grains in potato cells P, Q and R.

[1]
Reveal mark scheme Mark scheme for question 3(a)(i)
(a)(ii)

Which structures are found in plant cells but are not found in animal cells?

Question 3, shown as an image
[1]
Reveal mark scheme Mark scheme for question 3(a)(ii)
(b)

A scientist investigated how the length of starch grains in potatoes changed when the potatoes were stored in the dark.

Figure 5 shows a potato after being stored in the dark.

Figure for question 3

Figure 5

Three potatoes were used in the investigation.

The length of starch grains in potato 1 were measured at the start.

The length of starch grains in potato 2 were measured after 5 weeks in the dark.

The length of starch grains in potato 3 were measured after 10 weeks in the dark.

Figure 6 shows the results.

Figure for question 3
(b)(i)

Calculate the percentage difference in the mean length of starch grains in potato 2 at 5 weeks and in potato 3 at 10 weeks.

[2]
Reveal mark scheme Mark scheme for question 3(b)(i)
(b)(ii)

State two variables the scientist should have controlled to improve this investigation.

[2]
Reveal mark scheme Mark scheme for question 3(b)(ii)
(b)(iii)

The starch grains in the potatoes became smaller as the starch was converted into glucose.

State why the potatoes need glucose.

[1]
Reveal mark scheme Mark scheme for question 3(b)(iii)
(b)(iv)

Describe how starch is broken down into glucose.

[2]
Reveal mark scheme Mark scheme for question 3(b)(iv)

Paper 2 November 2020 Higher tier, Question 5 11 marks

Also involves Digestion

Trypsin is a protease enzyme used in the manufacture of food for babies.

(a)(i)

Which food group is digested by trypsin?

Question 5, shown as an image
[1]
Reveal mark scheme Mark scheme for question 5(a)(i)
(a)(ii)

The food is mashed before the trypsin is added.

Explain the advantage of mashing the food before adding the trypsin.

[2]
Reveal mark scheme Mark scheme for question 5(a)(ii)
(b)

A manufacturer of baby food wanted to find out the optimum pH for trypsin.

Equal volumes of different pH solutions were placed in six separate test tubes.

5 cm3 of 1% trypsin solution was added to each test tube.

1.5 g of mashed food was placed in each test tube.

The time taken to digest the food was recorded.

(b)(i)

State one other variable that should be controlled in this investigation.

[1]
Reveal mark scheme Mark scheme for question 5(b)(i)
(b)(ii)

State how this variable could be controlled.

[1]
Reveal mark scheme Mark scheme for question 5(b)(ii)
(c)

The results are shown in Figure 10.

Figure for question 5
(c)(i)

Describe the trends shown in this data.

[2]
Reveal mark scheme Mark scheme for question 5(c)(i)
(c)(ii)

At pH 4, the trypsin digested 1.5 g of mashed food at a rate of 0.8 g per minute.

Calculate the rate of digestion at pH 1.

Give your answer to one significant figure.

[2]
Reveal mark scheme Mark scheme for question 5(c)(ii)
(c)(iii)

Explain the difference in the rate of reaction at pH 1 and the rate of reaction at pH 4.

[2]
Reveal mark scheme Mark scheme for question 5(c)(iii)

Paper 1 June 2019 Foundation tier, Question 5 9 marks

(a)

Figure 7 shows the activity of the enzymes pepsin and trypsin at different pH levels.

Figure for question 5
(a)(i)

Describe the trend in the graph for the enzyme trypsin.

Use data from the graph to support your answer.

[4]
Reveal mark scheme Mark scheme for question 5(a)(i)
(a)(ii)

State the optimum pH for the enzyme pepsin.

[1]
Reveal mark scheme Mark scheme for question 5(a)(ii)
(a)(iii)

Pepsin only works effectively in the stomach.

Describe the conditions in the stomach that allow pepsin to work effectively.

[2]
Reveal mark scheme Mark scheme for question 5(a)(iii)
(b)

At high pH values the active site of the enzyme pepsin changes shape.

When the active site of the enzyme changes shape, the enzyme is

Question 5, shown as an image
[1]
Reveal mark scheme Mark scheme for question 5(b)
(c)

State what is produced when proteins are digested.

[1]
Reveal mark scheme Mark scheme for question 5(c)

Paper 1 June 2019 Foundation tier, Question 7 11 marks

Starch is a nutrient in food.

Starch is a source of energy.

(a)

Name the enzyme that breaks down starch.

[1]
Reveal mark scheme Mark scheme for question 7(a)
(b)
Figure for question 7 Figure for question 7
(b)(i)

Give one reason why the contents of both test tubes were blue-black at the beginning of the investigation.

[1]
Reveal mark scheme Mark scheme for question 7(b)(i)
(b)(ii)

Explain the results of this investigation after ten minutes.

[3]
Reveal mark scheme Mark scheme for question 7(b)(ii)
(c)

*(c) The diagram shows equipment that can be used to measure the energy content of different foods.

Figure for question 7

Devise a method to compare the energy content of two foods using this equipment.

Include details of how to control the variables.

[6]
Reveal mark scheme Mark scheme for question 7(c)

Paper 2 June 2019 Foundation tier, Question 7 12 marks

Also involves Digestion Β· Land use Β· Food security

The increasing human population is affecting farming and the habitats of animals.

Figure 12 shows the human population of the UK from 1960 to 2018.

Figure for question 7
(a)

Extend the line to estimate the human population of the UK in 2030 if this trend continues.

[1]
Reveal mark scheme Mark scheme for question 7(a)
(b)

Food security means that a population has enough safe and healthy food.

Which of these would improve food security?

Question 7, shown as an image
[1]
Reveal mark scheme Mark scheme for question 7(b)
(c)

A scientist tested three samples of different foods.

Figure 13 shows the results.

Figure for question 7
Question 7, shown as an image
(c)(i)

Name the food group in sample E.

[1]
Reveal mark scheme Mark scheme for question 7(c)(i)
(c)(ii)

Name the food groups in sample F.

[1]
Reveal mark scheme Mark scheme for question 7(c)(ii)
(c)(iii)

The emulsion test shows that food sample G contained fat. Describe how fat is digested in the body.

[2]
Reveal mark scheme Mark scheme for question 7(c)(iii)
(d)

*(d) Figure 14 shows a field of a crop in one area of Africa.

The crop cannot be eaten by people.

The crop is used to produce biofuel.

Figure for question 7

(Source: Β© KAMBOU SIA/Stringer/Getty Images)

Figure 14

Describe the advantages and disadvantages of growing this crop to produce biofuel.

[6]
Reveal mark scheme Mark scheme for question 7(d)

Paper 2 June 2018 Foundation tier, Question 6 9 marks

Also involves Leaf structure Β· Carbohydrates

(a) Figure 12 shows a cross section through a leaf.

Figure for question 6
(a)
(a)(i)

What is the name of the part labelled R in Figure 12?

Question 6, shown as an image
[1]
Reveal mark scheme Mark scheme for question 6(a)(i)
(a)(ii)

Figure 13 shows the mass of glucose produced in each layer of a leaf per hour.

Figure for question 6

Describe the difference in the mass of glucose produced per hour in the palisade mesophyll and the mass of glucose produced in the spongy mesophyll shown in Figure 13.

[2]
Reveal mark scheme Mark scheme for question 6(a)(ii)
(b)

Figure 14 shows how light intensity changed during one day.

Figure for question 6

Use information in Figure 14 to explain why oxygen moved out of the leaf between 9 am and midday.

[2]
Reveal mark scheme Mark scheme for question 6(b)
(c)(i)

Glucose is produced in a leaf.

Glucose is a

Question 6, shown as an image
[1]
Reveal mark scheme Mark scheme for question 6(c)(i)
(c)(ii)

Describe a test for glucose.

[2]
Reveal mark scheme Mark scheme for question 6(c)(ii)
(d)

Figure 15 shows an enzyme and three substrates found in plant cells.

Figure for question 6

The enzyme will only break down one of these substrates.

State the name of this enzyme.

[1]
Reveal mark scheme Mark scheme for question 6(d)

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