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Edexcel GCSE Biology

Topic questions Cell biology Eukaryotic & prokaryotic cells

Eukaryotic & prokaryotic cells

36 questions · 347 marks · about 6 hours

Eukaryotic and prokaryotic cells questions

Edexcel 1BI0 Eukaryotic and prokaryotic cells 36 questions

Paper 1 June 2025 Foundation tier, Question 1 7 marks

(a)

Genes control natural hair colour in humans.

(a)(i)

Which term describes the differences in hair colour?

Question 1, shown as an image
[1]
Reveal mark scheme Mark scheme for question 1(a)(i)
(a)(ii)

Genes are found on chromosomes.

Name the part of the human cell where chromosomes are found.

[1]
Reveal mark scheme Mark scheme for question 1(a)(ii)
(b)

The hair colour of 24 students was recorded.

Figure 1 shows the results.

Figure for question 1
(b)(i)

Complete Figure 2 to show the tally and the total for brown hair.

Figure for question 1
[2]
Reveal mark scheme Mark scheme for question 1(b)(i)
(b)(ii)

Complete the bar chart to show the totals in Figure 2 and label the x ‑axis.

Figure for question 1
[3]
Reveal mark scheme Mark scheme for question 1(b)(ii)

Paper 1 June 2025 Foundation tier, Question 2 7 marks

(a)

Figure 3 shows a sperm cell.

Figure for question 2
(a)(i)

Name the part labelled R.

[1]
Reveal mark scheme Mark scheme for question 2(a)(i)
(a)(ii)

Draw one straight line from each part of the sperm cell to its function.

Figure for question 2
[2]
Reveal mark scheme Mark scheme for question 2(a)(ii)
(b)

Animal and plant cells are both eukaryotic.

State one structure found in a plant cell that is not found in an animal cell.

[1]
Reveal mark scheme Mark scheme for question 2(b)
(c)

DNA is found in cells.

Figure 4 shows part of a DNA molecule.

Figure for question 2
(c)(i)

Which type of large molecule is DNA?

Question 2, shown as an image
[1]
Reveal mark scheme Mark scheme for question 2(c)(i)
(c)(ii)

Describe how the bases of a DNA molecule are held together.

[2]
Reveal mark scheme Mark scheme for question 2(c)(ii)

Paper 1 June 2025 Higher tier, Question 6 9 marks

(a)

The pathogen Vibrio cholerae causes the disease cholera.

Figure 7 shows Vibrio cholerae bacteria.

Figure for question 6
(a)(i)

Complete the table to show the function of structure P and structure Q.

Figure for question 6
[2]
Reveal mark scheme Mark scheme for question 6(a)(i)
(a)(ii)

On the original image, the length of one bacterial cell is 12 mm.

The actual length of this bacterial cell is 2.0 Β΅ m.

Calculate the magnification.

[2]
Reveal mark scheme Mark scheme for question 6(a)(ii)
(a)(iii)

State one symptom of the disease caused by Vibrio cholerae.

[1]
Reveal mark scheme Mark scheme for question 6(a)(iii)
(a)(iv)

State how the disease caused by Vibrio cholerae is transmitted.

[1]
Reveal mark scheme Mark scheme for question 6(a)(iv)
(b)

Describe the specific immune response when a pathogen infects the body.

[3]
Reveal mark scheme Mark scheme for question 6(b)

Paper 1 June 2024 Higher tier, Question 5 11 marks

(a)

A student made a microscope slide of cells taken from the inside of their mouth.

(a)(i)

The student wore gloves while using a swab to collect cells from their mouth.

Give one other safety precaution the student should take.

[1]
Reveal mark scheme Mark scheme for question 5(a)(i)
(a)(ii)

A light microscope was used to obtain an image similar to the one shown in Figure 6.

Figure for question 5

(Source: Β© STEVE GSCHMEISSNER/SCIENCE PHOTO LIBRARY)

Figure 6

Describe how the student used the light microscope to view these cells at a magnification of maths symbol400.

[3]
Reveal mark scheme Mark scheme for question 5(a)(ii)
(b)

The cytoplasm of a cell contains a nucleus.

Explain the role of one other structure in the cytoplasm of a human cell.

[2]
Reveal mark scheme Mark scheme for question 5(b)
(c)

DNA can be extracted from human cells in a similar way to the method used to extract DNA from fruits.

Describe the stages of the method used to extract DNA from cells.

[3]
Reveal mark scheme Mark scheme for question 5(c)
(d)

The Human Genome Project sequenced the order of the bases in the human genome.

Give two other outcomes from the Human Genome Project.

[2]
Reveal mark scheme Mark scheme for question 5(d)

Paper 2 June 2024 Foundation tier, Question 1 7 marks

Scientists use microscopes to study cells.

Figure 1 shows a light microscope.

Figure for question 1
(a)

Draw one straight line from each part of the microscope to its function.

Figure for question 1
[2]
Reveal mark scheme Mark scheme for question 1(a)
(b)

Figure 2 shows two photographs of bacteria.

Photograph A was taken through a light microscope.

Photograph B was taken using an electron microscope.

Figure for question 1
(b)(i)

Draw, in the box, the bacterial cell labelled X.

Label one part of the bacterial cell on your diagram.

Figure for question 1
[3]
Reveal mark scheme Mark scheme for question 1(b)(i)
(b)(ii)

State one advantage of using a light microscope and one advantage of using an electron microscope to study these bacterial cells.

A light microscope........

An electron microscope........

[2]
Reveal mark scheme Mark scheme for question 1(b)(ii)

Paper 2 June 2024 Foundation tier, Question 5 9 marks

Also involves Leaf structure Β· Adaptations

Figure 7 shows the structure of a leaf.

Figure for question 5
(a)
(a)(i)

Which layer has the highest number of chloroplasts per cell?

Question 5, shown as an image
[1]
Reveal mark scheme Mark scheme for question 5(a)(i)
(a)(ii)

When iodine solution was put onto these cells, small parts of the cells became blue‑black.

Name the substance stored in the parts of the cells that turned blue‑black.

[1]
Reveal mark scheme Mark scheme for question 5(a)(ii)
(a)(iii)

State how the guard cells control the amount of gas exchange that occurs through the stomata.

[1]
Reveal mark scheme Mark scheme for question 5(a)(iii)
(b)

A scientist measured the thickness of the cuticle from the leaves of plants growing in soil that had a different percentage of water content.

The scientist measured six plants at each percentage of water content.

Figure 8 shows the results.

Figure for question 5
(b)(i)

Calculate the mean thickness of cuticle for the plants growing in soil containing 15% water.

Give your answer to one decimal place.

[3]
Reveal mark scheme Mark scheme for question 5(b)(i)
(b)(ii)

Explain why the thickness of the cuticle is different when a plant is grown in soil with a higher water content.

[2]
Reveal mark scheme Mark scheme for question 5(b)(ii)
(b)(iii)

State one other way that the leaves of plants are adapted to help plants grow in soil with low water content.

[1]
Reveal mark scheme Mark scheme for question 5(b)(iii)

Paper 2 June 2024 Foundation tier, Question 9 13 marks

(a)

Figure 13 shows a root hair cell from a plant.

Figure for question 9
(a)(i)

Name the part labelled X.

[1]
Reveal mark scheme Mark scheme for question 9(a)(i)
(a)(ii)

State one way that the structure of the root hair cell increases the volume of substances it absorbs.

[1]
Reveal mark scheme Mark scheme for question 9(a)(ii)
(a)(iii)

Explain why root hair cells do not contain chloroplasts.

[3]
Reveal mark scheme Mark scheme for question 9(a)(iii)
(b)
Question 9, shown as an image
Figure for question 9
Question 9, shown as an image
[2]
Reveal mark scheme Mark scheme for question 9(b)
(c)

*(c) The arrows in Figure 15 show the direction of water movement through a tree.

Figure for question 9

Explain how water is moved from the soil, through the plant and into the air.

[6]
Reveal mark scheme Mark scheme for question 9(c)

Paper 2 June 2024 Higher tier, Question 3 10 marks

Also involves Turgor and plant support

(a)

3 (a) Figure 2 shows a root hair cell from a plant.

Figure for question 3
(a)(i)

(i) Name the part labelled X.

[1]
Reveal mark scheme Mark scheme for question 3(a)(i)
(a)(ii)

(ii) State one way that the structure of the root hair cell increases the volume of substances it absorbs.

[1]
Reveal mark scheme Mark scheme for question 3(a)(ii)
(a)(iii)

(iii) Explain why root hair cells do not contain chloroplasts.

[3]
Reveal mark scheme Mark scheme for question 3(a)(iii)
(b)
Figure for question 3
(b)(i)
Question 3, shown as an image

from the Elodea cells in tap water.

[2]
Reveal mark scheme Mark scheme for question 3(b)(i)
(b)(ii)

(ii) Explain why placing the Elodea cells in the 10% salt solution causes the changes seen in Figure 3.

[3]
Reveal mark scheme Mark scheme for question 3(b)(ii)

Paper 1 June 2023 Foundation tier, Question 1 7 marks

(a)

Figure 1 shows an animal cell.

Figure for question 1
(a)(i)

Which part of the cell is labelled Y?

Question 1, shown as an image
[1]
Reveal mark scheme Mark scheme for question 1(a)(i)
(a)(ii)

Which structures are found in the part labelled Z?

Question 1, shown as an image
[1]
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(a)(iii)

Name the part of an animal cell where respiration occurs.

[1]
Reveal mark scheme Mark scheme for question 1(a)(iii)
(b)

A microscope can be used to observe the structure of a cell.

Figure 2 shows a microscope.

Figure for question 1
(b)(i)

Give one advantage of using a microscope to look at cells.

[1]
Reveal mark scheme Mark scheme for question 1(b)(i)
(b)(ii)

Draw one straight line from each part of the microscope to its function.

Figure for question 1
[2]
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(c)

Figure 3 shows some of the units used when cells and organelles are measured.

Figure for question 1

Give the name of the smallest unit shown in Figure 3.

[1]
Reveal mark scheme Mark scheme for question 1(c)

Paper 1 June 2023 Foundation tier, Question 3 8 marks

Also involves The eye

(a)

Figure 6 shows the bones in the limbs of a bird and a whale.

Figure for question 3
(a)(i)

The bird and the whale have evolved from a common ancestor.

Give one way the structure of these limbs provides evidence for this evolution.

[1]
Reveal mark scheme Mark scheme for question 3(a)(i)
(a)(ii)

Charles Darwin developed the theory of evolution by natural selection.

Which scientist worked with Darwin on the theory of evolution by natural selection?

Question 3, shown as an image
[1]
Reveal mark scheme Mark scheme for question 3(a)(ii)
(b)

DNA is found in bones and stem cells.

(b)(i)

Suggest one reason why DNA is found in bones.

[1]
Reveal mark scheme Mark scheme for question 3(b)(i)
(b)(ii)

Describe how stem cells help animals to grow.

[2]
Reveal mark scheme Mark scheme for question 3(b)(ii)
(b)(iii)

Scientists have transplanted stem cells into the retina of the eye.

Name one type of light sensitive cell found in the retina.

[1]
Reveal mark scheme Mark scheme for question 3(b)(iii)
(b)(iv)

Explain one reason for transplanting stem cells into the retina.

[2]
Reveal mark scheme Mark scheme for question 3(b)(iv)

Paper 1 June 2023 Foundation tier, Question 9 13 marks

Also involves Culturing microorganisms

Figure 17 shows colonies of bacteria growing on an agar plate.

Figure for question 9

Each colony starts as one bacterium.

Every time bacteria reproduce, the number of bacteria in each colony doubles.

(a)

Calculate the number of bacteria in a colony after five hours, if each bacterium reproduces every 30 minutes.

[2]
Reveal mark scheme Mark scheme for question 9(a)
(b)

Some bacteria are pathogens.

(b)(i)

State the meaning of the term pathogen.

[1]
Reveal mark scheme Mark scheme for question 9(b)(i)
(b)(ii)

Explain why antibiotics can be used to treat bacterial infections.

[2]
Reveal mark scheme Mark scheme for question 9(b)(ii)
(b)(iii)

A rod-shaped bacterium is 0.005 mm long.

A student draws the rod-shaped bacterium.

The bacterium in the drawing is 80 mm long.

Calculate the magnification of this drawing.

[2]
Reveal mark scheme Mark scheme for question 9(b)(iii)
(c)

* (c) Figure 18 shows a bacterial cell and a plant cell.

Figure for question 9

Describe the similarities and differences of a bacterial cell and a plant cell.

[6]
Reveal mark scheme Mark scheme for question 9(c)

Paper 1 June 2023 Higher tier, Question 8 11 marks

Also involves Turgor and plant support

A student investigated the movement of water in potatoes.

The student used three identical cubes of potato.

The size of a cube is shown in Figure 12.

Figure for question 8
Question 8, shown as an image
(a)
(a)(i)

Calculate the volume of this cube.

Include the units in your answer.

[2]
Reveal mark scheme Mark scheme for question 8(a)(i)
(a)(ii)

One cube was placed in water and each of the other two cubes were placed in solutions with different concentrations of salt.

The cubes were left for 20 minutes.

Figure 13 shows the student’s results.

Figure for question 8

Give one way the student could ensure the measurement of the mass of the cubes is accurate.

[1]
Reveal mark scheme Mark scheme for question 8(a)(ii)
(a)(iii)

Explain the mass change in the cube in the concentrated salt solution.

[3]
Reveal mark scheme Mark scheme for question 8(a)(iii)
(a)(iv)

The student wanted to find the concentration of salt solution where the potato cube did not change mass.

Describe how the student could modify this investigation to find this concentration.

[3]
Reveal mark scheme Mark scheme for question 8(a)(iv)
(b)

Explain why potato cells do not burst when placed in water.

[2]
Reveal mark scheme Mark scheme for question 8(b)

Paper 1 June 2022 Foundation tier, Question 10 11 marks

Also involves The brain Β· The eye

(a)

Figure 18 shows two light receptor cells from the human eye.

Figure for question 10
(a)(i)

Which part of the eye contains light receptor cells?

Question 10, shown as an image
[1]
Reveal mark scheme Mark scheme for question 10(a)(i)
(a)(ii)

These cells require energy.

The cell organelles labelled X release energy during respiration.

Name the organelles labelled X.

[1]
Reveal mark scheme Mark scheme for question 10(a)(ii)
(a)(iii)

The cell organelle labelled Y contains chromosomes.

Name the organelle labelled Y.

[1]
Reveal mark scheme Mark scheme for question 10(a)(iii)
(a)(iv)

Cell A responds to dim light and is responsible for night vision.

Name cell A.

[1]
Reveal mark scheme Mark scheme for question 10(a)(iv)
(a)(v)

Describe how the role of light receptor cell B is different from the role of light receptor cell A.

[2]
Reveal mark scheme Mark scheme for question 10(a)(v)
(b)

The optic nerve carries information from the back of the eye to the brain.

The optic nerve is 47 mm in length.

Nerve impulses travel at 75 metres per second.

(b)(i)

Calculate the time an impulse takes to travel the length of the optic nerve. Use the equation: speed = fraction

[3]
Reveal mark scheme Mark scheme for question 10(b)(i)
(b)(ii)

The impulse travels to the occipital lobe of the brain. The occipital lobe is labelled in Figure 19.

Figure for question 10

Which part of the brain contains the occipital lobe?

Question 10, shown as an image
[1]
Reveal mark scheme Mark scheme for question 10(b)(ii)
(b)(iii)

State the sense most likely to be affected if the occipital lobe is damaged.

[1]
Reveal mark scheme Mark scheme for question 10(b)(iii)

Paper 1 June 2022 Higher tier, Question 4 11 marks

Also involves The brain Β· The eye

(a)

Figure 3 shows two light receptor cells from the human eye.

Figure for question 4
(a)(i)

Which part of the eye contains light receptor cells?

Question 4, shown as an image
[1]
Reveal mark scheme Mark scheme for question 4(a)(i)
(a)(ii)

These cells require energy.

The cell organelles labelled X release energy during respiration.

Name the organelles labelled X.

[1]
Reveal mark scheme Mark scheme for question 4(a)(ii)
(a)(iii)

The cell organelle labelled Y contains chromosomes.

Name the organelle labelled Y.

[1]
Reveal mark scheme Mark scheme for question 4(a)(iii)
(a)(iv)

Cell A responds to dim light and is responsible for night vision.

Name cell A.

[1]
Reveal mark scheme Mark scheme for question 4(a)(iv)
(a)(v)

Describe how the role of light receptor cell B is different from the role of light receptor cell A.

[2]
Reveal mark scheme Mark scheme for question 4(a)(v)
(b)

The optic nerve carries information from the back of the eye to the brain.

The optic nerve is 47 mm in length.

Nerve impulses travel at 75 metres per second.

(b)(i)

Calculate the time an impulse takes to travel the length of the optic nerve. Use the equation: speed = fraction

[3]
Reveal mark scheme Mark scheme for question 4(b)(i)
(b)(ii)

The impulse travels to the occipital lobe of the brain. The occipital lobe is labelled in Figure 4.

Figure for question 4

Which part of the brain contains the occipital lobe?

Question 4, shown as an image
[1]
Reveal mark scheme Mark scheme for question 4(b)(ii)
(b)(iii)

State the sense most likely to be affected if the occipital lobe is damaged.

[1]
Reveal mark scheme Mark scheme for question 4(b)(iii)

Paper 1 June 2022 Higher tier, Question 5 9 marks

Also involves Mutation

(a)

In 2017, a new strain of Klebsiella pneumoniae bacteria was discovered that was resistant to 26 different antibiotics.

(a)(i)

Explain how Klebsiella pneumoniae bacteria developed resistance to antibiotics.

[4]
Reveal mark scheme Mark scheme for question 5(a)(i)
(a)(ii)

State how the use of antibiotics could contribute to Klebsiella pneumoniae bacteria developing resistance to antibiotics.

[1]
Reveal mark scheme Mark scheme for question 5(a)(ii)
(a)(iii)

Klebsiella pneumoniae is a prokaryotic cell.

Which is a characteristic feature of a prokaryotic cell?

Question 5, shown as an image
[1]
Reveal mark scheme Mark scheme for question 5(a)(iii)
(b)

New antibiotics are being developed to treat the disease caused by Klebsiella pneumoniae.

Describe the stages of antibiotic development that would occur after the discovery of a new antibiotic.

[3]
Reveal mark scheme Mark scheme for question 5(b)

Paper 2 June 2022 Foundation tier, Question 2 8 marks

(a)

2 (a) Blood contains red blood cells, white blood cells, plasma and platelets.

(a)(i)

(i) Draw one straight line from each part of the blood to its function.

part of the blood function

Figure for question 2 Figure for question 2 Figure for question 2 Figure for question 2 Figure for question 2

Figure 2 shows some red blood cells.

Figure for question 2

(Source: Β© SciePro/Shutterstock)

Figure 2

[2]
Reveal mark scheme Mark scheme for question 2(a)(i)
(a)(ii)

(ii) State two features that can be seen in the red blood cells in Figure 2.

[2]
Reveal mark scheme Mark scheme for question 2(a)(ii)
(b)

(b) Lymphocytes are white blood cells that produce large amounts of protein.

(b)(i)

(i) Which organelle is needed to produce large amounts of protein?

Question 2, shown as an image

A small lymphocyte has a diameter of 10 Β΅ m (micrometres). A microscope magnifies this lymphocyte 400 times.

[1]
Reveal mark scheme Mark scheme for question 2(b)(i)
(b)(ii)

(ii) Calculate the diameter of the image of the lymphocyte seen using this microscope.

image size..............................................................

[2]
Reveal mark scheme Mark scheme for question 2(b)(ii)
(b)(iii)

(iii) How many micrometres are in 1 mm (millimetre)?

Question 2, shown as an image
[1]
Reveal mark scheme Mark scheme for question 2(b)(iii)

Paper 2 June 2022 Foundation tier, Question 4 9 marks

(a)

4 (a) Figure 5 shows some onion cells that have been soaked in a concentrated salt solution.

Figure for question 4

(Source: Β© Rattiya Thongdumhyu/Shutterstock)

Figure 5

(a)(i)

(i) The cells in Figure 5 have been stained. Give one reason why the cells have been stained.

[1]
Reveal mark scheme Mark scheme for question 4(a)(i)
(a)(ii)

(ii) Which is the name of the structure labelled V?

Question 4, shown as an image
[1]
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(a)(iii)

(iii) The salt solution outside the cell has a higher concentration than the solution inside the cell. Explain why the cytoplasm shrinks away from the sides of the cell when the cells are in salt solution.

[2]
Reveal mark scheme Mark scheme for question 4(a)(iii)
(b)

(b) Figure 6 shows the equipment used to prepare a microscope slide of onion cells.

Figure for question 4

Describe how this equipment could be used to prepare a slide of onion cells to view under a microscope.

[3]
Reveal mark scheme Mark scheme for question 4(b)
(c)

(c) A student investigated the percentage change in mass of potato cylinders placed in sucrose solutions of different concentrations. Figure 7 shows the results of the student’s investigation.

Figure for question 4

concentration of sucrose solution in mol/dm3

Figure 7

State two conclusions that can be made from these results.

[2]
Reveal mark scheme Mark scheme for question 4(c)

Paper 2 June 2022 Foundation tier, Question 8 12 marks

(a)

8 (a) Figure 14 shows a diagram of a plant root hair cell.

Figure for question 8

Figure 14

(a)(i)

(i) Name the part labelled R.

[1]
Reveal mark scheme Mark scheme for question 8(a)(i)
(a)(ii)

(ii) Explain one adaptation of a root hair cell that increases the absorption of water and mineral ions.

[2]
Reveal mark scheme Mark scheme for question 8(a)(ii)
(b)

(b) Figure 15 shows xylem and phloem from the stem of a plant.

Figure for question 8

Figure 15

(b)(i)

(i) Living cells in phloem use energy to transport sucrose. Which organelles release energy in living cells?

Question 8, shown as an image
[1]
Reveal mark scheme Mark scheme for question 8(b)(i)
(b)(ii)

(ii) Describe two features of the structure of xylem vessels that can be seen in Figure 15.

[2]
Reveal mark scheme Mark scheme for question 8(b)(ii)
(c)

(c) A scientist investigated how the flow of air affected the rate of transpiration in a plant. A fan was used to change the flow of air. The volume of water taken up by the plant was measured. Figure 16 shows the results of this investigation. fan switched on

Figure for question 8
Question 8, shown as an image

time in minutes

Figure 16

(c)(i)

(i) Explain why switching on the fan caused a change in the volume of water taken up by the plant.

[3]
Reveal mark scheme Mark scheme for question 8(c)(i)
(c)(ii)

(ii) Give one reason why the volume of water taken up by the plant was also measured when the fan was not switched on.

[1]
Reveal mark scheme Mark scheme for question 8(c)(ii)
(c)(iii)

(iii) Calculate the rate of water uptake from 8 minutes to 10 minutes when the fan was switched on. Use the equation

Question 8, shown as an image

..............................................................mm3 per minute

[2]
Reveal mark scheme Mark scheme for question 8(c)(iii)

Paper 2 June 2022 Higher tier, Question 2 9 marks

(a)

2 (a) Figure 2 shows xylem and phloem from the stem of a plant.

Figure for question 2
(a)(i)

(i) Living cells in phloem use energy to transport sucrose. Which organelles release energy in living cells?

Question 2, shown as an image
[1]
Reveal mark scheme Mark scheme for question 2(a)(i)
(a)(ii)

(ii) Describe two features of the structure of xylem vessels that can be seen in Figure 2.

[2]
Reveal mark scheme Mark scheme for question 2(a)(ii)
(b)

(b) A scientist investigated how the flow of air affected the rate of transpiration in a plant. A fan was used to change the flow of air. The volume of water taken up by the plant was measured. Figure 3 shows the results of this investigation. fan switched on

Figure for question 2
Question 2, shown as an image

time in minutes

Figure 3

(b)(i)

(i) Explain why switching on the fan caused a change in the volume of water taken up by the plant.

[3]
Reveal mark scheme Mark scheme for question 2(b)(i)
(b)(ii)

(ii) Give one reason why the volume of water taken up by the plant was also measured when the fan was not switched on.

[1]
Reveal mark scheme Mark scheme for question 2(b)(ii)
(b)(iii)

(iii) Calculate the rate of water uptake from 8 minutes to 10 minutes when the fan was switched on. Use the equation

Question 2, shown as an image

..............................................................mm3 per minute

[2]
Reveal mark scheme Mark scheme for question 2(b)(iii)

Paper 1 November 2021 Foundation tier, Question 1 7 marks

(a)

1 (a) Animals and plants are made of cells. Figure 1 shows two types of cell from a human.

Figure for question 1

cheek cell sperm cell

Figure 1

(a)(i)

(i) Which part of the cheek cell is labelled W?

Question 1, shown as an image
[1]
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(a)(ii)

(ii) Which labelled part of the sperm cell is also found in the cheek cell?

Question 1, shown as an image
[1]
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(b)

(b) Name the part of a plant cell that gives the cell support and protection.

[1]
Reveal mark scheme Mark scheme for question 1(b)
(c)

(c) Some cells contain starch. Describe the chemical test for starch.

[2]
Reveal mark scheme Mark scheme for question 1(c)
(d)

(d) Figure 2 shows the results of some food tests.

Figure for question 1
(d)(i)

(i) Give the letter of the food sample that contains fat.

[1]
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(d)(ii)

(ii) Give the letter of the food sample that contains reducing sugars and protein.

[1]
Reveal mark scheme Mark scheme for question 1(d)(ii)

Paper 2 November 2021 Foundation tier, Question 1 8 marks

Figure 1 shows human blood seen using a light microscope.

Figure for question 1
(a)(i)

The organelle labelled X controls the activities of the white blood cell.

What is the name of organelle X?

Question 1, shown as an image
[1]
Reveal mark scheme Mark scheme for question 1(a)(i)
(a)(ii)

Use words from the box to complete the sentences.

Figure for question 1

Red blood cells contain the substance........ .

Blood plasma is a........ .

[2]
Reveal mark scheme Mark scheme for question 1(a)(ii)
(a)(iii)

Describe two ways that white blood cells protect the body from disease.

[2]
Reveal mark scheme Mark scheme for question 1(a)(iii)
(b)

Figure 2 shows a white blood cell on a 100 Β΅ m scale.

Figure for question 1

State the width of the white blood cell.

[1]
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(c)

Figure 1 shows human blood seen using a light microscope.

Explain why using an electron microscope shows the structures in the white blood cells more clearly.

[2]
Reveal mark scheme Mark scheme for question 1(c)

Paper 1 November 2020 Foundation tier, Question 2 6 marks

(a)

Figure 4 shows three cells.

Figure for question 2
(a)(i)

What is structure X ?

Question 2, shown as an image
[1]
Reveal mark scheme Mark scheme for question 2(a)(i)
(a)(ii)

The bacterial cell in Figure 4 has a flagellum.

State the function of a flagellum.

[1]
Reveal mark scheme Mark scheme for question 2(a)(ii)
(a)(iii)

Give one other difference between the bacterial cell and the animal cell shown in Figure 4.

[1]
Reveal mark scheme Mark scheme for question 2(a)(iii)
(b)

Substances move into and out of cells.

How does oxygen move into and out of cells?

Question 2, shown as an image
[1]
Reveal mark scheme Mark scheme for question 2(b)
(c)

A plant leaf cell is 0.04 mm long.

Calculate the length of the image after this cell has been magnified 500 times.

[2]
Reveal mark scheme Mark scheme for question 2(c)

Paper 1 November 2020 Foundation tier, Question 9 13 marks

Figure 14 shows a banana plantation.

Figure for question 9

After the bananas have been harvested, the old plants are cut down.

The suckers then develop into mature plants producing the next crop of bananas.

The tip of each sucker contains a group of cells called a meristem.

(a)(i)

Describe the function of a meristem in the growth of a plant.

[2]
Reveal mark scheme Mark scheme for question 9(a)(i)
(a)(ii)

A student took a sample of cells from a meristem to view under a light microscope.

Describe how the student would prepare a microscope slide using these cells.

[3]
Reveal mark scheme Mark scheme for question 9(a)(ii)
(b)

Figure 15 is a drawing of a eukaryotic cell.

Structure Z is found in plant leaf cells.

Figure for question 9
(b)(i)

Name structure Z.

[1]
Reveal mark scheme Mark scheme for question 9(b)(i)
(b)(ii)

Give one function of the mitochondrion.

[1]
Reveal mark scheme Mark scheme for question 9(b)(ii)
(c)

*(c) DNA is found in the nucleus of cells.

Describe the structure of DNA and how it can be extracted from plant cells.

[6]
Reveal mark scheme Mark scheme for question 9(c)

Paper 1 November 2020 Higher tier, Question 3 9 marks

Figure 2 shows a banana plantation.

Figure for question 3

After the bananas have been harvested, the old plants are cut down.

The suckers then develop into mature plants producing the next crop of bananas.

The tip of each sucker contains a group of cells called a meristem.

(a)(i)

Describe the function of a meristem in the growth of a plant.

[2]
Reveal mark scheme Mark scheme for question 3(a)(i)
(a)(ii)

A student took a sample of cells from a meristem to view under a light microscope.

Describe how the student would prepare a microscope slide using these cells.

[3]
Reveal mark scheme Mark scheme for question 3(a)(ii)
(b)

Figure 3 is a drawing of a eukaryotic cell.

Structure Z is found in plant leaf cells.

Figure for question 3
(b)(i)

Name structure Z.

[1]
Reveal mark scheme Mark scheme for question 3(b)(i)
(b)(ii)

Give one function of the mitochondrion.

[1]
Reveal mark scheme Mark scheme for question 3(b)(ii)
(b)(iii)

Describe how a prokaryotic cell is different from the cell in Figure 3.

[2]
Reveal mark scheme Mark scheme for question 3(b)(iii)

Paper 1 November 2020 Higher tier, Question 5 9 marks

Figure 5 shows a great tit on a bird feeder.

Figure for question 5

Scientists have found that great tits living now have longer beaks than great tits living 50 years ago.

Genetic analysis shows changes in the sequence of the bird’s DNA.

(a)(i)

Give the complementary strand sequence for this DNA template.

Figure for question 5
[1]
Reveal mark scheme Mark scheme for question 5(a)(i)
(a)(ii)

Which statement correctly describes a DNA molecule?

Question 5, shown as an image
[1]
Reveal mark scheme Mark scheme for question 5(a)(ii)
(a)(iii)

State the term used to describe a change in the sequence of DNA bases.

[1]
Reveal mark scheme Mark scheme for question 5(a)(iii)
(b)

Scientists think that great tits living now have longer beaks because of the increased use of bird feeders during the last 50 years.

Explain how natural selection could have caused an increase in beak length because of the use of bird feeders.

[4]
Reveal mark scheme Mark scheme for question 5(b)
(c)

Birds are classified in the domain Eukarya.

(c)(i)

Why are the cells from birds described as eukaryotic?

Question 5, shown as an image
[1]
Reveal mark scheme Mark scheme for question 5(c)(i)
(c)(ii)

Give one reason why the three domain classification system was proposed.

[1]
Reveal mark scheme Mark scheme for question 5(c)(ii)

Paper 2 November 2020 Foundation tier, Question 3 9 marks

Also involves Decomposition

(a)

Figure 6 shows a root hair cell from a strawberry plant.

Figure for question 3
(a)(i)

Label the cell vacuole in Figure 6.

[1]
Reveal mark scheme Mark scheme for question 3(a)(i)
(a)(ii)

Explain how the structure of root hair cells increases water absorption from the soil.

[2]
Reveal mark scheme Mark scheme for question 3(a)(ii)
(b)

Figure 7 shows fungus growing on strawberries.

The fungus is decomposing the strawberries.

Figure for question 3

A scientist investigated the effect of temperature on the decomposition of strawberries.

The scientist spread fresh strawberries on six trays.

Each tray was kept at a different temperature.

After five days the scientist measured the area of fungus that had grown on each tray of strawberries.

The results are shown in Figure 8.

Figure for question 3
(b)(i)

The mean rate of growth of fungus at 25maths symbolC was 12 cm2 per day.

Calculate the mean rate of growth of fungus at 30maths symbolC.

........ cm2 per day

[2]
Reveal mark scheme Mark scheme for question 3(b)(i)
(b)(ii)

State the effect of temperature on the growth of fungus on strawberries from 5maths symbolC to 30maths symbolC.

[1]
Reveal mark scheme Mark scheme for question 3(b)(ii)
(c)

Decomposition of strawberries can be prevented by boiling the strawberries with sugar to make jam.

(c)(i)

Enzymes in the fungus caused decomposition.

Explain how boiling stops the enzymes from working.

[2]
Reveal mark scheme Mark scheme for question 3(c)(i)
(c)(ii)

Cells from a fungus can land on jam.

The sugar solution inside the jam is more concentrated than the sugar solution inside the fungus cells.

State how osmosis causes the fungus cells to die.

[1]
Reveal mark scheme Mark scheme for question 3(c)(ii)

Paper 2 November 2020 Foundation tier, Question 8 12 marks

Figure 18 shows the leaves and flowers of water lily plants (Nymphaea odorata) on a lake.

Figure for question 8
(a)

Water lilies have stomata on the upper surface of the leaves.

Explain why water lilies have no stomata on the lower surface of the leaves.

[2]
Reveal mark scheme Mark scheme for question 8(a)
(b)(i)

The white petals of the water lily flowers cannot photosynthesise.

Which structure in leaf cells is the site of photosynthesis?

Question 8, shown as an image
[1]
Reveal mark scheme Mark scheme for question 8(b)(i)
(b)(ii)

Glucose is made by photosynthesis.

Glucose is converted to another sugar to be transported in the plant.

What is the name of this sugar?

Question 8, shown as an image
[1]
Reveal mark scheme Mark scheme for question 8(b)(ii)
(b)(iii)

Describe how this sugar is transported from the leaves to the flowers of the water lily.

[2]
Reveal mark scheme Mark scheme for question 8(b)(iii)
(c)

Figure 19 shows water lilies growing in a lake in Europe.

Figure for question 8
(c)(i)

One water lily plant was brought from America 10 years ago and planted in the lake shown in Figure 19.

Explain why this non‑indigenous plant now covers the whole surface of the lake.

[3]
Reveal mark scheme Mark scheme for question 8(c)(i)
(c)(ii)

Explain how the water lilies will affect the biodiversity of this lake.

[3]
Reveal mark scheme Mark scheme for question 8(c)(ii)

Paper 2 November 2020 Foundation tier, Question 9 13 marks

A slide of potato cells was viewed using a light microscope.

Figure 20 is a drawing of the slide showing starch grains in the potato cells.

Figure for question 9
(a)(i)

Calculate the mean number of starch grains in potato cells P, Q and R.

[1]
Reveal mark scheme Mark scheme for question 9(a)(i)
(a)(ii)

Which structures are found in plant cells but are not found in animal cells?

Question 9, shown as an image
[1]
Reveal mark scheme Mark scheme for question 9(a)(ii)
(b)

A scientist investigated how the length of starch grains in potatoes changed when the potatoes were stored in the dark.

Figure 21 shows a potato after being stored in the dark.

Figure for question 9

Three potatoes were used in the investigation.

The length of starch grains in potato 1 were measured at the start.

The length of starch grains were measured in potato 2 after 5 weeks in the dark.

The length of starch grains were measured in potato 3 after 10 weeks in the dark.

Figure 22 shows the results.

Figure for question 9
(b)(i)

Calculate the percentage difference in the mean length of starch grains in potato 2 at 5 weeks and in potato 3 at 10 weeks.

[2]
Reveal mark scheme Mark scheme for question 9(b)(i)
(b)(ii)

State two variables the scientist should have controlled to improve this investigation.

[2]
Reveal mark scheme Mark scheme for question 9(b)(ii)
(b)(iii)

The starch grains in the potatoes became smaller as the starch was converted into glucose.

State why the potatoes need glucose.

[1]
Reveal mark scheme Mark scheme for question 9(b)(iii)
(c)

*(c) Figure 23 shows a diagram of some equipment that can be used to investigate the rate of photosynthesis.

Figure for question 9

Devise a plan to investigate the effect of light intensity on the rate of photosynthesis.

Include variables you would need to control.

[6]
Reveal mark scheme Mark scheme for question 9(c)

Paper 2 November 2020 Higher tier, Question 2 9 marks

Figure 2 shows the leaves and flowers of water lily plants (Nymphaea odorata) on a lake.

Figure for question 2
(a)

Water lilies have stomata on the upper surface of the leaves.

Explain why water lilies have no stomata on the lower surface of the leaves.

[2]
Reveal mark scheme Mark scheme for question 2(a)
(b)(i)

The white petals of the water lily flowers cannot photosynthesise.

Which structure in leaf cells is the site of photosynthesis?

Question 2, shown as an image
[1]
Reveal mark scheme Mark scheme for question 2(b)(i)
(b)(ii)

Glucose is made by photosynthesis.

Glucose is converted to another sugar to be transported in the plant.

What is the name of this sugar?

Question 2, shown as an image
[1]
Reveal mark scheme Mark scheme for question 2(b)(ii)
(b)(iii)

Describe how this sugar is transported from the leaves to the flowers of the water lily.

[2]
Reveal mark scheme Mark scheme for question 2(b)(iii)
(c)

Figure 3 shows water lilies growing in a lake in Europe.

Figure for question 2

One water lily plant was brought from America 10 years ago and planted in the lake shown in Figure 3.

Explain why this non‑indigenous plant now covers the whole surface of the lake.

[3]
Reveal mark scheme Mark scheme for question 2(c)

Paper 2 November 2020 Higher tier, Question 3 9 marks

A slide of potato cells was viewed using a light microscope.

Figure 4 is a drawing of the slide showing starch grains in the potato cells.

Figure for question 3
(a)(i)

Calculate the mean number of starch grains in potato cells P, Q and R.

[1]
Reveal mark scheme Mark scheme for question 3(a)(i)
(a)(ii)

Which structures are found in plant cells but are not found in animal cells?

Question 3, shown as an image
[1]
Reveal mark scheme Mark scheme for question 3(a)(ii)
(b)

A scientist investigated how the length of starch grains in potatoes changed when the potatoes were stored in the dark.

Figure 5 shows a potato after being stored in the dark.

Figure for question 3

Figure 5

Three potatoes were used in the investigation.

The length of starch grains in potato 1 were measured at the start.

The length of starch grains in potato 2 were measured after 5 weeks in the dark.

The length of starch grains in potato 3 were measured after 10 weeks in the dark.

Figure 6 shows the results.

Figure for question 3
(b)(i)

Calculate the percentage difference in the mean length of starch grains in potato 2 at 5 weeks and in potato 3 at 10 weeks.

[2]
Reveal mark scheme Mark scheme for question 3(b)(i)
(b)(ii)

State two variables the scientist should have controlled to improve this investigation.

[2]
Reveal mark scheme Mark scheme for question 3(b)(ii)
(b)(iii)

The starch grains in the potatoes became smaller as the starch was converted into glucose.

State why the potatoes need glucose.

[1]
Reveal mark scheme Mark scheme for question 3(b)(iii)
(b)(iv)

Describe how starch is broken down into glucose.

[2]
Reveal mark scheme Mark scheme for question 3(b)(iv)

Paper 1 June 2019 Higher tier, Question 5 12 marks

(a)

Organisms can be classified by the five kingdom or three domain method.

(a)(i)

What is the name of the domain that plants belong to?

Question 5, shown as an image
[1]
Reveal mark scheme Mark scheme for question 5(a)(i)
(a)(ii)

Plant cells contain chloroplasts.

What happens in a chloroplast?

Figure for question 5
[1]
Reveal mark scheme Mark scheme for question 5(a)(ii)
(a)(iii)

Give a reason why the three domain method of classification has been suggested.

[1]
Reveal mark scheme Mark scheme for question 5(a)(iii)
(b)

Figure 7 shows a cyanobacterium magnified 50 000 times.

The line AB shows the diameter of the bacterial cell.

Figure for question 5

(Source: Β© The Christian Science Monitor)

Figure 7

(b)(i)

Calculate the actual diameter of the cyanobacterium.

Give your answer in micrometres (Β΅ m).

[3]
Reveal mark scheme Mark scheme for question 5(b)(i)
(b)(ii)

Bacterial cells contain plasmids.

Describe three other features of a bacterial cell.

[3]
Reveal mark scheme Mark scheme for question 5(b)(ii)
(c)

Figure 8 shows a plasmid containing the human insulin gene.

Figure for question 5

Explain how the human insulin gene can be inserted into a plasmid.

[3]
Reveal mark scheme Mark scheme for question 5(c)

Paper 2 June 2019 Foundation tier, Question 6 11 marks

Figure 10 shows a plant cell as seen under a light microscope.

Figure for question 6

(Source: Β© HERVE CONGE, ISM/SCIENCE PHOTO LIBRARY)

Figure 10

(a)

Draw this plant cell in the box below.

Label three parts of this cell.

[4]
Reveal mark scheme Mark scheme for question 6(a)
(b)

Mitochondria cannot be seen with a light microscope.

What is the function of mitochondria in a plant cell?

Question 6, shown as an image
[1]
Reveal mark scheme Mark scheme for question 6(b)
(c)

A student wanted to investigate the movement of water into and out of cells in potatoes.

The student had the equipment shown in Figure 11.

Figure for question 6

The test tubes in the rack contain different concentrations of sodium chloride solution.

The solutions were 0.1 M, 0.2 M, 0.3 M, 0.4 M and 0.5 M sodium chloride solution.

The test tube in the beaker contains distilled water.

There are three potato chips in each of the six test tubes.

(c)(i)

State why the test tube in the beaker only contains distilled water and three potato chips.

[1]
Reveal mark scheme Mark scheme for question 6(c)(i)
(c)(ii)

State two variables that need to be controlled in this investigation.

[2]
Reveal mark scheme Mark scheme for question 6(c)(ii)
(c)(iii)

Explain why the chips in the 0.5 M sodium chloride solution lost mass.

[3]
Reveal mark scheme Mark scheme for question 6(c)(iii)

Paper 1 June 2018 Higher tier, Question 3 9 marks

Also involves Surface area to volume ratio

(a) Figure 5 shows two potato chips.

Question 3, shown as an image
Figure for question 3

Figure 6 shows some information about each potato chip.

Figure for question 3
(a)
(a)(i)

Calculate the total surface area of potato chip B using the formula,

Total surface area = 2XY + 2XZ + 2YZ

[2]
Reveal mark scheme Mark scheme for question 3(a)(i)
(a)(ii)

The potato chips were placed in distilled water for 20 minutes.

Figure 7 shows the increase in mass of each potato chip.

Figure for question 3

Explain why potato chip B has a greater increase in mass than potato chip A.

[2]
Reveal mark scheme Mark scheme for question 3(a)(ii)
(a)(iii)

Potato chip A is transferred from the distilled water into a concentrated salt solution.

Explain what will happen to the cells in potato chip A.

[3]
Reveal mark scheme Mark scheme for question 3(a)(iii)
(b)

The potatoes of a potato plant develop underground.

Explain one difference in the sub-cellular structures in a cell in the potato and those in a cell in the leaf of the potato plant.

[2]
Reveal mark scheme Mark scheme for question 3(b)

Paper 1 June 2018 Higher tier, Question 5 9 marks

Streptococcus bacteria can cause a sore throat or skin infection.

An illness called scarlet fever can also develop during an infection with this bacterium.

(a)(i)

Give two precautions a doctor should take when treating a patient who is infected with Streptococcus.

[2]
Reveal mark scheme Mark scheme for question 5(a)(i)
(a)(ii)

From September 2013 to March 2014 there were 2 830 cases of scarlet fever in the UK.

From September 2014 to March 2015 there were 5 943 cases of scarlet fever.

Calculate the percentage increase of the number of cases of scarlet fever between the periods September 2014 to March 2015 and September 2013 to March 2014.

[2]
Reveal mark scheme Mark scheme for question 5(a)(ii)
(a)(iii)

Figure 10 shows some Streptococcus bacteria.

Figure for question 5

Some bacteria are motile, meaning they can move themselves.

Why is a Streptococcus bacterium not motile?

Question 5, shown as an image
[1]
Reveal mark scheme Mark scheme for question 5(a)(iii)
(b)

Patients with scarlet fever can be treated with antibiotics.

New antibiotics need to be tested before they can be used in patients.

Which is the correct sequence for the development of a new medicine?

Question 5, shown as an image

volunteers
cultured cells
on patients

Question 5, shown as an image

cultured cells
on patients
volunteers

Question 5, shown as an image

volunteers
on patients
cultured cells

Question 5, shown as an image

cultured cells
volunteers
on patients

[1]
Reveal mark scheme Mark scheme for question 5(b)
(c)

Most cases of scarlet fever occur in children.

Adults have usually developed immunity to a toxin that the Streptococcus bacteria produce during infection.

Explain how an adult develops immunity to the toxin.

[3]
Reveal mark scheme Mark scheme for question 5(c)

Paper 2 June 2018 Foundation tier, Question 8 12 marks

(a) Figure 19 shows a diagram of a red blood cell from a turtle and a diagram of a red blood cell from a human.

Figure for question 8
(a)
(a)(i)

These cells are animal cells.

Animal cells do not have

Question 8, shown as an image
[1]
Reveal mark scheme Mark scheme for question 8(a)(i)
(a)(ii)

The actual length of the red blood cell from a turtle is 20.5 ΞΌ m.

Calculate the length of the magnified image of the red blood cell of the turtle when magnified 400 Γ—.

[2]
Reveal mark scheme Mark scheme for question 8(a)(ii)
(a)(iii)

The width of the human red blood cell, when magnified 400 Γ—, is 3.08 mm.

Calculate the actual width of the cell and show your answer in standard form.

[2]
Reveal mark scheme Mark scheme for question 8(a)(iii)
(b)

Red blood cells are carried in veins and arteries.

Figure 20 shows the equipment used to measure the elasticity of an artery.

Figure for question 8
(b)(i)

Describe a method you could use to see how much the ring of tissue from an artery could stretch before it no longer returned to its original size.

[3]
Reveal mark scheme Mark scheme for question 8(b)(i)
(b)(ii)

Give one safety precaution you need to take when handling animal tissue such as blood vessels.

[1]
Reveal mark scheme Mark scheme for question 8(b)(ii)
(c)

Figure 21 shows the circulatory system of a frog.

Figure for question 8

Explain why the circulatory system of a frog is less efficient at carrying oxygen to the tissues than the circulatory system of a human.

[3]
Reveal mark scheme Mark scheme for question 8(c)

Paper 2 June 2018 Higher tier, Question 2 9 marks

(a) Figure 3 shows a diagram of a red blood cell from a turtle and a diagram of a red blood cell from a human.

Figure for question 2
(a)
(a)(i)

These cells are animal cells.

Animal cells do not have

Question 2, shown as an image
[1]
Reveal mark scheme Mark scheme for question 2(a)(i)
(a)(ii)

The actual length of the red blood cell from a turtle is 20.5 ΞΌ m.

Calculate the length of the magnified image of the red blood cell of the turtle when magnified 400 Γ—.

[2]
Reveal mark scheme Mark scheme for question 2(a)(ii)
(a)(iii)

The width of the human red blood cell, when magnified 400 Γ—, is 3.08 mm.

Calculate the actual width of the cell and show your answer in standard form.

[2]
Reveal mark scheme Mark scheme for question 2(a)(iii)
(b)

Red blood cells are carried in veins and arteries.

Figure 4 shows the equipment used to measure the elasticity of an artery.

Figure for question 2
(b)(i)

Describe a method you could use to see how much the ring of tissue from an artery could stretch before it no longer returned to its original size.

[3]
Reveal mark scheme Mark scheme for question 2(b)(i)
(b)(ii)

Give one safety precaution you need to take when handling animal tissue such as blood vessels.

[1]
Reveal mark scheme Mark scheme for question 2(b)(ii)

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