BREAKING
Student sits three sciences, gets two grades, wants a recount★Cover teacher explains biology using only physics equations★Nation in shock as student wears goggles on actual eyes★
  1. Home
  2. GCSE
  3. Combined Science
  4. OCR
  5. Respiration

OCR GCSE Combined Science

Topic questions Human physiology Respiration

Respiration

15 questions · 117 marks · about 2.5 hours

Respiration questions

OCR J250 Respiration 15 questions

Biology Paper 1 June 2025 Foundation tier, Question 3 1 mark

Which statement is correct about anaerobic respiration in plants?

A It produces glucose.

B It produces carbon dioxide.

C It produces lactic acid.

D It produces oxygen.

Question 3, shown as an image
[1]
Reveal mark scheme Mark scheme for question 3

Biology Paper 2 June 2025 Foundation tier, Question 13 8 marks

(a)

The diagram shows the carbon cycle.

(a)(i)

Complete the two labels in the diagram to identify the processes involved in the carbon cycle.

Figure for question 13
[2]
Reveal mark scheme Mark scheme for question 13(a)(i)
(a)(ii)

Explain the role of decomposers in the carbon cycle.

[2]
Reveal mark scheme Mark scheme for question 13(a)(ii)
(a)(iii)

Decomposition can take place aerobically or anaerobically.

What is meant by the term anaerobically ?

[1]
Reveal mark scheme Mark scheme for question 13(a)(iii)
(b)
Figure for question 13
[1]
Reveal mark scheme Mark scheme for question 13(b)
(c)

Human activity has led to rising carbon dioxide levels in the atmosphere.

This contributes to global warming and reduces global biodiversity.

Describe two ways in which human activity can reduce local biodiversity.

[2]
Reveal mark scheme Mark scheme for question 13(c)

Biology Paper 1 June 2023 Foundation tier, Question 16, also on the Higher paper 12 marks

A scientist investigates the effect of temperature on anaerobic respiration in yeast.

The diagram shows the apparatus they use.

Figure for question 16

This is the method they follow:

• Collect the gas produced by the yeast for five minutes.

• Increase the temperature of the water bath.

• Repeat the investigation with fresh sugar solution.

• Do each temperature three times.

(a)(i)

Suggest why the scientist used fresh sugar solution each time.

[1]
Reveal mark scheme Mark scheme for question 16(a)(i)
(a)(ii)

Identify one variable the scientist should keep constant throughout the experiment.

Tick (✓) one box.

Question 16, shown as an image
[1]
Reveal mark scheme Mark scheme for question 16(a)(ii)
(a)(iii)

Which gas is collected by the scientist in the gas syringe?

[1]
Reveal mark scheme Mark scheme for question 16(a)(iii)
(b)
Figure for question 16
(b)(i)

When calculating the mean for 55 °C, they did not include Trial 1.

Give the reason why.

[1]
Reveal mark scheme Mark scheme for question 16(b)(i)
(b)(ii)

Plot the mean values from the table on the graph.

[3]
Reveal mark scheme Mark scheme for question 16(b)(ii)
(b)(iii)

Draw a curve of best fit.

Figure for question 16
[1]
Reveal mark scheme Mark scheme for question 16(b)(iii)
(b)(iv)

Anaerobic respiration is an enzyme-controlled reaction.

Explain the results between 15 °C and 35 °C. Include ideas about enzyme particles.

[2]
Reveal mark scheme Mark scheme for question 16(b)(iv)
(b)(v)

The scientist concludes that the best temperature for anaerobic respiration is approximately 40 °C.

How could they alter their investigation to identify a more accurate temperature?

[2]
Reveal mark scheme Mark scheme for question 16(b)(v)

Biology Paper 7 June 2023 Higher tier, Question 11, also on the Foundation paper 12 marks

A scientist investigates the effect of temperature on anaerobic respiration in yeast.

The diagram shows the apparatus they use.

Figure for question 11

This is the method they follow:

• Collect the gas produced by the yeast for five minutes.

• Increase the temperature of the water bath.

• Repeat the investigation with fresh sugar solution.

• Do each temperature three times.

(a)(i)

Suggest why the scientist used fresh sugar solution each time.

[1]
Reveal mark scheme Mark scheme for question 11(a)(i)
(a)(ii)

Identify one variable the scientist should keep constant throughout the experiment.

Tick (✓) one box.

Question 11, shown as an image
[1]
Reveal mark scheme Mark scheme for question 11(a)(ii)
(a)(iii)

Which gas is collected by the scientist in the gas syringe?

[1]
Reveal mark scheme Mark scheme for question 11(a)(iii)
(b)
Figure for question 11
(b)(i)

When calculating the mean for 55 °C, they did not include Trial 1.

Give the reason why.

[1]
Reveal mark scheme Mark scheme for question 11(b)(i)
(b)(ii)

Plot the mean values from the table on the graph.

[3]
Reveal mark scheme Mark scheme for question 11(b)(ii)
(b)(iii)

Draw a curve of best fit.

Figure for question 11
[1]
Reveal mark scheme Mark scheme for question 11(b)(iii)
(b)(iv)

Anaerobic respiration is an enzyme-controlled reaction.

Explain the results between 15 °C and 35 °C. Include ideas about enzyme particles.

[2]
Reveal mark scheme Mark scheme for question 11(b)(iv)
(b)(v)

The scientist concludes that the best temperature for anaerobic respiration is approximately 40 °C.

How could they alter their investigation to identify a more accurate temperature?

[2]
Reveal mark scheme Mark scheme for question 11(b)(v)

Biology Paper 7 June 2023 Higher tier, Question 15 11 marks

(a)

15* (a) Sickle cell disease is a blood disorder causing some red blood cells to become sickle shaped.

The diagram shows red blood cells from a person with sickle cell disease.

Figure for question 15

The change in shape causes the cells to clump together. This makes sickle shaped red blood cells less efficient at carrying out their role.

Symptoms of sickle cell disease are tiredness and a lack of energy.

Explain why someone with sickle cell disease has these symptoms. Include information from the diagram.

[6]
Reveal mark scheme Mark scheme for question 15(a)
(b)

The photograph shows part of an artery seen using a light microscope.

Figure for question 15

The image has been magnified 8 times.

Calculate the actual thickness of the artery between points X and Y in fraction m.

Give your answer in standard form.

Actual size =........ maths symbolm

[3]
Reveal mark scheme Mark scheme for question 15(b)
(c)

Explain how the structure of a vein is adapted to its function.

[2]
Reveal mark scheme Mark scheme for question 15(c)

Biology Paper 1 June 2022 Foundation tier, Question 14 6 marks

Respiration releases energy from food. The energy content of food can be measured by burning the food. A student measures the energy content of some different foods.

(a)
Figure for question 14
(a)(i)

The student finds the energy content by measuring the change in temperature of the water.

Identify the piece of apparatus labelled X in the diagram.

[1]
Reveal mark scheme Mark scheme for question 14(a)(i)
(a)(ii)

The table shows the change in temperature for one type of food.

Temperature at the start (°C)Temperature at the end (°C)
2065

Calculate the energy content of the food using this formula.

Energy content = 20 × 4.2 × change in temperature

[2]
Reveal mark scheme Mark scheme for question 14(a)(ii)
(b)

The student converted all their results to find the energy content in kJ per gram of food.

The graph shows the results.

Figure for question 14
(b)(i)

What is the energy content of food type D ?........ kJ per gram

[1]
Reveal mark scheme Mark scheme for question 14(b)(i)
(b)(ii)

Eating food type B provides the body with more ATP molecules than eating the same mass of food type E.

Use your knowledge of cellular respiration to explain why.

[2]
Reveal mark scheme Mark scheme for question 14(b)(ii)

Biology Paper 2 June 2022 Foundation tier, Question 11 7 marks

(a)

The diagram shows some of the levels of organisation within the ecosystem.

Complete the diagram using words in the list.

Figure for question 11
[2]
Reveal mark scheme Mark scheme for question 11(a)
(b)

Explain why the carbon cycle is important to plants.

[2]
Reveal mark scheme Mark scheme for question 11(b)
(c)
Figure for question 11
[3]
Reveal mark scheme Mark scheme for question 11(c)

Biology Paper 7 November 2020 Higher tier, Question 6 1 mark

What are the product(s) of anaerobic respiration in animals?

A Alcohol

B Alcohol and carbon dioxide

C Lactic acid

D Lactic acid and carbon dioxide

Question 6, shown as an image
[1]
Reveal mark scheme Mark scheme for question 6

Biology Paper 7 November 2020 Higher tier, Question 16 8 marks

(a)

Fig. 16.1 shows a single-celled organism called an alga.

Figure for question 16
(a)(i)

The alga cell is a eukaryotic cell.

Describe two differences in structure between eukaryotic and prokaryotic cells.

[2]
Reveal mark scheme Mark scheme for question 16(a)(i)
(a)(ii)

Explain why chloroplasts are needed for photosynthesis.

[1]
Reveal mark scheme Mark scheme for question 16(a)(ii)
(b)

Fig. 16.2 shows algae growing on the surface of a lake.

Figure for question 16

In the summer the area covered by the algae increases.

Other plants growing at the bottom of the lake receive less light.

Explain how this could affect the growth of the plants at the bottom of the lake.

[2]
Reveal mark scheme Mark scheme for question 16(b)
(c)

Compare the process of photosynthesis with the process of aerobic respiration.

[3]
Reveal mark scheme Mark scheme for question 16(c)

Biology Paper 1 June 2018 Foundation tier, Question 15 14 marks

Figure for question 15
(a)

Which gas makes the bubbles?

[1]
Reveal mark scheme Mark scheme for question 15(a)
(b)

* The students think they could improve their method.

They will count the bubbles three times at each temperature. This would show up any anomalous results.

Describe other ways they could improve their method to obtain more precise and repeatable results.

For each improvement explain why it is needed.

[6]
Reveal mark scheme Mark scheme for question 15(b)
(c)

The students count the bubbles three times at each temperature. They then calculate the mean number of bubbles at each temperature.

The table shows their results.

Temperature (°C)Mean number of bubbles per minute
103
206
3011
405
502
601
(c)(i)

Plot the results on the grid.

Figure for question 15
[2]
Reveal mark scheme Mark scheme for question 15(c)(i)
(c)(ii)

Draw a line of best fit.

[1]
Reveal mark scheme Mark scheme for question 15(c)(ii)
(d)

Respiration is an enzyme controlled reaction.

Use ideas about enzymes to explain the pattern in the results.

[4]
Reveal mark scheme Mark scheme for question 15(d)

Biology Paper 2 June 2018 Foundation tier, Question 11 10 marks

(a)

Look at the diagram of the water cycle.

Figure for question 11

Complete these sentences about the diagram.

Choose words from the list.

combustion evaporation photosynthesis precipitation

run-off respiration transpiration

(a)(i)

Arrows labelled A represent the process of........

[1]
Reveal mark scheme Mark scheme for question 11(a)(i)
(a)(ii)

Arrows labelled B represent the process of........

[1]
Reveal mark scheme Mark scheme for question 11(a)(ii)
(a)(iii)

Arrows labelled C represent the process of........

[1]
Reveal mark scheme Mark scheme for question 11(a)(iii)
(b)
Figure for question 11
(b)(i)

How many predators does the shrimp have in this food web?

[1]
Reveal mark scheme Mark scheme for question 11(b)(i)
(b)(ii)

When plant material is decomposed by fungi, there is an increase in temperature.

Complete the sentences to explain why.

Choose words from the list.

endothermic excretion exothermic

respiration photosynthesis

During decomposition fungi release energy from the plants by the process of

........

This process releases energy as heat because the reaction is

........

[2]
Reveal mark scheme Mark scheme for question 11(b)(ii)
(c)

Dogfish and minnows are fish that live in lakes.

Dogfish build nests to lay their eggs in. Minnows lay their eggs in the same nests as dogfish.

The dogfish protect the nest from predators.

Minnows move in and out of the nest. This helps to remove harmful bacteria and get oxygen to the eggs.

Dogfish usually eat minnows. When the dogfish have eggs they do not eat minnows.

(c)(i)

Dogfish have two different interactions with the minnows.

Write down the names of these two types of interactions.

Describe when each interaction takes place.

[2]
Reveal mark scheme Mark scheme for question 11(c)(i)
(c)(ii)

One of the interactions benefits both minnows and dogfish.

Explain how.

[2]
Reveal mark scheme Mark scheme for question 11(c)(ii)

Biology Paper 7 June 2018 Higher tier, Question 14 10 marks

Figure for question 14
(a)

Compare the structures of these two carbohydrates.

[2]
Reveal mark scheme Mark scheme for question 14(a)
(b)

Two students investigate anaerobic respiration using yeast with sucrose solution.

They measure the volume of gas collected every 5 minutes for 40 minutes.

The students then repeat the investigation using yeast with glucose solution.

Figure for question 14
(b)(i)

Explain how and why the temperature of the solution could change during the investigation and how this could be controlled.

Figure for question 14
[2]
Reveal mark scheme Mark scheme for question 14(b)(i)
(b)(ii)
Figure for question 14
[6]
Reveal mark scheme Mark scheme for question 14(b)(ii)

Biology Paper 8 June 2018 Higher tier, Question 12 15 marks

(a)

Cardiovascular disease (CVD) is a major cause of death in the UK.

Look at the diagram of the external features of a heart.

Figure for question 12
(a)(i)

The coronary artery supplies the cardiac muscle with oxygen.

Label the diagram to show the position of one of the coronary arteries.

[1]
Reveal mark scheme Mark scheme for question 12(a)(i)
(a)(ii)

Angina is a symptom of CVD. Pain from angina is caused by cardiac muscle respiring anaerobically.

Explain why angina causes pain.

[2]
Reveal mark scheme Mark scheme for question 12(a)(ii)
(b)(i)

A 55 year old patient has severe chest pains due to a narrowed coronary artery.

The diagram shows the cross-section of a normal coronary artery and the patient’s artery.

Figure for question 12

Normal coronary artery
Patient’s coronary artery

The cross-sectional area of the normal coronary artery lumen is 18.1 mm2.

Calculate the cross-sectional area of the lumen of the patient’s artery.

Use the equations:

Question 12, shown as an image

Give your answer to 2 significant figures.

[3]
Reveal mark scheme Mark scheme for question 12(b)(i)
(b)(ii)

Calculate the percentage reduction in cross-sectional area for the lumen of the patient’s artery.

[1]
Reveal mark scheme Mark scheme for question 12(b)(ii)
(b)(iii)

CVD can be treated by different combinations of lifestyle changes, medicine and surgery.

Look at the information on CVD and how much the coronary artery has been narrowed

Figure for question 12

Justify why the patient would need surgery.

[2]
Reveal mark scheme Mark scheme for question 12(b)(iii)
(c)

* Doctors rely on different types of surgery to treat cardiovascular disease.

The table shows features of three surgical treatments.

Figure for question 12

Evaluate the three surgical treatments and decide which would be the best type of surgery for the 55 year old patient.

[6]
Reveal mark scheme Mark scheme for question 12(c)

Report a problem with a question on this page
What is wrong?

Goes to whoever maintains the question split. No account needed and nothing is published on this page.

Memes

Certified Combined Science memes. Peer-reviewed by nobody.

Laugh now. Cry in the exam hall later. Then come back and do a past paper.

Revise all three sciences
Just revise the fun one
Me the night before the chemistry paper
Knowing it's three sciences
Knowing which teacher does which
Remembering which equations are given
Remembering which science you're actually sitting today
Science enlightenment, combined

Mum 💖

which science is it today? 🥰

all of them somehow

go on genius!!! 💪

📱 Screen time this week · YouTube6h 21m

None of them were revised

Combined Science starter pack

Goggles worn on foreheadBunsen on the yellow flamePractical write-up, half doneThis website
Three sciences, four items